Directly related questions
- EXE.1A.SL.TZ0.17: Three current-carrying wires lie in the same plane and carry currents of 6 A, 2 A and 4 A. The...
- EXE.1A.SL.TZ0.17: Three current-carrying wires lie in the same plane and carry currents of 6 A, 2 A and 4 A. The...
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EXE.1A.SL.TZ0.15:
Two long parallel wires X and Y carry equal currents I. The magnetic force exerted per unit length of each wire is .
The current in X is halved and the current in Y is doubled. What is the force per unit length of each wire after the change?
Force per unit length of X Force per unit length of Y A. B. C. D. -
EXE.1A.SL.TZ0.15:
Two long parallel wires X and Y carry equal currents I. The magnetic force exerted per unit length of each wire is .
The current in X is halved and the current in Y is doubled. What is the force per unit length of each wire after the change?
Force per unit length of X Force per unit length of Y A. B. C. D. - EXE.1A.SL.TZ0.18: A 4.0 cm length of a conducting wire carries a current of 2.5 A. The length is parallel to...
- EXE.1A.SL.TZ0.18: A 4.0 cm length of a conducting wire carries a current of 2.5 A. The length is parallel to...
- EXE.1A.SL.TZ0.16: The force per unit length between two long parallel current-carrying wires is F. The distance...
- EXE.1A.SL.TZ0.16: The force per unit length between two long parallel current-carrying wires is F. The distance...
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23M.2.HL.TZ1.7b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
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23M.2.HL.TZ1.7b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
-
23M.2.HL.TZ1.b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.ii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.ii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.i: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.i: outline the magnetic force acting on it due to the current in PQ.
-
EXE.2.SL.TZ0.14a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
-
EXE.2.SL.TZ0.14a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
-
EXE.2.SL.TZ0.a:
State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P.
- EXE.2.SL.TZ0.15bi: magnetic field at A;
- EXE.2.SL.TZ0.15bi: magnetic field at A;
- EXE.2.SL.TZ0.i: magnetic field at A;
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EXE.2.SL.TZ0.17b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
-
EXE.2.SL.TZ0.17b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
-
EXE.2.SL.TZ0.b:
Both wires are 7.5 m long and are 0.25 m apart. The current in both wires is 12 A. Determine the force that acts on one wire due to the other.
- EXE.2.SL.TZ0.14cii: Deduce the current in R.
- EXE.2.SL.TZ0.14cii: Deduce the current in R.
- EXE.2.SL.TZ0.ii: Deduce the current in R.
- EXE.2.SL.TZ0.17aii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
- EXE.2.SL.TZ0.17aii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
- EXE.2.SL.TZ0.ii: State and explain, using your diagram, why a force acts on B due to A in the plane of the paper.
- EXE.2.SL.TZ0.15bii: magnetic force on section AB of the loop.
- EXE.2.SL.TZ0.15bii: magnetic force on section AB of the loop.
- EXE.2.SL.TZ0.ii: magnetic force on section AB of the loop.
-
EXE.2.SL.TZ0.15ci:
magnitude of the net force acting on the loop;
-
EXE.2.SL.TZ0.15ci:
magnitude of the net force acting on the loop;
-
EXE.2.SL.TZ0.i:
magnitude of the net force acting on the loop;
-
EXE.2.SL.TZ0.16a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.16a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.a:
Determine the magnetic force acting on the 15 Ω wire due to the current in the 30 Ω wire.
-
EXE.2.SL.TZ0.14b:
Calculate the current in wire Q.
-
EXE.2.SL.TZ0.14b:
Calculate the current in wire Q.
-
EXE.2.SL.TZ0.b:
Calculate the current in wire Q.
- EXE.2.SL.TZ0.14ci: State the direction of the current in R, relative to the current in P.
- EXE.2.SL.TZ0.14ci: State the direction of the current in R, relative to the current in P.
- EXE.2.SL.TZ0.i: State the direction of the current in R, relative to the current in P.
- EXE.2.SL.TZ0.15cii: direction of the net force acting on the loop.
- EXE.2.SL.TZ0.15cii: direction of the net force acting on the loop.
- EXE.2.SL.TZ0.ii: direction of the net force acting on the loop.
-
EXE.2.SL.TZ0.17ai:
Draw the magnetic field lines due to A.
-
EXE.2.SL.TZ0.17ai:
Draw the magnetic field lines due to A.
-
EXE.2.SL.TZ0.i:
Draw the magnetic field lines due to A.
-
EXE.2.SL.TZ0.15a:
State the fundamental SI units for permeability of free space, .
-
EXE.2.SL.TZ0.15a:
State the fundamental SI units for permeability of free space, .
-
EXE.2.SL.TZ0.a:
State the fundamental SI units for permeability of free space, .
-
EXE.2.SL.TZ0.16b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
-
EXE.2.SL.TZ0.16b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
-
EXE.2.SL.TZ0.b:
The magnetic field strength of Earth’s field at the location of the wires is 45 μT.
Discuss the assumption made in this question.
- 22N.1A.SL.TZ0.19: A loop of wire lies in a magnetic field directed into the plane of the page. The loop carries a...
- 22N.1A.SL.TZ0.19: A loop of wire lies in a magnetic field directed into the plane of the page. The loop carries a...
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.5c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.c.ii: Every current-carrying wire produces a magnetic field. Describe one piece of evidence that...
- 22N.2.SL.TZ0.5c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.SL.TZ0.5c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.SL.TZ0.c.ii: Identify the direction of the magnetic force on the wire.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.5c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
- 22N.2.SL.TZ0.c.i: Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.17:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.26:
Two long parallel wires P and Q are a distance d apart. They each carry a current.
A magnetic force per unit length acts on P due to Q.
The distance between the wires is increased to 2d and the current in Q is decreased to .
What is the magnetic force per unit length that acts on P due to Q after the changes?
A.B.
C.
D.
-
19M.1A.HL.TZ1.16:
Two parallel plates are a distance apart with a potential difference between them. A point charge moves from the negatively charged plate to the positively charged plate. The charge gains kinetic energy W. The distance between the plates is doubled and the potential difference between them is halved. What is the kinetic energy gained by an identical charge moving between these plates?
A.
B. W
C. 2W
D. 4W
-
19M.1A.HL.TZ1.16:
Two parallel plates are a distance apart with a potential difference between them. A point charge moves from the negatively charged plate to the positively charged plate. The charge gains kinetic energy W. The distance between the plates is doubled and the potential difference between them is halved. What is the kinetic energy gained by an identical charge moving between these plates?
A.
B. W
C. 2W
D. 4W
- 19M.1A.SL.TZ1.18: Two currents of 3 A and 1 A are established in the same direction through two parallel straight...
- 19M.1A.SL.TZ1.18: Two currents of 3 A and 1 A are established in the same direction through two parallel straight...
- 19M.1A.SL.TZ1.19: A horizontal electrical cable carries a steady current out of the page. The Earth’s magnetic...
- 19M.1A.SL.TZ1.19: A horizontal electrical cable carries a steady current out of the page. The Earth’s magnetic...
- 19M.1A.SL.TZ2.31: A proton of velocity v enters a region of electric and magnetic fields. The proton is not...
- 19M.1A.SL.TZ2.31: A proton of velocity v enters a region of electric and magnetic fields. The proton is not...
-
19M.1A.SL.TZ1.23:
A beam of negative ions flows in the plane of the page through the magnetic field due to two bar magnets.
What is the direction in which the negative ions will be deflected?
A. Out of the page
B. Into the page X
C. Up the page ↑
D. Down the page ↓
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19M.1A.SL.TZ1.23:
A beam of negative ions flows in the plane of the page through the magnetic field due to two bar magnets.
What is the direction in which the negative ions will be deflected?
A. Out of the page
B. Into the page X
C. Up the page ↑
D. Down the page ↓
- 19M.1A.SL.TZ2.21: A horizontal wire PQ lies perpendicular to a uniform horizontal magnetic field. A length of...
- 19M.1A.SL.TZ2.21: A horizontal wire PQ lies perpendicular to a uniform horizontal magnetic field. A length of...
- 19N.1A.SL.TZ0.32: An electron enters a uniform electric field of strength E with a velocity v. The direction of v...
- 19N.1A.SL.TZ0.32: An electron enters a uniform electric field of strength E with a velocity v. The direction of v...
- 19N.1A.SL.TZ0.20: When a wire with an electric current I is placed in a magnetic field of strength B it experiences...
- 19N.1A.SL.TZ0.20: When a wire with an electric current I is placed in a magnetic field of strength B it experiences...
- 19N.2.SL.TZ0.4a: Explain why the path of the proton is a circle.
- 19N.2.SL.TZ0.4a: Explain why the path of the proton is a circle.
- 19N.2.SL.TZ0.a: Explain why the path of the proton is a circle.
-
19N.2.SL.TZ0.4b(i):
Show that the radius of the path is about 6 cm.
-
19N.2.SL.TZ0.4b(i):
Show that the radius of the path is about 6 cm.
-
19N.2.SL.TZ0.b(i):
Show that the radius of the path is about 6 cm.
- 20N.1A.SL.TZ0.20: A current in a wire lies between the poles of a magnet. What is the direction of the...
- 20N.1A.SL.TZ0.20: A current in a wire lies between the poles of a magnet. What is the direction of the...
- 21M.1A.SL.TZ1.18: An electron enters the space inside a current-carrying solenoid. The velocity of the electron...
- 21M.1A.SL.TZ1.18: An electron enters the space inside a current-carrying solenoid. The velocity of the electron...
- 21M.1A.SL.TZ1.21: A long straight vertical conductor carries a current I upwards. An electron moves with horizontal...
- 21M.1A.SL.TZ1.21: A long straight vertical conductor carries a current I upwards. An electron moves with horizontal...
- 21M.1A.SL.TZ2.19: An ion moves in a circle in a uniform magnetic field. Which single change would increase...
- 21M.1A.SL.TZ2.19: An ion moves in a circle in a uniform magnetic field. Which single change would increase...
- 21N.1A.SL.TZ0.18: Two parallel wires carry equal currents in the same direction out of the paper. Which diagram...
- 21N.1A.SL.TZ0.18: Two parallel wires carry equal currents in the same direction out of the paper. Which diagram...
-
21N.2.SL.TZ0.5c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
-
21N.2.SL.TZ0.5c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
-
21N.2.SL.TZ0.c.ii:
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
- 21N.2.SL.TZ0.4c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
- 21N.2.SL.TZ0.4c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
- 21N.2.SL.TZ0.c.ii: Determine the magnitude and direction of the resultant magnetic field at Q.
- 22M.1A.SL.TZ1.22: A conductor is placed in a uniform magnetic field perpendicular to the plane of the paper. A...
- 22M.1A.SL.TZ1.22: A conductor is placed in a uniform magnetic field perpendicular to the plane of the paper. A...
- 22M.1A.SL.TZ2.22: A rectangular coil of wire RSTU is connected to a battery and placed in a magnetic field Z...
- 22M.1A.SL.TZ2.22: A rectangular coil of wire RSTU is connected to a battery and placed in a magnetic field Z...
- 23M.1A.SL.TZ1.18: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.21: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.21: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.18: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.18: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.21: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.21: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ1.18: An electron enters a region of uniform magnetic field at a speed v. The direction of the electron...
- 23M.1A.SL.TZ2.21: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.18: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.18: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.21: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.21: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.18: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.18: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
- 23M.1A.SL.TZ2.21: A negatively charged sphere is falling through a magnetic field. What is the direction of the...
-
23M.1A.SL.TZ2.22:
An electron is accelerated from rest through a potential difference V.
What is the maximum speed of the electron?
A.B.
C.
D.
-
23M.1A.SL.TZ2.22:
An electron is accelerated from rest through a potential difference V.
What is the maximum speed of the electron?
A.B.
C.
D.
-
23M.1A.SL.TZ2.22:
An electron is accelerated from rest through a potential difference V.
What is the maximum speed of the electron?
A.B.
C.
D.
-
23M.1A.SL.TZ2.22:
An electron is accelerated from rest through a potential difference V.
What is the maximum speed of the electron?
A.B.
C.
D.
-
23M.2.HL.TZ1.7b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
-
23M.2.HL.TZ1.7b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
-
23M.2.HL.TZ1.b:
Just before the loop is about to completely exit the region of magnetic field, the loop moves with constant terminal speed v.
The following data is available:
Mass of loop m = 4.0 g Resistance of loop R = 25 mΩ Width of loop L = 15 cm Magnetic flux density B = 0.80 T Determine, in m s−1 the terminal speed v.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.i: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4ci: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.i: outline the magnetic force acting on it due to the current in PQ.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.ii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.4cii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.
- 23M.2.SL.TZ2.ii: state and explain the net magnetic force acting on it due to the currents in PQ and TU.