DP Physics (last assessment 2024)

Question 19M.3.HL.TZ1.b.ii

Date	May 2019	Marks available	[Maximum mark: 2]	Reference code	19M.3.HL.TZ1.b.ii
Level	HL	Paper	3	Time zone	TZ1
Command term	Calculate	Question number	b.ii	Adapted from	N/A

b.ii.

[Maximum mark: 2]

19M.3.HL.TZ1.b.ii

Gasoline of density 720 kg m^–3 flows in a pipe of constant diameter.

Calculate the difference in pressure between X and Y.

[2]

Markscheme

Bernoulli: « $\frac{1}{2}$ $\rho v_x^2$ + 0 + P_x = $\frac{1}{2}$ $\rho v_y^2$ + pgH + P_y » gives P_x − P_y = pgH ✔

P_x − P_y= 720 × 9.81 × 1.2 = 8.5 «kPa» ✔

Award [2] for bald correct answer.

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Examiners report

In b) most candidates well noted and understood the application of the continuity equation and successfully went on to correctly calculate the pressure difference.

Syllabus sections

Option B: Engineering physics

Option B: Engineering physics » Option B: Engineering physics (Additional higher level option topics) » B.3 – Fluids and fluid dynamics (HL only)

Option B: Engineering physics » Option B: Engineering physics (Additional higher level option topics)

Question 19M.3.HL.TZ1.b.ii

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