DP Chemistry (first assessment 2025)
Question 21N.2.SL.TZ0.11b
Date | November 2021 | Marks available | [Maximum mark: 1] | Reference code | 21N.2.SL.TZ0.11b |
Level | SL | Paper | 2 | Time zone | TZ0 |
Command term | Calculate | Question number | b | Adapted from | N/A |
b.
[Maximum mark: 1]
21N.2.SL.TZ0.11b
(b)
The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.
[1]
Markscheme
«pOH = –log(0.362) = 0.441»
«pH = 14.000 – 0.441 =» 13.559 ✔

Syllabus sections
Reactivity 3. What are the mechanisms of chemical change? » Reactivity 3.1—Proton transfer reactions » Reactivity 3.1.5—The ion product constant of water, Kw, shows an inverse relationship between [H+] and [OH–]. Kw = [H+] [OH–]. Recognize solutions as acidic, neutral and basic from the relative values of [H+] and [OH–].