Syllabus sections » |
5.4 – Magnetic effects of electric currents
Description
Nature of science:
Models and visualization: Magnetic field lines provide a powerful visualization of a magnetic field. Historically, the field lines helped scientists and engineers to understand a link that begins with the influence of one moving charge on another and leads onto relativity. (1.10)
Understandings:
- Magnetic fields
- Magnetic force
Applications and skills:
- Determining the direction of force on a charge moving in a magnetic field
- Determining the direction of force on a current-carrying conductor in a magnetic field
- Sketching and interpreting magnetic field patterns
- Determining the direction of the magnetic field based on current direction
- Solving problems involving magnetic forces, fields, current and charges
Guidance:
- Magnetic field patterns will be restricted to long straight conductors, solenoids, and bar magnets
Data booklet reference:
International-mindedness:
- The investigation of magnetism is one of the oldest studies by man and was used extensively by voyagers in the Mediterranean and beyond thousands of years ago
Theory of knowledge:
- Field patterns provide a visualization of a complex phenomenon, essential to an understanding of this topic. Why might it be useful to regard knowledge in a similar way, using the metaphor of knowledge as a map – a simplified representation of reality?
Utilization:
- Only comparatively recently has the magnetic compass been superseded by different technologies after hundreds of years of our dependence on it
- Modern medical scanners rely heavily on the strong, uniform magnetic fields produced by devices that utilize superconductors
- Particle accelerators such as the Large Hadron Collider at CERN rely on a variety of precise magnets for aligning the particle beams
Aims:
- Aims 2 and 9: visualizations frequently provide us with insights into the action of magnetic fields; however, the visualizations themselves have their own limitations
- Aim 7: computer-based simulations enable the visualization of electromagnetic fields in three-dimensional space
Directly related questions
- 17N.1.SL.TZ0.20: The diagram shows two current-carrying wires, P and Q, that both lie in the plane of the paper....
- 17N.1.SL.TZ0.20: The diagram shows two current-carrying wires, P and Q, that both lie in the plane of the paper....
- 17N.1.HL.TZ0.18: The diagram shows the magnetic field surrounding two current-carrying metal wires P and Q. The...
- 17N.1.HL.TZ0.18: The diagram shows the magnetic field surrounding two current-carrying metal wires P and Q. The...
- 21M.1.SL.TZ2.22: Magnetic field lines are an example of A. a discovery that helps us understand magnetism. B. a...
- 21M.1.SL.TZ2.22: Magnetic field lines are an example of A. a discovery that helps us understand magnetism. B. a...
- 18M.1.SL.TZ1.19: A liquid that contains negative charge carriers is flowing through a square pipe with sides A, B,...
- 18M.1.SL.TZ1.19: A liquid that contains negative charge carriers is flowing through a square pipe with sides A, B,...
-
18M.2.SL.TZ1.5a:
State the direction of the magnetic field.
-
18M.2.SL.TZ1.5a:
State the direction of the magnetic field.
-
18M.2.SL.TZ1.a:
State the direction of the magnetic field.
-
18M.2.SL.TZ1.5b:
Calculate, in N, the magnitude of the magnetic force acting on the electron.
-
18M.2.SL.TZ1.5b:
Calculate, in N, the magnitude of the magnetic force acting on the electron.
-
18M.2.SL.TZ1.b:
Calculate, in N, the magnitude of the magnetic force acting on the electron.
- 22M.1.HL.TZ1.22: A conductor is placed in a uniform magnetic field perpendicular to the plane of the paper. A...
- 22M.1.HL.TZ1.22: A conductor is placed in a uniform magnetic field perpendicular to the plane of the paper. A...
- 22M.1.SL.TZ2.22: A rectangular coil of wire RSTU is connected to a battery and placed in a magnetic field Z...
- 22M.1.SL.TZ2.22: A rectangular coil of wire RSTU is connected to a battery and placed in a magnetic field Z...
- 19M.2.HL.TZ2.5aii: Label with arrows on the diagram the velocity vector v of the proton.
- 19M.2.HL.TZ2.5aii: Label with arrows on the diagram the velocity vector v of the proton.
- 19M.2.HL.TZ2.aii: Label with arrows on the diagram the velocity vector v of the proton.
-
19M.2.HL.TZ2.5bi:
For this proton, determine, in m, the radius of the circular path. Give your answer to an appropriate number of significant figures.
-
19M.2.HL.TZ2.5bi:
For this proton, determine, in m, the radius of the circular path. Give your answer to an appropriate number of significant figures.
-
19M.2.HL.TZ2.bi:
For this proton, determine, in m, the radius of the circular path. Give your answer to an appropriate number of significant figures.
- 19M.2.HL.TZ2.5ai: Label with arrows on the diagram the magnetic force F on the proton.
- 19M.2.HL.TZ2.5ai: Label with arrows on the diagram the magnetic force F on the proton.
- 19M.2.HL.TZ2.ai: Label with arrows on the diagram the magnetic force F on the proton.
-
19M.1.SL.TZ1.23:
A beam of negative ions flows in the plane of the page through the magnetic field due to two bar magnets.
What is the direction in which the negative ions will be deflected?
A. Out of the page
B. Into the page X
C. Up the page ↑
D. Down the page ↓
-
19M.1.SL.TZ1.23:
A beam of negative ions flows in the plane of the page through the magnetic field due to two bar magnets.
What is the direction in which the negative ions will be deflected?
A. Out of the page
B. Into the page X
C. Up the page ↑
D. Down the page ↓
- 19M.2.SL.TZ2.5aii: Label with arrows on the velocity vector v of the proton.
- 19M.2.SL.TZ2.5aii: Label with arrows on the velocity vector v of the proton.
- 19M.2.SL.TZ2.aii: Label with arrows on the velocity vector v of the proton.
- 19M.1.SL.TZ2.21: A horizontal wire PQ lies perpendicular to a uniform horizontal magnetic field. A length of...
- 19M.1.SL.TZ2.21: A horizontal wire PQ lies perpendicular to a uniform horizontal magnetic field. A length of...
- 19M.1.HL.TZ1.19: A horizontal electrical cable carries a steady current out of the page. The Earth’s magnetic...
- 19M.1.HL.TZ1.19: A horizontal electrical cable carries a steady current out of the page. The Earth’s magnetic...
-
19N.2.SL.TZ0.4b(i):
Show that the radius of the path is about 6 cm.
-
19N.2.SL.TZ0.4b(i):
Show that the radius of the path is about 6 cm.
-
19N.2.SL.TZ0.b(i):
Show that the radius of the path is about 6 cm.
- 22N.1.SL.TZ0.19: A loop of wire lies in a magnetic field directed into the plane of the page. The loop carries a...
- 22N.1.SL.TZ0.19: A loop of wire lies in a magnetic field directed into the plane of the page. The loop carries a...
- 22N.2.SL.TZ0.5c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.5c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.HL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.HL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.HL.TZ0.c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.HL.TZ0.5c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.HL.TZ0.5c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.HL.TZ0.c.ii: Identify the direction of the magnetic force on the wire.
- 17N.2.HL.TZ0.2c: The cable between the satellites cuts the magnetic field lines of the Earth at right...
- 17N.2.HL.TZ0.2c: The cable between the satellites cuts the magnetic field lines of the Earth at right...
- 17N.2.HL.TZ0.c: The cable between the satellites cuts the magnetic field lines of the Earth at right...
- 18M.1.SL.TZ2.21: A beam of electrons moves between the poles of a magnet. ...
- 18M.1.SL.TZ2.21: A beam of electrons moves between the poles of a magnet. ...
- 18N.1.SL.TZ0.21: Two parallel wires are perpendicular to the page. The wires carry equal currents in opposite...
- 18N.1.SL.TZ0.21: Two parallel wires are perpendicular to the page. The wires carry equal currents in opposite...
- 18N.1.SL.TZ0.22: A particle of mass m and charge of magnitude q enters a region of uniform magnetic field B...
- 18N.1.SL.TZ0.22: A particle of mass m and charge of magnitude q enters a region of uniform magnetic field B...
- 18N.1.HL.TZ0.18: Two parallel wires P and Q are perpendicular to the page and carry equal currents. Point S is...
- 18N.1.HL.TZ0.18: Two parallel wires P and Q are perpendicular to the page and carry equal currents. Point S is...
- 19M.1.HL.TZ2.31: A proton of velocity v enters a region of electric and magnetic fields. The proton is not...
- 19M.1.HL.TZ2.31: A proton of velocity v enters a region of electric and magnetic fields. The proton is not...
-
19M.2.SL.TZ2.5b:
The speed of the proton is 2.16 × 106 m s-1 and the magnetic field strength is 0.042 T. For this proton, determine, in m, the radius of the circular path. Give your answer to an appropriate number of significant figures.
-
19M.2.SL.TZ2.5b:
The speed of the proton is 2.16 × 106 m s-1 and the magnetic field strength is 0.042 T. For this proton, determine, in m, the radius of the circular path. Give your answer to an appropriate number of significant figures.
-
19M.2.SL.TZ2.b:
The speed of the proton is 2.16 × 106 m s-1 and the magnetic field strength is 0.042 T. For this proton, determine, in m, the radius of the circular path. Give your answer to an appropriate number of significant figures.
- 19M.1.HL.TZ1.18: Two currents of 3 A and 1 A are established in the same direction through two parallel straight...
- 19M.1.HL.TZ1.18: Two currents of 3 A and 1 A are established in the same direction through two parallel straight...
- 19N.1.SL.TZ0.20: When a wire with an electric current I is placed in a magnetic field of strength B it experiences...
- 19N.1.SL.TZ0.20: When a wire with an electric current I is placed in a magnetic field of strength B it experiences...
- 19N.2.SL.TZ0.4a: Explain why the path of the proton is a circle.
- 19N.2.SL.TZ0.4a: Explain why the path of the proton is a circle.
- 19N.2.SL.TZ0.a: Explain why the path of the proton is a circle.
- 20N.1.SL.TZ0.20: A current in a wire lies between the poles of a magnet. What is the direction of the...
- 20N.1.SL.TZ0.20: A current in a wire lies between the poles of a magnet. What is the direction of the...
- 21M.1.HL.TZ1.18: An electron enters the space inside a current-carrying solenoid. The velocity of the electron...
- 21M.1.HL.TZ1.18: An electron enters the space inside a current-carrying solenoid. The velocity of the electron...
- 21M.1.SL.TZ1.21: A long straight vertical conductor carries a current I upwards. An electron moves with horizontal...
- 21M.1.SL.TZ1.21: A long straight vertical conductor carries a current I upwards. An electron moves with horizontal...
- 21M.1.SL.TZ2.19: An ion moves in a circle in a uniform magnetic field. Which single change would increase...
- 21M.1.SL.TZ2.19: An ion moves in a circle in a uniform magnetic field. Which single change would increase...
- 21N.1.HL.TZ0.18: Two parallel wires carry equal currents in the same direction out of the paper. Which diagram...
- 21N.1.HL.TZ0.18: Two parallel wires carry equal currents in the same direction out of the paper. Which diagram...
- 21N.2.SL.TZ0.4c.i: On the diagram draw an arrow to show the direction of the magnetic field at Q due to wire X alone.
- 21N.2.SL.TZ0.4c.i: On the diagram draw an arrow to show the direction of the magnetic field at Q due to wire X alone.
- 21N.2.SL.TZ0.c.i: On the diagram draw an arrow to show the direction of the magnetic field at Q due to wire X alone.
- 21N.2.SL.TZ0.4c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
- 21N.2.SL.TZ0.4c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
- 21N.2.SL.TZ0.c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
-
21N.2.HL.TZ0.5c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
-
21N.2.HL.TZ0.5c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
-
21N.2.HL.TZ0.c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
- 22M.1.HL.TZ2.19: The coil of a direct current electric motor is turning with a period T. At t = 0 the coil is in...
- 22M.1.HL.TZ2.19: The coil of a direct current electric motor is turning with a period T. At t = 0 the coil is in...
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 23M.1.HL.TZ1.18: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1.SL.TZ1.21: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1.SL.TZ1.21: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1.HL.TZ1.18: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
-
23M.2.HL.TZ1.7a:
Explain, by reference to Faraday’s law of electromagnetic induction, why there is an electromotive force (emf) induced in the loop as it leaves the region of magnetic field.
-
23M.2.HL.TZ1.7a:
Explain, by reference to Faraday’s law of electromagnetic induction, why there is an electromotive force (emf) induced in the loop as it leaves the region of magnetic field.
-
23M.2.HL.TZ1.a:
Explain, by reference to Faraday’s law of electromagnetic induction, why there is an electromotive force (emf) induced in the loop as it leaves the region of magnetic field.
- 23M.3.HL.TZ1.3a: Outline why there can be no magnetic force on the proton in the proton’s rest frame.
- 23M.3.SL.TZ1.3a: Outline why there can be no magnetic force on the proton in the proton’s rest frame.
- 23M.3.HL.TZ1.3a: Outline why there can be no magnetic force on the proton in the proton’s rest frame.
- 23M.3.HL.TZ1.a: Outline why there can be no magnetic force on the proton in the proton’s rest frame.
- 23M.3.SL.TZ1.3a: Outline why there can be no magnetic force on the proton in the proton’s rest frame.
- 23M.3.SL.TZ1.a: Outline why there can be no magnetic force on the proton in the proton’s rest frame.
- 23M.1.SL.TZ2.21: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1.HL.TZ2.18: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1.SL.TZ2.21: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1.HL.TZ2.18: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
-
23M.1.SL.TZ2.22:
An electron is accelerated from rest through a potential difference V.
What is the maximum speed of the electron?
A.B.
C.
D.
-
23M.1.SL.TZ2.22:
An electron is accelerated from rest through a potential difference V.
What is the maximum speed of the electron?
A.B.
C.
D.
-
23M.2.SL.TZ2.4a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.HL.TZ2.4a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.HL.TZ2.4a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.HL.TZ2.a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.SL.TZ2.4a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.SL.TZ2.a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.