DP Chemistry (first assessment 2025)
Question 19M.2.SL.TZ1.5c(ii)
| Date | May 2019 | Marks available | [Maximum mark: 2] | Reference code | 19M.2.SL.TZ1.5c(ii) |
| Level | SL | Paper | 2 | Time zone | TZ1 |
| Command term | Deduce | Question number | c(ii) | Adapted from | N/A |
c(ii).
[Maximum mark: 2]
19M.2.SL.TZ1.5c(ii)
(c(ii))
Deduce the molecular geometry of chloramine and estimate its H–N–H bond angle.
Molecular geometry:
H–N–H bond angle:
[2]
Markscheme
Molecular geometry:
«trigonal» pyramidal [✔]
H–N–H bond angle:
107° [✔]
Note: Accept angles in the range of 100–109.
Examiners report
The molecular geometry and bond angles often did not correspond to each other with quite a few candidates stating trigonal planar and then 107 for the angle.
Syllabus sections
Structure 2. Models of bonding and structure » Structure 2.2—The covalent model » Structure 2.2.4—The valence shell electron pair repulsion (VSEPR) model enables the shapes of molecules to be predicted from the repulsion of electron domains around a central atom. Predict the electron domain geometry and the molecular geometry for species with up to four electron domains.