Directly related questions
-
23M.2.SL.TZ1.1bii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.1bii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.1bii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.ii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.1bii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.ii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.1aii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.1aii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.1aii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.ii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.1aii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.ii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.1bi:
Show that the collision is elastic.
-
23M.2.SL.TZ1.1bi:
Show that the collision is elastic.
-
23M.2.SL.TZ1.1bi:
Show that the collision is elastic.
-
23M.2.SL.TZ1.i:
Show that the collision is elastic.
-
23M.2.SL.TZ1.1bi:
Show that the collision is elastic.
-
23M.2.SL.TZ1.i:
Show that the collision is elastic.
-
23M.2.SL.TZ1.1c:
The coefficient of dynamic friction between the block and the rough surface is 0.400.
Estimate the distance travelled by the block on the rough surface until it stops.
-
23M.2.SL.TZ1.1c:
The coefficient of dynamic friction between the block and the rough surface is 0.400.
Estimate the distance travelled by the block on the rough surface until it stops.
-
23M.2.SL.TZ1.1c:
The coefficient of dynamic friction between the block and the rough surface is 0.400.
Estimate the distance travelled by the block on the rough surface until it stops.
-
23M.2.SL.TZ1.c:
The coefficient of dynamic friction between the block and the rough surface is 0.400.
Estimate the distance travelled by the block on the rough surface until it stops.
-
23M.2.SL.TZ1.1c:
The coefficient of dynamic friction between the block and the rough surface is 0.400.
Estimate the distance travelled by the block on the rough surface until it stops.
-
23M.2.SL.TZ1.c:
The coefficient of dynamic friction between the block and the rough surface is 0.400.
Estimate the distance travelled by the block on the rough surface until it stops.
-
23M.2.SL.TZ2.1ci:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.1ci:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.i:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
- EXE.2.SL.TZ0.2aii: the mechanical power output of the motor.
- EXE.2.SL.TZ0.2aii: the mechanical power output of the motor.
- EXE.2.SL.TZ0.ii: the mechanical power output of the motor.
-
EXE.2.SL.TZ0.2c:
The total friction in the system acting on the tram is equivalent to an opposing force of 750 N.
For one particular journey, the tram is full of passengers.
Estimate the maximum speed v of the tram as it leaves the lower station.
-
EXE.2.SL.TZ0.2c:
The total friction in the system acting on the tram is equivalent to an opposing force of 750 N.
For one particular journey, the tram is full of passengers.
Estimate the maximum speed v of the tram as it leaves the lower station.
-
EXE.2.SL.TZ0.c:
The total friction in the system acting on the tram is equivalent to an opposing force of 750 N.
For one particular journey, the tram is full of passengers.
Estimate the maximum speed v of the tram as it leaves the lower station.
-
22N.1A.SL.TZ0.8:
An engine is exerting a horizontal force on an object that is moving along a horizontal surface at a constant velocity . The mass of the object is and the coefficient of dynamic friction between the object and the surface is .
What is the power of the engine?
A.B.
C.
D.
-
22N.1A.SL.TZ0.8:
An engine is exerting a horizontal force on an object that is moving along a horizontal surface at a constant velocity . The mass of the object is and the coefficient of dynamic friction between the object and the surface is .
What is the power of the engine?
A.B.
C.
D.
- 22N.1A.SL.TZ0.6: A person lifts a total mass of 20 kg through a vertical distance of 0.60 m. The person...
- 22N.1A.SL.TZ0.6: A person lifts a total mass of 20 kg through a vertical distance of 0.60 m. The person...
-
22N.2.SL.TZ0.1c.i:
Determine the energy transferred to the air during the first 3.0 s of motion. State your answer to an appropriate number of significant figures.
-
22N.2.SL.TZ0.c.i:
Determine the energy transferred to the air during the first 3.0 s of motion. State your answer to an appropriate number of significant figures.
-
22N.2.SL.TZ0.1c.i:
Determine the energy transferred to the air during the first 3.0 s of motion. State your answer to an appropriate number of significant figures.
-
22N.2.SL.TZ0.1c.ii:
Describe the energy change that takes place for t > 3.0 s.
-
22N.2.SL.TZ0.c.ii:
Describe the energy change that takes place for t > 3.0 s.
-
22N.2.SL.TZ0.1c.ii:
Describe the energy change that takes place for t > 3.0 s.
-
22N.2.SL.TZ0.6b.ii:
The polonium nucleus was stationary before the decay.
Show, by reference to the momentum of the particles, that the kinetic energy of the alpha particle is much greater than the kinetic energy of the lead nucleus.
-
22N.2.SL.TZ0.6b.ii:
The polonium nucleus was stationary before the decay.
Show, by reference to the momentum of the particles, that the kinetic energy of the alpha particle is much greater than the kinetic energy of the lead nucleus.
-
22N.2.SL.TZ0.b.ii:
The polonium nucleus was stationary before the decay.
Show, by reference to the momentum of the particles, that the kinetic energy of the alpha particle is much greater than the kinetic energy of the lead nucleus.
- SPM.2.HL.TZ0.5d: Outline why work must be done on ring B as it moves towards ring A at a constant speed.
- SPM.2.HL.TZ0.5d: Outline why work must be done on ring B as it moves towards ring A at a constant speed.
- SPM.2.HL.TZ0.d: Outline why work must be done on ring B as it moves towards ring A at a constant speed.
- SPM.1A.SL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.HL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.SL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.SL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.HL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.HL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.SL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.HL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.SL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.HL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.SL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
- SPM.1A.HL.TZ0.3: A net force of 8.0 N accelerates a 4.0 kg body from rest to a speed of 5.0 m s−1. What is the...
-
SPM.1A.HL.TZ0.6:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.5:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.5:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.5:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.6:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.5:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.6:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.5:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.SL.TZ0.5:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
SPM.1A.HL.TZ0.6:
An object is released from rest in a vacuum at a height above the Earth’s surface.
As the object falls it passes a point at a height of 0.75 above the surface.
What is ?
A.B.
C.
D.
-
19M.1A.SL.TZ1.11:
An insulated tube is filled with a large number n of lead spheres, each of mass m. The tube is inverted s times so that the spheres completely fall through an average distance L each time. The temperature of the spheres is measured before and after the inversions and the resultant change in temperature is ΔT.
What is the specific heat capacity of lead?
A.
B.
C.
D.
-
19M.1A.SL.TZ1.11:
An insulated tube is filled with a large number n of lead spheres, each of mass m. The tube is inverted s times so that the spheres completely fall through an average distance L each time. The temperature of the spheres is measured before and after the inversions and the resultant change in temperature is ΔT.
What is the specific heat capacity of lead?
A.
B.
C.
D.
-
19M.1A.SL.TZ1.6:
An object of mass m is sliding down a ramp at constant speed. During the motion it travels a distance along the ramp and falls through a vertical distance h. The coefficient of dynamic friction between the ramp and the object is μ. What is the total energy transferred into thermal energy when the object travels distance ?
A. mgh
B. mgx
C. μmgh
D. μmgx
-
19M.1A.SL.TZ1.6:
An object of mass m is sliding down a ramp at constant speed. During the motion it travels a distance along the ramp and falls through a vertical distance h. The coefficient of dynamic friction between the ramp and the object is μ. What is the total energy transferred into thermal energy when the object travels distance ?
A. mgh
B. mgx
C. μmgh
D. μmgx
-
19M.1A.SL.TZ2.5:
An object has a weight of 6.10 × 102 N. What is the change in gravitational potential energy of the object when it moves through 8.0 m vertically?
A. 5 kJ
B. 4.9 kJ
C. 4.88 kJ
D. 4.880 kJ
-
19M.1A.SL.TZ2.5:
An object has a weight of 6.10 × 102 N. What is the change in gravitational potential energy of the object when it moves through 8.0 m vertically?
A. 5 kJ
B. 4.9 kJ
C. 4.88 kJ
D. 4.880 kJ
- 19M.1A.SL.TZ2.6: A boat with an output engine power of 15 kW moves through water at a speed of 10 m s-1. What is...
- 19M.1A.SL.TZ2.6: A boat with an output engine power of 15 kW moves through water at a speed of 10 m s-1. What is...
- 19M.1A.SL.TZ2.7: An astronaut is moving at a constant velocity in the absence of a gravitational field when he...
- 19M.1A.SL.TZ2.7: An astronaut is moving at a constant velocity in the absence of a gravitational field when he...
-
19M.2.SL.TZ1.5a.ii:
Outline why this force does no work on Phobos.
-
19M.2.SL.TZ1.5a.ii:
Outline why this force does no work on Phobos.
-
19M.2.SL.TZ1.a.ii:
Outline why this force does no work on Phobos.
-
19M.2.SL.TZ2.1aii:
Calculate the average power delivered to the ball during the impact.
-
19M.2.SL.TZ2.1aii:
Calculate the average power delivered to the ball during the impact.
-
19M.2.SL.TZ2.aii:
Calculate the average power delivered to the ball during the impact.
-
19M.2.SL.TZ2.1biii:
Determine the speed of the tennis ball as it strikes the ground.
-
19M.2.SL.TZ2.1biii:
Determine the speed of the tennis ball as it strikes the ground.
-
19M.2.SL.TZ2.biii:
Determine the speed of the tennis ball as it strikes the ground.
- 19M.2.SL.TZ1.5b: Show that the collision is inelastic.
- 19M.2.SL.TZ1.5b: Show that the collision is inelastic.
- 19M.2.SL.TZ1.b: Show that the collision is inelastic.
- 19M.2.SL.TZ1.5c: Describe the changes in gravitational potential energy of the oscillating system from t = 0 as it...
- 19M.2.SL.TZ1.5c: Describe the changes in gravitational potential energy of the oscillating system from t = 0 as it...
- 19M.2.SL.TZ1.c: Describe the changes in gravitational potential energy of the oscillating system from t = 0 as it...
-
19M.2.SL.TZ1.6c.ii:
Outline why this force does no work on the Moon.
-
19M.2.SL.TZ1.6c.ii:
Outline why this force does no work on the Moon.
-
19M.2.SL.TZ1.c.ii:
Outline why this force does no work on the Moon.
-
19M.2.SL.TZ2.1aii:
Calculate the average power delivered to the ball during the impact.
-
19M.2.SL.TZ2.1aii:
Calculate the average power delivered to the ball during the impact.
-
19M.2.SL.TZ2.aii:
Calculate the average power delivered to the ball during the impact.
-
19M.2.SL.TZ2.1biii:
Determine the speed of the tennis ball as it strikes the ground.
-
19M.2.SL.TZ2.1biii:
Determine the speed of the tennis ball as it strikes the ground.
-
19M.2.SL.TZ2.biii:
Determine the speed of the tennis ball as it strikes the ground.
-
19M.2.SL.TZ2.2b:
Estimate the average speed of the helium atoms in the container.
-
19M.2.SL.TZ2.2b:
Estimate the average speed of the helium atoms in the container.
-
19M.2.SL.TZ2.b:
Estimate the average speed of the helium atoms in the container.
- 19N.1A.SL.TZ0.6: A nuclear particle has an energy of 108 eV. A grain of sand has a mass of 32 mg. What speed must...
- 19N.1A.SL.TZ0.6: A nuclear particle has an energy of 108 eV. A grain of sand has a mass of 32 mg. What speed must...
-
19N.1A.SL.TZ0.22:
An object of mass m makes n revolutions per second around a circle of radius r at a constant speed. What is the kinetic energy of the object?
A. 0
B.
C.
D.
-
19N.1A.SL.TZ0.22:
An object of mass m makes n revolutions per second around a circle of radius r at a constant speed. What is the kinetic energy of the object?
A. 0
B.
C.
D.
- 19N.1A.SL.TZ0.7: A ball is thrown vertically upwards. Air resistance is negligible. What is the variation with...
- 19N.1A.SL.TZ0.7: A ball is thrown vertically upwards. Air resistance is negligible. What is the variation with...
-
19N.1A.SL.TZ0.8:
The tension in a horizontal spring is directly proportional to the extension of the spring. The energy stored in the spring at extension is . What is the work done by the spring when its extension changes from to ?
A.
B.
C.
D.
-
19N.1A.SL.TZ0.8:
The tension in a horizontal spring is directly proportional to the extension of the spring. The energy stored in the spring at extension is . What is the work done by the spring when its extension changes from to ?
A.
B.
C.
D.
-
19N.2.SL.TZ0.1c:
Determine, with reference to the work done by the average force, the horizontal distance travelled by the ball while it was in contact with the racket.
-
19N.2.SL.TZ0.1c:
Determine, with reference to the work done by the average force, the horizontal distance travelled by the ball while it was in contact with the racket.
-
19N.2.SL.TZ0.c:
Determine, with reference to the work done by the average force, the horizontal distance travelled by the ball while it was in contact with the racket.
-
19N.2.SL.TZ0.4c:
Explain why the kinetic energy of the proton is constant.
-
19N.2.SL.TZ0.4c:
Explain why the kinetic energy of the proton is constant.
-
19N.2.SL.TZ0.c:
Explain why the kinetic energy of the proton is constant.
-
19N.2.SL.TZ0.7b(ii):
Calculate the ratio .
-
19N.2.SL.TZ0.7b(ii):
Calculate the ratio .
-
19N.2.SL.TZ0.b(ii):
Calculate the ratio .
- 20N.1A.SL.TZ0.5: A car is driven from rest along a straight horizontal road. The car engine exerts a constant...
- 20N.1A.SL.TZ0.5: A car is driven from rest along a straight horizontal road. The car engine exerts a constant...
-
20N.1A.SL.TZ0.13:
A bicycle of mass comes to rest from speed using the back brake. The brake has a specific heat capacity of and a mass . Half of the kinetic energy is absorbed by the brake.
What is the change in temperature of the brake?
A.
B.
C.
D.
-
20N.1A.SL.TZ0.13:
A bicycle of mass comes to rest from speed using the back brake. The brake has a specific heat capacity of and a mass . Half of the kinetic energy is absorbed by the brake.
What is the change in temperature of the brake?
A.
B.
C.
D.
-
20N.1A.SL.TZ0.19:
An electric motor raises an object of weight through a vertical distance of in . The current in the electric motor is at a potential difference of . What is the efficiency of the electric motor?
A.
B.
C.
D.
-
20N.1A.SL.TZ0.19:
An electric motor raises an object of weight through a vertical distance of in . The current in the electric motor is at a potential difference of . What is the efficiency of the electric motor?
A.
B.
C.
D.
-
20N.1A.SL.TZ0.3:
An object of mass moving at velocity collides with a stationary object of mass . The objects stick together after the collision. What is the final speed and the change in total kinetic energy immediately after the collision?
-
20N.1A.SL.TZ0.3:
An object of mass moving at velocity collides with a stationary object of mass . The objects stick together after the collision. What is the final speed and the change in total kinetic energy immediately after the collision?
-
20N.1A.SL.TZ0.4:
An object of mass is thrown downwards from a height of . The initial speed of the object is .
The object hits the ground at a speed of . Assume . What is the best estimate of the energy transferred from the object to the air as it falls?A.
B.
C.
D.
-
20N.1A.SL.TZ0.4:
An object of mass is thrown downwards from a height of . The initial speed of the object is .
The object hits the ground at a speed of . Assume . What is the best estimate of the energy transferred from the object to the air as it falls?A.
B.
C.
D.
-
20N.2.SL.TZ0.1a(iv):
Calculate the power transferred to the air by the aircraft.
-
20N.2.SL.TZ0.1a(iv):
Calculate the power transferred to the air by the aircraft.
-
20N.2.SL.TZ0.a(iv):
Calculate the power transferred to the air by the aircraft.
-
21M.1A.SL.TZ1.5:
A mass is released from the top of a smooth ramp of height . After leaving the ramp, the mass slides on a rough horizontal surface.
The mass comes to rest in a distance d. What is the coefficient of dynamic friction between the mass and the horizontal surface?
-
21M.1A.SL.TZ1.5:
A mass is released from the top of a smooth ramp of height . After leaving the ramp, the mass slides on a rough horizontal surface.
The mass comes to rest in a distance d. What is the coefficient of dynamic friction between the mass and the horizontal surface?
- 21M.1A.SL.TZ1.6: Masses X and Y rest on a smooth horizontal surface and are connected by a massless spring. The...
- 21M.1A.SL.TZ1.6: Masses X and Y rest on a smooth horizontal surface and are connected by a massless spring. The...
- 21M.1A.SL.TZ1.5: A car takes 20 minutes to climb a hill at constant speed. The mass of the car is 1200 kg and the...
- 21M.1A.SL.TZ1.5: A car takes 20 minutes to climb a hill at constant speed. The mass of the car is 1200 kg and the...
- 21M.1A.SL.TZ1.9: An electron has a linear momentum of 4.0 × 10−25 kg m s−1. What is the order of magnitude of the...
- 21M.1A.SL.TZ1.9: An electron has a linear momentum of 4.0 × 10−25 kg m s−1. What is the order of magnitude of the...
- 21M.1A.SL.TZ2.8: A projectile is launched upwards at an angle θ to the horizontal with an initial momentum p0 and...
- 21M.1A.SL.TZ2.8: A projectile is launched upwards at an angle θ to the horizontal with an initial momentum p0 and...
-
21M.1A.SL.TZ2.9:
The graph shows the variation with distance of a horizontal force acting on an object. The object, initially at rest, moves horizontally through a distance of .
A constant frictional force of opposes the motion. What is the final kinetic energy of the object after it has moved ?
A.
B.
C.
D.
-
21M.1A.SL.TZ2.9:
The graph shows the variation with distance of a horizontal force acting on an object. The object, initially at rest, moves horizontally through a distance of .
A constant frictional force of opposes the motion. What is the final kinetic energy of the object after it has moved ?
A.
B.
C.
D.
-
21M.2.SL.TZ1.1d.i:
Determine the kinetic energy of the ball immediately after the bounce.
-
21M.2.SL.TZ1.1d.i:
Determine the kinetic energy of the ball immediately after the bounce.
-
21M.2.SL.TZ1.d.i:
Determine the kinetic energy of the ball immediately after the bounce.
-
21M.2.SL.TZ2.6c:
The maximum intensity of sunlight incident on the photovoltaic cell at the place on the Earth’s surface is 680 W m−2.
A measure of the efficiency of a photovoltaic cell is the ratio
Determine the efficiency of this photovoltaic cell when the intensity incident upon it is at a maximum.
-
21M.2.SL.TZ2.6c:
The maximum intensity of sunlight incident on the photovoltaic cell at the place on the Earth’s surface is 680 W m−2.
A measure of the efficiency of a photovoltaic cell is the ratio
Determine the efficiency of this photovoltaic cell when the intensity incident upon it is at a maximum.
-
21M.2.SL.TZ2.c:
The maximum intensity of sunlight incident on the photovoltaic cell at the place on the Earth’s surface is 680 W m−2.
A measure of the efficiency of a photovoltaic cell is the ratio
Determine the efficiency of this photovoltaic cell when the intensity incident upon it is at a maximum.
- 21N.1A.SL.TZ0.5: A cyclist rides up a hill of vertical height 100 m in 500 s at a constant speed. The combined...
- 21N.1A.SL.TZ0.5: A cyclist rides up a hill of vertical height 100 m in 500 s at a constant speed. The combined...
- 21N.1A.SL.TZ0.6: A block rests on a frictionless horizontal surface. An air rifle pellet is fired horizontally...
- 21N.1A.SL.TZ0.6: A block rests on a frictionless horizontal surface. An air rifle pellet is fired horizontally...
-
21N.1A.SL.TZ0.28:
A fuel has mass density and energy density . What mass of the fuel has to be burned to release thermal energy ?
A.
B.
C.
D.
-
21N.1A.SL.TZ0.28:
A fuel has mass density and energy density . What mass of the fuel has to be burned to release thermal energy ?
A.
B.
C.
D.
- 21N.1A.SL.TZ0.29: The Sankey diagram shows the energy transfers in a nuclear power station. Electrical power...
- 21N.1A.SL.TZ0.29: The Sankey diagram shows the energy transfers in a nuclear power station. Electrical power...
- 21N.1A.SL.TZ0.7: An object of mass 1.0 kg hangs at rest from a spring. The spring has a negligible mass and the...
- 21N.1A.SL.TZ0.7: An object of mass 1.0 kg hangs at rest from a spring. The spring has a negligible mass and the...
-
21N.2.SL.TZ0.5d.i:
Show that the energy dissipated in the loop from t = 0 to t = 3.5 s is 0.13 J.
-
21N.2.SL.TZ0.5d.i:
Show that the energy dissipated in the loop from t = 0 to t = 3.5 s is 0.13 J.
-
21N.2.SL.TZ0.d.i:
Show that the energy dissipated in the loop from t = 0 to t = 3.5 s is 0.13 J.
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22M.1A.SL.TZ1.8:
A cart travels from rest along a horizontal surface with a constant acceleration. What is the variation of the kinetic energy Ek of the cart with its distance s travelled? Air resistance is negligible.
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22M.1A.SL.TZ1.8:
A cart travels from rest along a horizontal surface with a constant acceleration. What is the variation of the kinetic energy Ek of the cart with its distance s travelled? Air resistance is negligible.
- 22M.1A.SL.TZ2.30: The Sankey diagrams for a filament lamp and for an LED bulb are shown below. What is the...
- 22M.1A.SL.TZ2.30: The Sankey diagrams for a filament lamp and for an LED bulb are shown below. What is the...
- 23M.1A.SL.TZ1.2: The kinetic energy of a body is determined from measurements of its momentum p and its mass...
- 23M.1A.SL.TZ1.2: The kinetic energy of a body is determined from measurements of its momentum p and its mass...
- 23M.1A.HL.TZ1.33: Which law is equivalent to the law of conservation of energy? A. Coulomb’s law B. Ohm’s Law C. ...
- 23M.1A.HL.TZ1.33: Which law is equivalent to the law of conservation of energy? A. Coulomb’s law B. Ohm’s Law C. ...
- 23M.1A.HL.TZ1.33: Which law is equivalent to the law of conservation of energy? A. Coulomb’s law B. Ohm’s Law C. ...
- 23M.1A.HL.TZ1.33: Which law is equivalent to the law of conservation of energy? A. Coulomb’s law B. Ohm’s Law C. ...
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23M.1A.SL.TZ1.4:
A stone of mass m is projected vertically upwards with speed u from the top of a cliff. The speed of the stone when it is just about to hit the ground is v.
What is the magnitude of the change in momentum of the stone?
A.B.
C.
D.
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23M.1A.SL.TZ1.4:
A stone of mass m is projected vertically upwards with speed u from the top of a cliff. The speed of the stone when it is just about to hit the ground is v.
What is the magnitude of the change in momentum of the stone?
A.B.
C.
D.
-
23M.1A.SL.TZ1.4:
A stone of mass m is projected vertically upwards with speed u from the top of a cliff. The speed of the stone when it is just about to hit the ground is v.
What is the magnitude of the change in momentum of the stone?
A.B.
C.
D.
-
23M.1A.SL.TZ1.4:
A stone of mass m is projected vertically upwards with speed u from the top of a cliff. The speed of the stone when it is just about to hit the ground is v.
What is the magnitude of the change in momentum of the stone?
A.B.
C.
D.
- 23M.1A.SL.TZ1.9: The input power of an electric motor is 200 W. It is used to raise a mass of 10 kg at constant...
- 23M.1A.SL.TZ1.8: The input power of an electric motor is 200 W. It is used to raise a mass of 10 kg at constant...
- 23M.1A.SL.TZ1.9: The input power of an electric motor is 200 W. It is used to raise a mass of 10 kg at constant...
- 23M.1A.SL.TZ1.8: The input power of an electric motor is 200 W. It is used to raise a mass of 10 kg at constant...
- 23M.1A.SL.TZ1.9: The input power of an electric motor is 200 W. It is used to raise a mass of 10 kg at constant...
- 23M.1A.SL.TZ1.8: The input power of an electric motor is 200 W. It is used to raise a mass of 10 kg at constant...
- 23M.1A.SL.TZ1.9: The input power of an electric motor is 200 W. It is used to raise a mass of 10 kg at constant...
- 23M.1A.SL.TZ1.8: The input power of an electric motor is 200 W. It is used to raise a mass of 10 kg at constant...
-
23M.1A.SL.TZ2.6:
A spring of negligible mass is compressed and placed between two stationary masses m and M. The mass of M is twice that of m. The spring is released so that the masses move in opposite directions.
What is ?
A.B. 1
C. 2
D. 4
-
23M.1A.SL.TZ2.6:
A spring of negligible mass is compressed and placed between two stationary masses m and M. The mass of M is twice that of m. The spring is released so that the masses move in opposite directions.
What is ?
A.B. 1
C. 2
D. 4
-
23M.1A.SL.TZ2.6:
A spring of negligible mass is compressed and placed between two stationary masses m and M. The mass of M is twice that of m. The spring is released so that the masses move in opposite directions.
What is ?
A.B. 1
C. 2
D. 4
-
23M.1A.SL.TZ2.6:
A spring of negligible mass is compressed and placed between two stationary masses m and M. The mass of M is twice that of m. The spring is released so that the masses move in opposite directions.
What is ?
A.B. 1
C. 2
D. 4
- 23M.1A.SL.TZ2.7: An object of mass M is accelerated vertically upwards by a motor at a constant acceleration.The...
- 23M.1A.SL.TZ2.7: An object of mass M is accelerated vertically upwards by a motor at a constant acceleration.The...
- 23M.1A.SL.TZ2.7: An object of mass M is accelerated vertically upwards by a motor at a constant acceleration.The...
- 23M.1A.SL.TZ2.7: An object of mass M is accelerated vertically upwards by a motor at a constant acceleration.The...
-
23M.1A.SL.TZ2.8:
An object is released from rest at X and slides to Y. The vertical distance between X and Y is 10 m. During the motion, 20 % of the object’s initial gravitational potential energy is lost as friction.
What is the speed of the object at Y?
A.B.
C.
D.
-
23M.1A.SL.TZ2.8:
An object is released from rest at X and slides to Y. The vertical distance between X and Y is 10 m. During the motion, 20 % of the object’s initial gravitational potential energy is lost as friction.
What is the speed of the object at Y?
A.B.
C.
D.
-
23M.1A.SL.TZ2.8:
An object is released from rest at X and slides to Y. The vertical distance between X and Y is 10 m. During the motion, 20 % of the object’s initial gravitational potential energy is lost as friction.
What is the speed of the object at Y?
A.B.
C.
D.
-
23M.1A.SL.TZ2.8:
An object is released from rest at X and slides to Y. The vertical distance between X and Y is 10 m. During the motion, 20 % of the object’s initial gravitational potential energy is lost as friction.
What is the speed of the object at Y?
A.B.
C.
D.
-
23M.1A.SL.TZ2.8:
An object is released from rest at X and slides to Y. The vertical distance between X and Y is 10 m. During the motion, 20 % of the object’s initial gravitational potential energy is lost as friction.
What is the speed of the object at Y?
A.B.
C.
D.
-
23M.1A.SL.TZ2.8:
An object is released from rest at X and slides to Y. The vertical distance between X and Y is 10 m. During the motion, 20 % of the object’s initial gravitational potential energy is lost as friction.
What is the speed of the object at Y?
A.B.
C.
D.
-
23M.1A.SL.TZ2.8:
An object is released from rest at X and slides to Y. The vertical distance between X and Y is 10 m. During the motion, 20 % of the object’s initial gravitational potential energy is lost as friction.
What is the speed of the object at Y?
A.B.
C.
D.
-
23M.1A.SL.TZ2.8:
An object is released from rest at X and slides to Y. The vertical distance between X and Y is 10 m. During the motion, 20 % of the object’s initial gravitational potential energy is lost as friction.
What is the speed of the object at Y?
A.B.
C.
D.
- 23M.1A.SL.TZ1.10: A tennis ball is dropped from rest from a height. It hits the ground and bounces back to a lower...
- 23M.1A.SL.TZ1.10: A tennis ball is dropped from rest from a height. It hits the ground and bounces back to a lower...
- 23M.1A.SL.TZ1.6: A ball falls with terminal velocity through air. What is correct about the kinetic energy and the...
- 23M.1A.SL.TZ1.6: A ball falls with terminal velocity through air. What is correct about the kinetic energy and the...
- 23M.1A.SL.TZ1.6: A ball falls with terminal velocity through air. What is correct about the kinetic energy and the...
- 23M.1A.SL.TZ1.6: A ball falls with terminal velocity through air. What is correct about the kinetic energy and the...
- 23M.1A.SL.TZ2.25: A car engine has a useful power output of 20 kW and an efficiency of 50 %. The engine consumes 1...
- 23M.1A.SL.TZ2.25: A car engine has a useful power output of 20 kW and an efficiency of 50 %. The engine consumes 1...
- 23M.1A.SL.TZ2.25: A car engine has a useful power output of 20 kW and an efficiency of 50 %. The engine consumes 1...
- 23M.1A.SL.TZ2.25: A car engine has a useful power output of 20 kW and an efficiency of 50 %. The engine consumes 1...
- 23M.1A.SL.TZ2.7: An object of mass M is accelerated vertically upwards by a motor at a constant acceleration.The...
- 23M.1A.SL.TZ2.7: An object of mass M is accelerated vertically upwards by a motor at a constant acceleration.The...
- 23M.1A.SL.TZ2.7: An object of mass M is accelerated vertically upwards by a motor at a constant acceleration.The...
- 23M.1A.SL.TZ2.7: An object of mass M is accelerated vertically upwards by a motor at a constant acceleration.The...
-
23M.2.SL.TZ1.1aii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.1aii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.1aii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.ii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.1aii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.ii:
show that the speed of the ball is about 4.3 m s−1.
-
23M.2.SL.TZ1.1bii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.1bii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.1bii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.ii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.1bii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ1.ii:
Calculate the maximum height risen by the centre of the ball.
-
23M.2.SL.TZ2.1ci:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.1ci:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.i:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.1ci:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.1ci:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.i:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.1ci:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.1ci:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ2.i:
Calculate the fraction of the kinetic energy of the bottle that remains after the bounce.
-
23M.2.SL.TZ1.8c:
Calculate the energy lost during the collision.
-
23M.2.SL.TZ1.6c:
Calculate the energy lost during the collision.
-
23M.2.SL.TZ1.c:
Calculate the energy lost during the collision.
-
23M.2.SL.TZ1.c:
Calculate the energy lost during the collision.