DP Physics (last assessment 2024)

Test builder »

Question 19M.2.HL.TZ2.5bi

Select a Test
Date May 2019 Marks available [Maximum mark: 3] Reference code 19M.2.HL.TZ2.5bi
Level HL Paper 2 Time zone TZ2
Command term Determine Question number bi Adapted from N/A
bi.
[Maximum mark: 3]
19M.2.HL.TZ2.5bi

A proton moves along a circular path in a region of a uniform magnetic field. The magnetic field is directed into the plane of the page.

The speed of the proton is 2.16 × 106 m s-1 and the magnetic field strength is 0.042 T.

(bi)

For this proton, determine, in m, the radius of the circular path. Give your answer to an appropriate number of significant figures.

[3]

Markscheme

« q v B = m v 2 R ⇒ » R = m v q B / 1.673 × 10 − 27 × 2.16 × 10 6 1.60 × 10 − 19 × 0.042  ✔

R = 0.538«m»  ✔

R = 0.54«m»   ✔

Examiners report

This was generally well answered although usually to 3 sf. Common mistakes were to substitute 0.042 for F and 1 for q. Also some candidates tried to answer in terms of electric fields.

Syllabus sections