Directly related questions
- EXM.1A.HL.TZ0.1: Which of the following is most likely to be a transition metal?
- EXM.1A.SL.TZ0.1: Which of the following is most likely to be a transition metal?
- EXM.1A.HL.TZ0.1: Which of the following is most likely to be a transition metal?
- EXM.1A.SL.TZ0.1: Which of the following is most likely to be a transition metal?
- EXM.2.HL.TZ0.1: The transition metal copper, Cu, is used in electrical circuits given its high electrical...
- EXM.2.HL.TZ0.1: The transition metal copper, Cu, is used in electrical circuits given its high electrical...
- EXM.2.SL.TZ0.1: Explain in terms of their metallic bonding why aluminium, Al and not calcium, Ca, can be used to...
- EXM.2.SL.TZ0.1: Explain in terms of their metallic bonding why aluminium, Al and not calcium, Ca, can be used to...
- EXM.1B.SL.TZ0.2c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.HL.TZ0.2c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.HL.TZ0.2c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.HL.TZ0.c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.SL.TZ0.2c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.SL.TZ0.c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- 22N.1A.SL.TZ0.12: Alloying a metal with a metal of smaller atomic radius can disrupt the lattice and make it more...
- 22N.1A.SL.TZ0.12: Alloying a metal with a metal of smaller atomic radius can disrupt the lattice and make it more...
-
22N.1A.SL.TZ0.13:
Chlorofluorocarbons (CFCs) contain bonds of the following lengths:
C—C = 1.54 × 10−10 m
C—F = 1.38 × 10−10 m
C—Cl = 1.77 × 10−10 m
What is the order of increasing bond strength in the CFC molecule?
A. C—C < C—F < C—Cl
B. C—C < C—Cl < C—F
C. C—Cl < C—C < C—F
D. C—F < C—C < C—Cl
-
22N.1A.SL.TZ0.13:
Chlorofluorocarbons (CFCs) contain bonds of the following lengths:
C—C = 1.54 × 10−10 m
C—F = 1.38 × 10−10 m
C—Cl = 1.77 × 10−10 m
What is the order of increasing bond strength in the CFC molecule?
A. C—C < C—F < C—Cl
B. C—C < C—Cl < C—F
C. C—Cl < C—C < C—F
D. C—F < C—C < C—Cl
-
22N.1A.SL.TZ0.10:
Which molecule is polar?
A. BeH2B. AlH3
C. PH3
D. SiH4
-
22N.1A.SL.TZ0.10:
Which molecule is polar?
A. BeH2B. AlH3
C. PH3
D. SiH4
- 22N.1A.SL.TZ0.11: Which structure of CF2Cl2 is shown with correct bond and molecular dipoles?
- 22N.1A.SL.TZ0.11: Which structure of CF2Cl2 is shown with correct bond and molecular dipoles?
-
22N.2.SL.TZ0.4a.iii:
Explain, with reference to intermolecular forces, why B is more volatile than A.
-
22N.2.SL.TZ0.4a.iii:
Explain, with reference to intermolecular forces, why B is more volatile than A.
-
22N.2.SL.TZ0.a.iii:
Explain, with reference to intermolecular forces, why B is more volatile than A.
- 22N.2.SL.TZ0.4a.i: Deduce the structural and empirical formulas of B.
- 22N.2.SL.TZ0.4a.i: Deduce the structural and empirical formulas of B.
- 22N.2.SL.TZ0.a.i: Deduce the structural and empirical formulas of B.
Sub sections and their related questions
Structure 2.1—The ionic model
-
19M.1A.SL.TZ2.16:
Which equation represents lattice enthalpy?
A. NaCl (g) → Na+ (g) + Cl− (g)
B. NaCl (s) → Na+ (g) + Cl− (g)
C. NaCl (s) → Na+ (aq) + Cl− (aq)
D. NaCl (s) → Na+ (s) + Cl− (s)
-
22M.2.SL.TZ1.1e(iii):
The nitride ion and the magnesium ion are isoelectronic (they have the same electron configuration). Determine, giving a reason, which has the greater ionic radius.
-
22M.2.SL.TZ1.1g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
- 22M.1A.SL.TZ1.9: A compound consists of the ions Ca2+ and PO43–. What are the name and formula of the compound?
- 22M.1A.SL.TZ1.10: What is the explanation for the high melting point of sodium chloride? A. The covalent bond...
- 19N.1A.SL.TZ0.9: Which is correct for all solid ionic compounds? A. High volatility B. Poor electrical...
-
19M.2.SL.TZ2.5b(iii):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
- 21N.1A.SL.TZ0.10: Which combination would create the strongest ionic bond?
- 21N.1A.SL.TZ0.11: Which compound contains both ionic and covalent bonds? A. CH3COONa B. CH3COOH C. K2O D. ...
- 19M.1A.SL.TZ2.9: How does a lithium atom form the most stable ion? A. The atom gains a proton to form a positive...
-
19M.2.SL.TZ2.5d(i):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
- 19M.1A.SL.TZ1.11: Which describes an ionic compound?
- 19M.1A.SL.TZ2.9: How does a lithium atom form the most stable ion? A. The atom gains a proton to form a positive...
-
21M.1A.HL.TZ2.11:
What is the formula of the compound formed from Ca2+ and PO43−?
A. CaPO4
B. Ca3(PO4)2
C. Ca2(PO4)3
D. Ca(PO4)2
- 21M.2.SL.TZ2.2a(ii): Explain the decrease in radius from Na to Na+.
-
20N.2.SL.TZ0.3a:
Outline the two distinct phases of this composite.
- 21M.1A.SL.TZ1.11: Which substance is most likely to be ionic?
-
21M.1A.SL.TZ1.10:
Which compound contains both ionic and covalent bonds?
A.
B.
C.
D.
- 21M.2.SL.TZ1.1d(i): Describe the bonding in this type of solid.
-
21M.2.SL.TZ1.1d(iv):
Outline, in terms of their electronic structures, why the ionic radius of the sulfide ion is greater than that of the oxide ion.
- 21M.2.SL.TZ1.1d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.1c(i): Describe the bonding in this type of solid.
-
21M.2.SL.TZ1.1c(iii):
Outline, in terms of their electronic structures, why the ionic radius of the sulfide ion is greater than that of the oxide ion.
- 21M.2.SL.TZ1.1c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
-
20N.2.SL.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.1A.SL.TZ0.9:
Which formula is correct?
A.
B.
C.
D.
- 22M.1A.SL.TZ2.10: What is the type of bonding in a compound that has high boiling and melting points, poor...
-
21M.1A.SL.TZ1.17:
Which substance has the highest lattice enthalpy?
A.
B.
C.
D.
- 21N.1A.SL.TZ0.20: Which ions are present in an aqueous solution of Na2CO3? I. HCO3−II. OH−III. CO32− A. I and...
-
19M.1A.SL.TZ2.16:
Which equation represents lattice enthalpy?
A. NaCl (g) → Na+ (g) + Cl− (g)
B. NaCl (s) → Na+ (g) + Cl− (g)
C. NaCl (s) → Na+ (aq) + Cl− (aq)
D. NaCl (s) → Na+ (s) + Cl− (s)
-
22M.2.SL.TZ1.1e(iii):
The nitride ion and the magnesium ion are isoelectronic (they have the same electron configuration). Determine, giving a reason, which has the greater ionic radius.
-
22M.2.SL.TZ1.1g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
-
22M.2.SL.TZ1.e(iii):
The nitride ion and the magnesium ion are isoelectronic (they have the same electron configuration). Determine, giving a reason, which has the greater ionic radius.
-
22M.2.SL.TZ1.g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
- 22M.1A.SL.TZ1.9: A compound consists of the ions Ca2+ and PO43–. What are the name and formula of the compound?
- 22M.1A.SL.TZ1.10: What is the explanation for the high melting point of sodium chloride? A. The covalent bond...
- 19N.1A.SL.TZ0.9: Which is correct for all solid ionic compounds? A. High volatility B. Poor electrical...
-
19M.2.SL.TZ2.5b(iii):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
-
19M.2.SL.TZ2.b(iii):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
- 21N.1A.SL.TZ0.10: Which combination would create the strongest ionic bond?
- 21N.1A.SL.TZ0.11: Which compound contains both ionic and covalent bonds? A. CH3COONa B. CH3COOH C. K2O D. ...
- 19M.1A.SL.TZ2.9: How does a lithium atom form the most stable ion? A. The atom gains a proton to form a positive...
-
19M.2.SL.TZ2.5d(i):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
-
19M.2.SL.TZ2.d(i):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
- 19M.1A.SL.TZ1.11: Which describes an ionic compound?
- 19M.1A.SL.TZ2.9: How does a lithium atom form the most stable ion? A. The atom gains a proton to form a positive...
-
21M.1A.HL.TZ2.11:
What is the formula of the compound formed from Ca2+ and PO43−?
A. CaPO4
B. Ca3(PO4)2
C. Ca2(PO4)3
D. Ca(PO4)2
- 21M.2.SL.TZ2.2a(ii): Explain the decrease in radius from Na to Na+.
- 21M.2.SL.TZ2.a(ii): Explain the decrease in radius from Na to Na+.
-
20N.2.SL.TZ0.a:
Outline the two distinct phases of this composite.
- 21M.1A.SL.TZ1.11: Which substance is most likely to be ionic?
-
21M.1A.SL.TZ1.10:
Which compound contains both ionic and covalent bonds?
A.
B.
C.
D.
- 21M.2.SL.TZ1.1d(i): Describe the bonding in this type of solid.
-
21M.2.SL.TZ1.1d(iv):
Outline, in terms of their electronic structures, why the ionic radius of the sulfide ion is greater than that of the oxide ion.
- 21M.2.SL.TZ1.1d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.d(i): Describe the bonding in this type of solid.
-
21M.2.SL.TZ1.d(iv):
Outline, in terms of their electronic structures, why the ionic radius of the sulfide ion is greater than that of the oxide ion.
- 21M.2.SL.TZ1.d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.1c(i): Describe the bonding in this type of solid.
-
21M.2.SL.TZ1.1c(iii):
Outline, in terms of their electronic structures, why the ionic radius of the sulfide ion is greater than that of the oxide ion.
- 21M.2.SL.TZ1.1c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.c(i): Describe the bonding in this type of solid.
-
21M.2.SL.TZ1.c(iii):
Outline, in terms of their electronic structures, why the ionic radius of the sulfide ion is greater than that of the oxide ion.
- 21M.2.SL.TZ1.c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
-
20N.2.SL.TZ0.a:
Outline the two distinct phases of this composite.
-
20N.1A.SL.TZ0.9:
Which formula is correct?
A.
B.
C.
D.
- 22M.1A.SL.TZ2.10: What is the type of bonding in a compound that has high boiling and melting points, poor...
-
21M.1A.SL.TZ1.17:
Which substance has the highest lattice enthalpy?
A.
B.
C.
D.
- 21N.1A.SL.TZ0.20: Which ions are present in an aqueous solution of Na2CO3? I. HCO3−II. OH−III. CO32− A. I and...
Structure 2.2—The covalent model
- 22M.2.SL.TZ1.5a(ii): Compound A and Compound B are both liquids at room temperature and pressure. Identify the...
-
22M.2.HL.TZ1.5a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
- 22M.2.HL.TZ1.5a(iv): Deduce the hybridization of the central carbon atom in Compound A.
-
22M.2.HL.TZ1.6a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
- 22M.2.HL.TZ2.3d(i): Draw the Lewis structure of NO3−.
- 22M.2.HL.TZ2.3d(ii): Explain the electron domain geometry of NO3−.
-
22M.2.SL.TZ1.1g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
- 22M.2.SL.TZ1.3c(ii): Identify the strongest force between the molecules of Compound B.
- 19N.2.HL.TZ0.1a: Draw the Lewis structures of oxygen, O2, and ozone, O3.
- 19N.2.SL.TZ0.1b: Outline why both bonds in the ozone molecule are the same length and predict the bond length in...
-
22M.1A.SL.TZ2.9:
Which statement best describes the intramolecular bonding in HCN (l)?
A. Electrostatic attractions between H+ and CN− ions
B. Hydrogen bonding
C. Van der Waals forces and hydrogen bonding
D. Electrostatic attractions between pairs of electrons and positively charged nuclei
-
22M.1A.SL.TZ2.12:
What is the main interaction between liquid CH4 molecules?
A. London (dispersion) forces
B. Dipole–dipole forces
C. Hydrogen bonding
D. Covalent bonding
- 22M.1A.SL.TZ1.11: Which molecule is most polar? A. CF4 B. CCl4 C. CHF3 D. CClF3
- 22M.1A.SL.TZ1.10: What is the explanation for the high melting point of sodium chloride? A. The covalent bond...
- 22M.1A.HL.TZ1.12: For which species can resonance structures be drawn? A. HCOOH B. HCOO– C. CH3OH D. H2CO3
- 22M.1A.HL.TZ2.12: What is the molecular geometry of SF4? A. Tetrahedral B. Trigonal bipyramidal C. ...
-
21N.2.SL.TZ0.3a(i):
Sketch the Lewis (electron dot) structure of the P4 molecule, containing only single bonds.
- 21N.2.SL.TZ0.3b(i): Deduce the electron domain and molecular geometry using VSEPR theory, and estimate the Cl–P–Cl...
- 21N.2.SL.TZ0.3b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
- 19M.1A.SL.TZ2.11: Which molecule contains an incomplete octet of electrons? A. NF3 B. BF3 C. BrF D. SF2
-
19M.2.SL.TZ2.5b(iii):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
-
19M.2.HL.TZ2.6d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
- 22M.2.HL.TZ2.6c(i): Draw the Lewis structure of SO3.
-
22M.2.HL.TZ2.6c(ii):
Explain the electron domain geometry of SO3.
-
22M.2.HL.TZ2.7b(i):
Sketch the shape of one sigma () and one pi () bond.
-
22M.2.HL.TZ2.7b(ii):
Identify the number of sigma and pi bonds in HCN.
- 22M.2.HL.TZ2.7b(iii): State the hybridization of the carbon atom in HCN.
-
22M.2.SL.TZ2.7c:
Suggest why hydrogen chloride, HCl, has a lower boiling point than hydrogen cyanide, HCN.
-
22M.2.SL.TZ2.8a(i):
Outline two differences between the bonding of carbon atoms in C60 and diamond.
-
22M.2.SL.TZ2.8a(ii):
Explain why C60 and diamond sublime at different temperatures and pressures.
- 21N.1A.SL.TZ0.9: Which molecule has the weakest nitrogen to nitrogen bond? A. N2 B. N2H2 C. N2H4 D.
- 21N.1A.SL.TZ0.11: Which compound contains both ionic and covalent bonds? A. CH3COONa B. CH3COOH C. K2O D. ...
- 21N.1A.SL.TZ0.13: Which alcohol is least soluble in water? A. CH3OH B. CH3CH2OH C. CH3CH2CH2OH D. ...
-
19M.2.HL.TZ1.1b:
Draw the structure of one other isomer of xylene which retains the benzene ring.
-
19M.2.HL.TZ1.1b:
Draw the structure of one other isomer of xylene which retains the benzene ring.
- 19M.1A.HL.TZ1.12: Which species has delocalized electrons? A. OH− B. H2CO C. CO2 D. CO32−
- 19M.1A.HL.TZ1.13: How many carbon atoms are sp3, sp2 and sp hybridized in the molecule?
- 19M.1A.HL.TZ1.36: Which statement is not correct regarding benzene? A. It is planar. B. The ring contains...
-
19M.1A.HL.TZ2.12:
How many sigma (σ) and pi (π) bonds are present in hydrogen cyanide, HCN?
-
19M.2.SL.TZ2.5d(i):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
-
19M.2.SL.TZ1.10a:
The melting points of cocoa butter and coconut oil are 34 °C and 25 °C respectively.
Explain this in terms of their saturated fatty acid composition.
-
19M.2.SL.TZ2.11c:
Lecithin aids the body’s absorption of vitamin E.
Suggest why vitamin E is fat-soluble.
-
19M.2.SL.TZ1.9a:
The melting points of cocoa butter and coconut oil are 34 °C and 25 °C respectively.
Explain this in terms of their saturated fatty acid composition.
-
19M.2.SL.TZ1.5c(i):
Draw a Lewis (electron dot) structure of chloramine.
-
19M.2.SL.TZ1.5c(ii):
Deduce the molecular geometry of chloramine and estimate its H–N–H bond angle.
Molecular geometry:
H–N–H bond angle:
-
19M.2.SL.TZ2.7d:
Lecithin aids the body’s absorption of vitamin E.
Suggest why vitamin E is fat-soluble.
- 19M.1A.HL.TZ1.10: Which species does not have resonance structures? A. C6H6 B. NH4+ C. CO32− D. O3
- 19M.1A.SL.TZ2.12: Which compound has hydrogen bonds between its molecules? A. CH4 B. CH4O C. CH3Cl D. CH2O
- 19M.1A.HL.TZ2.13: What is the hybridization of carbon and oxygen in methanol?
-
19M.2.HL.TZ2.3d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
-
19M.2.SL.TZ2.3d(ii):
State, giving a reason, the shape of the dinitrogen monoxide molecule.
-
19M.2.HL.TZ2.3d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
-
19M.1A.SL.TZ1.9:
What is the order of increasing boiling point?
A. CH3CH2CH2CH3 < CH3CH(OH)CH3 < CH3COCH3 < CH3CO2H
B. CH3CH2CH2CH3 < CH3COCH3 < CH3CH(OH)CH3 < CH3CO2H
C. CH3CO2H < CH3COCH3 < CH3CH(OH)CH3 < CH3CH2CH2CH3
D. CH3CH2CH2CH3 < CH3COCH3 < CH3CO2H < CH3CH(OH)CH3
-
19M.1A.SL.TZ2.24:
Which compound has the lowest boiling point?
A. CH3CH2CH2CH2CH2CH3
B. CH3CH2CH2CH2CH3
C. CH3CH(CH3)CH2CH3
D. CH3C(CH3)2CH3
- 19M.1A.HL.TZ2.11: Which species has a square planar molecular geometry? A. SF4 B. XeF4 C. CF4 D. PF4+
-
19M.1A.SL.TZ2.32:
Which compound has the lowest boiling point?
A. CH3CH2CH2CH2CH2CH3
B. CH3CH2CH2CH2CH3
C. CH3CH(CH3)CH2CH3
D. CH3C(CH3)2CH3
- 22M.1A.HL.TZ1.12: In which compound are all carbon atoms sp3 hybridized? A. C2H2 B. C2H2Cl2 C. C2Cl4 D. C2Cl6
- 22M.1A.HL.TZ1.13: What are the electron domain and molecular geometries of the XeF4 molecule?
- 21N.1A.SL.TZ0.12: The following compounds have similar relative molecular masses. What is the order of increasing...
-
19M.2.SL.TZ1.10:
Ascorbic acid and retinol are two important vitamins.
Explain why ascorbic acid is soluble in water and retinol is not. Use section 35 of the data booklet.
-
21N.1A.HL.TZ0.12:
Which molecules contain two pi () bonds?
I. HCN
II. H2CO3
III. H2C2O4
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
-
19M.1A.SL.TZ1.9:
What is the order of increasing boiling point?
A. CH3CH2CH2CH3 < CH3CH(OH)CH3 < CH3COCH3 < CH3CO2H
B. CH3CH2CH2CH3 < CH3COCH3 < CH3CH(OH)CH3 < CH3CO2H
C. CH3CO2H < CH3COCH3 < CH3CH(OH)CH3 < CH3CH2CH2CH3
D. CH3CH2CH2CH3 < CH3COCH3 < CH3CO2H < CH3CH(OH)CH3
-
21M.2.HL.TZ1.7a(i):
Draw a Lewis (electron dot) structure for ozone.
- 21M.2.HL.TZ1.7a(ii): Discuss the relative length of the two O−O bonds in ozone.
-
20N.1A.HL.TZ0.11:
Which combination correctly describes the geometry of ?
-
19M.2.HL.TZ1.2a:
Draw the structure of the conjugate base of benzoic acid showing all the atoms and all the bonds.
-
19M.2.HL.TZ1.2b(i):
The pH of an aqueous solution of benzoic acid at 298 K is 2.95. Determine the concentration of hydroxide ions in the solution, using section 2 of the data booklet.
-
19M.2.HL.TZ1.2b(ii):
Formulate the equation for the complete combustion of benzoic acid in oxygen using only integer coefficients.
-
19M.2.HL.TZ1.2c:
Suggest how benzoic acid, Mr = 122.13, forms an apparent dimer, Mr = 244.26, when dissolved in a non-polar solvent such as hexane.
-
19N.1A.SL.TZ0.12:
What is the structure and bonding in SiO2 (s)?
-
21M.2.SL.TZ2.2c:
Deduce the Lewis (electron dot) structure and molecular geometry of sulfur dichloride, SCl2.
- 21M.2.SL.TZ2.2d: Suggest, giving reasons, the relative volatilities of SCl2 and H2O.
- 19N.1A.HL.TZ0.11: Which describes a resonance structure? A. Double bond can be drawn in alternative...
- 19N.1A.HL.TZ0.12: Which atom is sp2 hybridized? A. C in H2CO B. C in CO2 C. N in CH3NH2 D. O in H2O
- 19N.1A.SL.TZ0.13: Which atom does not obey the octet rule? A. C in CO2 B. F in BF3 C. O in H2O D. S in SF6
- 19N.1A.SL.TZ0.10: Which compound has the shortest C to O bond? A. CH3CHO B. CO C. CO2 D. C2H5OC2H5
-
20N.2.SL.TZ0.3a:
Outline the two distinct phases of this composite.
- 21M.1A.HL.TZ1.12: Which contain delocalised electrons? I. C6H5OHII. CH3COO−III. CO32− A. I and II only B. I...
- 21M.1A.SL.TZ1.9: The Lewis structure of methylamine is shown. What is the molecular geometry around N? A. ...
- 21M.1A.SL.TZ1.12: Along which series is the bond angle increasing? A. NH3 H2O CH4 B. CH4 NH3 H2O C. H2O ...
- 21M.2.SL.TZ1.1d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
-
21N.2.SL.TZ0.3a(i):
Sketch the Lewis (electron dot) structure of the P4 molecule, containing only single bonds.
- 21N.2.SL.TZ0.3b(i): Deduce the electron domain and molecular geometry using VSEPR theory, and estimate the Cl–P–Cl...
- 21N.2.SL.TZ0.3b(ii): Explain the polarity of PCl3.
- 21M.1A.SL.TZ2.9: Which compound has the greatest volatility under the same conditions? A. SO2 B. SiO2 C. ...
- 21M.1A.SL.TZ2.12: Which is the correct order based on increasing strength? A. covalent bonds < hydrogen bonds...
-
21M.1A.SL.TZ2.10:
Which compound has the shortest C to N bond?
A. HCN
B. CH3CH2NH2
C. CH3CHNH
D. (CH3)2NH
- 21M.1A.HL.TZ2.12: Which atom has an expanded octet? A. C in CO2 B. S in SCl4 C. O in H2O2 D. P in PCl3
- 21M.1A.SL.TZ2.13: What is the electron domain geometry of Si in SiO2? A. bent B. linear C. square planar D. ...
- 21M.2.SL.TZ1.1c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
-
21M.2.SL.TZ1.2a(i):
Draw the Lewis (electron dot) structure of hydrogen sulfide.
- 21M.2.SL.TZ1.2a(ii): Predict the shape of the hydrogen sulfide molecule.
-
20N.1A.SL.TZ0.11:
Which combination correctly describes the geometry of the carbonate ion, ?
-
20N.1A.SL.TZ0.9:
Which of these species contains the shortest carbon to oxygen bond length?
A.
B.
C.
D.
-
20N.2.SL.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.1A.SL.TZ0.10:
Which molecule is most polar?
A.
B.
C.
D.
- 21M.1A.SL.TZ1.24: Which series is in order of increasing boiling point? A. CH2CH2CH3OH CH3COCH3 ...
- 21M.1A.HL.TZ1.13: In which series are all carbon atoms sp2 hybridized? A. C2H2 H2CO HCOOH B. C2H4 ...
- 22M.1A.SL.TZ2.10: What is the type of bonding in a compound that has high boiling and melting points, poor...
- 21N.1A.HL.TZ0.13: What is the hybridization of nitrogen and chlorine in NCl3?
- 22N.1A.HL.TZ0.10: Which elements are capable of forming expanded octets? I. NitrogenII. PhosphorusIII....
-
22N.2.SL.TZ0.4a.iii:
Explain, with reference to intermolecular forces, why B is more volatile than A.
- 22N.1A.SL.TZ0.11: Which structure of CF2Cl2 is shown with correct bond and molecular dipoles?
-
22N.1A.SL.TZ0.13:
Chlorofluorocarbons (CFCs) contain bonds of the following lengths:
C—C = 1.54 × 10−10 m
C—F = 1.38 × 10−10 m
C—Cl = 1.77 × 10−10 m
What is the order of increasing bond strength in the CFC molecule?
A. C—C < C—F < C—Cl
B. C—C < C—Cl < C—F
C. C—Cl < C—C < C—F
D. C—F < C—C < C—Cl
-
22N.1A.SL.TZ0.10:
Which molecule is polar?
A. BeH2B. AlH3
C. PH3
D. SiH4
- 22N.1A.HL.TZ0.11: Which molecule has a tetrahedral molecular geometry? A. HNO3 B. SF4 C. XeF4 D. XeO4
- EXM.1B.HL.TZ0.2c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.SL.TZ0.2c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- 22M.2.SL.TZ1.5a(ii): Compound A and Compound B are both liquids at room temperature and pressure. Identify the...
-
22M.2.HL.TZ1.5a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
- 22M.2.HL.TZ1.5a(iv): Deduce the hybridization of the central carbon atom in Compound A.
- 22M.2.SL.TZ1.a(ii): Compound A and Compound B are both liquids at room temperature and pressure. Identify the...
-
22M.2.HL.TZ1.a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
- 22M.2.HL.TZ1.a(iv): Deduce the hybridization of the central carbon atom in Compound A.
-
22M.2.HL.TZ1.6a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
-
22M.2.HL.TZ1.a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
- 22M.2.HL.TZ2.3d(i): Draw the Lewis structure of NO3−.
- 22M.2.HL.TZ2.3d(ii): Explain the electron domain geometry of NO3−.
- 22M.2.HL.TZ2.d(i): Draw the Lewis structure of NO3−.
- 22M.2.HL.TZ2.d(ii): Explain the electron domain geometry of NO3−.
-
22M.2.SL.TZ1.1g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
-
22M.2.SL.TZ1.g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
- 22M.2.SL.TZ1.3c(ii): Identify the strongest force between the molecules of Compound B.
- 22M.2.SL.TZ1.c(ii): Identify the strongest force between the molecules of Compound B.
- 19N.2.HL.TZ0.1a: Draw the Lewis structures of oxygen, O2, and ozone, O3.
- 19N.2.SL.TZ0.1b: Outline why both bonds in the ozone molecule are the same length and predict the bond length in...
- 19N.2.HL.TZ0.a: Draw the Lewis structures of oxygen, O2, and ozone, O3.
- 19N.2.SL.TZ0.b: Outline why both bonds in the ozone molecule are the same length and predict the bond length in...
-
22M.1A.SL.TZ2.9:
Which statement best describes the intramolecular bonding in HCN (l)?
A. Electrostatic attractions between H+ and CN− ions
B. Hydrogen bonding
C. Van der Waals forces and hydrogen bonding
D. Electrostatic attractions between pairs of electrons and positively charged nuclei
-
22M.1A.SL.TZ2.12:
What is the main interaction between liquid CH4 molecules?
A. London (dispersion) forces
B. Dipole–dipole forces
C. Hydrogen bonding
D. Covalent bonding
- 22M.1A.SL.TZ1.11: Which molecule is most polar? A. CF4 B. CCl4 C. CHF3 D. CClF3
- 22M.1A.SL.TZ1.10: What is the explanation for the high melting point of sodium chloride? A. The covalent bond...
- 22M.1A.HL.TZ1.12: For which species can resonance structures be drawn? A. HCOOH B. HCOO– C. CH3OH D. H2CO3
- 22M.1A.HL.TZ2.12: What is the molecular geometry of SF4? A. Tetrahedral B. Trigonal bipyramidal C. ...
-
21N.2.SL.TZ0.3a(i):
Sketch the Lewis (electron dot) structure of the P4 molecule, containing only single bonds.
- 21N.2.SL.TZ0.3b(i): Deduce the electron domain and molecular geometry using VSEPR theory, and estimate the Cl–P–Cl...
- 21N.2.SL.TZ0.3b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
-
21N.2.SL.TZ0.a(i):
Sketch the Lewis (electron dot) structure of the P4 molecule, containing only single bonds.
- 21N.2.SL.TZ0.b(i): Deduce the electron domain and molecular geometry using VSEPR theory, and estimate the Cl–P–Cl...
- 21N.2.SL.TZ0.b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
- 19M.1A.SL.TZ2.11: Which molecule contains an incomplete octet of electrons? A. NF3 B. BF3 C. BrF D. SF2
-
19M.2.SL.TZ2.5b(iii):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
-
19M.2.SL.TZ2.b(iii):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
-
19M.2.HL.TZ2.6d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
-
19M.2.HL.TZ2.d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
- 22M.2.HL.TZ2.6c(i): Draw the Lewis structure of SO3.
-
22M.2.HL.TZ2.6c(ii):
Explain the electron domain geometry of SO3.
- 22M.2.HL.TZ2.c(i): Draw the Lewis structure of SO3.
-
22M.2.HL.TZ2.c(ii):
Explain the electron domain geometry of SO3.
-
22M.2.HL.TZ2.7b(i):
Sketch the shape of one sigma () and one pi () bond.
-
22M.2.HL.TZ2.7b(ii):
Identify the number of sigma and pi bonds in HCN.
- 22M.2.HL.TZ2.7b(iii): State the hybridization of the carbon atom in HCN.
-
22M.2.SL.TZ2.7c:
Suggest why hydrogen chloride, HCl, has a lower boiling point than hydrogen cyanide, HCN.
-
22M.2.HL.TZ2.b(i):
Sketch the shape of one sigma () and one pi () bond.
-
22M.2.HL.TZ2.b(ii):
Identify the number of sigma and pi bonds in HCN.
- 22M.2.HL.TZ2.b(iii): State the hybridization of the carbon atom in HCN.
-
22M.2.SL.TZ2.c:
Suggest why hydrogen chloride, HCl, has a lower boiling point than hydrogen cyanide, HCN.
-
22M.2.SL.TZ2.8a(i):
Outline two differences between the bonding of carbon atoms in C60 and diamond.
-
22M.2.SL.TZ2.8a(ii):
Explain why C60 and diamond sublime at different temperatures and pressures.
-
22M.2.SL.TZ2.a(i):
Outline two differences between the bonding of carbon atoms in C60 and diamond.
-
22M.2.SL.TZ2.a(ii):
Explain why C60 and diamond sublime at different temperatures and pressures.
- 21N.1A.SL.TZ0.9: Which molecule has the weakest nitrogen to nitrogen bond? A. N2 B. N2H2 C. N2H4 D.
- 21N.1A.SL.TZ0.11: Which compound contains both ionic and covalent bonds? A. CH3COONa B. CH3COOH C. K2O D. ...
- 21N.1A.SL.TZ0.13: Which alcohol is least soluble in water? A. CH3OH B. CH3CH2OH C. CH3CH2CH2OH D. ...
-
19M.2.HL.TZ1.1b:
Draw the structure of one other isomer of xylene which retains the benzene ring.
-
19M.2.HL.TZ1.b:
Draw the structure of one other isomer of xylene which retains the benzene ring.
-
19M.2.HL.TZ1.1b:
Draw the structure of one other isomer of xylene which retains the benzene ring.
-
19M.2.HL.TZ1.b:
Draw the structure of one other isomer of xylene which retains the benzene ring.
- 19M.1A.HL.TZ1.12: Which species has delocalized electrons? A. OH− B. H2CO C. CO2 D. CO32−
- 19M.1A.HL.TZ1.13: How many carbon atoms are sp3, sp2 and sp hybridized in the molecule?
- 19M.1A.HL.TZ1.36: Which statement is not correct regarding benzene? A. It is planar. B. The ring contains...
-
19M.1A.HL.TZ2.12:
How many sigma (σ) and pi (π) bonds are present in hydrogen cyanide, HCN?
-
19M.2.SL.TZ2.5d(i):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
-
19M.2.SL.TZ2.d(i):
Identify the type of bonding in sodium hydrogencarbonate.
Between sodium and hydrogencarbonate:
Between hydrogen and oxygen in hydrogencarbonate:
-
19M.2.SL.TZ1.a:
The melting points of cocoa butter and coconut oil are 34 °C and 25 °C respectively.
Explain this in terms of their saturated fatty acid composition.
-
19M.2.SL.TZ2.c:
Lecithin aids the body’s absorption of vitamin E.
Suggest why vitamin E is fat-soluble.
-
19M.2.SL.TZ1.a:
The melting points of cocoa butter and coconut oil are 34 °C and 25 °C respectively.
Explain this in terms of their saturated fatty acid composition.
-
19M.2.SL.TZ1.5c(i):
Draw a Lewis (electron dot) structure of chloramine.
-
19M.2.SL.TZ1.5c(ii):
Deduce the molecular geometry of chloramine and estimate its H–N–H bond angle.
Molecular geometry:
H–N–H bond angle:
-
19M.2.SL.TZ1.c(i):
Draw a Lewis (electron dot) structure of chloramine.
-
19M.2.SL.TZ1.c(ii):
Deduce the molecular geometry of chloramine and estimate its H–N–H bond angle.
Molecular geometry:
H–N–H bond angle:
-
19M.2.SL.TZ2.d:
Lecithin aids the body’s absorption of vitamin E.
Suggest why vitamin E is fat-soluble.
- 19M.1A.HL.TZ1.10: Which species does not have resonance structures? A. C6H6 B. NH4+ C. CO32− D. O3
- 19M.1A.SL.TZ2.12: Which compound has hydrogen bonds between its molecules? A. CH4 B. CH4O C. CH3Cl D. CH2O
- 19M.1A.HL.TZ2.13: What is the hybridization of carbon and oxygen in methanol?
-
19M.2.HL.TZ2.3d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
-
19M.2.SL.TZ2.3d(ii):
State, giving a reason, the shape of the dinitrogen monoxide molecule.
-
19M.2.HL.TZ2.3d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
-
19M.2.HL.TZ2.d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
-
19M.2.SL.TZ2.d(ii):
State, giving a reason, the shape of the dinitrogen monoxide molecule.
-
19M.2.HL.TZ2.d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
-
19M.1A.SL.TZ1.9:
What is the order of increasing boiling point?
A. CH3CH2CH2CH3 < CH3CH(OH)CH3 < CH3COCH3 < CH3CO2H
B. CH3CH2CH2CH3 < CH3COCH3 < CH3CH(OH)CH3 < CH3CO2H
C. CH3CO2H < CH3COCH3 < CH3CH(OH)CH3 < CH3CH2CH2CH3
D. CH3CH2CH2CH3 < CH3COCH3 < CH3CO2H < CH3CH(OH)CH3
-
19M.1A.SL.TZ2.24:
Which compound has the lowest boiling point?
A. CH3CH2CH2CH2CH2CH3
B. CH3CH2CH2CH2CH3
C. CH3CH(CH3)CH2CH3
D. CH3C(CH3)2CH3
- 19M.1A.HL.TZ2.11: Which species has a square planar molecular geometry? A. SF4 B. XeF4 C. CF4 D. PF4+
-
19M.1A.SL.TZ2.32:
Which compound has the lowest boiling point?
A. CH3CH2CH2CH2CH2CH3
B. CH3CH2CH2CH2CH3
C. CH3CH(CH3)CH2CH3
D. CH3C(CH3)2CH3
- 22M.1A.HL.TZ1.12: In which compound are all carbon atoms sp3 hybridized? A. C2H2 B. C2H2Cl2 C. C2Cl4 D. C2Cl6
- 22M.1A.HL.TZ1.13: What are the electron domain and molecular geometries of the XeF4 molecule?
- 21N.1A.SL.TZ0.12: The following compounds have similar relative molecular masses. What is the order of increasing...
-
19M.2.SL.TZ1.10:
Ascorbic acid and retinol are two important vitamins.
Explain why ascorbic acid is soluble in water and retinol is not. Use section 35 of the data booklet.
-
21N.1A.HL.TZ0.12:
Which molecules contain two pi () bonds?
I. HCN
II. H2CO3
III. H2C2O4
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
-
19M.1A.SL.TZ1.9:
What is the order of increasing boiling point?
A. CH3CH2CH2CH3 < CH3CH(OH)CH3 < CH3COCH3 < CH3CO2H
B. CH3CH2CH2CH3 < CH3COCH3 < CH3CH(OH)CH3 < CH3CO2H
C. CH3CO2H < CH3COCH3 < CH3CH(OH)CH3 < CH3CH2CH2CH3
D. CH3CH2CH2CH3 < CH3COCH3 < CH3CO2H < CH3CH(OH)CH3
-
21M.2.HL.TZ1.7a(i):
Draw a Lewis (electron dot) structure for ozone.
- 21M.2.HL.TZ1.7a(ii): Discuss the relative length of the two O−O bonds in ozone.
-
21M.2.HL.TZ1.a(i):
Draw a Lewis (electron dot) structure for ozone.
- 21M.2.HL.TZ1.a(ii): Discuss the relative length of the two O−O bonds in ozone.
-
20N.1A.HL.TZ0.11:
Which combination correctly describes the geometry of ?
-
19M.2.HL.TZ1.2a:
Draw the structure of the conjugate base of benzoic acid showing all the atoms and all the bonds.
-
19M.2.HL.TZ1.2b(i):
The pH of an aqueous solution of benzoic acid at 298 K is 2.95. Determine the concentration of hydroxide ions in the solution, using section 2 of the data booklet.
-
19M.2.HL.TZ1.2b(ii):
Formulate the equation for the complete combustion of benzoic acid in oxygen using only integer coefficients.
-
19M.2.HL.TZ1.2c:
Suggest how benzoic acid, Mr = 122.13, forms an apparent dimer, Mr = 244.26, when dissolved in a non-polar solvent such as hexane.
-
19M.2.HL.TZ1.a:
Draw the structure of the conjugate base of benzoic acid showing all the atoms and all the bonds.
-
19M.2.HL.TZ1.b(i):
The pH of an aqueous solution of benzoic acid at 298 K is 2.95. Determine the concentration of hydroxide ions in the solution, using section 2 of the data booklet.
-
19M.2.HL.TZ1.b(ii):
Formulate the equation for the complete combustion of benzoic acid in oxygen using only integer coefficients.
-
19M.2.HL.TZ1.c:
Suggest how benzoic acid, Mr = 122.13, forms an apparent dimer, Mr = 244.26, when dissolved in a non-polar solvent such as hexane.
-
19N.1A.SL.TZ0.12:
What is the structure and bonding in SiO2 (s)?
-
21M.2.SL.TZ2.2c:
Deduce the Lewis (electron dot) structure and molecular geometry of sulfur dichloride, SCl2.
- 21M.2.SL.TZ2.2d: Suggest, giving reasons, the relative volatilities of SCl2 and H2O.
-
21M.2.SL.TZ2.c:
Deduce the Lewis (electron dot) structure and molecular geometry of sulfur dichloride, SCl2.
- 21M.2.SL.TZ2.d: Suggest, giving reasons, the relative volatilities of SCl2 and H2O.
- 19N.1A.HL.TZ0.11: Which describes a resonance structure? A. Double bond can be drawn in alternative...
- 19N.1A.HL.TZ0.12: Which atom is sp2 hybridized? A. C in H2CO B. C in CO2 C. N in CH3NH2 D. O in H2O
- 19N.1A.SL.TZ0.13: Which atom does not obey the octet rule? A. C in CO2 B. F in BF3 C. O in H2O D. S in SF6
- 19N.1A.SL.TZ0.10: Which compound has the shortest C to O bond? A. CH3CHO B. CO C. CO2 D. C2H5OC2H5
-
20N.2.SL.TZ0.a:
Outline the two distinct phases of this composite.
- 21M.1A.HL.TZ1.12: Which contain delocalised electrons? I. C6H5OHII. CH3COO−III. CO32− A. I and II only B. I...
- 21M.1A.SL.TZ1.9: The Lewis structure of methylamine is shown. What is the molecular geometry around N? A. ...
- 21M.1A.SL.TZ1.12: Along which series is the bond angle increasing? A. NH3 H2O CH4 B. CH4 NH3 H2O C. H2O ...
- 21M.2.SL.TZ1.1d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
-
21N.2.SL.TZ0.3a(i):
Sketch the Lewis (electron dot) structure of the P4 molecule, containing only single bonds.
- 21N.2.SL.TZ0.3b(i): Deduce the electron domain and molecular geometry using VSEPR theory, and estimate the Cl–P–Cl...
- 21N.2.SL.TZ0.3b(ii): Explain the polarity of PCl3.
-
21N.2.SL.TZ0.a(i):
Sketch the Lewis (electron dot) structure of the P4 molecule, containing only single bonds.
- 21N.2.SL.TZ0.b(i): Deduce the electron domain and molecular geometry using VSEPR theory, and estimate the Cl–P–Cl...
- 21N.2.SL.TZ0.b(ii): Explain the polarity of PCl3.
- 21M.1A.SL.TZ2.9: Which compound has the greatest volatility under the same conditions? A. SO2 B. SiO2 C. ...
- 21M.1A.SL.TZ2.12: Which is the correct order based on increasing strength? A. covalent bonds < hydrogen bonds...
-
21M.1A.SL.TZ2.10:
Which compound has the shortest C to N bond?
A. HCN
B. CH3CH2NH2
C. CH3CHNH
D. (CH3)2NH
- 21M.1A.HL.TZ2.12: Which atom has an expanded octet? A. C in CO2 B. S in SCl4 C. O in H2O2 D. P in PCl3
- 21M.1A.SL.TZ2.13: What is the electron domain geometry of Si in SiO2? A. bent B. linear C. square planar D. ...
- 21M.2.SL.TZ1.1c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
-
21M.2.SL.TZ1.2a(i):
Draw the Lewis (electron dot) structure of hydrogen sulfide.
- 21M.2.SL.TZ1.2a(ii): Predict the shape of the hydrogen sulfide molecule.
-
21M.2.SL.TZ1.a(i):
Draw the Lewis (electron dot) structure of hydrogen sulfide.
- 21M.2.SL.TZ1.a(ii): Predict the shape of the hydrogen sulfide molecule.
-
20N.1A.SL.TZ0.11:
Which combination correctly describes the geometry of the carbonate ion, ?
-
20N.1A.SL.TZ0.9:
Which of these species contains the shortest carbon to oxygen bond length?
A.
B.
C.
D.
-
20N.2.SL.TZ0.a:
Outline the two distinct phases of this composite.
-
20N.1A.SL.TZ0.10:
Which molecule is most polar?
A.
B.
C.
D.
- 21M.1A.SL.TZ1.24: Which series is in order of increasing boiling point? A. CH2CH2CH3OH CH3COCH3 ...
- 21M.1A.HL.TZ1.13: In which series are all carbon atoms sp2 hybridized? A. C2H2 H2CO HCOOH B. C2H4 ...
- 22M.1A.SL.TZ2.10: What is the type of bonding in a compound that has high boiling and melting points, poor...
- 21N.1A.HL.TZ0.13: What is the hybridization of nitrogen and chlorine in NCl3?
- 22N.1A.HL.TZ0.10: Which elements are capable of forming expanded octets? I. NitrogenII. PhosphorusIII....
-
22N.2.SL.TZ0.4a.iii:
Explain, with reference to intermolecular forces, why B is more volatile than A.
-
22N.2.SL.TZ0.a.iii:
Explain, with reference to intermolecular forces, why B is more volatile than A.
- 22N.1A.SL.TZ0.11: Which structure of CF2Cl2 is shown with correct bond and molecular dipoles?
-
22N.1A.SL.TZ0.13:
Chlorofluorocarbons (CFCs) contain bonds of the following lengths:
C—C = 1.54 × 10−10 m
C—F = 1.38 × 10−10 m
C—Cl = 1.77 × 10−10 m
What is the order of increasing bond strength in the CFC molecule?
A. C—C < C—F < C—Cl
B. C—C < C—Cl < C—F
C. C—Cl < C—C < C—F
D. C—F < C—C < C—Cl
-
22N.1A.SL.TZ0.10:
Which molecule is polar?
A. BeH2B. AlH3
C. PH3
D. SiH4
- 22N.1A.HL.TZ0.11: Which molecule has a tetrahedral molecular geometry? A. HNO3 B. SF4 C. XeF4 D. XeO4
- EXM.1B.HL.TZ0.2c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.HL.TZ0.c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.SL.TZ0.2c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
- EXM.1B.SL.TZ0.c: Suggest why water was chosen to extract ascorbic acid from the spinach leaves with reference to...
Structure 2.3—The metallic model
-
22M.2.SL.TZ1.1g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
- 22M.1A.SL.TZ1.10: What is the explanation for the high melting point of sodium chloride? A. The covalent bond...
-
22M.2.SL.TZ2.5c:
Describe the bonding in iron, Fe (s).
- 19M.1A.SL.TZ1.11: Which combination corresponds to a strong metallic bond?
- 19M.1A.SL.TZ2.10: Which combination causes the strength of metallic bonding to increase?
- 19M.1A.SL.TZ1.12: Which combination corresponds to a strong metallic bond?
- 19M.1A.SL.TZ2.10: Which combination causes the strength of metallic bonding to increase?
- 19N.2.SL.TZ0.4a(ii): Suggest why the resistance of metals increases with temperature.
- 21M.2.SL.TZ2.2b(ii): Describe metallic bonding and how it contributes to electrical conductivity.
-
19M.2.SL.TZ2.6b:
Determine the density of calcium, in g cm−3, using section 2 of the data booklet.
Ar = 40.08; metallic radius (r) = 1.97 × 10−10 m
-
20N.2.SL.TZ0.3a:
Outline the two distinct phases of this composite.
- 21M.2.SL.TZ1.1a: Outline why metals, like iron, can conduct electricity.
- 21M.2.SL.TZ1.1d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.1a: Outline why metals, like iron, can conduct electricity.
- 21M.2.SL.TZ1.1c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
-
20N.1A.SL.TZ0.12:
Which series shows the correct order of metallic bond strength from strongest to weakest?
A.
B.
C.
D.
- 22M.1A.SL.TZ2.10: What is the type of bonding in a compound that has high boiling and melting points, poor...
- EXM.1A.HL.TZ0.1: Which of the following is most likely to be a transition metal?
- EXM.1A.SL.TZ0.1: Which of the following is most likely to be a transition metal?
- EXM.2.HL.TZ0.1: The transition metal copper, Cu, is used in electrical circuits given its high electrical...
- EXM.2.SL.TZ0.1: Explain in terms of their metallic bonding why aluminium, Al and not calcium, Ca, can be used to...
-
22M.2.SL.TZ1.1g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
-
22M.2.SL.TZ1.g:
State the types of bonding in magnesium, oxygen and magnesium oxide, and how the valence electrons produce these types of bonding.
- 22M.1A.SL.TZ1.10: What is the explanation for the high melting point of sodium chloride? A. The covalent bond...
-
22M.2.SL.TZ2.5c:
Describe the bonding in iron, Fe (s).
-
22M.2.SL.TZ2.c:
Describe the bonding in iron, Fe (s).
- 19M.1A.SL.TZ1.11: Which combination corresponds to a strong metallic bond?
- 19M.1A.SL.TZ2.10: Which combination causes the strength of metallic bonding to increase?
- 19M.1A.SL.TZ1.12: Which combination corresponds to a strong metallic bond?
- 19M.1A.SL.TZ2.10: Which combination causes the strength of metallic bonding to increase?
- 19N.2.SL.TZ0.a(ii): Suggest why the resistance of metals increases with temperature.
- 21M.2.SL.TZ2.2b(ii): Describe metallic bonding and how it contributes to electrical conductivity.
- 21M.2.SL.TZ2.b(ii): Describe metallic bonding and how it contributes to electrical conductivity.
-
19M.2.SL.TZ2.b:
Determine the density of calcium, in g cm−3, using section 2 of the data booklet.
Ar = 40.08; metallic radius (r) = 1.97 × 10−10 m
-
20N.2.SL.TZ0.a:
Outline the two distinct phases of this composite.
- 21M.2.SL.TZ1.1a: Outline why metals, like iron, can conduct electricity.
- 21M.2.SL.TZ1.1d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.a: Outline why metals, like iron, can conduct electricity.
- 21M.2.SL.TZ1.d(v): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.1a: Outline why metals, like iron, can conduct electricity.
- 21M.2.SL.TZ1.1c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
- 21M.2.SL.TZ1.a: Outline why metals, like iron, can conduct electricity.
- 21M.2.SL.TZ1.c(iv): Suggest why chemists find it convenient to classify bonding into ionic, covalent and metallic.
-
20N.1A.SL.TZ0.12:
Which series shows the correct order of metallic bond strength from strongest to weakest?
A.
B.
C.
D.
- 22M.1A.SL.TZ2.10: What is the type of bonding in a compound that has high boiling and melting points, poor...
- EXM.1A.HL.TZ0.1: Which of the following is most likely to be a transition metal?
- EXM.1A.SL.TZ0.1: Which of the following is most likely to be a transition metal?
- EXM.2.HL.TZ0.1: The transition metal copper, Cu, is used in electrical circuits given its high electrical...
- EXM.2.SL.TZ0.1: Explain in terms of their metallic bonding why aluminium, Al and not calcium, Ca, can be used to...
Structure 2.4—From models to materials
- 22M.2.SL.TZ1.5b(iii): Deduce the structural formula of the repeating unit of the polymer formed from this alkene.
- 22M.2.SL.TZ1.3d(ii): Deduce the structural formula of the repeating unit of the polymer formed from this alkene.
-
20N.2.HL.TZ0.6a:
Deduce the products of the hydrolysis of a non-substituted phospholipid, where and represent long alkyl chains.
- 22M.1A.SL.TZ2.9: In which of the following compounds does ionic bonding predominate? A. HCl B. NaF C. ...
-
19M.2.SL.TZ2.6a:
Draw the repeating unit of polyphenylethene.
-
19M.2.SL.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.2.HL.TZ1.8a:
Draw the structure of the repeating unit of starch and state the type of linkage formed between these units.
Type of linkage:
-
19M.2.HL.TZ1.8b:
Formulate the equation for the complete hydrolysis of a starch molecule, (C6H10O5)n.
-
19M.2.HL.TZ1.7a:
Draw the structure of the repeating unit of starch and state the type of linkage formed between these units.
Type of linkage:
-
19M.2.HL.TZ1.7b:
Formulate the equation for the complete hydrolysis of a starch molecule, (C6H10O5)n.
-
19M.2.SL.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.2.HL.TZ1.4d:
Classify polybutadiene as either an addition or condensation polymer, giving a reason.
-
19M.2.SL.TZ1.4e:
State one factor considered when making green chemistry polymers.
-
22M.1A.SL.TZ2.25:
Which structure represents a repeating unit of a polymer formed from propene?
A. –CH2–CH(CH3)–
B. –CH2–CH2–CH2–
C. –CH(CH3)–CH(CH3)–
D. –CH2–CH2–
-
19N.2.HL.TZ0.5a:
Draw the structure of the monomers of Kevlar® if the by-product of the condensation polymerization is hydrogen chloride.
- 19N.1A.SL.TZ0.28: Which compound cannot undergo addition polymerization?
-
21M.1A.SL.TZ1.27:
Which monomer would produce the polymer shown?
A.
B.
C.
D.
- 21M.2.SL.TZ1.1f: Explain why the addition of small amounts of carbon to iron makes the metal harder.
-
21M.1A.SL.TZ2.26:
Which monomer forms the polymer shown?
A.
B.
C.
D.
- 21M.2.SL.TZ1.1e: Explain why the addition of small amounts of carbon to iron makes the metal harder.
- 21M.2.SL.TZ1.5d: A white solid was formed when ethene was subjected to high pressure. Deduce the type of reaction...
- 20N.2.HL.TZ0.3c: Classify PVC and polyethene terephthalate, PET, as addition or condensation polymers and deduce...
- 22N.2.SL.TZ0.4a.i: Deduce the structural and empirical formulas of B.
- 22N.1A.SL.TZ0.12: Alloying a metal with a metal of smaller atomic radius can disrupt the lattice and make it more...
- 22M.2.SL.TZ1.5b(iii): Deduce the structural formula of the repeating unit of the polymer formed from this alkene.
- 22M.2.SL.TZ1.b(iii): Deduce the structural formula of the repeating unit of the polymer formed from this alkene.
- 22M.2.SL.TZ1.3d(ii): Deduce the structural formula of the repeating unit of the polymer formed from this alkene.
- 22M.2.SL.TZ1.d(ii): Deduce the structural formula of the repeating unit of the polymer formed from this alkene.
-
20N.2.HL.TZ0.a:
Deduce the products of the hydrolysis of a non-substituted phospholipid, where and represent long alkyl chains.
- 22M.1A.SL.TZ2.9: In which of the following compounds does ionic bonding predominate? A. HCl B. NaF C. ...
-
19M.2.SL.TZ2.6a:
Draw the repeating unit of polyphenylethene.
-
19M.2.SL.TZ2.a:
Draw the repeating unit of polyphenylethene.
-
19M.2.SL.TZ2.d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.2.HL.TZ1.a:
Draw the structure of the repeating unit of starch and state the type of linkage formed between these units.
Type of linkage:
-
19M.2.HL.TZ1.b:
Formulate the equation for the complete hydrolysis of a starch molecule, (C6H10O5)n.
-
19M.2.HL.TZ1.a:
Draw the structure of the repeating unit of starch and state the type of linkage formed between these units.
Type of linkage:
-
19M.2.HL.TZ1.b:
Formulate the equation for the complete hydrolysis of a starch molecule, (C6H10O5)n.
-
19M.2.SL.TZ2.d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.2.HL.TZ1.d:
Classify polybutadiene as either an addition or condensation polymer, giving a reason.
-
19M.2.SL.TZ1.e:
State one factor considered when making green chemistry polymers.
-
22M.1A.SL.TZ2.25:
Which structure represents a repeating unit of a polymer formed from propene?
A. –CH2–CH(CH3)–
B. –CH2–CH2–CH2–
C. –CH(CH3)–CH(CH3)–
D. –CH2–CH2–
-
19N.2.HL.TZ0.a:
Draw the structure of the monomers of Kevlar® if the by-product of the condensation polymerization is hydrogen chloride.
- 19N.1A.SL.TZ0.28: Which compound cannot undergo addition polymerization?
-
21M.1A.SL.TZ1.27:
Which monomer would produce the polymer shown?
A.
B.
C.
D.
- 21M.2.SL.TZ1.1f: Explain why the addition of small amounts of carbon to iron makes the metal harder.
- 21M.2.SL.TZ1.f: Explain why the addition of small amounts of carbon to iron makes the metal harder.
-
21M.1A.SL.TZ2.26:
Which monomer forms the polymer shown?
A.
B.
C.
D.
- 21M.2.SL.TZ1.1e: Explain why the addition of small amounts of carbon to iron makes the metal harder.
- 21M.2.SL.TZ1.e: Explain why the addition of small amounts of carbon to iron makes the metal harder.
- 21M.2.SL.TZ1.5d: A white solid was formed when ethene was subjected to high pressure. Deduce the type of reaction...
- 21M.2.SL.TZ1.d: A white solid was formed when ethene was subjected to high pressure. Deduce the type of reaction...
- 20N.2.HL.TZ0.c: Classify PVC and polyethene terephthalate, PET, as addition or condensation polymers and deduce...
- 22N.2.SL.TZ0.4a.i: Deduce the structural and empirical formulas of B.
- 22N.2.SL.TZ0.a.i: Deduce the structural and empirical formulas of B.
- 22N.1A.SL.TZ0.12: Alloying a metal with a metal of smaller atomic radius can disrupt the lattice and make it more...