Syllabus sections » |
8.2 – Thermal energy transfer
Description
Nature of science:
Simple and complex modelling: The kinetic theory of gases is a simple mathematical model that produces a good approximation of the behaviour of real gases. Scientists are also attempting to model the Earth’s climate, which is a far more complex system. Advances in data availability and the ability to include more processes in the models together with continued testing and scientific debate on the various models will improve the ability to predict climate change more accurately. (1.12)
Understandings:
- Conduction, convection and thermal radiation
- Black-body radiation
- Albedo and emissivity
- The solar constant
- The greenhouse effect
- Energy balance in the Earth surface–atmosphere system
Applications and skills:
- Sketching and interpreting graphs showing the variation of intensity with wavelength for bodies emitting thermal radiation at different temperatures
- Solving problems involving the Stefan–Boltzmann law and Wien’s displacement law
- Describing the effects of the Earth’s atmosphere on the mean surface temperature
- Solving problems involving albedo, emissivity, solar constant and the Earth’s average temperature
Guidance:
- Discussion of conduction and convection will be qualitative only
- Discussion of conduction is limited to intermolecular and electron collisions
- Discussion of convection is limited to simple gas or liquid transfer via density differences
- The absorption of infrared radiation by greenhouse gases should be described in terms of the molecular energy levels and the subsequent emission of radiation in all directions
- The greenhouse gases to be considered are CH4, H2O, CO2 and N2O. It is sufficient for students to know that each has both natural and man-made origins.
- Earth’s albedo varies daily and is dependent on season (cloud formations) and latitude. The global annual mean albedo will be taken to be 0.3 (30%) for Earth.
Data booklet reference:
International-mindedness:
- The concern over the possible impact of climate change has resulted in an abundance of international press coverage, many political discussions within and between nations, and the consideration of people, corporations, and the environment when deciding on future plans for our planet. IB graduates should be aware of the science behind many of these scenarios.
Theory of knowledge:
- The debate about global warming illustrates the difficulties that arise when scientists cannot always agree on the interpretation of the data, especially as the solution would involve large-scale action through international government cooperation. When scientists disagree, how do we decide between competing theories?
Utilization:
- Climate models and the variation in detail/processes included
- Environmental chemistry (see Chemistry option topic C)
- Climate change (see Biology sub-topic 4.4 and Environmental systems andsocieties topics 5 and 6)
- The normal distribution curve is explored in Mathematical studies SL sub-topic 4.1
Aims:
- Aim 4: this topic gives students the opportunity to understand the wide range of scientific analysis behind climate change issues
- Aim 6: simulations of energy exchange in the Earth surface–atmosphere system
- Aim 8: while science has the ability to analyse and possibly help solve climate change issues, students should be aware of the impact of science on the initiation of conditions that allowed climate change due to human contributions to occur. Students should also be aware of the way science can be used to promote the interests of one side of the debate on climate change (or, conversely, to hinder debate).
Directly related questions
- 17N.1.SL.TZ0.29: The three statements give possible reasons why an average value should be used for the solar...
- 17N.1.SL.TZ0.29: The three statements give possible reasons why an average value should be used for the solar...
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17N.2.SL.TZ0.5b.i:
Determine the mean temperature of the Earth.
-
17N.2.SL.TZ0.5b.i:
Determine the mean temperature of the Earth.
-
17N.2.SL.TZ0.b.i:
Determine the mean temperature of the Earth.
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21M.2.SL.TZ1.4a.i:
Explain why the power incident on the planet is
-
21M.2.SL.TZ1.4a.i:
Explain why the power incident on the planet is
-
21M.2.SL.TZ1.a.i:
Explain why the power incident on the planet is
- 18M.1.SL.TZ1.30: The diagram shows a simple climate model for the Earth. What does this model predict for the...
- 18M.1.SL.TZ1.30: The diagram shows a simple climate model for the Earth. What does this model predict for the...
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18M.2.SL.TZ1.6c.ii:
Discuss how the frequency of the radiation emitted by a black body can be used to estimate the temperature of the body.
-
18M.2.SL.TZ1.6c.ii:
Discuss how the frequency of the radiation emitted by a black body can be used to estimate the temperature of the body.
-
18M.2.SL.TZ1.c.ii:
Discuss how the frequency of the radiation emitted by a black body can be used to estimate the temperature of the body.
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18M.1.SL.TZ2.30:
Mars and Earth act as black bodies. The and .
What is the value of ?
A.
B.
C.
D.
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18M.1.SL.TZ2.30:
Mars and Earth act as black bodies. The and .
What is the value of ?
A.
B.
C.
D.
- 21N.1.SL.TZ0.30: Which is correct for a black-body radiator? A. The power it emits from a unit surface area...
- 21N.1.SL.TZ0.30: Which is correct for a black-body radiator? A. The power it emits from a unit surface area...
- 21N.2.SL.TZ0.6a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
- 21N.2.SL.TZ0.6a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
- 21N.2.SL.TZ0.a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
- 21N.2.HL.TZ0.6a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
- 21N.2.HL.TZ0.6a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
- 21N.2.HL.TZ0.a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
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21N.2.HL.TZ0.6a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2.
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21N.2.HL.TZ0.6a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2.
-
21N.2.HL.TZ0.a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2.
- 18N.2.SL.TZ0.6c: The atmosphere of Mars is composed mainly of carbon dioxide and has a pressure less than 1 % of...
- 18N.2.SL.TZ0.6c: The atmosphere of Mars is composed mainly of carbon dioxide and has a pressure less than 1 % of...
- 18N.2.SL.TZ0.c: The atmosphere of Mars is composed mainly of carbon dioxide and has a pressure less than 1 % of...
- 18N.1.SL.TZ0.30: Light of intensity I0 is incident on a snow-covered area of Earth. In a model of this...
- 18N.1.SL.TZ0.30: Light of intensity I0 is incident on a snow-covered area of Earth. In a model of this...
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18N.2.HL.TZ0.8c.i:
Show that the intensity of solar radiation at the orbit of Mars is about 600 W m–2.
-
18N.2.HL.TZ0.c.i:
Show that the intensity of solar radiation at the orbit of Mars is about 600 W m–2.
-
18N.2.HL.TZ0.8c.i:
Show that the intensity of solar radiation at the orbit of Mars is about 600 W m–2.
- 18N.2.HL.TZ0.8c.iii: The atmosphere of Mars is composed mainly of carbon dioxide and has a pressure less than 1 % of...
- 18N.2.HL.TZ0.c.iii: The atmosphere of Mars is composed mainly of carbon dioxide and has a pressure less than 1 % of...
- 18N.2.HL.TZ0.8c.iii: The atmosphere of Mars is composed mainly of carbon dioxide and has a pressure less than 1 % of...
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18N.2.HL.TZ0.8c.ii:
Determine, in K, the mean surface temperature of Mars. Assume that Mars acts as a black body.
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18N.2.HL.TZ0.c.ii:
Determine, in K, the mean surface temperature of Mars. Assume that Mars acts as a black body.
-
18N.2.HL.TZ0.8c.ii:
Determine, in K, the mean surface temperature of Mars. Assume that Mars acts as a black body.
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22M.1.SL.TZ1.30:
The diagram shows, for a region on the Earth’s surface, the incident, radiated and reflected intensities of the solar radiation.
What is the albedo of the region?
A.
B.
C.
D.
-
22M.1.SL.TZ1.30:
The diagram shows, for a region on the Earth’s surface, the incident, radiated and reflected intensities of the solar radiation.
What is the albedo of the region?
A.
B.
C.
D.
- 22M.2.SL.TZ1.2d.i: State how energy is transferred from the inside of the metal pipe to the outside of the metal pipe.
- 22M.2.SL.TZ1.2d.i: State how energy is transferred from the inside of the metal pipe to the outside of the metal pipe.
- 22M.2.SL.TZ1.d.i: State how energy is transferred from the inside of the metal pipe to the outside of the metal pipe.
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22M.2.SL.TZ1.2d.ii:
The missing section of insulation is 0.56 m long and the external radius of the pipe is 0.067 m. The emissivity of the pipe surface is 0.40. Determine the energy lost every second from the pipe surface. Ignore any absorption of radiation by the pipe surface.
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22M.2.SL.TZ1.2d.ii:
The missing section of insulation is 0.56 m long and the external radius of the pipe is 0.067 m. The emissivity of the pipe surface is 0.40. Determine the energy lost every second from the pipe surface. Ignore any absorption of radiation by the pipe surface.
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22M.2.SL.TZ1.d.ii:
The missing section of insulation is 0.56 m long and the external radius of the pipe is 0.067 m. The emissivity of the pipe surface is 0.40. Determine the energy lost every second from the pipe surface. Ignore any absorption of radiation by the pipe surface.
- 19M.2.HL.TZ2.7ci: Calculate the additional intensity that must be lost by the oceans so that the water temperature...
- 19M.2.HL.TZ2.7ci: Calculate the additional intensity that must be lost by the oceans so that the water temperature...
- 19M.2.HL.TZ2.ci: Calculate the additional intensity that must be lost by the oceans so that the water temperature...
- 19M.2.HL.TZ2.7cii: Suggest a mechanism by which the additional intensity can be lost.
- 19M.2.HL.TZ2.7cii: Suggest a mechanism by which the additional intensity can be lost.
- 19M.2.HL.TZ2.cii: Suggest a mechanism by which the additional intensity can be lost.
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19M.2.SL.TZ1.6b:
The albedo of the Earth’s atmosphere is 0.28. Outline why the maximum temperature of a black body on the Earth when the Sun is overhead is less than that at point A on the Moon.
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19M.2.SL.TZ1.6b:
The albedo of the Earth’s atmosphere is 0.28. Outline why the maximum temperature of a black body on the Earth when the Sun is overhead is less than that at point A on the Moon.
-
19M.2.SL.TZ1.b:
The albedo of the Earth’s atmosphere is 0.28. Outline why the maximum temperature of a black body on the Earth when the Sun is overhead is less than that at point A on the Moon.
- 19M.2.SL.TZ1.6a.ii: Another black body is on the Moon’s surface at point B. Outline, without calculation, why the...
- 19M.2.SL.TZ1.6a.ii: Another black body is on the Moon’s surface at point B. Outline, without calculation, why the...
- 19M.2.SL.TZ1.a.ii: Another black body is on the Moon’s surface at point B. Outline, without calculation, why the...
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19M.2.SL.TZ1.6a.i:
A black body is on the Moon’s surface at point A. Show that the maximum temperature that this body can reach is 400 K. Assume that the Earth and the Moon are the same distance from the Sun.
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19M.2.SL.TZ1.6a.i:
A black body is on the Moon’s surface at point A. Show that the maximum temperature that this body can reach is 400 K. Assume that the Earth and the Moon are the same distance from the Sun.
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19M.2.SL.TZ1.a.i:
A black body is on the Moon’s surface at point A. Show that the maximum temperature that this body can reach is 400 K. Assume that the Earth and the Moon are the same distance from the Sun.
- 19M.2.SL.TZ2.7b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.SL.TZ2.7b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.SL.TZ2.b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.SL.TZ2.7a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.SL.TZ2.7a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.SL.TZ2.a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19N.1.SL.TZ0.30: What is meant by the statement that the average albedo of the Moon is 0.1? A. 10% of the...
- 19N.1.SL.TZ0.30: What is meant by the statement that the average albedo of the Moon is 0.1? A. 10% of the...
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22N.1.SL.TZ0.27:
The electromagnetic spectrum radiated by a black body at temperature T shows a peak at wavelength p.
What is the variation of p with T?
-
22N.1.SL.TZ0.27:
The electromagnetic spectrum radiated by a black body at temperature T shows a peak at wavelength p.
What is the variation of p with T?
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22N.2.SL.TZ0.2a.ii:
Estimate, in °C, the temperature of the roof tiles.
-
22N.2.SL.TZ0.2a.ii:
Estimate, in °C, the temperature of the roof tiles.
-
22N.2.SL.TZ0.a.ii:
Estimate, in °C, the temperature of the roof tiles.
-
22N.2.HL.TZ0.2a.ii:
Estimate, in °C, the temperature of the roof tiles.
-
22N.2.HL.TZ0.2a.ii:
Estimate, in °C, the temperature of the roof tiles.
-
22N.2.HL.TZ0.a.ii:
Estimate, in °C, the temperature of the roof tiles.
-
17N.1.SL.TZ0.28:
A black body emits radiation with its greatest intensity at a wavelength of Imax. The surface temperature of the black body doubles without any other change occurring. What is the wavelength at which the greatest intensity of radiation is emitted?
A. Imax
B.
C.
D.
-
17N.1.SL.TZ0.28:
A black body emits radiation with its greatest intensity at a wavelength of Imax. The surface temperature of the black body doubles without any other change occurring. What is the wavelength at which the greatest intensity of radiation is emitted?
A. Imax
B.
C.
D.
- 17N.2.SL.TZ0.5b.ii: Suggest how the difference between λS and λE helps to account for the greenhouse effect.
- 17N.2.SL.TZ0.5b.ii: Suggest how the difference between λS and λE helps to account for the greenhouse effect.
- 17N.2.SL.TZ0.b.ii: Suggest how the difference between λS and λE helps to account for the greenhouse effect.
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18M.2.SL.TZ1.6c.i:
State what is meant by thermal radiation.
-
18M.2.SL.TZ1.6c.i:
State what is meant by thermal radiation.
-
18M.2.SL.TZ1.c.i:
State what is meant by thermal radiation.
-
18M.2.SL.TZ1.6c.iii:
Calculate the peak wavelength in the intensity of the radiation emitted by the ice sample.
-
18M.2.SL.TZ1.6c.iii:
Calculate the peak wavelength in the intensity of the radiation emitted by the ice sample.
-
18M.2.SL.TZ1.c.iii:
Calculate the peak wavelength in the intensity of the radiation emitted by the ice sample.
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18M.1.SL.TZ2.29:
Three gases in the atmosphere are
I. carbon dioxide (CO2)
II. dinitrogen monoxide (N2O)
III. oxygen (O2).
Which of these are considered to be greenhouse gases?
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
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18M.1.SL.TZ2.29:
Three gases in the atmosphere are
I. carbon dioxide (CO2)
II. dinitrogen monoxide (N2O)
III. oxygen (O2).
Which of these are considered to be greenhouse gases?
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
- 18M.1.HL.TZ1.24: The dashed line on the graph shows the variation with wavelength of the intensity of solar...
- 18M.1.HL.TZ1.24: The dashed line on the graph shows the variation with wavelength of the intensity of solar...
-
18M.2.HL.TZ1.6c.i:
State what is meant by thermal radiation.
-
18M.2.HL.TZ1.6c.i:
State what is meant by thermal radiation.
-
18M.2.HL.TZ1.c.i:
State what is meant by thermal radiation.
-
18M.2.HL.TZ1.6c.ii:
Discuss how the frequency of the radiation emitted by a black body can be used to estimate the temperature of the body.
-
18M.2.HL.TZ1.6c.ii:
Discuss how the frequency of the radiation emitted by a black body can be used to estimate the temperature of the body.
-
18M.2.HL.TZ1.c.ii:
Discuss how the frequency of the radiation emitted by a black body can be used to estimate the temperature of the body.
-
18M.2.HL.TZ1.6c.iii:
Calculate the peak wavelength in the intensity of the radiation emitted by the ice sample.
-
18M.2.HL.TZ1.6c.iii:
Calculate the peak wavelength in the intensity of the radiation emitted by the ice sample.
-
18M.2.HL.TZ1.c.iii:
Calculate the peak wavelength in the intensity of the radiation emitted by the ice sample.
-
18N.2.SL.TZ0.6a:
Show that the intensity of solar radiation at the orbit of Mars is about 600 W m–2.
-
18N.2.SL.TZ0.6a:
Show that the intensity of solar radiation at the orbit of Mars is about 600 W m–2.
-
18N.2.SL.TZ0.a:
Show that the intensity of solar radiation at the orbit of Mars is about 600 W m–2.
-
18N.2.SL.TZ0.6b:
Determine, in K, the mean surface temperature of Mars. Assume that Mars acts as a black body.
-
18N.2.SL.TZ0.6b:
Determine, in K, the mean surface temperature of Mars. Assume that Mars acts as a black body.
-
18N.2.SL.TZ0.b:
Determine, in K, the mean surface temperature of Mars. Assume that Mars acts as a black body.
- 19M.2.HL.TZ2.7a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.HL.TZ2.7a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.HL.TZ2.a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.HL.TZ2.7b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.HL.TZ2.7b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.HL.TZ2.b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.1.SL.TZ1.29: A beaker containing 1 kg of water at room temperature is heated on a 400 W hot plate. The...
- 19M.1.SL.TZ1.29: A beaker containing 1 kg of water at room temperature is heated on a 400 W hot plate. The...
- 19M.1.SL.TZ2.30: The orbital radius of the Earth around the Sun is 1.5 times that of Venus. What is the intensity...
- 19M.1.SL.TZ2.30: The orbital radius of the Earth around the Sun is 1.5 times that of Venus. What is the intensity...
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20N.1.SL.TZ0.26:
The average temperature of the surface of a planet is five times greater than the average temperature of the surface of its moon. The emissivities of the planet and the moon are the same. The average intensity radiated by the planet is . What is the average intensity radiated by its moon?
A.
B.
C.
D.
-
20N.1.SL.TZ0.26:
The average temperature of the surface of a planet is five times greater than the average temperature of the surface of its moon. The emissivities of the planet and the moon are the same. The average intensity radiated by the planet is . What is the average intensity radiated by its moon?
A.
B.
C.
D.
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21M.2.SL.TZ1.4a.ii:
The albedo of the planet is . The equilibrium surface temperature of the planet is T. Derive the expression
where e is the emissivity of the planet.
-
21M.2.SL.TZ1.4a.ii:
The albedo of the planet is . The equilibrium surface temperature of the planet is T. Derive the expression
where e is the emissivity of the planet.
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21M.2.SL.TZ1.a.ii:
The albedo of the planet is . The equilibrium surface temperature of the planet is T. Derive the expression
where e is the emissivity of the planet.
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21M.2.SL.TZ1.4b:
On average, the Moon is the same distance from the Sun as the Earth. The Moon can be assumed to have an emissivity e = 1 and an albedo = 0.13. The solar constant is 1.36 × 103 W m−2. Calculate the surface temperature of the Moon.
-
21M.2.SL.TZ1.4b:
On average, the Moon is the same distance from the Sun as the Earth. The Moon can be assumed to have an emissivity e = 1 and an albedo = 0.13. The solar constant is 1.36 × 103 W m−2. Calculate the surface temperature of the Moon.
-
21M.2.SL.TZ1.b:
On average, the Moon is the same distance from the Sun as the Earth. The Moon can be assumed to have an emissivity e = 1 and an albedo = 0.13. The solar constant is 1.36 × 103 W m−2. Calculate the surface temperature of the Moon.
-
21M.1.SL.TZ1.29:
A black body at temperature T emits radiation with peak wavelength and power P. What is the temperature of the black body and the power emitted for a peak wavelength of ?
-
21M.1.SL.TZ1.29:
A black body at temperature T emits radiation with peak wavelength and power P. What is the temperature of the black body and the power emitted for a peak wavelength of ?
- 21M.1.SL.TZ1.30: In a simple climate model for a planet, the incoming intensity is 400 W m−2 and the...
- 21M.1.SL.TZ1.30: In a simple climate model for a planet, the incoming intensity is 400 W m−2 and the...
-
21M.1.SL.TZ2.29:
A black-body radiator emits a peak wavelength of and a maximum power of . The peak wavelength emitted by a second black-body radiator with the same surface area is . What is the total power of the second black-body radiator?
A.
B.
C.
D.
-
21M.1.SL.TZ2.29:
A black-body radiator emits a peak wavelength of and a maximum power of . The peak wavelength emitted by a second black-body radiator with the same surface area is . What is the total power of the second black-body radiator?
A.
B.
C.
D.
- 21M.1.SL.TZ2.30: What is the main role of carbon dioxide in the greenhouse effect? A. It absorbs incoming...
- 21M.1.SL.TZ2.30: What is the main role of carbon dioxide in the greenhouse effect? A. It absorbs incoming...
-
21N.2.SL.TZ0.6a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2
-
21N.2.SL.TZ0.6a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2
-
21N.2.SL.TZ0.a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2
- 22M.1.SL.TZ1.29: Three mechanisms that affect the composition of the atmosphere of the Earth are: I. Loss of...
- 22M.1.SL.TZ1.29: Three mechanisms that affect the composition of the atmosphere of the Earth are: I. Loss of...
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22M.2.SL.TZ1.2d.iii:
Describe one other method by which significant amounts of energy can be transferred from the pipe to the surroundings.
-
22M.2.SL.TZ1.2d.iii:
Describe one other method by which significant amounts of energy can be transferred from the pipe to the surroundings.
-
22M.2.SL.TZ1.d.iii:
Describe one other method by which significant amounts of energy can be transferred from the pipe to the surroundings.
-
22N.1.SL.TZ0.30:
Planet and planet both emit radiation as black bodies. Planet has twice the surface temperature and one third of the radius of planet .
What is ?
A.B.
C.
D.
-
22N.1.SL.TZ0.30:
Planet and planet both emit radiation as black bodies. Planet has twice the surface temperature and one third of the radius of planet .
What is ?
A.B.
C.
D.
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23M.1.HL.TZ1.9:
The temperature of an object is changed from θ1 °C to θ2 °C. What is the change in temperature measured in kelvin?
A. (θ2 − θ1)B. (θ2 − θ1) + 273
C. (θ2 − θ1) − 273
D. 273 − (θ2 − θ1)
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23M.1.SL.TZ1.11:
The temperature of an object is changed from θ1 °C to θ2 °C. What is the change in temperature measured in kelvin?
A. (θ2 − θ1)B. (θ2 − θ1) + 273
C. (θ2 − θ1) − 273
D. 273 − (θ2 − θ1)
-
23M.1.HL.TZ1.9:
The temperature of an object is changed from θ1 °C to θ2 °C. What is the change in temperature measured in kelvin?
A. (θ2 − θ1)B. (θ2 − θ1) + 273
C. (θ2 − θ1) − 273
D. 273 − (θ2 − θ1)
-
23M.1.SL.TZ1.11:
The temperature of an object is changed from θ1 °C to θ2 °C. What is the change in temperature measured in kelvin?
A. (θ2 − θ1)B. (θ2 − θ1) + 273
C. (θ2 − θ1) − 273
D. 273 − (θ2 − θ1)
-
23M.1.HL.TZ1.10:
A metal cube X of length L is heated gaining thermal energy Q. Its temperature rises by ΔT. A second cube Y, of length 2L, made of the same material, gains thermal energy of 2Q.
What is the temperature rise of Y?
A.B.
C.
D.
-
23M.1.HL.TZ1.10:
A metal cube X of length L is heated gaining thermal energy Q. Its temperature rises by ΔT. A second cube Y, of length 2L, made of the same material, gains thermal energy of 2Q.
What is the temperature rise of Y?
A.B.
C.
D.
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23M.2.SL.TZ1.2a:
Show that the average rate at which thermal energy is transferred into the chocolate is about 15 W.
-
23M.2.HL.TZ1.2a:
Show that the average rate at which thermal energy is transferred into the chocolate is about 15 W.
-
23M.2.SL.TZ1.2a:
Show that the average rate at which thermal energy is transferred into the chocolate is about 15 W.
-
23M.2.SL.TZ1.a:
Show that the average rate at which thermal energy is transferred into the chocolate is about 15 W.
-
23M.2.HL.TZ1.2a:
Show that the average rate at which thermal energy is transferred into the chocolate is about 15 W.
-
23M.2.HL.TZ1.a:
Show that the average rate at which thermal energy is transferred into the chocolate is about 15 W.
- 23M.1.SL.TZ1.13: Two blocks X and Y at different temperatures are placed in thermal contact with each other until...
- 23M.1.SL.TZ1.13: Two blocks X and Y at different temperatures are placed in thermal contact with each other until...
- 23M.1.SL.TZ1.12: A solid is heated at constant power in an insulated container. The graph shows the variation of...
- 23M.1.SL.TZ1.12: A solid is heated at constant power in an insulated container. The graph shows the variation of...
- 23M.1.SL.TZ2.9: The temperature of a gas increases from 100 K to 330 K. What is the change in temperature of the...
- 23M.1.SL.TZ2.9: The temperature of a gas increases from 100 K to 330 K. What is the change in temperature of the...
- 23M.1.SL.TZ2.10: What is the internal energy of an ideal gas? A. The sum of the intermolecular potential energies...
- 23M.1.SL.TZ2.10: What is the internal energy of an ideal gas? A. The sum of the intermolecular potential energies...
- 23M.3.HL.TZ2.17a: State the main element that is undergoing nuclear fusion in star C.
- 23M.3.SL.TZ2.12a: State the main element that is undergoing nuclear fusion in star C.
- 23M.3.HL.TZ2.17a: State the main element that is undergoing nuclear fusion in star C.
- 23M.3.HL.TZ2.a: State the main element that is undergoing nuclear fusion in star C.
- 23M.3.SL.TZ2.12a: State the main element that is undergoing nuclear fusion in star C.
- 23M.3.SL.TZ2.a: State the main element that is undergoing nuclear fusion in star C.
- 23M.3.HL.TZ1.16a: The mass of star A is 52 M☉. Show that the luminosity of star A is about 106 L☉.
- 23M.3.SL.TZ1.11a: The mass of star A is 52 M☉. Show that the luminosity of star A is about 106 L☉.
- 23M.3.HL.TZ1.16a: The mass of star A is 52 M☉. Show that the luminosity of star A is about 106 L☉.
- 23M.3.HL.TZ1.a: The mass of star A is 52 M☉. Show that the luminosity of star A is about 106 L☉.
- 23M.3.SL.TZ1.11a: The mass of star A is 52 M☉. Show that the luminosity of star A is about 106 L☉.
- 23M.3.SL.TZ1.a: The mass of star A is 52 M☉. Show that the luminosity of star A is about 106 L☉.
-
23M.1.HL.TZ2.33:
An ac generator produces a root mean square (rms) voltage V. What is the peak output voltage when the frequency is doubled?
A.B.
C.
D.
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23M.1.HL.TZ2.33:
An ac generator produces a root mean square (rms) voltage V. What is the peak output voltage when the frequency is doubled?
A.B.
C.
D.
- 23M.1.HL.TZ2.34: Step-up transformers are used in the distribution of electrical energy to A. reduce the danger...
- 23M.1.HL.TZ2.34: Step-up transformers are used in the distribution of electrical energy to A. reduce the danger...
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23M.1.HL.TZ2.35:
Two capacitors C1 and C2 are connected in series to a cell as shown. The capacitance of C1 is four times the capacitance of C2. The charge stored on C1 is q1 and the charge stored on C2 is q2.
What is ?
A.B.
C. 1
D. 4
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23M.1.HL.TZ2.35:
Two capacitors C1 and C2 are connected in series to a cell as shown. The capacitance of C1 is four times the capacitance of C2. The charge stored on C1 is q1 and the charge stored on C2 is q2.
What is ?
A.B.
C. 1
D. 4
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23M.2.SL.TZ2.4a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.HL.TZ2.4a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.HL.TZ2.4a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.HL.TZ2.a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.SL.TZ2.4a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.SL.TZ2.a:
The designers state that the energy transferred by the resistor every second is 15 J.
Calculate the current in the resistor.
-
23M.2.HL.TZ2.9a:
Show, using the data, that the energy released in the decay of one magnesium-27 nucleus is about 2.62 MeV.
Mass of aluminium-27 atom = 26.98153 u
Mass of magnesium-27 atom = 26.98434 u
The unified atomic mass unit is 931.5 MeV c−2. -
23M.2.HL.TZ2.9a:
Show, using the data, that the energy released in the decay of one magnesium-27 nucleus is about 2.62 MeV.
Mass of aluminium-27 atom = 26.98153 u
Mass of magnesium-27 atom = 26.98434 u
The unified atomic mass unit is 931.5 MeV c−2. -
23M.2.HL.TZ2.a:
Show, using the data, that the energy released in the decay of one magnesium-27 nucleus is about 2.62 MeV.
Mass of aluminium-27 atom = 26.98153 u
Mass of magnesium-27 atom = 26.98434 u
The unified atomic mass unit is 931.5 MeV c−2. - 23M.3.HL.TZ2.16a: The Ghost of Jupiter is a nebula.
- 23M.3.SL.TZ2.11a: The Ghost of Jupiter is a nebula.
- 23M.3.HL.TZ2.16a: The Ghost of Jupiter is a nebula.
- 23M.3.HL.TZ2.a: The Ghost of Jupiter is a nebula.
- 23M.3.SL.TZ2.11a: The Ghost of Jupiter is a nebula.
- 23M.3.SL.TZ2.a: The Ghost of Jupiter is a nebula.