Question 21M.2.HL.TZ1.7
Date | May 2021 | Marks available | [Maximum mark: 7] | Reference code | 21M.2.HL.TZ1.7 |
Level | HL | Paper | 2 | Time zone | TZ1 |
Command term | Discuss, Draw, Explain | Question number | 7 | Adapted from | N/A |
Oxygen exists as two allotropes, diatomic oxygen, O2, and ozone, O3.
Draw a Lewis (electron dot) structure for ozone.
[1]
✔
Accept any combination of lines, dots or crosses to represent electrons.
Do not accept structures that represent 1.5 bonds.

Discuss the relative length of the two O−O bonds in ozone.
[2]
both equal ✔
delocalization/resonance ✔
Accept bond length between 121 and 148 pm/ that of single O−O bond and double O=O bond for M1.

Explain why there are frequencies of UV light that will dissociate O3 but not O2.
[2]
bond in O3 is weaker
OR
O3 bond order 1.5/< 2 ✔
Do not accept bond in O3 is longer for M1.
lower frequency/longer wavelength «UV light» has enough energy to break the O–O bond in O3 «but not that in O2» ✔
Accept “lower frequency/longer wavelength «UV light» has lower energy”.

Explain, using equations, how the presence of results in a chain reaction that decreases the concentration of ozone in the stratosphere.
[2]
✔
AND
✔
Do not penalize missing radical.
Accept:for M2:
AND
