DP Physics (first assessment 2025)
Question EXE.2.SL.TZ0.c
Date | Example questions Example questions | Marks available | [Maximum mark: 4] | Reference code | EXE.2.SL.TZ0.c |
Level | SL | Paper | 2 | Time zone | TZ0 |
Command term | Estimate | Question number | c | Adapted from | N/A |
c.
[Maximum mark: 4]
EXE.2.SL.TZ0.c
The total friction in the system acting on the tram is equivalent to an opposing force of 750 N.
For one particular journey, the tram is full of passengers.
Estimate the maximum speed v of the tram as it leaves the lower station.
[4]
Markscheme
Total weight of tram = 75 × 710 + 5 × 104 = 1.03 × 105 N ✓
Total force down track = 750 + 1.03 × 105 sin (10) = 1.87 × 104 N ✓
Use of P= F × v ✓
(v = 247 000 ÷ 1.87 × 104)= 13 m s−1 ✓

