Question 19M.2.SL.TZ1.c.ii
| Date | May 2019 | Marks available | [Maximum mark: 1] | Reference code | 19M.2.SL.TZ1.c.ii |
| Level | SL | Paper | 2 | Time zone | TZ1 |
| Command term | Outline | Question number | c.ii | Adapted from | N/A |
Outline why this force does no work on the Moon.
[1]
the force/field and the velocity/displacement are at 90° to each other OR there is no change in GPE of the moon ✔
Award [0] for any mention of no net force on the satellite.
Do not accept acceleration is perpendicular to velocity.
Some candidates connected the idea that the gravitational force is perpendicular to the velocity (and hence the displacement) for the mark. It was also allowed to discuss that there is no change in gravitational potential energy, so therefore no work was being done. It was not acceptable to simply state that the net displacement over one full orbit is zero. Unfortunately, some candidates suggested that there is no net force on the moon so there is no work done, or that the moon is so much smaller so no work could be done on it.
