DP Physics (first assessment 2025)

Question 23M.2.SL.TZ1.1bi

Date	May 2023	Marks available	[Maximum mark: 4]	Reference code	23M.2.SL.TZ1.1bi
Level	SL	Paper	2	Time zone	TZ1
Command term	Show	Question number	i	Adapted from	N/A

[Maximum mark: 4]

23M.2.SL.TZ1.1bi

(i)

Show that the collision is elastic.

[4]

Markscheme

Use of conservation of momentum. ✓
Rebound speed = 2.16 «m s⁻¹» ✓
Calculation of initial KE = « $\frac{1}{2}$ × 0.800 × 4.317²» = 7.46 « J » ✓
Calculation of final KE = « $\frac{1}{2}$ × 0.800 × 2.16²+ $\frac{1}{2}$ × 2.40 × 2.16²» = 7.46 «J» ✓
«hence elastic»

Syllabus sections

A. Space, time and motion » A.2 Forces and momentum

A. Space, time and motion » A.3 Work, energy and power

Question 23M.2.SL.TZ1.1bi

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