DP Physics (last assessment 2024)

Question 18N.2.HL.TZ0.6c

Date	November 2018	Marks available	[Maximum mark: 2]	Reference code	18N.2.HL.TZ0.6c
Level	HL	Paper	2	Time zone	TZ0
Command term	Explain	Question number	c	Adapted from	N/A

[Maximum mark: 2]

18N.2.HL.TZ0.6c

${}_{15}^{32}{\text{P}}$ is formed when a nucleus of deuterium ( ${}_{1}^{2}{\text{H}}$ ) collides with a nucleus of ${}_{15}^{31}{\text{P}}$ . The radius of a deuterium nucleus is 1.5 fm.

(c)

${}_{15}^{32}{\text{P}}$ undergoes beta-minus (β^–) decay. Explain why the energy gained by the emitted beta particles in this decay is not the same for every beta particle.

[2]

Markscheme

«electron» antineutrino also emitted ✔

energy split between electron and «anti»neutrino ✔

Syllabus sections

Core

Additional higher level (AHL)

Additional higher level (AHL) » Topic 12: Quantum and nuclear physics » 12.2 – Nuclear physics

Additional higher level (AHL) » Topic 12: Quantum and nuclear physics

Core » Topic 7: Atomic, nuclear and particle physics » 7.1 – Discrete energy and radioactivity

Core » Topic 7: Atomic, nuclear and particle physics

Question 18N.2.HL.TZ0.6c

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