DP Physics (last assessment 2024)

Question 19M.3.HL.TZ2.c

Date	May 2019	Marks available	[Maximum mark: 2]	Reference code	19M.3.HL.TZ2.c
Level	HL	Paper	3	Time zone	TZ2
Command term	Calculate	Question number	c	Adapted from	N/A

[Maximum mark: 2]

19M.3.HL.TZ2.c

A solid sphere is released from rest below the surface of a fluid and begins to fall.

The weight of the sphere is 6.16 mN and the radius is 5.00 × 10^-3 m. For a fluid of density 8.50 × 10² kg m^-3, the terminal speed is found to be 0.280 m s^-1. Calculate the viscosity of the fluid.

[2]

Markscheme

any evidence (numerical or algebraic) of a realisation that

$6\pi \eta rv + \rho gV = W$ ✔

« $\eta = \frac{{6.16 \times {{10}^{ - 3}} - 4.366 \times {{10}^{ - 3}}}}{{6\pi \times 0.005 \times 0.280}}$ »

$\eta = 0.0680$ «Pas»✔

Examiners report

When the condition for forces in equilibrium was correctly formed, many candidates managed to obtain the correct answer. The working was often poorly presented making it difficult to mark or award marks for the process.

Syllabus sections

Option B: Engineering physics

Option B: Engineering physics » Option B: Engineering physics (Additional higher level option topics) » B.3 – Fluids and fluid dynamics (HL only)

Option B: Engineering physics » Option B: Engineering physics (Additional higher level option topics)

Question 19M.3.HL.TZ2.c

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