DP Chemistry (first assessment 2025)

Test builder »

Question 21N.2.HL.TZ0.c(iii)

Select a Test
Date November 2021 Marks available [Maximum mark: 2] Reference code 21N.2.HL.TZ0.c(iii)
Level HL Paper 2 Time zone TZ0
Command term Calculate Question number c(iii) Adapted from N/A
c(iii).
[Maximum mark: 2]
21N.2.HL.TZ0.c(iii)

Calculate the Gibbs free energy change (ΔG), in kJ mol−1, for this reaction at 25 °C. Use section 1 of the data booklet.

If you did not obtain an answer in c(i) or c(ii) use −87.6 kJ mol−1 and −150.5 J mol−1 K−1 respectively, but these are not the correct answers.

[2]

Markscheme

«ΔS =» –0.1702 «kJ mol–1 K–1»
OR
298 «K» ✔

«ΔG = –92.5 kJ mol–1 – (298 K × –0.1702 kJ mol–1 K–1) =» –41.8 «kJ mol–1» ✔

 

Award [2] for correct final answer.

If –87.6 and -150.5 are used then –42.8.

Syllabus sections