Directly related questions
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EXE.1A.HL.TZ0.25:
A space probe moves in a circular orbit around Earth. The kinetic energy of the probe is .
The probe will reach the escape speed when its kinetic energy is increased at least to:
A.B.
C.
D.
-
EXE.1A.HL.TZ0.25:
A space probe moves in a circular orbit around Earth. The kinetic energy of the probe is .
The probe will reach the escape speed when its kinetic energy is increased at least to:
A.B.
C.
D.
-
EXE.1A.HL.TZ0.26:
What is the escape speed from the surface of a planet of radius that has an acceleration of gravity at its surface?
A.B.
C.
D.
-
EXE.1A.HL.TZ0.26:
What is the escape speed from the surface of a planet of radius that has an acceleration of gravity at its surface?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.13:
Planets X and Y move in circular orbits around the same star.
The orbital period of planet Y is twice the orbital period of planet X. The orbital radius of planet X is .
What is the orbital radius of planet Y?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.13:
Planets X and Y move in circular orbits around the same star.
The orbital period of planet Y is twice the orbital period of planet X. The orbital radius of planet X is .
What is the orbital radius of planet Y?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.15:
Two long parallel wires X and Y carry equal currents I. The magnetic force exerted per unit length of each wire is .
The current in X is halved and the current in Y is doubled. What is the force per unit length of each wire after the change?
Force per unit length of X Force per unit length of Y A. B. C. D. -
EXE.1A.SL.TZ0.15:
Two long parallel wires X and Y carry equal currents I. The magnetic force exerted per unit length of each wire is .
The current in X is halved and the current in Y is doubled. What is the force per unit length of each wire after the change?
Force per unit length of X Force per unit length of Y A. B. C. D. - EXE.1A.SL.TZ0.16: The force per unit length between two long parallel current-carrying wires is F. The distance...
- EXE.1A.SL.TZ0.16: The force per unit length between two long parallel current-carrying wires is F. The distance...
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EXE.1A.SL.TZ0.14:
Kepler’s Third law relates the orbital period of a planet about its sun to its orbital radius . The mass of the Sun is .
What is a correct algebraic form of the law?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.14:
Kepler’s Third law relates the orbital period of a planet about its sun to its orbital radius . The mass of the Sun is .
What is a correct algebraic form of the law?
A.B.
C.
D.
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EXE.2.HL.TZ0.2aii:
Outline how an emf is generated in the coil.
-
EXE.2.HL.TZ0.2aii:
Outline how an emf is generated in the coil.
-
EXE.2.HL.TZ0.ii:
Outline how an emf is generated in the coil.
- EXE.2.HL.TZ0.2b: Suggest two changes to the system that will make the geophone more sensitive.
- EXE.2.HL.TZ0.2b: Suggest two changes to the system that will make the geophone more sensitive.
- EXE.2.HL.TZ0.b: Suggest two changes to the system that will make the geophone more sensitive.
- EXE.2.HL.TZ0.2ai: State the movement direction for which the geophone has its greatest sensitivity.
- EXE.2.HL.TZ0.2ai: State the movement direction for which the geophone has its greatest sensitivity.
- EXE.2.HL.TZ0.i: State the movement direction for which the geophone has its greatest sensitivity.
-
EXE.2.HL.TZ0.2aiii:
Explain why the magnitude of the emf is related to the amplitude of the ground movement.
-
EXE.2.HL.TZ0.2aiii:
Explain why the magnitude of the emf is related to the amplitude of the ground movement.
-
EXE.2.HL.TZ0.iii:
Explain why the magnitude of the emf is related to the amplitude of the ground movement.
-
EXE.2.HL.TZ0.2aiv:
In one particular event, a maximum emf of 65 mV is generated in the geophone. The geophone coil has 150 turns.
Calculate the rate of flux change that leads to this emf.
-
EXE.2.HL.TZ0.2aiv:
In one particular event, a maximum emf of 65 mV is generated in the geophone. The geophone coil has 150 turns.
Calculate the rate of flux change that leads to this emf.
-
EXE.2.HL.TZ0.iv:
In one particular event, a maximum emf of 65 mV is generated in the geophone. The geophone coil has 150 turns.
Calculate the rate of flux change that leads to this emf.
-
EXE.2.HL.TZ0.16a:
The radius of the dwarf planet Pluto is 1.19 x 106 m. The acceleration due to gravity at its surface is 0.617 m s−2.
Determine the escape speed for an object at the surface of Pluto.
-
EXE.2.HL.TZ0.a:
The radius of the dwarf planet Pluto is 1.19 x 106 m. The acceleration due to gravity at its surface is 0.617 m s−2.
Determine the escape speed for an object at the surface of Pluto.
-
EXE.2.HL.TZ0.16a:
The radius of the dwarf planet Pluto is 1.19 x 106 m. The acceleration due to gravity at its surface is 0.617 m s−2.
Determine the escape speed for an object at the surface of Pluto.
- EXE.2.HL.TZ0.15ci: in its initial circular orbit;
- EXE.2.HL.TZ0.i: in its initial circular orbit;
- EXE.2.HL.TZ0.15cii: in its final orbit.
- EXE.2.HL.TZ0.ii: in its final orbit.
-
EXE.2.HL.TZ0.16b:
Pluto rotates about an axis through its centre. Its rotation is in the opposite sense to that of the Earth, i.e. from east to west.
Explain the advantage of an object launching from the equator of Pluto and travelling to the west.
-
EXE.2.HL.TZ0.b:
Pluto rotates about an axis through its centre. Its rotation is in the opposite sense to that of the Earth, i.e. from east to west.
Explain the advantage of an object launching from the equator of Pluto and travelling to the west.
-
EXE.2.HL.TZ0.16b:
Pluto rotates about an axis through its centre. Its rotation is in the opposite sense to that of the Earth, i.e. from east to west.
Explain the advantage of an object launching from the equator of Pluto and travelling to the west.
- EXE.2.SL.TZ0.11a: A comet orbits the Sun in an elliptical orbit. A and B are two positions of the comet. Explain,...
- EXE.2.SL.TZ0.11a: A comet orbits the Sun in an elliptical orbit. A and B are two positions of the comet. Explain,...
- EXE.2.SL.TZ0.a: A comet orbits the Sun in an elliptical orbit. A and B are two positions of the comet. Explain,...
-
EXE.2.SL.TZ0.11b:
An asteroid (minor planet) orbits the Sun in a circular orbit of radius 4.5 × 108 km. The radius of Earth’s orbit is 1.5 × 108 km. Calculate, in years, the orbital period of the asteroid.
-
EXE.2.SL.TZ0.11b:
An asteroid (minor planet) orbits the Sun in a circular orbit of radius 4.5 × 108 km. The radius of Earth’s orbit is 1.5 × 108 km. Calculate, in years, the orbital period of the asteroid.
-
EXE.2.SL.TZ0.b:
An asteroid (minor planet) orbits the Sun in a circular orbit of radius 4.5 × 108 km. The radius of Earth’s orbit is 1.5 × 108 km. Calculate, in years, the orbital period of the asteroid.
-
EXE.2.SL.TZ0.12a:
Show that .
-
EXE.2.SL.TZ0.12a:
Show that .
-
EXE.2.SL.TZ0.a:
Show that .
-
EXE.2.SL.TZ0.12c:
Determine the mass of Mars.
-
EXE.2.SL.TZ0.12c:
Determine the mass of Mars.
-
EXE.2.SL.TZ0.c:
Determine the mass of Mars.
- EXE.2.SL.TZ0.17aii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
- EXE.2.SL.TZ0.17aii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
- EXE.2.SL.TZ0.ii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
- EXE.2.SL.TZ0.15bi: magnetic field at A;
- EXE.2.SL.TZ0.15bi: magnetic field at A;
- EXE.2.SL.TZ0.i: magnetic field at A;
-
EXE.2.SL.TZ0.16b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
-
EXE.2.SL.TZ0.16b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
-
EXE.2.SL.TZ0.b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
- EXE.2.SL.TZ0.14cii: Deduce the current in R.
- EXE.2.SL.TZ0.14cii: Deduce the current in R.
- EXE.2.SL.TZ0.ii: Deduce the current in R.
-
EXE.2.SL.TZ0.13a:
Show that for the planets in a solar system where is the orbital period of a planet and is the radius of circular orbit of planet about its sun.
-
EXE.2.SL.TZ0.13a:
Show that for the planets in a solar system where is the orbital period of a planet and is the radius of circular orbit of planet about its sun.
-
EXE.2.SL.TZ0.a:
Show that for the planets in a solar system where is the orbital period of a planet and is the radius of circular orbit of planet about its sun.
-
EXE.2.SL.TZ0.13bi:
Outline what is meant by one astronomical unit (1 AU)
-
EXE.2.SL.TZ0.13bi:
Outline what is meant by one astronomical unit (1 AU)
-
EXE.2.SL.TZ0.i:
Outline what is meant by one astronomical unit (1 AU)
-
EXE.2.SL.TZ0.14b:
Calculate the current in wire Q.
-
EXE.2.SL.TZ0.14b:
Calculate the current in wire Q.
-
EXE.2.SL.TZ0.b:
Calculate the current in wire Q.
- EXE.2.SL.TZ0.15bii: magnetic force on section AB of the loop.
- EXE.2.SL.TZ0.15bii: magnetic force on section AB of the loop.
- EXE.2.SL.TZ0.ii: magnetic force on section AB of the loop.
-
EXE.2.SL.TZ0.15ci:
magnitude of the net force acting on the loop;
-
EXE.2.SL.TZ0.15ci:
magnitude of the net force acting on the loop;
-
EXE.2.SL.TZ0.i:
magnitude of the net force acting on the loop;
-
EXE.2.SL.TZ0.16a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.16a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.13bii:
Pluto is a dwarf planet of the Sun that orbits at a distance of 5.9 × 109 km from the Sun. Determine, in years, the orbital period of Pluto.
-
EXE.2.SL.TZ0.13bii:
Pluto is a dwarf planet of the Sun that orbits at a distance of 5.9 × 109 km from the Sun. Determine, in years, the orbital period of Pluto.
-
EXE.2.SL.TZ0.ii:
Pluto is a dwarf planet of the Sun that orbits at a distance of 5.9 × 109 km from the Sun. Determine, in years, the orbital period of Pluto.
-
EXE.2.SL.TZ0.14a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
-
EXE.2.SL.TZ0.14a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
-
EXE.2.SL.TZ0.a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
- EXE.2.SL.TZ0.15cii: direction of the net force acting on the loop.
- EXE.2.SL.TZ0.15cii: direction of the net force acting on the loop.
- EXE.2.SL.TZ0.ii: direction of the net force acting on the loop.
-
EXE.2.SL.TZ0.17b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
-
EXE.2.SL.TZ0.17b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
-
EXE.2.SL.TZ0.b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
- EXE.1A.SL.TZ0.18: A 4.0 cm length of a conducting wire carries a current of 2.5 A. The length is parallel to...
- EXE.1A.SL.TZ0.18: A 4.0 cm length of a conducting wire carries a current of 2.5 A. The length is parallel to...
- EXE.2.SL.TZ0.14ci: State the direction of the current in R, relative to the current in P.
- EXE.2.SL.TZ0.14ci: State the direction of the current in R, relative to the current in P.
- EXE.2.SL.TZ0.i: State the direction of the current in R, relative to the current in P.
-
EXE.2.SL.TZ0.15a:
State the fundamental SI units for permeability of free space, .
-
EXE.2.SL.TZ0.15a:
State the fundamental SI units for permeability of free space, .
-
EXE.2.SL.TZ0.a:
State the fundamental SI units for permeability of free space, .
-
EXE.2.SL.TZ0.17ai:
Draw the magnetic field lines due to A.
-
EXE.2.SL.TZ0.17ai:
Draw the magnetic field lines due to A.
-
EXE.2.SL.TZ0.i:
Draw the magnetic field lines due to A.
- EXE.1A.SL.TZ0.17: Three current-carrying wires lie in the same plane and carry currents of 6 A, 2 A and 4 A. The...
- EXE.1A.SL.TZ0.17: Three current-carrying wires lie in the same plane and carry currents of 6 A, 2 A and 4 A. The...
-
EXE.2.HL.TZ0.15aii:
escape speed from its orbit.
-
EXE.2.HL.TZ0.ii:
escape speed from its orbit.
-
EXE.2.HL.TZ0.15ai:
orbital speed;
-
EXE.2.HL.TZ0.i:
orbital speed;
-
22N.1A.HL.TZ0.31:
An electric field is established between two electrodes separated by distance d, held at a potential difference of V. A charged particle in this field experiences a force F.
What is the charge on the particle?
A.B.
C.
D.
-
22N.1A.HL.TZ0.31:
An electric field is established between two electrodes separated by distance d, held at a potential difference of V. A charged particle in this field experiences a force F.
What is the charge on the particle?
A.B.
C.
D.
- 22N.1A.HL.TZ0.32: Two satellites are in circular orbits around the Earth. Both satellites have the same mass...
- 22N.1A.HL.TZ0.32: Two satellites are in circular orbits around the Earth. Both satellites have the same mass...
- 22N.1A.SL.TZ0.19: A loop of wire lies in a magnetic field directed into the plane of the page. The loop carries a...
- 22N.1A.SL.TZ0.19: A loop of wire lies in a magnetic field directed into the plane of the page. The loop carries a...
-
22N.1A.SL.TZ0.22:
The centre of the Earth and the Moon are a distance apart. There is a point X between them where their gravitational fields cancel out. The distance from the centre of the Earth to X is . The mass of the Earth is and the mass of the Moon is .
What is correct at X?
A.B.
C.
D.
-
22N.1A.SL.TZ0.22:
The centre of the Earth and the Moon are a distance apart. There is a point X between them where their gravitational fields cancel out. The distance from the centre of the Earth to X is . The mass of the Earth is and the mass of the Moon is .
What is correct at X?
A.B.
C.
D.
- 22N.1A.HL.TZ0.33: A resistor connects two parallel conducting rails a distance d apart. A conducting bar rolls...
- 22N.1A.HL.TZ0.33: A resistor connects two parallel conducting rails a distance d apart. A conducting bar rolls...
- 22N.1A.HL.TZ0.34: Two coils of wire are wound around an iron cylinder. One coil is connected in a circuit with...
- 22N.1A.HL.TZ0.34: Two coils of wire are wound around an iron cylinder. One coil is connected in a circuit with...
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.5c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.5c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.SL.TZ0.5c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.SL.TZ0.c.ii: Identify the direction of the magnetic force on the wire.
-
22N.2.HL.TZ0.8a:
The diagram shows field lines for an electrostatic field. X and Y are two points on the same field line.
Outline which of the two points has the larger electric potential.
-
22N.2.HL.TZ0.8a:
The diagram shows field lines for an electrostatic field. X and Y are two points on the same field line.
Outline which of the two points has the larger electric potential.
-
22N.2.HL.TZ0.a:
The diagram shows field lines for an electrostatic field. X and Y are two points on the same field line.
Outline which of the two points has the larger electric potential.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
-
22N.2.HL.TZ0.8b.ii:
Determine the minimum energy required to launch the satellite. Ignore the original kinetic energy of the satellite due to Earth’s rotation.
-
22N.2.HL.TZ0.8b.ii:
Determine the minimum energy required to launch the satellite. Ignore the original kinetic energy of the satellite due to Earth’s rotation.
-
22N.2.HL.TZ0.b.ii:
Determine the minimum energy required to launch the satellite. Ignore the original kinetic energy of the satellite due to Earth’s rotation.
-
22N.2.HL.TZ0.8b.i:
Show that the kinetic energy of the satellite in orbit is about 2 × 1010 J.
-
22N.2.HL.TZ0.8b.i:
Show that the kinetic energy of the satellite in orbit is about 2 × 1010 J.
-
22N.2.HL.TZ0.b.i:
Show that the kinetic energy of the satellite in orbit is about 2 × 1010 J.
- SPM.1A.HL.TZ0.27: P is a point in a uniform electric field. What is the direction in which the electric potential...
- SPM.1A.HL.TZ0.27: P is a point in a uniform electric field. What is the direction in which the electric potential...
- SPM.1A.HL.TZ0.27: P is a point in a uniform electric field. What is the direction in which the electric potential...
- SPM.1A.HL.TZ0.27: P is a point in a uniform electric field. What is the direction in which the electric potential...
- SPM.2.HL.TZ0.5a: Outline why the magnetic flux in ring B increases.
- SPM.2.HL.TZ0.5a: Outline why the magnetic flux in ring B increases.
- SPM.2.HL.TZ0.a: Outline why the magnetic flux in ring B increases.
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.HL.TZ0.32: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.HL.TZ0.32: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.HL.TZ0.32: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.HL.TZ0.32: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.28:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.28:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.28:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.28:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.2.SL.TZ0.3a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.HL.TZ0.4a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.SL.TZ0.3a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.SL.TZ0.3a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.HL.TZ0.4a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.HL.TZ0.a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.SL.TZ0.a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.SL.TZ0.a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
-
SPM.1A.HL.TZ0.31:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.HL.TZ0.31:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.HL.TZ0.31:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
-
SPM.1A.HL.TZ0.31:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.HL.TZ0.24: A solid metallic sphere is positively charged and isolated from all other charges. The electric...
- SPM.1A.HL.TZ0.24: A solid metallic sphere is positively charged and isolated from all other charges. The electric...
- SPM.1A.HL.TZ0.24: A solid metallic sphere is positively charged and isolated from all other charges. The electric...
- SPM.1A.HL.TZ0.24: A solid metallic sphere is positively charged and isolated from all other charges. The electric...
- SPM.1A.HL.TZ0.25: A planet orbits the Sun in an elliptical orbit moving in the direction shown. At the position...
- SPM.1A.HL.TZ0.25: A planet orbits the Sun in an elliptical orbit moving in the direction shown. At the position...
- SPM.1A.HL.TZ0.25: A planet orbits the Sun in an elliptical orbit moving in the direction shown. At the position...
- SPM.1A.HL.TZ0.25: A planet orbits the Sun in an elliptical orbit moving in the direction shown. At the position...
- SPM.1A.HL.TZ0.29: A rectangular conducting coil rotates at a constant angular velocity in a uniform magnetic field....
- SPM.1A.HL.TZ0.29: A rectangular conducting coil rotates at a constant angular velocity in a uniform magnetic field....
- SPM.1A.HL.TZ0.29: A rectangular conducting coil rotates at a constant angular velocity in a uniform magnetic field....
- SPM.1A.HL.TZ0.29: A rectangular conducting coil rotates at a constant angular velocity in a uniform magnetic field....
- SPM.1A.HL.TZ0.30: A spherical planet has a radius R0. The graph shows the variation of the gravitational potential...
- SPM.1A.HL.TZ0.30: A spherical planet has a radius R0. The graph shows the variation of the gravitational potential...
- SPM.1A.HL.TZ0.30: A spherical planet has a radius R0. The graph shows the variation of the gravitational potential...
- SPM.1A.HL.TZ0.30: A spherical planet has a radius R0. The graph shows the variation of the gravitational potential...
-
EXE.2.SL.TZ0.12b:
The table gives data relating to the two moons of Mars.
Moon T / hour r / Mm Phobos 7.66 9.38 Deimos 30.4 - Determine r for Deimos.
-
EXE.2.SL.TZ0.12b:
The table gives data relating to the two moons of Mars.
Moon T / hour r / Mm Phobos 7.66 9.38 Deimos 30.4 - Determine r for Deimos.
-
EXE.2.SL.TZ0.b:
The table gives data relating to the two moons of Mars.
Moon T / hour r / Mm Phobos 7.66 9.38 Deimos 30.4 - Determine r for Deimos.
- SPM.2.HL.TZ0.9ai: Draw the electric field lines due to the charged plates.
- SPM.2.SL.TZ0.7ai: Draw the electric field lines due to the charged plates.
- SPM.2.SL.TZ0.7ai: Draw the electric field lines due to the charged plates.
- SPM.2.SL.TZ0.7ai: Draw the electric field lines due to the charged plates.
- SPM.2.SL.TZ0.i: Draw the electric field lines due to the charged plates.
- SPM.2.HL.TZ0.9ai: Draw the electric field lines due to the charged plates.
- SPM.2.HL.TZ0.i: Draw the electric field lines due to the charged plates.
- SPM.2.SL.TZ0.i: Draw the electric field lines due to the charged plates.
-
SPM.2.HL.TZ0.9ciii:
Show that the electric charge on the oil drop is given by
where is the density of oil and is the volume of the oil drop.
-
SPM.2.HL.TZ0.9ciii:
Show that the electric charge on the oil drop is given by
where is the density of oil and is the volume of the oil drop.
-
SPM.2.HL.TZ0.iii:
Show that the electric charge on the oil drop is given by
where is the density of oil and is the volume of the oil drop.
Sub sections and their related questions
D.1 Gravitational fields
-
19M.1A.HL.TZ1.34:
A satellite in a circular orbit around the Earth needs to reduce its orbital radius.
What is the work done by the satellite rocket engine and the change in kinetic energy resulting from this shift in orbital height?
- 22M.1A.HL.TZ2.24: Three statements about Newton’s law of gravitation are: I. It can be used to predict the...
-
22M.1A.SL.TZ2.29:
A simple pendulum has a time period on the Earth. The pendulum is taken to the Moon where the gravitational field strength is that of the Earth.
What is the time period of the pendulum on the Moon?
A.
B.
C.
D.
- 22M.1A.SL.TZ2.21: An astronaut is orbiting Earth in a spaceship. Why does the astronaut experience...
- 19M.2.SL.TZ1.6c.i: Outline why a force acts on the Moon.
- 19N.1A.SL.TZ0.17: A negatively charged particle in a uniform gravitational field is positioned mid-way between two...
- 19N.1A.SL.TZ0.23: A satellite travels around the Earth in a circular orbit. What is true about the forces acting in...
- 19M.2.SL.TZ1.5a.i: Outline the origin of the force that acts on Phobos.
-
19M.2.SL.TZ1.5b.i:
The orbital period T of a moon orbiting a planet of mass M is given by
where R is the average distance between the centre of the planet and the centre of the moon.
Show that
-
19M.2.SL.TZ1.5b.ii:
The following data for the Mars–Phobos system and the Earth–Moon system are available:
Mass of Earth = 5.97 × 1024 kg
The Earth–Moon distance is 41 times the Mars–Phobos distance.
The orbital period of the Moon is 86 times the orbital period of Phobos.
Calculate, in kg, the mass of Mars.
- 19M.2.HL.TZ1.5c: The graph shows the variation of the gravitational potential between the Earth and Moon with...
- 19M.1A.SL.TZ2.23: Which graph shows the relationship between gravitational force F between two point masses and...
-
19M.2.HL.TZ2.9ai:
Show that the total energy of the planet is given by the equation shown.
-
19M.2.HL.TZ2.9aii:
Suppose the star could contract to half its original radius without any loss of mass. Discuss the effect, if any, this has on the total energy of the planet.
-
21M.2.HL.TZ1.2c.i:
Show that the gravitational potential due to the planet and the star at the surface of the planet is about −5 × 109 J kg−1.
-
21M.2.HL.TZ1.2c.ii:
Estimate the escape speed of the spacecraft from the planet–star system.
-
21M.2.SL.TZ2.10a:
Calculate, for the surface of , the gravitational field strength gIo due to the mass of . State an appropriate unit for your answer.
-
21M.2.HL.TZ2.10b.i:
Show that the is about 80.
-
21M.2.HL.TZ2.10b.ii:
Outline, using (b)(i), why it is not correct to use the equation to calculate the speed required for the spacecraft to reach infinity from the surface of .
-
21M.2.HL.TZ2.10c:
An engineer needs to move a space probe of mass 3600 kg from Ganymede to Callisto. Calculate the energy required to move the probe from the orbital radius of Ganymede to the orbital radius of Callisto. Ignore the mass of the moons in your calculation.
-
19M.1A.HL.TZ2.10:
Satellite X is in orbit around the Earth. An identical satellite Y is in a higher orbit. What is correct for the total energy and the kinetic energy of the satellite Y compared with satellite X?
-
19N.1A.HL.TZ0.30:
The gravitational potential is at a distance above the surface of a spherical planet of radius and uniform density. What is the gravitational potential a distance above the surface of the planet?
A.
B.
C.
D.
-
21M.1A.HL.TZ2.32:
A satellite orbits planet with a speed at a distance from the centre of planet . Another satellite orbits planet at a speed of at a distance from the centre of planet . The mass of planet is and the mass of planet is . What is the ratio of ?
A. 0.25B. 0.5
C. 2.0
D. 4.0
- 20N.1A.HL.TZ0.31: P and S are two points on a gravitational equipotential surface around a planet. Q and R are two...
- 20N.1A.HL.TZ0.30: Two satellites W and X have the same mass. They have circular orbits around the same planet. W is...
-
20N.1A.SL.TZ0.23:
Planet X has a gravitational field strength of at its surface. Planet Y has the same density as X but three times the radius of X. What is the gravitational field strength at the surface of Y?
A.
B.
C.
D.
- 21M.1A.HL.TZ1.31: Which is a correct unit for gravitational potential? A. m2 s−2 B. J kg C. m s−2 D. N m−1 kg−1
-
21M.1A.SL.TZ1.23:
Which is the definition of gravitational field strength at a point?
A. The sum of the gravitational fields created by all masses around the point
B. The gravitational force per unit mass experienced by a small point mass at that point
C. , where is the mass of a planet and is the distance from the planet to the point
D. The resultant force of gravitational attraction on a mass at that point
-
21M.1A.SL.TZ2.30:
An object of mass released from rest near the surface of a planet has an initial acceleration . What is the gravitational field strength near the surface of the planet?
A.
B.
C.
D.
- 21M.1A.HL.TZ1.32: A planet has radius R. The escape speed from the surface of the planet is v. At what...
-
19M.1A.SL.TZ1.25:
Satellite X orbits a planet with orbital radius R. Satellite Y orbits the same planet with orbital radius 2R. Satellites X and Y have the same mass.
What is the ratio ?
A.
B.
C. 2
D. 4
-
19M.1A.HL.TZ2.11:
The escape speed from a planet of radius R is vesc. A satellite orbits the planet at a distance R from the surface of the planet. What is the orbital speed of the satellite?
A.
B.
C.
D.
-
21N.1A.SL.TZ0.23:
The gravitational field strength at the surface of a planet of radius R is . A satellite is moving in a circular orbit a distance R above the surface of the planet. What is the magnitude of the acceleration of the satellite?
A.B.
C.
D.
-
21N.2.SL.TZ0.6b.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.SL.TZ0.6b.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
-
21N.1A.HL.TZ0.32:
A satellite of mass orbits a planet of mass in a circular orbit of radius . What is the work that must be done on the satellite to increase its orbital radius to ?
A.B.
C.
D.
-
22M.1A.SL.TZ1.24:
P and Q are two moons of equal densities orbiting a planet. The orbital radius of P is twice the orbital radius of Q. The volume of P is half that of Q. The force exerted by the planet on P is F. What is the force exerted by the planet on Q?
A. F
B. 2F
C. 4F
D. 8F
-
22M.1A.HL.TZ1.33:
An object of mass is launched from the surface of the Earth. The Earth has a mass and radius . The acceleration due to gravity at the surface of the Earth is . What is the escape speed of the object from the surface of the Earth?
A.
B.
C.
D.
-
22M.1A.SL.TZ2.23:
A satellite is orbiting Earth in a circular path at constant speed. Three statements about the resultant force on the satellite are:
I. It is equal to the gravitational force of attraction on the satellite.
II. It is equal to the mass of the satellite multiplied by its acceleration.
III. It is equal to the centripetal force on the satellite.Which combination of statements is correct?
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
22N.1A.SL.TZ0.22:
The centre of the Earth and the Moon are a distance apart. There is a point X between them where their gravitational fields cancel out. The distance from the centre of the Earth to X is . The mass of the Earth is and the mass of the Moon is .
What is correct at X?
A.B.
C.
D.
- 22N.1A.HL.TZ0.32: Two satellites are in circular orbits around the Earth. Both satellites have the same mass...
-
22N.2.HL.TZ0.8b.i:
Show that the kinetic energy of the satellite in orbit is about 2 × 1010 J.
-
22N.2.HL.TZ0.8b.ii:
Determine the minimum energy required to launch the satellite. Ignore the original kinetic energy of the satellite due to Earth’s rotation.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.2.SL.TZ0.3a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.1A.HL.TZ0.25: A planet orbits the Sun in an elliptical orbit moving in the direction shown. At the position...
-
SPM.1A.HL.TZ0.28:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.1A.HL.TZ0.30: A spherical planet has a radius R0. The graph shows the variation of the gravitational potential...
- SPM.2.HL.TZ0.4a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
-
EXE.1A.HL.TZ0.25:
A space probe moves in a circular orbit around Earth. The kinetic energy of the probe is .
The probe will reach the escape speed when its kinetic energy is increased at least to:
A.B.
C.
D.
-
EXE.1A.HL.TZ0.26:
What is the escape speed from the surface of a planet of radius that has an acceleration of gravity at its surface?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.13:
Planets X and Y move in circular orbits around the same star.
The orbital period of planet Y is twice the orbital period of planet X. The orbital radius of planet X is .
What is the orbital radius of planet Y?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.14:
Kepler’s Third law relates the orbital period of a planet about its sun to its orbital radius . The mass of the Sun is .
What is a correct algebraic form of the law?
A.B.
C.
D.
-
EXE.2.HL.TZ0.15ai:
orbital speed;
- EXE.2.HL.TZ0.15ci: in its initial circular orbit;
- EXE.2.HL.TZ0.15cii: in its final orbit.
-
EXE.2.HL.TZ0.16a:
The radius of the dwarf planet Pluto is 1.19 x 106 m. The acceleration due to gravity at its surface is 0.617 m s−2.
Determine the escape speed for an object at the surface of Pluto.
-
EXE.2.HL.TZ0.16b:
Pluto rotates about an axis through its centre. Its rotation is in the opposite sense to that of the Earth, i.e. from east to west.
Explain the advantage of an object launching from the equator of Pluto and travelling to the west.
-
23M.2.HL.TZ1.6c:
The charges Q are replaced by neutral masses M and the charge q by a neutral mass m. The mass m is displaced away from C by a small distance and released. Discuss whether the motion of m will be the same as that of q.
-
23M.2.SL.TZ2.6a:
Determine .
-
23M.2.HL.TZ2.6bi:
State and explain the magnitude of the resultant gravitational field strength at O.
-
23M.2.HL.TZ2.6bii:
Outline why the graph between P and O is negative.
-
23M.2.HL.TZ2.6biii:
Show that the gravitational potential VP at the surface of P due to the mass of P is given by VP = −gP RP where RP is the radius of the planet.
-
23M.2.HL.TZ2.6biv:
The gravitational potential due to the mass of M at the surface of P can be assumed to be negligible.
Estimate, using the graph, the gravitational potential at the surface of M due to the mass of M.
-
23M.2.HL.TZ2.6bv:
Draw on the axes the variation of gravitational potential between O and M.
-
23M.1A.HL.TZ1.30:
Two isolated point masses, P of mass m and Q of mass 2m, are separated by a distance 3d. X is a point a distance d from P and 2d from Q.
What is the net gravitational field strength at X and the net gravitational potential at X?
Net gravitational field strength at X Net gravitational
potential at XA. 0 B. C. 0 D. -
23M.1A.HL.TZ1.32:
The escape speed from the surface of earth is vesc. The radius of earth is R. A satellite of mass m is in orbit at a height above the surface of the Earth. What is the energy required to move the satellite to infinity?
A.B.
C.
D.
-
23M.1A.SL.TZ1.23:
The radius of the Earth is R. A satellite is launched to a height h = above the Earth’s surface.
What is ?
A.B.
C.
D.
-
23M.1A.HL.TZ2.31:
The mass of Mars is about ten times that of the Moon. The radius of Mars is about twice that of the Moon.
What is the ?
A.B. 2
C. 5
D. 25
- EXE.2.SL.TZ0.11a: A comet orbits the Sun in an elliptical orbit. A and B are two positions of the comet. Explain,...
-
EXE.2.SL.TZ0.11b:
An asteroid (minor planet) orbits the Sun in a circular orbit of radius 4.5 × 108 km. The radius of Earth’s orbit is 1.5 × 108 km. Calculate, in years, the orbital period of the asteroid.
-
EXE.2.SL.TZ0.12a:
Show that .
-
EXE.2.SL.TZ0.12b:
The table gives data relating to the two moons of Mars.
Moon T / hour r / Mm Phobos 7.66 9.38 Deimos 30.4 - Determine r for Deimos.
-
EXE.2.SL.TZ0.12c:
Determine the mass of Mars.
-
EXE.2.SL.TZ0.13a:
Show that for the planets in a solar system where is the orbital period of a planet and is the radius of circular orbit of planet about its sun.
-
EXE.2.SL.TZ0.13bi:
Outline what is meant by one astronomical unit (1 AU)
-
EXE.2.SL.TZ0.13bii:
Pluto is a dwarf planet of the Sun that orbits at a distance of 5.9 × 109 km from the Sun. Determine, in years, the orbital period of Pluto.
-
EXE.2.HL.TZ0.15aii:
escape speed from its orbit.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.1A.HL.TZ0.25: A planet orbits the Sun in an elliptical orbit moving in the direction shown. At the position...
-
SPM.1A.HL.TZ0.28:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.1A.HL.TZ0.30: A spherical planet has a radius R0. The graph shows the variation of the gravitational potential...
- SPM.2.SL.TZ0.3a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
-
19M.1A.HL.TZ1.34:
A satellite in a circular orbit around the Earth needs to reduce its orbital radius.
What is the work done by the satellite rocket engine and the change in kinetic energy resulting from this shift in orbital height?
- 22M.1A.HL.TZ2.24: Three statements about Newton’s law of gravitation are: I. It can be used to predict the...
-
22M.1A.SL.TZ2.29:
A simple pendulum has a time period on the Earth. The pendulum is taken to the Moon where the gravitational field strength is that of the Earth.
What is the time period of the pendulum on the Moon?
A.
B.
C.
D.
- 22M.1A.SL.TZ2.21: An astronaut is orbiting Earth in a spaceship. Why does the astronaut experience...
- 19M.2.SL.TZ1.6c.i: Outline why a force acts on the Moon.
- 19M.2.SL.TZ1.c.i: Outline why a force acts on the Moon.
- 19N.1A.SL.TZ0.17: A negatively charged particle in a uniform gravitational field is positioned mid-way between two...
- 19N.1A.SL.TZ0.23: A satellite travels around the Earth in a circular orbit. What is true about the forces acting in...
- 19M.2.SL.TZ1.5a.i: Outline the origin of the force that acts on Phobos.
-
19M.2.SL.TZ1.5b.i:
The orbital period T of a moon orbiting a planet of mass M is given by
where R is the average distance between the centre of the planet and the centre of the moon.
Show that
-
19M.2.SL.TZ1.5b.ii:
The following data for the Mars–Phobos system and the Earth–Moon system are available:
Mass of Earth = 5.97 × 1024 kg
The Earth–Moon distance is 41 times the Mars–Phobos distance.
The orbital period of the Moon is 86 times the orbital period of Phobos.
Calculate, in kg, the mass of Mars.
- 19M.2.HL.TZ1.5c: The graph shows the variation of the gravitational potential between the Earth and Moon with...
- 19M.2.SL.TZ1.a.i: Outline the origin of the force that acts on Phobos.
-
19M.2.SL.TZ1.b.i:
The orbital period T of a moon orbiting a planet of mass M is given by
where R is the average distance between the centre of the planet and the centre of the moon.
Show that
-
19M.2.SL.TZ1.b.ii:
The following data for the Mars–Phobos system and the Earth–Moon system are available:
Mass of Earth = 5.97 × 1024 kg
The Earth–Moon distance is 41 times the Mars–Phobos distance.
The orbital period of the Moon is 86 times the orbital period of Phobos.
Calculate, in kg, the mass of Mars.
- 19M.2.HL.TZ1.c: The graph shows the variation of the gravitational potential between the Earth and Moon with...
- 19M.1A.SL.TZ2.23: Which graph shows the relationship between gravitational force F between two point masses and...
-
19M.2.HL.TZ2.9ai:
Show that the total energy of the planet is given by the equation shown.
-
19M.2.HL.TZ2.9aii:
Suppose the star could contract to half its original radius without any loss of mass. Discuss the effect, if any, this has on the total energy of the planet.
-
19M.2.HL.TZ2.ai:
Show that the total energy of the planet is given by the equation shown.
-
19M.2.HL.TZ2.aii:
Suppose the star could contract to half its original radius without any loss of mass. Discuss the effect, if any, this has on the total energy of the planet.
-
21M.2.HL.TZ1.2c.i:
Show that the gravitational potential due to the planet and the star at the surface of the planet is about −5 × 109 J kg−1.
-
21M.2.HL.TZ1.2c.ii:
Estimate the escape speed of the spacecraft from the planet–star system.
-
21M.2.HL.TZ1.c.i:
Show that the gravitational potential due to the planet and the star at the surface of the planet is about −5 × 109 J kg−1.
-
21M.2.HL.TZ1.c.ii:
Estimate the escape speed of the spacecraft from the planet–star system.
-
21M.2.SL.TZ2.10a:
Calculate, for the surface of , the gravitational field strength gIo due to the mass of . State an appropriate unit for your answer.
-
21M.2.HL.TZ2.10b.i:
Show that the is about 80.
-
21M.2.HL.TZ2.10b.ii:
Outline, using (b)(i), why it is not correct to use the equation to calculate the speed required for the spacecraft to reach infinity from the surface of .
-
21M.2.HL.TZ2.10c:
An engineer needs to move a space probe of mass 3600 kg from Ganymede to Callisto. Calculate the energy required to move the probe from the orbital radius of Ganymede to the orbital radius of Callisto. Ignore the mass of the moons in your calculation.
-
21M.2.SL.TZ2.a:
Calculate, for the surface of , the gravitational field strength gIo due to the mass of . State an appropriate unit for your answer.
-
21M.2.HL.TZ2.b.i:
Show that the is about 80.
-
21M.2.HL.TZ2.b.ii:
Outline, using (b)(i), why it is not correct to use the equation to calculate the speed required for the spacecraft to reach infinity from the surface of .
-
21M.2.HL.TZ2.c:
An engineer needs to move a space probe of mass 3600 kg from Ganymede to Callisto. Calculate the energy required to move the probe from the orbital radius of Ganymede to the orbital radius of Callisto. Ignore the mass of the moons in your calculation.
-
19M.1A.HL.TZ2.10:
Satellite X is in orbit around the Earth. An identical satellite Y is in a higher orbit. What is correct for the total energy and the kinetic energy of the satellite Y compared with satellite X?
-
19N.1A.HL.TZ0.30:
The gravitational potential is at a distance above the surface of a spherical planet of radius and uniform density. What is the gravitational potential a distance above the surface of the planet?
A.
B.
C.
D.
-
21M.1A.HL.TZ2.32:
A satellite orbits planet with a speed at a distance from the centre of planet . Another satellite orbits planet at a speed of at a distance from the centre of planet . The mass of planet is and the mass of planet is . What is the ratio of ?
A. 0.25B. 0.5
C. 2.0
D. 4.0
- 20N.1A.HL.TZ0.31: P and S are two points on a gravitational equipotential surface around a planet. Q and R are two...
- 20N.1A.HL.TZ0.30: Two satellites W and X have the same mass. They have circular orbits around the same planet. W is...
-
20N.1A.SL.TZ0.23:
Planet X has a gravitational field strength of at its surface. Planet Y has the same density as X but three times the radius of X. What is the gravitational field strength at the surface of Y?
A.
B.
C.
D.
- 21M.1A.HL.TZ1.31: Which is a correct unit for gravitational potential? A. m2 s−2 B. J kg C. m s−2 D. N m−1 kg−1
-
21M.1A.SL.TZ1.23:
Which is the definition of gravitational field strength at a point?
A. The sum of the gravitational fields created by all masses around the point
B. The gravitational force per unit mass experienced by a small point mass at that point
C. , where is the mass of a planet and is the distance from the planet to the point
D. The resultant force of gravitational attraction on a mass at that point
-
21M.1A.SL.TZ2.30:
An object of mass released from rest near the surface of a planet has an initial acceleration . What is the gravitational field strength near the surface of the planet?
A.
B.
C.
D.
- 21M.1A.HL.TZ1.32: A planet has radius R. The escape speed from the surface of the planet is v. At what...
-
19M.1A.SL.TZ1.25:
Satellite X orbits a planet with orbital radius R. Satellite Y orbits the same planet with orbital radius 2R. Satellites X and Y have the same mass.
What is the ratio ?
A.
B.
C. 2
D. 4
-
19M.1A.HL.TZ2.11:
The escape speed from a planet of radius R is vesc. A satellite orbits the planet at a distance R from the surface of the planet. What is the orbital speed of the satellite?
A.
B.
C.
D.
-
21N.1A.SL.TZ0.23:
The gravitational field strength at the surface of a planet of radius R is . A satellite is moving in a circular orbit a distance R above the surface of the planet. What is the magnitude of the acceleration of the satellite?
A.B.
C.
D.
-
21N.2.SL.TZ0.6b.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.SL.TZ0.6b.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
-
21N.2.SL.TZ0.b.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.SL.TZ0.b.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
-
21N.1A.HL.TZ0.32:
A satellite of mass orbits a planet of mass in a circular orbit of radius . What is the work that must be done on the satellite to increase its orbital radius to ?
A.B.
C.
D.
-
22M.1A.SL.TZ1.24:
P and Q are two moons of equal densities orbiting a planet. The orbital radius of P is twice the orbital radius of Q. The volume of P is half that of Q. The force exerted by the planet on P is F. What is the force exerted by the planet on Q?
A. F
B. 2F
C. 4F
D. 8F
-
22M.1A.HL.TZ1.33:
An object of mass is launched from the surface of the Earth. The Earth has a mass and radius . The acceleration due to gravity at the surface of the Earth is . What is the escape speed of the object from the surface of the Earth?
A.
B.
C.
D.
-
22M.1A.SL.TZ2.23:
A satellite is orbiting Earth in a circular path at constant speed. Three statements about the resultant force on the satellite are:
I. It is equal to the gravitational force of attraction on the satellite.
II. It is equal to the mass of the satellite multiplied by its acceleration.
III. It is equal to the centripetal force on the satellite.Which combination of statements is correct?
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
22N.1A.SL.TZ0.22:
The centre of the Earth and the Moon are a distance apart. There is a point X between them where their gravitational fields cancel out. The distance from the centre of the Earth to X is . The mass of the Earth is and the mass of the Moon is .
What is correct at X?
A.B.
C.
D.
- 22N.1A.HL.TZ0.32: Two satellites are in circular orbits around the Earth. Both satellites have the same mass...
-
22N.2.HL.TZ0.8b.i:
Show that the kinetic energy of the satellite in orbit is about 2 × 1010 J.
-
22N.2.HL.TZ0.8b.ii:
Determine the minimum energy required to launch the satellite. Ignore the original kinetic energy of the satellite due to Earth’s rotation.
-
22N.2.HL.TZ0.b.i:
Show that the kinetic energy of the satellite in orbit is about 2 × 1010 J.
-
22N.2.HL.TZ0.b.ii:
Determine the minimum energy required to launch the satellite. Ignore the original kinetic energy of the satellite due to Earth’s rotation.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.2.SL.TZ0.3a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.SL.TZ0.a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.1A.HL.TZ0.25: A planet orbits the Sun in an elliptical orbit moving in the direction shown. At the position...
-
SPM.1A.HL.TZ0.28:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.1A.HL.TZ0.30: A spherical planet has a radius R0. The graph shows the variation of the gravitational potential...
- SPM.2.HL.TZ0.4a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
- SPM.2.HL.TZ0.a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
-
EXE.1A.HL.TZ0.25:
A space probe moves in a circular orbit around Earth. The kinetic energy of the probe is .
The probe will reach the escape speed when its kinetic energy is increased at least to:
A.B.
C.
D.
-
EXE.1A.HL.TZ0.26:
What is the escape speed from the surface of a planet of radius that has an acceleration of gravity at its surface?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.13:
Planets X and Y move in circular orbits around the same star.
The orbital period of planet Y is twice the orbital period of planet X. The orbital radius of planet X is .
What is the orbital radius of planet Y?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.14:
Kepler’s Third law relates the orbital period of a planet about its sun to its orbital radius . The mass of the Sun is .
What is a correct algebraic form of the law?
A.B.
C.
D.
-
EXE.2.HL.TZ0.i:
orbital speed;
- EXE.2.HL.TZ0.i: in its initial circular orbit;
- EXE.2.HL.TZ0.ii: in its final orbit.
-
EXE.2.HL.TZ0.a:
The radius of the dwarf planet Pluto is 1.19 x 106 m. The acceleration due to gravity at its surface is 0.617 m s−2.
Determine the escape speed for an object at the surface of Pluto.
-
EXE.2.HL.TZ0.b:
Pluto rotates about an axis through its centre. Its rotation is in the opposite sense to that of the Earth, i.e. from east to west.
Explain the advantage of an object launching from the equator of Pluto and travelling to the west.
-
23M.2.HL.TZ1.6c:
The charges Q are replaced by neutral masses M and the charge q by a neutral mass m. The mass m is displaced away from C by a small distance and released. Discuss whether the motion of m will be the same as that of q.
-
23M.2.HL.TZ1.c:
The charges Q are replaced by neutral masses M and the charge q by a neutral mass m. The mass m is displaced away from C by a small distance and released. Discuss whether the motion of m will be the same as that of q.
-
23M.2.SL.TZ2.6a:
Determine .
-
23M.2.HL.TZ2.6bi:
State and explain the magnitude of the resultant gravitational field strength at O.
-
23M.2.HL.TZ2.6bii:
Outline why the graph between P and O is negative.
-
23M.2.HL.TZ2.6biii:
Show that the gravitational potential VP at the surface of P due to the mass of P is given by VP = −gP RP where RP is the radius of the planet.
-
23M.2.HL.TZ2.6biv:
The gravitational potential due to the mass of M at the surface of P can be assumed to be negligible.
Estimate, using the graph, the gravitational potential at the surface of M due to the mass of M.
-
23M.2.HL.TZ2.6bv:
Draw on the axes the variation of gravitational potential between O and M.
-
23M.2.SL.TZ2.a:
Determine .
-
23M.2.HL.TZ2.i:
State and explain the magnitude of the resultant gravitational field strength at O.
-
23M.2.HL.TZ2.ii:
Outline why the graph between P and O is negative.
-
23M.2.HL.TZ2.iii:
Show that the gravitational potential VP at the surface of P due to the mass of P is given by VP = −gP RP where RP is the radius of the planet.
-
23M.2.HL.TZ2.iv:
The gravitational potential due to the mass of M at the surface of P can be assumed to be negligible.
Estimate, using the graph, the gravitational potential at the surface of M due to the mass of M.
-
23M.2.HL.TZ2.v:
Draw on the axes the variation of gravitational potential between O and M.
-
23M.1A.HL.TZ1.30:
Two isolated point masses, P of mass m and Q of mass 2m, are separated by a distance 3d. X is a point a distance d from P and 2d from Q.
What is the net gravitational field strength at X and the net gravitational potential at X?
Net gravitational field strength at X Net gravitational
potential at XA. 0 B. C. 0 D. -
23M.1A.HL.TZ1.32:
The escape speed from the surface of earth is vesc. The radius of earth is R. A satellite of mass m is in orbit at a height above the surface of the Earth. What is the energy required to move the satellite to infinity?
A.B.
C.
D.
-
23M.1A.SL.TZ1.23:
The radius of the Earth is R. A satellite is launched to a height h = above the Earth’s surface.
What is ?
A.B.
C.
D.
-
23M.1A.HL.TZ2.31:
The mass of Mars is about ten times that of the Moon. The radius of Mars is about twice that of the Moon.
What is the ?
A.B. 2
C. 5
D. 25
- EXE.2.SL.TZ0.11a: A comet orbits the Sun in an elliptical orbit. A and B are two positions of the comet. Explain,...
-
EXE.2.SL.TZ0.11b:
An asteroid (minor planet) orbits the Sun in a circular orbit of radius 4.5 × 108 km. The radius of Earth’s orbit is 1.5 × 108 km. Calculate, in years, the orbital period of the asteroid.
- EXE.2.SL.TZ0.a: A comet orbits the Sun in an elliptical orbit. A and B are two positions of the comet. Explain,...
-
EXE.2.SL.TZ0.b:
An asteroid (minor planet) orbits the Sun in a circular orbit of radius 4.5 × 108 km. The radius of Earth’s orbit is 1.5 × 108 km. Calculate, in years, the orbital period of the asteroid.
-
EXE.2.SL.TZ0.12a:
Show that .
-
EXE.2.SL.TZ0.12b:
The table gives data relating to the two moons of Mars.
Moon T / hour r / Mm Phobos 7.66 9.38 Deimos 30.4 - Determine r for Deimos.
-
EXE.2.SL.TZ0.12c:
Determine the mass of Mars.
-
EXE.2.SL.TZ0.a:
Show that .
-
EXE.2.SL.TZ0.b:
The table gives data relating to the two moons of Mars.
Moon T / hour r / Mm Phobos 7.66 9.38 Deimos 30.4 - Determine r for Deimos.
-
EXE.2.SL.TZ0.c:
Determine the mass of Mars.
-
EXE.2.SL.TZ0.13a:
Show that for the planets in a solar system where is the orbital period of a planet and is the radius of circular orbit of planet about its sun.
-
EXE.2.SL.TZ0.13bi:
Outline what is meant by one astronomical unit (1 AU)
-
EXE.2.SL.TZ0.13bii:
Pluto is a dwarf planet of the Sun that orbits at a distance of 5.9 × 109 km from the Sun. Determine, in years, the orbital period of Pluto.
-
EXE.2.SL.TZ0.a:
Show that for the planets in a solar system where is the orbital period of a planet and is the radius of circular orbit of planet about its sun.
-
EXE.2.SL.TZ0.i:
Outline what is meant by one astronomical unit (1 AU)
-
EXE.2.SL.TZ0.ii:
Pluto is a dwarf planet of the Sun that orbits at a distance of 5.9 × 109 km from the Sun. Determine, in years, the orbital period of Pluto.
-
EXE.2.HL.TZ0.ii:
escape speed from its orbit.
-
EXE.2.HL.TZ0.16a:
The radius of the dwarf planet Pluto is 1.19 x 106 m. The acceleration due to gravity at its surface is 0.617 m s−2.
Determine the escape speed for an object at the surface of Pluto.
-
EXE.2.HL.TZ0.16b:
Pluto rotates about an axis through its centre. Its rotation is in the opposite sense to that of the Earth, i.e. from east to west.
Explain the advantage of an object launching from the equator of Pluto and travelling to the west.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.18:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.1A.HL.TZ0.25: A planet orbits the Sun in an elliptical orbit moving in the direction shown. At the position...
-
SPM.1A.HL.TZ0.28:
Planets X and Y orbit the same star.
The average distance between planet X and the star is five times greater than the average distance between planet Y and the star.
What is ?
A.B.
C.
D.
- SPM.1A.HL.TZ0.30: A spherical planet has a radius R0. The graph shows the variation of the gravitational potential...
- SPM.2.SL.TZ0.a: Draw an arrow on the diagram to represent the direction of the acceleration of the satellite.
D.2 Electric and magnetic fields
- 19M.1A.SL.TZ1.20: Two charges, +Q and −Q, are placed as shown. What is the magnitude of the electric field...
- 22M.1A.SL.TZ2.19: A charge Q is at a point between two electric charges Q1 and Q2. The net electric force on Q is...
- 22M.1A.HL.TZ2.32: Two positive and two negative charges are located at the corners of a square as shown. Point X is...
- 22M.1A.HL.TZ2.33: The graph shows the variation with distance r of the electric potential V from a charge...
- 19M.1A.HL.TZ1.32: A negative charge Q is to be moved within an electric field E, to equidistant points from its...
-
22M.1A.SL.TZ1.19:
P and Q are two opposite point charges. The force F acting on P due to Q and the electric field strength E at P are shown.
Which diagram shows the force on Q due to P and the electric field strength at Q?
- 22M.1A.SL.TZ1.20: Three point charges of equal magnitude are placed at the vertices of an equilateral triangle. The...
-
22M.1A.SL.TZ1.32:
A charged sphere in a gravitational field is initially stationary between two parallel metal plates. There is a potential difference V between the plates.
Three changes can be made:
I. Increase the separation of the metal plates
II. Increase V
III. Apply a magnetic field into the plane of the paperWhat changes made separately will cause the charged sphere to accelerate?
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
21N.2.SL.TZ0.4b.i:
Determine the force on Q at the instant it is released.
- 21N.2.SL.TZ0.4c.i: On the diagram draw an arrow to show the direction of the magnetic field at Q due to wire X alone.
-
21N.2.SL.TZ0.3a.i:
Show that the magnitude of the resultant electric field at P is 3 MN C−1
- 21N.2.SL.TZ0.3a.ii: State the direction of the resultant electric field at P.
-
22M.1A.SL.TZ2.16:
Four particles, two of charge +Q and two of charge −Q, are positioned on the -axis as shown. A particle P with a positive charge is placed on the -axis. What is the direction of the net electrostatic force on this particle?
- 19N.1A.SL.TZ0.17: A negatively charged particle in a uniform gravitational field is positioned mid-way between two...
- 21N.1A.HL.TZ0.30: The diagram shows equipotential lines for an electric field. Which arrow represents...
- 21N.1A.HL.TZ0.31: Two charged parallel plates have electric potentials of 10 V and 20 V. A particle with charge...
-
21N.2.HL.TZ0.7a:
Show that the charge on the surface of the sphere is +18 μC.
-
21N.2.HL.TZ0.7b.ii:
Predict the charge on each sphere.
-
19M.1A.HL.TZ2.18:
A particle with a charge ne is accelerated through a potential difference V.
What is the magnitude of the work done on the particle?
A.
B.
C.
D.
- 19M.1A.HL.TZ2.30: An electron is fixed in position in a uniform electric field. What is the position for which the...
-
19M.2.SL.TZ2.9b:
The diagram shows some of the electric field lines for two fixed, charged particles X and Y.
The magnitude of the charge on X is and that on Y is . The distance between X and Y is 0.600 m. The distance between P and Y is 0.820 m.
At P the electric field is zero. Determine, to one significant figure, the ratio .
-
21N.1A.SL.TZ0.18:
A charge +Q and a charge −2Q are a distance 3x apart. Point P is on the line joining the charges, at a distance x from +Q.
The magnitude of the electric field produced at P by the charge +Q alone is .
What is the total electric field at P?
A. to the rightB. to the left
C. to the right
D. to the left
-
19N.2.SL.TZ0.5a:
Show that the electric field strength due to the point charge at the position of the electron is 3.4 × 108 N C–1.
-
19N.2.SL.TZ0.5b(i):
Calculate the magnitude of the initial acceleration of the electron.
- 19N.2.SL.TZ0.5b(ii): Describe the subsequent motion of the electron.
-
19N.1A.SL.TZ0.31:
The force acting between two point charges is when the separation of the charges is . What is the force between the charges when the separation is increased to ?
A.
B.
C.
D.
-
20N.1A.HL.TZ0.32:
The graph shows the variation of electric field strength with distance from a point charge.
The shaded area X is the area under the graph between two separations and from the charge.
What is X?
A. The electric field average between and
B. The electric potential difference between and
C. The work done in moving a charge from to
D. The work done in moving a charge from to
-
20N.2.HL.TZ0.8a:
Explain why the electric potential decreases from A to B.
-
20N.2.HL.TZ0.8b:
Draw, on the axes, the variation of electric potential with distance from the centre of the sphere.
-
20N.2.HL.TZ0.8c(i):
Calculate the electric potential difference between points A and B.
-
20N.2.HL.TZ0.8c(ii):
Determine the charge of the sphere.
- 20N.2.HL.TZ0.8d: The concept of potential is also used in the context of gravitational fields. Suggest why...
- 21M.1A.SL.TZ1.18: Two charges Q1 and Q2, each equal to 2 nC, are separated by a distance 3 m in a vacuum. What is...
- 21M.1A.HL.TZ1.30: A particle with charge −2.5 × 10−6 C moves from point X to point Y due to a uniform electrostatic...
- 21M.1A.SL.TZ2.22: Magnetic field lines are an example of A. a discovery that helps us understand magnetism. B. a...
-
21M.1A.HL.TZ2.31:
The points X and Y are in a uniform electric field of strength . The distance OX is and the distance OY is .
What is the magnitude of the change in electric potential between X and Y?
A.
B.
C.
D.
-
22N.1A.HL.TZ0.31:
An electric field is established between two electrodes separated by distance d, held at a potential difference of V. A charged particle in this field experiences a force F.
What is the charge on the particle?
A.B.
C.
D.
-
22N.2.HL.TZ0.8a:
The diagram shows field lines for an electrostatic field. X and Y are two points on the same field line.
Outline which of the two points has the larger electric potential.
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.2.SL.TZ0.7ai: Draw the electric field lines due to the charged plates.
- SPM.1A.HL.TZ0.24: A solid metallic sphere is positively charged and isolated from all other charges. The electric...
- SPM.1A.HL.TZ0.27: P is a point in a uniform electric field. What is the direction in which the electric potential...
-
SPM.1A.HL.TZ0.31:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.HL.TZ0.32: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.2.HL.TZ0.9ai: Draw the electric field lines due to the charged plates.
-
SPM.2.HL.TZ0.9ciii:
Show that the electric charge on the oil drop is given by
where is the density of oil and is the volume of the oil drop.
- 23M.2.HL.TZ1.6ai: Sketch, on the axes, how the electric potential V due to the two charges varies with the distance...
-
23M.2.HL.TZ1.6aii:
Calculate the work done to bring a small charge q from infinity to point C.
Data given:
Q = 2.0 × 10−3 C,
q = 4.0 × 10−9 C
D = 1.2 m
- 23M.1A.SL.TZ1.15: Two positive charges of magnitude q and 2q are fixed as shown. At which position is the electric...
-
23M.1A.SL.TZ1.19:
P and R are parallel wires carrying the same current into the plane of the paper. P and R are equidistant from a point Q. The line PQ is perpendicular to the line RQ.
The magnetic field due to P at Q is . What is the magnitude of the resultant magnetic field at Q due to both wires?
A.B.
C.
D.
-
23M.1A.HL.TZ1.31:
A negatively charged particle is stationary halfway between two horizontal charged plates. The plates are separated by a distance d with potential difference V between them.
What is the magnitude of the electric field and direction of the electric field at the position of the particle?
Magnitude of
electric fieldDirection of
electric fieldA. up B. up C. down D. down - 23M.1A.SL.TZ1.18: Two positive charges of magnitude q and 2q are fixed as shown. At which position is the electric...
- 23M.1A.SL.TZ2.15: Three point charges, +Q, +Q and −Q, are fixed at the three corners of a square. What is the...
- 23M.1A.HL.TZ2.30: Two spheres have the same positive charge. A point M is midway between the two spheres. Along...
- 23M.1A.SL.TZ2.19: Three point charges, +Q, +Q and −Q, are fixed at the three corners of a square. What is the...
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.HL.TZ0.24: A solid metallic sphere is positively charged and isolated from all other charges. The electric...
- SPM.1A.HL.TZ0.27: P is a point in a uniform electric field. What is the direction in which the electric potential...
-
SPM.1A.HL.TZ0.31:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.HL.TZ0.32: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.2.SL.TZ0.7ai: Draw the electric field lines due to the charged plates.
- 19M.1A.SL.TZ1.20: Two charges, +Q and −Q, are placed as shown. What is the magnitude of the electric field...
- 22M.1A.SL.TZ2.19: A charge Q is at a point between two electric charges Q1 and Q2. The net electric force on Q is...
- 22M.1A.HL.TZ2.32: Two positive and two negative charges are located at the corners of a square as shown. Point X is...
- 22M.1A.HL.TZ2.33: The graph shows the variation with distance r of the electric potential V from a charge...
- 19M.1A.HL.TZ1.32: A negative charge Q is to be moved within an electric field E, to equidistant points from its...
-
22M.1A.SL.TZ1.19:
P and Q are two opposite point charges. The force F acting on P due to Q and the electric field strength E at P are shown.
Which diagram shows the force on Q due to P and the electric field strength at Q?
- 22M.1A.SL.TZ1.20: Three point charges of equal magnitude are placed at the vertices of an equilateral triangle. The...
-
22M.1A.SL.TZ1.32:
A charged sphere in a gravitational field is initially stationary between two parallel metal plates. There is a potential difference V between the plates.
Three changes can be made:
I. Increase the separation of the metal plates
II. Increase V
III. Apply a magnetic field into the plane of the paperWhat changes made separately will cause the charged sphere to accelerate?
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
21N.2.SL.TZ0.4b.i:
Determine the force on Q at the instant it is released.
- 21N.2.SL.TZ0.4c.i: On the diagram draw an arrow to show the direction of the magnetic field at Q due to wire X alone.
-
21N.2.SL.TZ0.b.i:
Determine the force on Q at the instant it is released.
- 21N.2.SL.TZ0.c.i: On the diagram draw an arrow to show the direction of the magnetic field at Q due to wire X alone.
-
21N.2.SL.TZ0.3a.i:
Show that the magnitude of the resultant electric field at P is 3 MN C−1
- 21N.2.SL.TZ0.3a.ii: State the direction of the resultant electric field at P.
-
21N.2.SL.TZ0.a.i:
Show that the magnitude of the resultant electric field at P is 3 MN C−1
- 21N.2.SL.TZ0.a.ii: State the direction of the resultant electric field at P.
-
22M.1A.SL.TZ2.16:
Four particles, two of charge +Q and two of charge −Q, are positioned on the -axis as shown. A particle P with a positive charge is placed on the -axis. What is the direction of the net electrostatic force on this particle?
- 19N.1A.SL.TZ0.17: A negatively charged particle in a uniform gravitational field is positioned mid-way between two...
- 21N.1A.HL.TZ0.30: The diagram shows equipotential lines for an electric field. Which arrow represents...
- 21N.1A.HL.TZ0.31: Two charged parallel plates have electric potentials of 10 V and 20 V. A particle with charge...
-
21N.2.HL.TZ0.7a:
Show that the charge on the surface of the sphere is +18 μC.
-
21N.2.HL.TZ0.7b.ii:
Predict the charge on each sphere.
-
21N.2.HL.TZ0.a:
Show that the charge on the surface of the sphere is +18 μC.
-
21N.2.HL.TZ0.b.ii:
Predict the charge on each sphere.
-
19M.1A.HL.TZ2.18:
A particle with a charge ne is accelerated through a potential difference V.
What is the magnitude of the work done on the particle?
A.
B.
C.
D.
- 19M.1A.HL.TZ2.30: An electron is fixed in position in a uniform electric field. What is the position for which the...
-
19M.2.SL.TZ2.9b:
The diagram shows some of the electric field lines for two fixed, charged particles X and Y.
The magnitude of the charge on X is and that on Y is . The distance between X and Y is 0.600 m. The distance between P and Y is 0.820 m.
At P the electric field is zero. Determine, to one significant figure, the ratio .
-
19M.2.SL.TZ2.b:
The diagram shows some of the electric field lines for two fixed, charged particles X and Y.
The magnitude of the charge on X is and that on Y is . The distance between X and Y is 0.600 m. The distance between P and Y is 0.820 m.
At P the electric field is zero. Determine, to one significant figure, the ratio .
-
21N.1A.SL.TZ0.18:
A charge +Q and a charge −2Q are a distance 3x apart. Point P is on the line joining the charges, at a distance x from +Q.
The magnitude of the electric field produced at P by the charge +Q alone is .
What is the total electric field at P?
A. to the rightB. to the left
C. to the right
D. to the left
-
19N.2.SL.TZ0.5a:
Show that the electric field strength due to the point charge at the position of the electron is 3.4 × 108 N C–1.
-
19N.2.SL.TZ0.5b(i):
Calculate the magnitude of the initial acceleration of the electron.
- 19N.2.SL.TZ0.5b(ii): Describe the subsequent motion of the electron.
-
19N.2.SL.TZ0.a:
Show that the electric field strength due to the point charge at the position of the electron is 3.4 × 108 N C–1.
-
19N.2.SL.TZ0.b(i):
Calculate the magnitude of the initial acceleration of the electron.
- 19N.2.SL.TZ0.b(ii): Describe the subsequent motion of the electron.
-
19N.1A.SL.TZ0.31:
The force acting between two point charges is when the separation of the charges is . What is the force between the charges when the separation is increased to ?
A.
B.
C.
D.
-
20N.1A.HL.TZ0.32:
The graph shows the variation of electric field strength with distance from a point charge.
The shaded area X is the area under the graph between two separations and from the charge.
What is X?
A. The electric field average between and
B. The electric potential difference between and
C. The work done in moving a charge from to
D. The work done in moving a charge from to
-
20N.2.HL.TZ0.8a:
Explain why the electric potential decreases from A to B.
-
20N.2.HL.TZ0.8b:
Draw, on the axes, the variation of electric potential with distance from the centre of the sphere.
-
20N.2.HL.TZ0.8c(i):
Calculate the electric potential difference between points A and B.
-
20N.2.HL.TZ0.8c(ii):
Determine the charge of the sphere.
- 20N.2.HL.TZ0.8d: The concept of potential is also used in the context of gravitational fields. Suggest why...
-
20N.2.HL.TZ0.a:
Explain why the electric potential decreases from A to B.
-
20N.2.HL.TZ0.b:
Draw, on the axes, the variation of electric potential with distance from the centre of the sphere.
-
20N.2.HL.TZ0.c(i):
Calculate the electric potential difference between points A and B.
-
20N.2.HL.TZ0.c(ii):
Determine the charge of the sphere.
- 20N.2.HL.TZ0.d: The concept of potential is also used in the context of gravitational fields. Suggest why...
- 21M.1A.SL.TZ1.18: Two charges Q1 and Q2, each equal to 2 nC, are separated by a distance 3 m in a vacuum. What is...
- 21M.1A.HL.TZ1.30: A particle with charge −2.5 × 10−6 C moves from point X to point Y due to a uniform electrostatic...
- 21M.1A.SL.TZ2.22: Magnetic field lines are an example of A. a discovery that helps us understand magnetism. B. a...
-
21M.1A.HL.TZ2.31:
The points X and Y are in a uniform electric field of strength . The distance OX is and the distance OY is .
What is the magnitude of the change in electric potential between X and Y?
A.
B.
C.
D.
-
22N.1A.HL.TZ0.31:
An electric field is established between two electrodes separated by distance d, held at a potential difference of V. A charged particle in this field experiences a force F.
What is the charge on the particle?
A.B.
C.
D.
-
22N.2.HL.TZ0.8a:
The diagram shows field lines for an electrostatic field. X and Y are two points on the same field line.
Outline which of the two points has the larger electric potential.
-
22N.2.HL.TZ0.a:
The diagram shows field lines for an electrostatic field. X and Y are two points on the same field line.
Outline which of the two points has the larger electric potential.
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.2.SL.TZ0.7ai: Draw the electric field lines due to the charged plates.
- SPM.2.SL.TZ0.i: Draw the electric field lines due to the charged plates.
- SPM.1A.HL.TZ0.24: A solid metallic sphere is positively charged and isolated from all other charges. The electric...
- SPM.1A.HL.TZ0.27: P is a point in a uniform electric field. What is the direction in which the electric potential...
-
SPM.1A.HL.TZ0.31:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.HL.TZ0.32: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.2.HL.TZ0.9ai: Draw the electric field lines due to the charged plates.
-
SPM.2.HL.TZ0.9ciii:
Show that the electric charge on the oil drop is given by
where is the density of oil and is the volume of the oil drop.
- SPM.2.HL.TZ0.i: Draw the electric field lines due to the charged plates.
-
SPM.2.HL.TZ0.iii:
Show that the electric charge on the oil drop is given by
where is the density of oil and is the volume of the oil drop.
- 23M.2.HL.TZ1.6ai: Sketch, on the axes, how the electric potential V due to the two charges varies with the distance...
-
23M.2.HL.TZ1.6aii:
Calculate the work done to bring a small charge q from infinity to point C.
Data given:
Q = 2.0 × 10−3 C,
q = 4.0 × 10−9 C
D = 1.2 m
- 23M.2.HL.TZ1.i: Sketch, on the axes, how the electric potential V due to the two charges varies with the distance...
-
23M.2.HL.TZ1.ii:
Calculate the work done to bring a small charge q from infinity to point C.
Data given:
Q = 2.0 × 10−3 C,
q = 4.0 × 10−9 C
D = 1.2 m
- 23M.1A.SL.TZ1.15: Two positive charges of magnitude q and 2q are fixed as shown. At which position is the electric...
-
23M.1A.SL.TZ1.19:
P and R are parallel wires carrying the same current into the plane of the paper. P and R are equidistant from a point Q. The line PQ is perpendicular to the line RQ.
The magnetic field due to P at Q is . What is the magnitude of the resultant magnetic field at Q due to both wires?
A.B.
C.
D.
-
23M.1A.HL.TZ1.31:
A negatively charged particle is stationary halfway between two horizontal charged plates. The plates are separated by a distance d with potential difference V between them.
What is the magnitude of the electric field and direction of the electric field at the position of the particle?
Magnitude of
electric fieldDirection of
electric fieldA. up B. up C. down D. down - 23M.1A.SL.TZ1.18: Two positive charges of magnitude q and 2q are fixed as shown. At which position is the electric...
- 23M.1A.SL.TZ2.15: Three point charges, +Q, +Q and −Q, are fixed at the three corners of a square. What is the...
- 23M.1A.HL.TZ2.30: Two spheres have the same positive charge. A point M is midway between the two spheres. Along...
- 23M.1A.SL.TZ2.19: Three point charges, +Q, +Q and −Q, are fixed at the three corners of a square. What is the...
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
-
SPM.1A.SL.TZ0.19:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.SL.TZ0.20: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.1A.HL.TZ0.24: A solid metallic sphere is positively charged and isolated from all other charges. The electric...
- SPM.1A.HL.TZ0.27: P is a point in a uniform electric field. What is the direction in which the electric potential...
-
SPM.1A.HL.TZ0.31:
A charged rod is brought near an initially neutral metal sphere without touching it.
When the sphere is grounded (earthed), there is an electric current for a short time from the sphere to the ground.
The ground connection is then removed.
What are the charge on the rod and the charge induced on the sphere when the connection is removed?
- SPM.1A.HL.TZ0.32: A positive point charge of magnitude 1.0 μC and a point charge q are separated by a distance...
- SPM.2.SL.TZ0.i: Draw the electric field lines due to the charged plates.
D.3 Motion in electromagnetic fields
-
19M.1A.HL.TZ1.16:
Two parallel plates are a distance apart with a potential difference between them. A point charge moves from the negatively charged plate to the positively charged plate. The charge gains kinetic energy W. The distance between the plates is doubled and the potential difference between them is halved. What is the kinetic energy gained by an identical charge moving between these plates?
A.
B. W
C. 2W
D. 4W
- 22M.1A.SL.TZ2.22: A rectangular coil of wire RSTU is connected to a battery and placed in a magnetic field Z...
- 19M.1A.SL.TZ1.19: A horizontal electrical cable carries a steady current out of the page. The Earth’s magnetic...
- 19M.1A.SL.TZ1.18: Two currents of 3 A and 1 A are established in the same direction through two parallel straight...
- 22M.1A.SL.TZ1.22: A conductor is placed in a uniform magnetic field perpendicular to the plane of the paper. A...
- 21N.2.SL.TZ0.4c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
- 19N.2.SL.TZ0.4a: Explain why the path of the proton is a circle.
-
19N.2.SL.TZ0.4b(i):
Show that the radius of the path is about 6 cm.
- 19N.1A.SL.TZ0.20: When a wire with an electric current I is placed in a magnetic field of strength B it experiences...
- 19N.1A.SL.TZ0.32: An electron enters a uniform electric field of strength E with a velocity v. The direction of v...
- 19M.1A.SL.TZ2.31: A proton of velocity v enters a region of electric and magnetic fields. The proton is not...
-
21N.2.SL.TZ0.5c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
- 19M.1A.SL.TZ2.21: A horizontal wire PQ lies perpendicular to a uniform horizontal magnetic field. A length of...
- 20N.1A.SL.TZ0.20: A current in a wire lies between the poles of a magnet. What is the direction of the...
-
19M.1A.SL.TZ1.23:
A beam of negative ions flows in the plane of the page through the magnetic field due to two bar magnets.
What is the direction in which the negative ions will be deflected?
A. Out of the page
B. Into the page X
C. Up the page ↑
D. Down the page ↓
- 21M.1A.SL.TZ1.21: A long straight vertical conductor carries a current I upwards. An electron moves with horizontal...
- 21M.1A.SL.TZ2.19: An ion moves in a circle in a uniform magnetic field. Which single change would increase...
- 21M.1A.SL.TZ1.18: An electron enters the space inside a current-carrying solenoid. The velocity of the electron...
- 21N.1A.SL.TZ0.18: Two parallel wires carry equal currents in the same direction out of the paper. Which diagram...
- 22N.1A.SL.TZ0.19: A loop of wire lies in a magnetic field directed into the plane of the page. The loop carries a...
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.15:
Two long parallel wires X and Y carry equal currents I. The magnetic force exerted per unit length of each wire is .
The current in X is halved and the current in Y is doubled. What is the force per unit length of each wire after the change?
Force per unit length of X Force per unit length of Y A. B. C. D. - EXE.1A.SL.TZ0.16: The force per unit length between two long parallel current-carrying wires is F. The distance...
- EXE.1A.SL.TZ0.17: Three current-carrying wires lie in the same plane and carry currents of 6 A, 2 A and 4 A. The...
- EXE.1A.SL.TZ0.18: A 4.0 cm length of a conducting wire carries a current of 2.5 A. The length is parallel to...
-
23M.2.HL.TZ1.7b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.1A.SL.TZ1.18: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.21: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ2.18: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.21: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
-
23M.1A.SL.TZ2.22:
An electron is accelerated from rest through a potential difference V.
What is the maximum speed of the electron?
A.B.
C.
D.
-
EXE.2.SL.TZ0.14a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
-
EXE.2.SL.TZ0.14b:
Calculate the current in wire Q.
- EXE.2.SL.TZ0.14ci: State the direction of the current in R, relative to the current in P.
- EXE.2.SL.TZ0.14cii: Deduce the current in R.
-
EXE.2.SL.TZ0.15a:
State the fundamental SI units for permeability of free space, .
- EXE.2.SL.TZ0.15bi: magnetic field at A;
- EXE.2.SL.TZ0.15bii: magnetic force on section AB of the loop.
-
EXE.2.SL.TZ0.15ci:
magnitude of the net force acting on the loop;
- EXE.2.SL.TZ0.15cii: direction of the net force acting on the loop.
-
EXE.2.SL.TZ0.16a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.16b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
-
EXE.2.SL.TZ0.17ai:
Draw the magnetic field lines due to A.
- EXE.2.SL.TZ0.17aii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
-
EXE.2.SL.TZ0.17b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
19M.1A.HL.TZ1.16:
Two parallel plates are a distance apart with a potential difference between them. A point charge moves from the negatively charged plate to the positively charged plate. The charge gains kinetic energy W. The distance between the plates is doubled and the potential difference between them is halved. What is the kinetic energy gained by an identical charge moving between these plates?
A.
B. W
C. 2W
D. 4W
- 22M.1A.SL.TZ2.22: A rectangular coil of wire RSTU is connected to a battery and placed in a magnetic field Z...
- 19M.1A.SL.TZ1.19: A horizontal electrical cable carries a steady current out of the page. The Earth’s magnetic...
- 19M.1A.SL.TZ1.18: Two currents of 3 A and 1 A are established in the same direction through two parallel straight...
- 22M.1A.SL.TZ1.22: A conductor is placed in a uniform magnetic field perpendicular to the plane of the paper. A...
- 21N.2.SL.TZ0.4c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
- 21N.2.SL.TZ0.c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
- 19N.2.SL.TZ0.4a: Explain why the path of the proton is a circle.
-
19N.2.SL.TZ0.4b(i):
Show that the radius of the path is about 6 cm.
- 19N.2.SL.TZ0.a: Explain why the path of the proton is a circle.
-
19N.2.SL.TZ0.b(i):
Show that the radius of the path is about 6 cm.
- 19N.1A.SL.TZ0.20: When a wire with an electric current I is placed in a magnetic field of strength B it experiences...
- 19N.1A.SL.TZ0.32: An electron enters a uniform electric field of strength E with a velocity v. The direction of v...
- 19M.1A.SL.TZ2.31: A proton of velocity v enters a region of electric and magnetic fields. The proton is not...
-
21N.2.SL.TZ0.5c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
-
21N.2.SL.TZ0.c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
- 19M.1A.SL.TZ2.21: A horizontal wire PQ lies perpendicular to a uniform horizontal magnetic field. A length of...
- 20N.1A.SL.TZ0.20: A current in a wire lies between the poles of a magnet. What is the direction of the...
-
19M.1A.SL.TZ1.23:
A beam of negative ions flows in the plane of the page through the magnetic field due to two bar magnets.
What is the direction in which the negative ions will be deflected?
A. Out of the page
B. Into the page X
C. Up the page ↑
D. Down the page ↓
- 21M.1A.SL.TZ1.21: A long straight vertical conductor carries a current I upwards. An electron moves with horizontal...
- 21M.1A.SL.TZ2.19: An ion moves in a circle in a uniform magnetic field. Which single change would increase...
- 21M.1A.SL.TZ1.18: An electron enters the space inside a current-carrying solenoid. The velocity of the electron...
- 21N.1A.SL.TZ0.18: Two parallel wires carry equal currents in the same direction out of the paper. Which diagram...
- 22N.1A.SL.TZ0.19: A loop of wire lies in a magnetic field directed into the plane of the page. The loop carries a...
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.SL.TZ0.c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
EXE.1A.SL.TZ0.15:
Two long parallel wires X and Y carry equal currents I. The magnetic force exerted per unit length of each wire is .
The current in X is halved and the current in Y is doubled. What is the force per unit length of each wire after the change?
Force per unit length of X Force per unit length of Y A. B. C. D. - EXE.1A.SL.TZ0.16: The force per unit length between two long parallel current-carrying wires is F. The distance...
- EXE.1A.SL.TZ0.17: Three current-carrying wires lie in the same plane and carry currents of 6 A, 2 A and 4 A. The...
- EXE.1A.SL.TZ0.18: A 4.0 cm length of a conducting wire carries a current of 2.5 A. The length is parallel to...
-
23M.2.HL.TZ1.7b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
-
23M.2.HL.TZ1.b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.i: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.ii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.i: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.ii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.1A.SL.TZ1.18: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.21: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ2.18: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.21: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
-
23M.1A.SL.TZ2.22:
An electron is accelerated from rest through a potential difference V.
What is the maximum speed of the electron?
A.B.
C.
D.
-
EXE.2.SL.TZ0.14a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
-
EXE.2.SL.TZ0.14b:
Calculate the current in wire Q.
- EXE.2.SL.TZ0.14ci: State the direction of the current in R, relative to the current in P.
- EXE.2.SL.TZ0.14cii: Deduce the current in R.
-
EXE.2.SL.TZ0.a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
-
EXE.2.SL.TZ0.b:
Calculate the current in wire Q.
- EXE.2.SL.TZ0.i: State the direction of the current in R, relative to the current in P.
- EXE.2.SL.TZ0.ii: Deduce the current in R.
-
EXE.2.SL.TZ0.15a:
State the fundamental SI units for permeability of free space, .
- EXE.2.SL.TZ0.15bi: magnetic field at A;
- EXE.2.SL.TZ0.15bii: magnetic force on section AB of the loop.
-
EXE.2.SL.TZ0.15ci:
magnitude of the net force acting on the loop;
- EXE.2.SL.TZ0.15cii: direction of the net force acting on the loop.
-
EXE.2.SL.TZ0.a:
State the fundamental SI units for permeability of free space, .
- EXE.2.SL.TZ0.i: magnetic field at A;
- EXE.2.SL.TZ0.ii: magnetic force on section AB of the loop.
-
EXE.2.SL.TZ0.i:
magnitude of the net force acting on the loop;
- EXE.2.SL.TZ0.ii: direction of the net force acting on the loop.
-
EXE.2.SL.TZ0.16a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.16b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
-
EXE.2.SL.TZ0.a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
-
EXE.2.SL.TZ0.17ai:
Draw the magnetic field lines due to A.
- EXE.2.SL.TZ0.17aii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
-
EXE.2.SL.TZ0.17b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
-
EXE.2.SL.TZ0.i:
Draw the magnetic field lines due to A.
- EXE.2.SL.TZ0.ii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
-
EXE.2.SL.TZ0.b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
D.4 Induction
-
22M.1A.SL.TZ1.34:
The graph shows the variation of magnetic flux in a coil with time .
What represents the variation with time of the induced emf across the coil?
- 19N.1A.HL.TZ0.33: X and Y are two plane coils parallel to each other that have a common axis. There is a constant...
- 19N.1A.HL.TZ0.34: A coil is rotated in a uniform magnetic field. An alternating emf is induced in the coil. What is...
- 19M.1A.HL.TZ2.29: A circular coil of wire moves through a region of uniform magnetic field directed out of the...
-
21N.2.HL.TZ0.5a:
Show that the speed of the loop is 20 cm s−1.
-
21N.2.HL.TZ0.5b.i:
Sketch, on the axes, a graph to show the variation with time of the magnetic flux linkage in the loop.
-
21N.2.HL.TZ0.5b.ii:
Sketch, on the axes, a graph to show the variation with time of the magnitude of the emf induced in the loop.
-
21N.2.HL.TZ0.5c.i:
There are 85 turns of wire in the loop. Calculate the maximum induced emf in the loop.
-
19M.1A.HL.TZ1.35:
The graph below shows the variation with time of the magnetic flux through a coil.
Which of the following gives three times for which the magnitude of the induced emf is a maximum?
A. 0, ,
B. 0, , T
C. 0, , T
D. , ,
-
20N.1A.HL.TZ0.35:
A rectangular coil rotates at a constant angular velocity. At the instant shown, the plane of the coil is at right angles to the line . A uniform magnetic field acts in the direction .
What rotation of the coil about a specified axis will produce the graph of electromotive force (emf) against time ?
A. Through about
B. Through about
C. Through about
D. Through about
-
20N.2.HL.TZ0.9a:
Explain, by reference to Faraday’s law of induction, how an electromotive force (emf) is induced in the coil.
-
20N.2.HL.TZ0.9b(iii):
The frequency of the generator is doubled with no other changes being made. Draw, on the axes, the variation with time of the voltage output of the generator.
- 21M.1A.HL.TZ1.34: The conservation of which quantity explains Lenz’s law? A. Charge B. Energy C. Magnetic...
-
21M.1A.HL.TZ2.35:
A magnet connected to a spring oscillates above a solenoid with a 240 turn coil as shown.
The graph below shows the variation with time of the emf across the solenoid with the period, , of the system shown.
The spring is replaced with one that allows the magnet to oscillate with a higher frequency. Which graph shows the new variation with time of the current in the resistor for this new set-up?
- 21M.1A.HL.TZ1.33: A conducting ring encloses an area of 2.0 cm2 and is perpendicular to a magnetic field...
- 21N.1A.HL.TZ0.33: A small magnet is released from rest to drop through a stationary horizontal conducting...
- 22M.1A.HL.TZ2.19: The coil of a direct current electric motor is turning with a period T. At t = 0 the coil is in...
- 22N.1A.HL.TZ0.33: A resistor connects two parallel conducting rails a distance d apart. A conducting bar rolls...
- 22N.1A.HL.TZ0.34: Two coils of wire are wound around an iron cylinder. One coil is connected in a circuit with...
- SPM.1A.HL.TZ0.29: A rectangular conducting coil rotates at a constant angular velocity in a uniform magnetic field....
- SPM.2.HL.TZ0.5a: Outline why the magnetic flux in ring B increases.
- EXE.2.HL.TZ0.2ai: State the movement direction for which the geophone has its greatest sensitivity.
-
EXE.2.HL.TZ0.2aii:
Outline how an emf is generated in the coil.
-
EXE.2.HL.TZ0.2aiii:
Explain why the magnitude of the emf is related to the amplitude of the ground movement.
-
EXE.2.HL.TZ0.2aiv:
In one particular event, a maximum emf of 65 mV is generated in the geophone. The geophone coil has 150 turns.
Calculate the rate of flux change that leads to this emf.
- EXE.2.HL.TZ0.2b: Suggest two changes to the system that will make the geophone more sensitive.
-
23M.2.HL.TZ1.7a:
Explain, by reference to Faraday’s law of electromagnetic induction, why there is an electromotive force (emf) induced in the loop as it leaves the region of magnetic field.
-
23M.1A.HL.TZ1.34:
Wire XY moves perpendicular to a magnetic field in the direction shown.
The graph shows the variation with time of the displacement of XY.
What is the graph of the electromotive force (emf) ε induced across XY?
- 23M.1A.HL.TZ2.32: A single loop of wire of resistance 10 Ω has its plane perpendicular to a changing magnetic...
- SPM.1A.HL.TZ0.29: A rectangular conducting coil rotates at a constant angular velocity in a uniform magnetic field....
-
22M.1A.SL.TZ1.34:
The graph shows the variation of magnetic flux in a coil with time .
What represents the variation with time of the induced emf across the coil?
- 19N.1A.HL.TZ0.33: X and Y are two plane coils parallel to each other that have a common axis. There is a constant...
- 19N.1A.HL.TZ0.34: A coil is rotated in a uniform magnetic field. An alternating emf is induced in the coil. What is...
- 19M.1A.HL.TZ2.29: A circular coil of wire moves through a region of uniform magnetic field directed out of the...
-
21N.2.HL.TZ0.5a:
Show that the speed of the loop is 20 cm s−1.
-
21N.2.HL.TZ0.5b.i:
Sketch, on the axes, a graph to show the variation with time of the magnetic flux linkage in the loop.
-
21N.2.HL.TZ0.5b.ii:
Sketch, on the axes, a graph to show the variation with time of the magnitude of the emf induced in the loop.
-
21N.2.HL.TZ0.5c.i:
There are 85 turns of wire in the loop. Calculate the maximum induced emf in the loop.
-
21N.2.HL.TZ0.a:
Show that the speed of the loop is 20 cm s−1.
-
21N.2.HL.TZ0.b.i:
Sketch, on the axes, a graph to show the variation with time of the magnetic flux linkage in the loop.
-
21N.2.HL.TZ0.b.ii:
Sketch, on the axes, a graph to show the variation with time of the magnitude of the emf induced in the loop.
-
21N.2.HL.TZ0.c.i:
There are 85 turns of wire in the loop. Calculate the maximum induced emf in the loop.
-
19M.1A.HL.TZ1.35:
The graph below shows the variation with time of the magnetic flux through a coil.
Which of the following gives three times for which the magnitude of the induced emf is a maximum?
A. 0, ,
B. 0, , T
C. 0, , T
D. , ,
-
20N.1A.HL.TZ0.35:
A rectangular coil rotates at a constant angular velocity. At the instant shown, the plane of the coil is at right angles to the line . A uniform magnetic field acts in the direction .
What rotation of the coil about a specified axis will produce the graph of electromotive force (emf) against time ?
A. Through about
B. Through about
C. Through about
D. Through about
-
20N.2.HL.TZ0.9a:
Explain, by reference to Faraday’s law of induction, how an electromotive force (emf) is induced in the coil.
-
20N.2.HL.TZ0.9b(iii):
The frequency of the generator is doubled with no other changes being made. Draw, on the axes, the variation with time of the voltage output of the generator.
-
20N.2.HL.TZ0.a:
Explain, by reference to Faraday’s law of induction, how an electromotive force (emf) is induced in the coil.
-
20N.2.HL.TZ0.b(iii):
The frequency of the generator is doubled with no other changes being made. Draw, on the axes, the variation with time of the voltage output of the generator.
- 21M.1A.HL.TZ1.34: The conservation of which quantity explains Lenz’s law? A. Charge B. Energy C. Magnetic...
-
21M.1A.HL.TZ2.35:
A magnet connected to a spring oscillates above a solenoid with a 240 turn coil as shown.
The graph below shows the variation with time of the emf across the solenoid with the period, , of the system shown.
The spring is replaced with one that allows the magnet to oscillate with a higher frequency. Which graph shows the new variation with time of the current in the resistor for this new set-up?
- 21M.1A.HL.TZ1.33: A conducting ring encloses an area of 2.0 cm2 and is perpendicular to a magnetic field...
- 21N.1A.HL.TZ0.33: A small magnet is released from rest to drop through a stationary horizontal conducting...
- 22M.1A.HL.TZ2.19: The coil of a direct current electric motor is turning with a period T. At t = 0 the coil is in...
- 22N.1A.HL.TZ0.33: A resistor connects two parallel conducting rails a distance d apart. A conducting bar rolls...
- 22N.1A.HL.TZ0.34: Two coils of wire are wound around an iron cylinder. One coil is connected in a circuit with...
- SPM.1A.HL.TZ0.29: A rectangular conducting coil rotates at a constant angular velocity in a uniform magnetic field....
- SPM.2.HL.TZ0.5a: Outline why the magnetic flux in ring B increases.
- SPM.2.HL.TZ0.a: Outline why the magnetic flux in ring B increases.
- EXE.2.HL.TZ0.2ai: State the movement direction for which the geophone has its greatest sensitivity.
-
EXE.2.HL.TZ0.2aii:
Outline how an emf is generated in the coil.
-
EXE.2.HL.TZ0.2aiii:
Explain why the magnitude of the emf is related to the amplitude of the ground movement.
-
EXE.2.HL.TZ0.2aiv:
In one particular event, a maximum emf of 65 mV is generated in the geophone. The geophone coil has 150 turns.
Calculate the rate of flux change that leads to this emf.
- EXE.2.HL.TZ0.2b: Suggest two changes to the system that will make the geophone more sensitive.
- EXE.2.HL.TZ0.i: State the movement direction for which the geophone has its greatest sensitivity.
-
EXE.2.HL.TZ0.ii:
Outline how an emf is generated in the coil.
-
EXE.2.HL.TZ0.iii:
Explain why the magnitude of the emf is related to the amplitude of the ground movement.
-
EXE.2.HL.TZ0.iv:
In one particular event, a maximum emf of 65 mV is generated in the geophone. The geophone coil has 150 turns.
Calculate the rate of flux change that leads to this emf.
- EXE.2.HL.TZ0.b: Suggest two changes to the system that will make the geophone more sensitive.
-
23M.2.HL.TZ1.7a:
Explain, by reference to Faraday’s law of electromagnetic induction, why there is an electromotive force (emf) induced in the loop as it leaves the region of magnetic field.
-
23M.2.HL.TZ1.a:
Explain, by reference to Faraday’s law of electromagnetic induction, why there is an electromotive force (emf) induced in the loop as it leaves the region of magnetic field.
-
23M.1A.HL.TZ1.34:
Wire XY moves perpendicular to a magnetic field in the direction shown.
The graph shows the variation with time of the displacement of XY.
What is the graph of the electromotive force (emf) ε induced across XY?
- 23M.1A.HL.TZ2.32: A single loop of wire of resistance 10 Ω has its plane perpendicular to a changing magnetic...
- SPM.1A.HL.TZ0.29: A rectangular conducting coil rotates at a constant angular velocity in a uniform magnetic field....