DP Physics (first assessment 2025)

Question 22N.2.HL.TZ0.8b.i

Date	November 2022	Marks available	[Maximum mark: 2]	Reference code	22N.2.HL.TZ0.8b.i
Level	HL	Paper	2	Time zone	TZ0
Command term	Show that	Question number	b.i	Adapted from	N/A

b.i.

[Maximum mark: 2]

22N.2.HL.TZ0.8b.i

(b.i)

Show that the kinetic energy of the satellite in orbit is about 2 × 10¹⁰ J.

[2]

Markscheme

orbital radius $= 6.4 \times 10^{6} + 5.0 \times 10^{5}$ « $= 6.9 \times 10^{6}$ m» ✓

$KE = \frac{1}{2} \times 8.0 \times 10^{2} \times \frac{6.67 \times 10^{- 11} \times 6.0 \times 10^{24}}{6.9 \times 10^{6}}$ OR $2.3 \times 10^{10}$ «J» ✓

Award [1] max for answers ignoring orbital height (KE = 2.5 × 10¹⁰ J).

Examiners report

This question was well done, with only a few missing the height of the satellite.

Syllabus sections

D. Fields

D. Fields » D.1 Gravitational fields

Question 22N.2.HL.TZ0.8b.i

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