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Question 21N.2.HL.TZ0.5c.i

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Date November 2021 Marks available [Maximum mark: 2] Reference code 21N.2.HL.TZ0.5c.i
Level HL Paper 2 Time zone TZ0
Command term Calculate Question number c.i Adapted from N/A
c.i.
[Maximum mark: 2]
21N.2.HL.TZ0.5c.i

A square loop of side 5.0 cm enters a region of uniform magnetic field at t = 0. The loop exits the region of magnetic field at t = 3.5 s. The magnetic field strength is 0.94 T and is directed into the plane of the paper. The magnetic field extends over a length 65 cm. The speed of the loop is constant.

(c.i)

There are 85 turns of wire in the loop. Calculate the maximum induced emf in the loop.

[2]

Markscheme

ALTERNATIVE 1

maximum flux at «5.0×5.0×10-4×85×0.94» =0.199750.20«Wb» ✓

emf = «0.200.25=» 0.80«V» ✓


ALTERNATIVE 2

emf induced in one turn = BvL0.94×0.20×0.05=0.0094«V» ✓

emf =85×0.0094=0.80«V» ✓

 

Award [2] marks for a bald correct answer.

Allow ECF from MP1.