Question 21N.2.SL.TZ0.a.i

«electric field at P from one charge is $\frac{kQ}{r^2}=$» $\frac{8.99\times {10}^9\times 44\times {10}^{-6}}{0.{48}^2}$

OR

$1.7168\times {10}^6$ «NC⁻¹» ✓

« net field is » $2\times 1.7168\times {10}^6\times \cos 30°=2.97\times {10}^6$ «NC⁻¹» ✓