DP Physics (first assessment 2025)

Test builder »

Question 23M.2.SL.TZ1.1bii

Select a Test
Date May 2023 Marks available [Maximum mark: 2] Reference code 23M.2.SL.TZ1.1bii
Level SL Paper 2 Time zone TZ1
Command term Calculate Question number ii Adapted from N/A
ii.
[Maximum mark: 2]
23M.2.SL.TZ1.1bii
(ii)

Calculate the maximum height risen by the centre of the ball.

[2]

Markscheme

ALTERNATIVE 1
Rebound speed is halved so energy less by a factor of 4 ✓
Hence height is 954 =23.8 «cm» ✓

ALTERNATIVE 2
Use of conservation of energy / 12 × 0.800 × 2.162 = 0.800 × 9.8 × h
OR

Use of proper kinematics equation (e.g. 0 = 2.162 − 2 × 9.8 × h) ✓

h = 23.8 «cm» ✓


Allow ECF from b(i)

Syllabus sections