DP Physics (first assessment 2025)

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Question 21N.2.HL.TZ0.c.i

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Date November 2021 Marks available [Maximum mark: 2] Reference code 21N.2.HL.TZ0.c.i
Level HL Paper 2 Time zone TZ0
Command term Calculate Question number c.i Adapted from N/A
c.i.
[Maximum mark: 2]
21N.2.HL.TZ0.c.i

There are 85 turns of wire in the loop. Calculate the maximum induced emf in the loop.

[2]

Markscheme

ALTERNATIVE 1

maximum flux at «5.0×5.0×10-4×85×0.94» =0.19975≈0.20 «Wb» ✓

emf = «0.200.25=» 0.80 «V» ✓


ALTERNATIVE 2

emf induced in one turn = BvL = 0.94×0.20×0.05=0.0094 «V» ✓

emf =85×0.0094=0.80 «V» ✓

 

Award [2] marks for a bald correct answer.

Allow ECF from MP1.

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