Directly related questions
- 23M.1A.SL.TZ1.5: Which statement best explains the first ionization energy of sulfur being lower than that of...
- 23M.1A.SL.TZ1.5: Which statement best explains the first ionization energy of sulfur being lower than that of...
-
EXM.1A.HL.TZ0.9:
Which of the following statements is correct when a 1.0 M NH4+/NH3 buffer (pH = 9.2) is diluted to 0.5 M with water?
I. The ability of the buffer to resist changes in pH when acids are added will decrease.
II. The ability of the buffer to resist changes in pH when bases are added will decrease.
III. The pH of the buffer will be equal to 7.
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
-
EXM.1A.HL.TZ0.9:
Which of the following statements is correct when a 1.0 M NH4+/NH3 buffer (pH = 9.2) is diluted to 0.5 M with water?
I. The ability of the buffer to resist changes in pH when acids are added will decrease.
II. The ability of the buffer to resist changes in pH when bases are added will decrease.
III. The pH of the buffer will be equal to 7.
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
-
EXM.2.HL.TZ0.2a:
Determine the ratio in which 0.1 mol dm–3 NaH2PO4 and 0.1 mol dm–3 Na2HPO4 should be mixed to obtain a buffer with pH= 7.8.
pKa NaH2PO4 = 7.20
-
EXM.2.HL.TZ0.2a:
Determine the ratio in which 0.1 mol dm–3 NaH2PO4 and 0.1 mol dm–3 Na2HPO4 should be mixed to obtain a buffer with pH= 7.8.
pKa NaH2PO4 = 7.20
-
EXM.2.HL.TZ0.a:
Determine the ratio in which 0.1 mol dm–3 NaH2PO4 and 0.1 mol dm–3 Na2HPO4 should be mixed to obtain a buffer with pH= 7.8.
pKa NaH2PO4 = 7.20
- EXM.2.HL.TZ0.2b: Suggest, giving your reasons, the effect of diluting the buffer 1/100 with water on its pH and...
- EXM.2.HL.TZ0.2b: Suggest, giving your reasons, the effect of diluting the buffer 1/100 with water on its pH and...
- EXM.2.HL.TZ0.b: Suggest, giving your reasons, the effect of diluting the buffer 1/100 with water on its pH and...
-
22N.1A.SL.TZ0.26:
Which conditions best favour oxidation of primary alcohols directly to carboxylic acids?
A. Excess acidified potassium dichromate (VI) and distillationB. Excess acidified potassium dichromate (VI) and reflux
C. Few drops of acidified potassium dichromate (VI) and distillation
D. Few drops of acidified potassium dichromate (VI) and reflux
-
22N.1A.SL.TZ0.26:
Which conditions best favour oxidation of primary alcohols directly to carboxylic acids?
A. Excess acidified potassium dichromate (VI) and distillationB. Excess acidified potassium dichromate (VI) and reflux
C. Few drops of acidified potassium dichromate (VI) and distillation
D. Few drops of acidified potassium dichromate (VI) and reflux
- 22N.1A.SL.TZ0.24: Which are isomers of C5H12? A. I and II only B. I and III only C. II and III only D. I, II...
- 22N.1A.SL.TZ0.24: Which are isomers of C5H12? A. I and II only B. I and III only C. II and III only D. I, II...
-
22N.1A.SL.TZ0.25:
Which homologous series has the general formula CnH2nO (n > 2)?
A. AlcoholsB. Carboxylic acids
C. Ethers
D. Ketones
-
22N.1A.SL.TZ0.25:
Which homologous series has the general formula CnH2nO (n > 2)?
A. AlcoholsB. Carboxylic acids
C. Ethers
D. Ketones
- 22N.1A.SL.TZ0.19: Equal volumes of 0.10 mol dm−3 weak acid and strong acid are titrated with 0.10 mol dm−3 NaOH...
- 22N.1A.SL.TZ0.19: Equal volumes of 0.10 mol dm−3 weak acid and strong acid are titrated with 0.10 mol dm−3 NaOH...
- 22N.1A.SL.TZ0.20: Which species has the weakest conjugate base? A. HCl B. NH4+ C. HCO3− D. H2O
- 22N.1A.SL.TZ0.20: Which species has the weakest conjugate base? A. HCl B. NH4+ C. HCO3− D. H2O
Sub sections and their related questions
Reactivity 3.1.1—Brønsted–Lowry acid is a proton donor and a Brønsted–Lowry base is a proton acceptor. Deduce the Br.nsted–Lowry acid and base in a reaction.
- 22M.2.SL.TZ2.3c(ii): State the meaning of a strong Brønsted–Lowry acid.
-
22M.1A.SL.TZ1.19:
Which species are acids in the equilibrium below?
CH3NH2 + H2O CH3NH3+ + OH–
A. CH3NH2 and H2O
B. H2O and CH3NH3+
C. H2O and OH–
D. CH3NH2 and CH3NH3+
- 22M.1A.HL.TZ2.27: Which species are both Lewis and Brønsted–Lowry bases? I. CN−II. OH−III. NH3 A. I and II...
- 22M.2.SL.TZ2.6d(ii): State the meaning of a strong Brønsted–Lowry acid.
- 21N.2.SL.TZ0.5d: Outline the reason that sodium hydroxide is considered a Brønsted–Lowry base.
-
19M.2.HL.TZ2.5e:
The reaction of the hydroxide ion with carbon dioxide and with the hydrogencarbonate ion can be represented by Equations 3 and 4.
Equation (3) OH− (aq) + CO2 (g) → HCO3− (aq)
Equation (4) OH− (aq) + HCO3− (aq) → H2O (l) + CO32− (aq)Discuss how these equations show the difference between a Lewis base and a Brønsted–Lowry base.
Equation (3):
Equation (4):
- 21N.2.HL.TZ0.5d: Outline the reasons that sodium hydroxide is considered a Brønsted–Lowry and Lewis base.
- 19N.1A.HL.TZ0.27: Which can act as a Lewis acid but not a Brønsted–Lowry acid? A. BF3 B. H2O C. NF3 D. NH3
- 19N.1A.SL.TZ0.20: What is the difference between a conjugate Brønsted–Lowry acid–base pair? A. Electron pair B. ...
-
21M.1A.HL.TZ1.26:
Which is a Lewis acid, but not a Brønsted-Lowry acid?
A.
B.
C.
D.
- 21M.1A.SL.TZ2.19: Which cannot act as a Brønsted–Lowry base? A. HPO42− B. H2O C. CH4 D. NH3
- 21M.1A.SL.TZ2.26: Which is correct? A. Electrophiles are Brønsted–Lowry acids. B. Nucleophiles are...
-
20N.1A.HL.TZ0.26:
Which species is a Lewis acid but not a Brønsted–Lowry acid?
A.
B.
C.
D.
- 22M.2.SL.TZ2.3c(ii): State the meaning of a strong Brønsted–Lowry acid.
- 22M.2.SL.TZ2.c(ii): State the meaning of a strong Brønsted–Lowry acid.
-
22M.1A.SL.TZ1.19:
Which species are acids in the equilibrium below?
CH3NH2 + H2O CH3NH3+ + OH–
A. CH3NH2 and H2O
B. H2O and CH3NH3+
C. H2O and OH–
D. CH3NH2 and CH3NH3+
- 22M.1A.HL.TZ2.27: Which species are both Lewis and Brønsted–Lowry bases? I. CN−II. OH−III. NH3 A. I and II...
- 22M.2.SL.TZ2.6d(ii): State the meaning of a strong Brønsted–Lowry acid.
- 22M.2.SL.TZ2.d(ii): State the meaning of a strong Brønsted–Lowry acid.
- 21N.2.SL.TZ0.5d: Outline the reason that sodium hydroxide is considered a Brønsted–Lowry base.
- 21N.2.SL.TZ0.d: Outline the reason that sodium hydroxide is considered a Brønsted–Lowry base.
-
19M.2.HL.TZ2.5e:
The reaction of the hydroxide ion with carbon dioxide and with the hydrogencarbonate ion can be represented by Equations 3 and 4.
Equation (3) OH− (aq) + CO2 (g) → HCO3− (aq)
Equation (4) OH− (aq) + HCO3− (aq) → H2O (l) + CO32− (aq)Discuss how these equations show the difference between a Lewis base and a Brønsted–Lowry base.
Equation (3):
Equation (4):
-
19M.2.HL.TZ2.e:
The reaction of the hydroxide ion with carbon dioxide and with the hydrogencarbonate ion can be represented by Equations 3 and 4.
Equation (3) OH− (aq) + CO2 (g) → HCO3− (aq)
Equation (4) OH− (aq) + HCO3− (aq) → H2O (l) + CO32− (aq)Discuss how these equations show the difference between a Lewis base and a Brønsted–Lowry base.
Equation (3):
Equation (4):
- 21N.2.HL.TZ0.5d: Outline the reasons that sodium hydroxide is considered a Brønsted–Lowry and Lewis base.
- 21N.2.HL.TZ0.d: Outline the reasons that sodium hydroxide is considered a Brønsted–Lowry and Lewis base.
- 19N.1A.HL.TZ0.27: Which can act as a Lewis acid but not a Brønsted–Lowry acid? A. BF3 B. H2O C. NF3 D. NH3
- 19N.1A.SL.TZ0.20: What is the difference between a conjugate Brønsted–Lowry acid–base pair? A. Electron pair B. ...
-
21M.1A.HL.TZ1.26:
Which is a Lewis acid, but not a Brønsted-Lowry acid?
A.
B.
C.
D.
- 21M.1A.SL.TZ2.19: Which cannot act as a Brønsted–Lowry base? A. HPO42− B. H2O C. CH4 D. NH3
- 21M.1A.SL.TZ2.26: Which is correct? A. Electrophiles are Brønsted–Lowry acids. B. Nucleophiles are...
-
20N.1A.HL.TZ0.26:
Which species is a Lewis acid but not a Brønsted–Lowry acid?
A.
B.
C.
D.
Reactivity 3.1.2—A pair of species differing by a single proton is called a conjugate acid–base pair. Deduce the formula of the conjugate acid or base of any Br.nsted–Lowry base or acid.
-
19M.1A.SL.TZ1.27:
Which has the strongest conjugate base?
A. HCOOH (Ka = 1.8 × 10−4)
B. HNO2 (Ka = 7.2 × 10−4)
C. HCN (Ka = 6.2 × 10−10)
D. HIO3 (Ka = 1.7 × 10−1)
- 19N.2.SL.TZ0.4a(i): Identify a conjugate acid–base pair in the equation.
-
19M.2.SL.TZ2.5a(ii):
The hydrogencarbonate ion, produced in Equilibrium (2), can also act as an acid.
State the formula of its conjugate base.
-
19M.2.SL.TZ2.5a(ii):
The hydrogencarbonate ion, produced in Equilibrium (2), can also act as an acid.
State the formula of its conjugate base.
- 19N.2.SL.TZ0.4a(i): Identify a conjugate acid–base pair in the equation.
- 19N.2.SL.TZ0.4a(ii): The value of Ka at 298 K for the first dissociation is 5.01 × 10−4. State, giving a reason, the...
-
19M.2.HL.TZ1.2a:
Draw the structure of the conjugate base of benzoic acid showing all the atoms and all the bonds.
- 21M.2.SL.TZ1.2b(i): State the formula of its conjugate base.
- 21N.1A.SL.TZ0.21: What is the conjugate acid of HS−? A. H2S B. S2− C. H2SO3 D. H2SO4
-
19M.1A.SL.TZ1.27:
Which has the strongest conjugate base?
A. HCOOH (Ka = 1.8 × 10−4)
B. HNO2 (Ka = 7.2 × 10−4)
C. HCN (Ka = 6.2 × 10−10)
D. HIO3 (Ka = 1.7 × 10−1)
- 19N.2.SL.TZ0.4a(i): Identify a conjugate acid–base pair in the equation.
- 19N.2.SL.TZ0.a(i): Identify a conjugate acid–base pair in the equation.
-
19M.2.SL.TZ2.5a(ii):
The hydrogencarbonate ion, produced in Equilibrium (2), can also act as an acid.
State the formula of its conjugate base.
-
19M.2.SL.TZ2.a(ii):
The hydrogencarbonate ion, produced in Equilibrium (2), can also act as an acid.
State the formula of its conjugate base.
-
19M.2.SL.TZ2.5a(ii):
The hydrogencarbonate ion, produced in Equilibrium (2), can also act as an acid.
State the formula of its conjugate base.
-
19M.2.SL.TZ2.a(ii):
The hydrogencarbonate ion, produced in Equilibrium (2), can also act as an acid.
State the formula of its conjugate base.
- 19N.2.SL.TZ0.4a(i): Identify a conjugate acid–base pair in the equation.
- 19N.2.SL.TZ0.4a(ii): The value of Ka at 298 K for the first dissociation is 5.01 × 10−4. State, giving a reason, the...
- 19N.2.SL.TZ0.a(i): Identify a conjugate acid–base pair in the equation.
- 19N.2.SL.TZ0.a(ii): The value of Ka at 298 K for the first dissociation is 5.01 × 10−4. State, giving a reason, the...
-
19M.2.HL.TZ1.2a:
Draw the structure of the conjugate base of benzoic acid showing all the atoms and all the bonds.
-
19M.2.HL.TZ1.a:
Draw the structure of the conjugate base of benzoic acid showing all the atoms and all the bonds.
- 21M.2.SL.TZ1.2b(i): State the formula of its conjugate base.
- 21M.2.SL.TZ1.b(i): State the formula of its conjugate base.
- 21N.1A.SL.TZ0.21: What is the conjugate acid of HS−? A. H2S B. S2− C. H2SO3 D. H2SO4
Reactivity 3.1.3—Some species can act as both Brønsted–Lowry acids and bases. Interpret and formulate equations to show acid–base reactions of these species.
NoneReactivity 3.1.4—The pH scale can be used to describe the [H+] of a solution: pH = –log10[H+]; [H+] = 10–pH. Perform calculations involving the logarithmic relationship between pH and [H+].
-
19M.1A.SL.TZ2.19:
What is the pH of 0.001 mol dm−3 NaOH (aq)?
A. 1
B. 3
C. 11
D. 13
-
19M.1A.SL.TZ2.24:
What is the pH of 0.001 mol dm−3 NaOH (aq)?
A. 1
B. 3
C. 11
D. 13
-
21M.2.SL.TZ1.2b(ii):
Saturated aqueous hydrogen sulfide has a concentration of 0.10 mol dm−3 and a pH of 4.0. Demonstrate whether it is a strong or weak acid.
-
21M.1A.SL.TZ1.20:
Which solution has a pH of 9?
A. 1.0 × 10−9 mol dm−3 (aq)
B. 1.0 × 10−5 mol dm−3 (aq)
C. 1.0 × 10−9 mol dm−3 (aq)
D. 1.0 × 10−5 mol dm−3 (aq)
-
21N.2.SL.TZ0.11b:
The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.
-
19M.1A.SL.TZ2.19:
What is the pH of 0.001 mol dm−3 NaOH (aq)?
A. 1
B. 3
C. 11
D. 13
-
19M.1A.SL.TZ2.24:
What is the pH of 0.001 mol dm−3 NaOH (aq)?
A. 1
B. 3
C. 11
D. 13
-
21M.2.SL.TZ1.2b(ii):
Saturated aqueous hydrogen sulfide has a concentration of 0.10 mol dm−3 and a pH of 4.0. Demonstrate whether it is a strong or weak acid.
-
21M.2.SL.TZ1.b(ii):
Saturated aqueous hydrogen sulfide has a concentration of 0.10 mol dm−3 and a pH of 4.0. Demonstrate whether it is a strong or weak acid.
-
21M.1A.SL.TZ1.20:
Which solution has a pH of 9?
A. 1.0 × 10−9 mol dm−3 (aq)
B. 1.0 × 10−5 mol dm−3 (aq)
C. 1.0 × 10−9 mol dm−3 (aq)
D. 1.0 × 10−5 mol dm−3 (aq)
-
21N.2.SL.TZ0.11b:
The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.
-
21N.2.SL.TZ0.b:
The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.
Reactivity 3.1.5—The ion product constant of water, Kw, shows an inverse relationship between [H+] and [OH–]. Kw = [H+] [OH–]. Recognize solutions as acidic, neutral and basic from the relative values of [H+] and [OH–].
-
19M.1A.SL.TZ1.24:
Which solution is basic at 25 °C?
Kw = 1.0 × 10−14
A. [H+] = 1.0 × 10−3 mol dm−3
B. [OH−] = 1.0 × 10−13 mol dm−3
C. solution of pH = 4.00
D. [H3O+] = 1.0 × 10−13 mol dm−3
-
22M.1A.SL.TZ2.24:
What happens to the amount of hydroxide ions and hydroxide ion concentration when water is added to a solution of NH3 (aq)?
-
19M.2.SL.TZ2.5b(i):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
19M.2.SL.TZ2.5d(ii):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
- 21N.1A.SL.TZ0.27: What is correct for pure hot water?
-
19M.1A.SL.TZ1.19:
Which solution is basic at 25 °C?
Kw = 1.0 × 10−14
A. [H+] = 1.0 × 10−3 mol dm−3
B. [OH−] = 1.0 × 10−13 mol dm−3
C. solution of pH = 4.00
D. [H3O+] = 1.0 × 10−13 mol dm−3
-
19M.2.HL.TZ1.2b(i):
The pH of an aqueous solution of benzoic acid at 298 K is 2.95. Determine the concentration of hydroxide ions in the solution, using section 2 of the data booklet.
-
19M.1A.SL.TZ2.27:
The following equation represents the dissociation of water at 25 °C.
2H2O (l) H3O+ (aq) + OH− (aq) ΔH = +56 kJ
Which changes occur as the temperature increases?
A. [H3O+] increases and pH will decrease.
B. [H3O+] decreases and pH will increase.
C. [H3O+] increases and pH will increase.
D. [H3O+] decreases and pH will decrease.
- 21M.2.SL.TZ1.2b(iii): Calculate the hydroxide ion concentration in saturated aqueous hydrogen sulfide.
-
21M.1A.SL.TZ1.20:
Which solution has a pH of 9?
A. 1.0 × 10−9 mol dm−3 (aq)
B. 1.0 × 10−5 mol dm−3 (aq)
C. 1.0 × 10−9 mol dm−3 (aq)
D. 1.0 × 10−5 mol dm−3 (aq)
-
21N.2.SL.TZ0.11b:
The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.
-
19M.1A.SL.TZ1.24:
Which solution is basic at 25 °C?
Kw = 1.0 × 10−14
A. [H+] = 1.0 × 10−3 mol dm−3
B. [OH−] = 1.0 × 10−13 mol dm−3
C. solution of pH = 4.00
D. [H3O+] = 1.0 × 10−13 mol dm−3
-
22M.1A.SL.TZ2.24:
What happens to the amount of hydroxide ions and hydroxide ion concentration when water is added to a solution of NH3 (aq)?
-
19M.2.SL.TZ2.5b(i):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
19M.2.SL.TZ2.b(i):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
19M.2.SL.TZ2.5d(ii):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
19M.2.SL.TZ2.d(ii):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
- 21N.1A.SL.TZ0.27: What is correct for pure hot water?
-
19M.1A.SL.TZ1.19:
Which solution is basic at 25 °C?
Kw = 1.0 × 10−14
A. [H+] = 1.0 × 10−3 mol dm−3
B. [OH−] = 1.0 × 10−13 mol dm−3
C. solution of pH = 4.00
D. [H3O+] = 1.0 × 10−13 mol dm−3
-
19M.2.HL.TZ1.2b(i):
The pH of an aqueous solution of benzoic acid at 298 K is 2.95. Determine the concentration of hydroxide ions in the solution, using section 2 of the data booklet.
-
19M.2.HL.TZ1.b(i):
The pH of an aqueous solution of benzoic acid at 298 K is 2.95. Determine the concentration of hydroxide ions in the solution, using section 2 of the data booklet.
-
19M.1A.SL.TZ2.27:
The following equation represents the dissociation of water at 25 °C.
2H2O (l) H3O+ (aq) + OH− (aq) ΔH = +56 kJ
Which changes occur as the temperature increases?
A. [H3O+] increases and pH will decrease.
B. [H3O+] decreases and pH will increase.
C. [H3O+] increases and pH will increase.
D. [H3O+] decreases and pH will decrease.
- 21M.2.SL.TZ1.2b(iii): Calculate the hydroxide ion concentration in saturated aqueous hydrogen sulfide.
- 21M.2.SL.TZ1.b(iii): Calculate the hydroxide ion concentration in saturated aqueous hydrogen sulfide.
-
21M.1A.SL.TZ1.20:
Which solution has a pH of 9?
A. 1.0 × 10−9 mol dm−3 (aq)
B. 1.0 × 10−5 mol dm−3 (aq)
C. 1.0 × 10−9 mol dm−3 (aq)
D. 1.0 × 10−5 mol dm−3 (aq)
-
21N.2.SL.TZ0.11b:
The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.
-
21N.2.SL.TZ0.b:
The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.
Reactivity 3.1.6—Strong and weak acids and bases differ in the extent of ionization. Recognize that acid–base equilibria lie in the direction of the weaker conjugate. and are strong acids, and group 1 hydroxides are strong bases.
- 22M.1A.SL.TZ1.20: Which 0.01 mol dm–3 aqueous solution has the highest pH? A. HCl B. H2SO4 C. NaOH D. NH3
- 19N.2.SL.TZ0.4a(ii): The value of the equilibrium constant for the first dissociation at 298 K is 5.01 × 10−4. State,...
-
19M.2.SL.TZ2.5a(i):
Distinguish between a weak and strong acid.
Weak acid:
Strong acid:
-
19M.2.SL.TZ2.5a(i):
Distinguish between a weak and strong acid.
Weak acid:
Strong acid:
-
19M.2.SL.TZ1.5a:
Outline why ethanoic acid is classified as a weak acid.
- 20N.1B.SL.TZ0.2g: Suggest a risk of using sulfuric acid as the catalyst.
-
21M.2.SL.TZ1.2b(ii):
Saturated aqueous hydrogen sulfide has a concentration of 0.10 mol dm−3 and a pH of 4.0. Demonstrate whether it is a strong or weak acid.
-
20N.1A.SL.TZ0.20:
Which of these acids has the weakest conjugate base?
A.
B.
C.
D.
- 22M.1A.SL.TZ1.26: Which statement explains the Lewis acid–base nature of the chloride ion in this reaction? C2H5+...
-
22M.1A.SL.TZ2.19:
Which of the 0.001 mol dm−3 solutions is most likely to have a pH of 11.3?
A. Ca(OH)2 (aq)
B. H3PO4 (aq)
C. NaOH (aq)
D. NH4OH (aq)
- 22N.1A.SL.TZ0.19: Equal volumes of 0.10 mol dm−3 weak acid and strong acid are titrated with 0.10 mol dm−3 NaOH...
- 22N.1A.SL.TZ0.20: Which species has the weakest conjugate base? A. HCl B. NH4+ C. HCO3− D. H2O
- 22N.1A.SL.TZ0.24: Which are isomers of C5H12? A. I and II only B. I and III only C. II and III only D. I, II...
-
22N.1A.SL.TZ0.25:
Which homologous series has the general formula CnH2nO (n > 2)?
A. AlcoholsB. Carboxylic acids
C. Ethers
D. Ketones
- 22M.1A.SL.TZ1.20: Which 0.01 mol dm–3 aqueous solution has the highest pH? A. HCl B. H2SO4 C. NaOH D. NH3
- 19N.2.SL.TZ0.4a(ii): The value of the equilibrium constant for the first dissociation at 298 K is 5.01 × 10−4. State,...
- 19N.2.SL.TZ0.a(ii): The value of the equilibrium constant for the first dissociation at 298 K is 5.01 × 10−4. State,...
-
19M.2.SL.TZ2.5a(i):
Distinguish between a weak and strong acid.
Weak acid:
Strong acid:
-
19M.2.SL.TZ2.a(i):
Distinguish between a weak and strong acid.
Weak acid:
Strong acid:
-
19M.2.SL.TZ2.5a(i):
Distinguish between a weak and strong acid.
Weak acid:
Strong acid:
-
19M.2.SL.TZ2.a(i):
Distinguish between a weak and strong acid.
Weak acid:
Strong acid:
-
19M.2.SL.TZ1.5a:
Outline why ethanoic acid is classified as a weak acid.
-
19M.2.SL.TZ1.a:
Outline why ethanoic acid is classified as a weak acid.
- 20N.1B.SL.TZ0.g: Suggest a risk of using sulfuric acid as the catalyst.
-
21M.2.SL.TZ1.2b(ii):
Saturated aqueous hydrogen sulfide has a concentration of 0.10 mol dm−3 and a pH of 4.0. Demonstrate whether it is a strong or weak acid.
-
21M.2.SL.TZ1.b(ii):
Saturated aqueous hydrogen sulfide has a concentration of 0.10 mol dm−3 and a pH of 4.0. Demonstrate whether it is a strong or weak acid.
-
20N.1A.SL.TZ0.20:
Which of these acids has the weakest conjugate base?
A.
B.
C.
D.
- 22M.1A.SL.TZ1.26: Which statement explains the Lewis acid–base nature of the chloride ion in this reaction? C2H5+...
-
22M.1A.SL.TZ2.19:
Which of the 0.001 mol dm−3 solutions is most likely to have a pH of 11.3?
A. Ca(OH)2 (aq)
B. H3PO4 (aq)
C. NaOH (aq)
D. NH4OH (aq)
- 22N.1A.SL.TZ0.19: Equal volumes of 0.10 mol dm−3 weak acid and strong acid are titrated with 0.10 mol dm−3 NaOH...
- 22N.1A.SL.TZ0.20: Which species has the weakest conjugate base? A. HCl B. NH4+ C. HCO3− D. H2O
- 22N.1A.SL.TZ0.24: Which are isomers of C5H12? A. I and II only B. I and III only C. II and III only D. I, II...
-
22N.1A.SL.TZ0.25:
Which homologous series has the general formula CnH2nO (n > 2)?
A. AlcoholsB. Carboxylic acids
C. Ethers
D. Ketones
Reactivity 3.1.7—Acids react with bases in neutralization reactions. Formulate equations for the reactions between acids and metal oxides, metal hydroxides, hydrogencarbonates and carbonates.
-
22M.2.SL.TZ1.1d(iii):
Deduce, giving reasons, whether the reaction of magnesium nitride with water is an acid–base reaction, a redox reaction, neither or both.
-
21N.2.SL.TZ0.5a:
Formulate an equation for the reaction of one mole of phosphoric acid with one mole of sodium hydroxide.
-
21N.2.SL.TZ0.5a:
Formulate an equation for the reaction of one mole of phosphoric acid with one mole of sodium hydroxide.
-
20N.1B.SL.TZ0.2d:
An additional experiment was conducted in which only the sulfuric acid catalyst was titrated with . Outline why this experiment was necessary.
-
19M.1A.SL.TZ1.25:
With which do most acids react?
I. sodium hydrogen carbonate
II. magnesium
III. calcium sulfateA. I and II only
B. I and III only
C. II and III only
D. I, II and III
- 23M.1A.SL.TZ1.5: Which statement best explains the first ionization energy of sulfur being lower than that of...
-
22M.2.SL.TZ1.1d(iii):
Deduce, giving reasons, whether the reaction of magnesium nitride with water is an acid–base reaction, a redox reaction, neither or both.
-
22M.2.SL.TZ1.d(iii):
Deduce, giving reasons, whether the reaction of magnesium nitride with water is an acid–base reaction, a redox reaction, neither or both.
-
21N.2.SL.TZ0.5a:
Formulate an equation for the reaction of one mole of phosphoric acid with one mole of sodium hydroxide.
-
21N.2.SL.TZ0.a:
Formulate an equation for the reaction of one mole of phosphoric acid with one mole of sodium hydroxide.
-
21N.2.SL.TZ0.5a:
Formulate an equation for the reaction of one mole of phosphoric acid with one mole of sodium hydroxide.
-
21N.2.SL.TZ0.a:
Formulate an equation for the reaction of one mole of phosphoric acid with one mole of sodium hydroxide.
-
20N.1B.SL.TZ0.d:
An additional experiment was conducted in which only the sulfuric acid catalyst was titrated with . Outline why this experiment was necessary.
-
19M.1A.SL.TZ1.25:
With which do most acids react?
I. sodium hydrogen carbonate
II. magnesium
III. calcium sulfateA. I and II only
B. I and III only
C. II and III only
D. I, II and III
- 23M.1A.SL.TZ1.5: Which statement best explains the first ionization energy of sulfur being lower than that of...
Reactivity 3.1.8—pH curves for neutralization reactions involving strong acids and bases have characteristic shapes and features. Sketch and interpret the general shape of the pH curve.
- 19M.1A.SL.TZ1.35: Which solvent is aprotic? A. H2O B. C6H5CH3 C. CH3OH D. CH3NH2
- 19M.1A.SL.TZ1.35: Which solvent is aprotic? A. H2O B. C6H5CH3 C. CH3OH D. CH3NH2
Reactivity 3.1.9—The pOH scale describes the [OH–] of a solution. pOH = –log10[OH–]; [OH–] = 10–pOH. Interconvert [H+], [OH–], pH and pOH values.
-
21M.2.HL.TZ2.1c(iii):
Saturated calcium hydroxide solution is used to test for carbon dioxide. Calculate the pH of a 2.33 × 10−2 mol dm−3 solution of calcium hydroxide, a strong base.
-
20N.1A.HL.TZ0.27:
What is the pH of an ammonia solution that has ?
A.
B.
C.
D.
-
21N.1A.HL.TZ0.25:
What is the pH of 0.01 mol dm−3 KOH (aq)?
A. 1.0B. 2.0
C. 12.0
D. 13.0
-
21M.2.HL.TZ2.1c(iii):
Saturated calcium hydroxide solution is used to test for carbon dioxide. Calculate the pH of a 2.33 × 10−2 mol dm−3 solution of calcium hydroxide, a strong base.
-
21M.2.HL.TZ2.c(iii):
Saturated calcium hydroxide solution is used to test for carbon dioxide. Calculate the pH of a 2.33 × 10−2 mol dm−3 solution of calcium hydroxide, a strong base.
-
20N.1A.HL.TZ0.27:
What is the pH of an ammonia solution that has ?
A.
B.
C.
D.
-
21N.1A.HL.TZ0.25:
What is the pH of 0.01 mol dm−3 KOH (aq)?
A. 1.0B. 2.0
C. 12.0
D. 13.0
Reactivity 3.1.10—The strengths of weak acids and bases are described by their Ka, Kb, pKa or pKb values. Interpret the relative strengths of acids and bases from these data.
- 19N.1A.HL.TZ0.28: What is the order, in increasing pH, of the following solutions of equal concentration? A....
- 19N.1A.HL.TZ0.28: What is the order, in increasing pH, of the following solutions of equal concentration? A....
Reactivity 3.1.11—For a conjugate acid–base pair, the relationship Ka Å~ Kb = Kw can be derived from the expressions for Ka and Kb. Solve problems involving these values.
-
22M.2.HL.TZ2.7a(ii):
Calculate the pH of a 1.00 × 10−2 mol dm−3 aqueous solution of ammonia.
pKb = 4.75 at 298 K.
-
19M.2.HL.TZ2.5c:
At 298 K the concentration of aqueous carbon dioxide in carbonated water is 0.200 mol dm−3 and the pKa for Equilibrium (2) is 6.36.
Calculate the pH of carbonated water.
-
21N.2.HL.TZ0.11a:
Calculate the initial pH before any sodium hydroxide was added, using section 21 of the data booklet.
-
22M.2.HL.TZ2.7a(ii):
Calculate the pH of a 1.00 × 10−2 mol dm−3 aqueous solution of ammonia.
pKb = 4.75 at 298 K.
-
22M.2.HL.TZ2.a(ii):
Calculate the pH of a 1.00 × 10−2 mol dm−3 aqueous solution of ammonia.
pKb = 4.75 at 298 K.
-
19M.2.HL.TZ2.5c:
At 298 K the concentration of aqueous carbon dioxide in carbonated water is 0.200 mol dm−3 and the pKa for Equilibrium (2) is 6.36.
Calculate the pH of carbonated water.
-
19M.2.HL.TZ2.c:
At 298 K the concentration of aqueous carbon dioxide in carbonated water is 0.200 mol dm−3 and the pKa for Equilibrium (2) is 6.36.
Calculate the pH of carbonated water.
-
21N.2.HL.TZ0.11a:
Calculate the initial pH before any sodium hydroxide was added, using section 21 of the data booklet.
-
21N.2.HL.TZ0.a:
Calculate the initial pH before any sodium hydroxide was added, using section 21 of the data booklet.
Reactivity 3.1.12—The pH of a salt solution depends on the relative strengths of the parent acid and base. Construct equations for the hydrolysis of ions in a salt, and predict the effect of each ion on the pH of the salt solution.
- 21M.1A.HL.TZ2.27: Which compound is acidic in aqueous solution? A. KBr B. CH3COONa C. NH4Cl D. Na2CO3
- 22M.1A.HL.TZ1.27: In which set are the salts arranged in order of increasing pH? A. HCOONH4 < KBr < NH4Br...
- 21M.1A.HL.TZ2.27: Which compound is acidic in aqueous solution? A. KBr B. CH3COONa C. NH4Cl D. Na2CO3
- 22M.1A.HL.TZ1.27: In which set are the salts arranged in order of increasing pH? A. HCOONH4 < KBr < NH4Br...
Reactivity 3.1.13—pH curves of different combinations of strong and weak monoprotic acids and bases have characteristic shapes and features. Interpret the general shapes of pH curves for all four combinations of strong and weak acids and bases.
- 22M.1A.HL.TZ2.26: A weak base is titrated with a strong acid. Which value of pKb can be estimated from this...
-
19M.2.HL.TZ2.5f:
Aqueous sodium hydrogencarbonate has a pH of approximately 7 at 298 K.
Sketch a graph of pH against volume when 25.0cm3 of 0.100 mol dm−3 NaOH (aq) is gradually added to 10.0cm3 of 0.0500 mol dm−3 NaHCO3 (aq).
-
19M.1A.HL.TZ2.26:
Where is the buffer region for the titration of a weak acid with a strong base?
- 21N.1A.HL.TZ0.26: What is a possible value of pH at the equivalence point in the titration of a strong acid with a...
- 19N.2.HL.TZ0.5a: A sample of ethanoic acid was titrated with sodium hydroxide solution, and the following pH curve...
-
21N.2.HL.TZ0.11c:
Sketch the neutralisation curve obtained and label the equivalence point.
- 22M.1A.HL.TZ2.26: A weak base is titrated with a strong acid. Which value of pKb can be estimated from this...
-
19M.2.HL.TZ2.5f:
Aqueous sodium hydrogencarbonate has a pH of approximately 7 at 298 K.
Sketch a graph of pH against volume when 25.0cm3 of 0.100 mol dm−3 NaOH (aq) is gradually added to 10.0cm3 of 0.0500 mol dm−3 NaHCO3 (aq).
-
19M.2.HL.TZ2.f:
Aqueous sodium hydrogencarbonate has a pH of approximately 7 at 298 K.
Sketch a graph of pH against volume when 25.0cm3 of 0.100 mol dm−3 NaOH (aq) is gradually added to 10.0cm3 of 0.0500 mol dm−3 NaHCO3 (aq).
-
19M.1A.HL.TZ2.26:
Where is the buffer region for the titration of a weak acid with a strong base?
- 21N.1A.HL.TZ0.26: What is a possible value of pH at the equivalence point in the titration of a strong acid with a...
- 19N.2.HL.TZ0.5a: A sample of ethanoic acid was titrated with sodium hydroxide solution, and the following pH curve...
- 19N.2.HL.TZ0.a: A sample of ethanoic acid was titrated with sodium hydroxide solution, and the following pH curve...
-
21N.2.HL.TZ0.11c:
Sketch the neutralisation curve obtained and label the equivalence point.
-
21N.2.HL.TZ0.c:
Sketch the neutralisation curve obtained and label the equivalence point.
Reactivity 3.1.14—Acid–base indicators are weak acids, where the components of the conjugate acid–base pair have different colours. The pH of the end point of an indicator, where it changes colour, approximately corresponds to its pKa value. Construct equilibria expressions to show why the colour of an indicator changes with pH.
NoneReactivity 3.1.15—An appropriate indicator for a titration has an end point range that coincides with the pH at the equivalence point. Identify an appropriate indicator for a titration from the identity of the salt and the pH range of the indicator.
- 19M.1A.SL.TZ1.20: Which is not a source of oxides of sulfur and nitrogen? A. burning coal B. internal combustion...
- 19N.2.HL.TZ0.5b(i): Identify the most suitable indicator for the titration using section 22 of the data booklet.
- 19M.1A.SL.TZ1.20: Which is not a source of oxides of sulfur and nitrogen? A. burning coal B. internal combustion...
- 19N.2.HL.TZ0.5b(i): Identify the most suitable indicator for the titration using section 22 of the data booklet.
- 19N.2.HL.TZ0.b(i): Identify the most suitable indicator for the titration using section 22 of the data booklet.
Reactivity 3.1.16—A buffer solution is one that resists change in pH on the addition of small amounts of acid or alkali. Describe the composition of acidic and basic buffers and explain their actions.
-
19N.2.HL.TZ0.5b(ii):
Describe, using a suitable equation, how the buffer solution formed during the titration resists pH changes when a small amount of acid is added.
-
22N.1A.SL.TZ0.26:
Which conditions best favour oxidation of primary alcohols directly to carboxylic acids?
A. Excess acidified potassium dichromate (VI) and distillationB. Excess acidified potassium dichromate (VI) and reflux
C. Few drops of acidified potassium dichromate (VI) and distillation
D. Few drops of acidified potassium dichromate (VI) and reflux
-
22N.1A.HL.TZ0.26:
Which solutions will form a buffer when mixed?
A. 50 cm3 of 1.0 mol dm−3 HCl and 50 cm3 of 1.0 mol dm−3 NaOHB. 50 cm3 of 1.0 mol dm−3 CH3COOH and 50 cm3 of 1.0 mol dm−3 NaOH
C. 50 cm3 of 1.0 mol dm−3 CH3COOH and 100 cm3 of 1.0 mol dm−3 NaOH
D. 100 cm3 of 1.0 mol dm−3 CH3COOH and 50 cm3 of 1.0 mol dm−3 NaOH
-
19N.2.HL.TZ0.5b(ii):
Describe, using a suitable equation, how the buffer solution formed during the titration resists pH changes when a small amount of acid is added.
-
19N.2.HL.TZ0.b(ii):
Describe, using a suitable equation, how the buffer solution formed during the titration resists pH changes when a small amount of acid is added.
-
22N.1A.SL.TZ0.26:
Which conditions best favour oxidation of primary alcohols directly to carboxylic acids?
A. Excess acidified potassium dichromate (VI) and distillationB. Excess acidified potassium dichromate (VI) and reflux
C. Few drops of acidified potassium dichromate (VI) and distillation
D. Few drops of acidified potassium dichromate (VI) and reflux
-
22N.1A.HL.TZ0.26:
Which solutions will form a buffer when mixed?
A. 50 cm3 of 1.0 mol dm−3 HCl and 50 cm3 of 1.0 mol dm−3 NaOHB. 50 cm3 of 1.0 mol dm−3 CH3COOH and 50 cm3 of 1.0 mol dm−3 NaOH
C. 50 cm3 of 1.0 mol dm−3 CH3COOH and 100 cm3 of 1.0 mol dm−3 NaOH
D. 100 cm3 of 1.0 mol dm−3 CH3COOH and 50 cm3 of 1.0 mol dm−3 NaOH
Reactivity 3.1.17—The pH of a buffer solution depends on both: • the pKa or pKb of its acid or base • the ratio of the concentration of acid or base to the concentration of the conjugate base or acid. Solve problems involving the composition and pH of a buffer solution, using the equilibrium constant.
-
19M.2.HL.TZ1.12b:
Enzymatic activity is studied in buffered aqueous solutions.
Calculate the ratio in which 0.1 mol dm−3 NaH2PO4 (aq) and 0.1 mol dm−3 Na2HPO4 (aq) should be mixed to obtain a buffer with pH = 6.10. Use section 1 of the data booklet.
pKa (NaH2PO4) = 7.20
- 22M.2.HL.TZ2.7a(iii): Justify whether a 1.0 dm3 solution made from 0.10 mol NH3 and 0.20 mol HCl will form a buffer...
-
19M.2.HL.TZ2.23b:
Some antacids contain carbonates.
Determine the pH of a buffer solution which contains 0.160 mol dm−3 CO32− and 0.200 mol dm−3 HCO3−, using section 1 of the data booklet.
pKa (HCO3−) = 10.32
-
19M.2.HL.TZ2.16b:
Some antacids contain carbonates.
Determine the pH of a buffer solution which contains 0.160 mol dm−3 CO32− and 0.200 mol dm−3 HCO3−, using section 1 of the data booklet.
pKa (HCO3−) = 10.32
- 21M.1A.HL.TZ1.27: Which combination will produce an alkaline buffer in water? A. 0.10 mol NH3 and 0.05 mol...
-
EXM.1A.HL.TZ0.9:
Which of the following statements is correct when a 1.0 M NH4+/NH3 buffer (pH = 9.2) is diluted to 0.5 M with water?
I. The ability of the buffer to resist changes in pH when acids are added will decrease.
II. The ability of the buffer to resist changes in pH when bases are added will decrease.
III. The pH of the buffer will be equal to 7.
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
-
EXM.2.HL.TZ0.2a:
Determine the ratio in which 0.1 mol dm–3 NaH2PO4 and 0.1 mol dm–3 Na2HPO4 should be mixed to obtain a buffer with pH= 7.8.
pKa NaH2PO4 = 7.20
- EXM.2.HL.TZ0.2b: Suggest, giving your reasons, the effect of diluting the buffer 1/100 with water on its pH and...
-
19M.2.HL.TZ1.b:
Enzymatic activity is studied in buffered aqueous solutions.
Calculate the ratio in which 0.1 mol dm−3 NaH2PO4 (aq) and 0.1 mol dm−3 Na2HPO4 (aq) should be mixed to obtain a buffer with pH = 6.10. Use section 1 of the data booklet.
pKa (NaH2PO4) = 7.20
- 22M.2.HL.TZ2.7a(iii): Justify whether a 1.0 dm3 solution made from 0.10 mol NH3 and 0.20 mol HCl will form a buffer...
- 22M.2.HL.TZ2.a(iii): Justify whether a 1.0 dm3 solution made from 0.10 mol NH3 and 0.20 mol HCl will form a buffer...
-
19M.2.HL.TZ2.b:
Some antacids contain carbonates.
Determine the pH of a buffer solution which contains 0.160 mol dm−3 CO32− and 0.200 mol dm−3 HCO3−, using section 1 of the data booklet.
pKa (HCO3−) = 10.32
-
19M.2.HL.TZ2.b:
Some antacids contain carbonates.
Determine the pH of a buffer solution which contains 0.160 mol dm−3 CO32− and 0.200 mol dm−3 HCO3−, using section 1 of the data booklet.
pKa (HCO3−) = 10.32
- 21M.1A.HL.TZ1.27: Which combination will produce an alkaline buffer in water? A. 0.10 mol NH3 and 0.05 mol...
-
EXM.1A.HL.TZ0.9:
Which of the following statements is correct when a 1.0 M NH4+/NH3 buffer (pH = 9.2) is diluted to 0.5 M with water?
I. The ability of the buffer to resist changes in pH when acids are added will decrease.
II. The ability of the buffer to resist changes in pH when bases are added will decrease.
III. The pH of the buffer will be equal to 7.
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
-
EXM.2.HL.TZ0.2a:
Determine the ratio in which 0.1 mol dm–3 NaH2PO4 and 0.1 mol dm–3 Na2HPO4 should be mixed to obtain a buffer with pH= 7.8.
pKa NaH2PO4 = 7.20
- EXM.2.HL.TZ0.2b: Suggest, giving your reasons, the effect of diluting the buffer 1/100 with water on its pH and...
-
EXM.2.HL.TZ0.a:
Determine the ratio in which 0.1 mol dm–3 NaH2PO4 and 0.1 mol dm–3 Na2HPO4 should be mixed to obtain a buffer with pH= 7.8.
pKa NaH2PO4 = 7.20
- EXM.2.HL.TZ0.b: Suggest, giving your reasons, the effect of diluting the buffer 1/100 with water on its pH and...