DP Physics (first assessment 2025)

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Question EXE.2.SL.TZ0.c

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Date Example questions Example questions Marks available [Maximum mark: 4] Reference code EXE.2.SL.TZ0.c
Level SL Paper 2 Time zone TZ0
Command term Estimate Question number c Adapted from N/A
c.
[Maximum mark: 4]
EXE.2.SL.TZ0.c

The total friction in the system acting on the tram is equivalent to an opposing force of 750 N.

For one particular journey, the tram is full of passengers.

Estimate the maximum speed v of the tram as it leaves the lower station.

[4]

Markscheme

Total weight of tram = 75 × 710 + 5 × 104 = 1.03 × 105 N ✓

Total force down track = 750 + 1.03 × 105 sin (10) = 1.87 × 104 N ✓

Use of P= F × v ✓

(v = 247 000 ÷ 1.87 × 104)= 13 m s−1 ✓

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