DP Physics (last assessment 2024)

Question 19M.2.SL.TZ2.6bi

Date	May 2019	Marks available	[Maximum mark: 2]	Reference code	19M.2.SL.TZ2.6bi
Level	SL	Paper	2	Time zone	TZ2
Command term	Determine	Question number	bi	Adapted from	N/A

bi.

[Maximum mark: 2]

19M.2.SL.TZ2.6bi

Deuterium, ${}_1^2{\text{H}}$ , undergoes fusion according to the following reaction.

${}_1^2{\text{H}} + {}_1^2{\text{H}} \to {}_1^3{\text{H}} + {\text{X}}$

The following data are available for binding energies per nucleon.

${}_1^2{\text{H}} = 1.12{\text{MeV}}$

${}_1^3{\text{H}} = 2.78{\text{MeV}}$

(bi)

Determine, in MeV, the energy released.

[2]

Markscheme

«3 x 2.78 − 2 × 2 × 1.12»

See 3 × 2.78/8.34 OR 2 × 2 × 1.12/4.48✔

3.86 «MeV» ✔

Examiners report

The majority of candidates missed the fact that the figures given were the binding energies per nucleon. Many complicated calculations were also seen, particularly at SL, that involved E = mc².

Syllabus sections

Core

Core » Topic 7: Atomic, nuclear and particle physics » 7.2 – Nuclear reactions

Core » Topic 7: Atomic, nuclear and particle physics

Question 19M.2.SL.TZ2.6bi

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