Question 23M.2.HL.TZ1.5
Date | May 2023 | Marks available | [Maximum mark: 15] | Reference code | 23M.2.HL.TZ1.5 |
Level | HL | Paper | 2 | Time zone | TZ1 |
Command term | Complete, Estimate, Identify, Label, Outline, Show that, State | Question number | 5 | Adapted from | N/A |
Identify with ticks [✓] in the table, the forces that can act on electrons and the forces that can act on quarks.
[2]
Weak nuclear: 2 ticks ✓
Strong nuclear: quarks only ✓
The following data is available for atomic masses for the fusion reaction
:
2.0141 u | |
3.0160 u | |
4.0026 u |
Show that the energy released is about 18 MeV.
[2]
«𝜇» = 2.0141 + 3.0160 − (4.0026 + 1.008665) «= 0.0188 u»
OR
In MeV: 1876.13415 + 2809.404 − (3728.4219 + 939.5714475) ✓
= 0.0188 × 931.5 OR = 17.512 «MeV» ✓
Must see either clear substitutions or answer to at least 3 s.f. for MP2.

Estimate the specific energy of hydrogen by finding the energy produced when 0.4 kg of and 0.6 kg of undergo fusion.
[2]
ALTERNATIVE 1
0.40 kg of deuterium is « × 6.02 × 1023» = 1.2 × 1026 nuclei
« 0.60 kg of tritium is the same number » ✓
So specific energy «» = 3.4 × 1014 «J kg−1»
ALTERNATIVE 2
«17.51 × 106 × 1.6 × 10−19 =» 2.8 × 10−12 «J»
AND
«(2.0141 + 3.0160) × 1.66 × 10−27 =» 8.35 × 10−27 ✓
«» = 3.4 × 1014 «J kg−1»
Allow ∼2.1 × 1027 MeV kg−1 for MP2.
Allow ECF from MP1 for both ALTs.

It is hoped that nuclear fusion can be used for commercial production of energy.
Outline
two difficulties of energy production by nuclear fusion.
[2]
Requires high temp/pressure ✓
Must overcome Coulomb/intermolecular repulsion ✓
Difficult to contain / control «at high temp/pressure» ✓
Difficult to produce excess energy/often energy input greater than output / OWTTE ✓
Difficult to capture energy from fusion reactions ✓
Difficult to maintain/sustain a constant reaction rate ✓

one advantage of energy production by nuclear fusion compared to nuclear fission.
[1]
Plentiful fuel supplies OR larger specific energy OR larger energy density OR little or no «major radioactive» waste products ✓
Allow descriptions such as “more energy per unit mass” or “more energy per unit volume”

Tritium () is unstable and decays into an isotope of helium (He) by beta minus decay with a half-life of 12.3 years.
State the nucleon number of the He isotope that decays into.
[1]
3 ✓
Do not accept by itself.

The following diagram is an incomplete Feynman diagram describing the beta minus decay of into He. Complete the diagram and label all the missing particles.
[3]
Proton shown ✓
W- shown ✓
Produces electron/e− / 𝛽− and antineutrino / with proper arrow directions. ✓
Allow solid, dashed, or wavy line for W-particle.
Must see bar on antineutrino if symbol used.
Estimate the fraction of tritium remaining after one year.
[2]
= «»0.056«y−1» OR OR
0.945 OR 94.5% ✓
Allow ECF from MP1
