DP Physics (last assessment 2024)

Question 18M.2.HL.TZ2.d.ii

Date	May 2018	Marks available	[Maximum mark: 1]	Reference code	18M.2.HL.TZ2.d.ii
Level	HL	Paper	2	Time zone	TZ2
Command term	Suggest	Question number	d.ii	Adapted from	N/A

d.ii.

[Maximum mark: 1]

18M.2.HL.TZ2.d.ii

Rhodium-106 ( $_{\,\,\,45}^{106}{\text{Rh}}$ ) decays into palladium-106 ( $_{\,\,\,46}^{106}{\text{Pd}}$ ) by beta minus (β^–) decay. The diagram shows some of the nuclear energy levels of rhodium-106 and palladium-106. The arrow represents the β^– decay.

M18/4/PHYSI/HP2/ENG/TZ2/09.d

Suggest why the β^– decay is followed by the emission of a gamma ray photon.

[1]

Markscheme

the palladium nucleus emits the photon when it decays into the ground state «from the excited state»

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Core

Core » Topic 7: Atomic, nuclear and particle physics » 7.1 – Discrete energy and radioactivity

Core » Topic 7: Atomic, nuclear and particle physics

Question 18M.2.HL.TZ2.d.ii

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