Directly related questions
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22N.2.SL.TZ0.2a.ii:
Estimate, in °C, the temperature of the roof tiles.
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22N.2.SL.TZ0.2a.ii:
Estimate, in °C, the temperature of the roof tiles.
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22N.2.SL.TZ0.a.ii:
Estimate, in °C, the temperature of the roof tiles.
- 19M.2.SL.TZ2.7a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.SL.TZ2.7a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.SL.TZ2.a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.SL.TZ2.7b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.SL.TZ2.7b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.SL.TZ2.b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.SL.TZ2.7ci: Calculate the additional intensity that must be lost by the oceans so that the water temperature...
- 19M.2.SL.TZ2.7ci: Calculate the additional intensity that must be lost by the oceans so that the water temperature...
- 19M.2.SL.TZ2.ci: Calculate the additional intensity that must be lost by the oceans so that the water temperature...
- 19M.2.SL.TZ2.7cii: Suggest a mechanism by which the additional intensity can be lost.
- 19M.2.SL.TZ2.7cii: Suggest a mechanism by which the additional intensity can be lost.
- 19M.2.SL.TZ2.cii: Suggest a mechanism by which the additional intensity can be lost.
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19M.2.SL.TZ1.6a.i:
A black body is on the Moon’s surface at point A. Show that the maximum temperature that this body can reach is 400 K. Assume that the Earth and the Moon are the same distance from the Sun.
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19M.2.SL.TZ1.6a.i:
A black body is on the Moon’s surface at point A. Show that the maximum temperature that this body can reach is 400 K. Assume that the Earth and the Moon are the same distance from the Sun.
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19M.2.SL.TZ1.a.i:
A black body is on the Moon’s surface at point A. Show that the maximum temperature that this body can reach is 400 K. Assume that the Earth and the Moon are the same distance from the Sun.
- 19M.2.SL.TZ1.6a.ii: Another black body is on the Moon’s surface at point B. Outline, without calculation, why the...
- 19M.2.SL.TZ1.6a.ii: Another black body is on the Moon’s surface at point B. Outline, without calculation, why the...
- 19M.2.SL.TZ1.a.ii: Another black body is on the Moon’s surface at point B. Outline, without calculation, why the...
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19M.2.SL.TZ1.6b:
The albedo of the Earth’s atmosphere is 0.28. Outline why the maximum temperature of a black body on the Earth when the Sun is overhead is less than that at point A on the Moon.
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19M.2.SL.TZ1.6b:
The albedo of the Earth’s atmosphere is 0.28. Outline why the maximum temperature of a black body on the Earth when the Sun is overhead is less than that at point A on the Moon.
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19M.2.SL.TZ1.b:
The albedo of the Earth’s atmosphere is 0.28. Outline why the maximum temperature of a black body on the Earth when the Sun is overhead is less than that at point A on the Moon.
- 19M.2.SL.TZ2.7a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.SL.TZ2.7a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.SL.TZ2.a: Show that the intensity radiated by the oceans is about 400 W m-2.
- 19M.2.SL.TZ2.7b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.SL.TZ2.7b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19M.2.SL.TZ2.b: Explain why some of this radiation is returned to the oceans from the atmosphere.
- 19N.1A.SL.TZ0.30: What is meant by the statement that the average albedo of the Moon is 0.1? A. 10% of the...
- 19N.1A.SL.TZ0.30: What is meant by the statement that the average albedo of the Moon is 0.1? A. 10% of the...
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20N.1A.SL.TZ0.26:
The average temperature of the surface of a planet is five times greater than the average temperature of the surface of its moon. The emissivities of the planet and the moon are the same. The average intensity radiated by the planet is . What is the average intensity radiated by its moon?
A.
B.
C.
D.
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20N.1A.SL.TZ0.26:
The average temperature of the surface of a planet is five times greater than the average temperature of the surface of its moon. The emissivities of the planet and the moon are the same. The average intensity radiated by the planet is . What is the average intensity radiated by its moon?
A.
B.
C.
D.
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21M.1A.SL.TZ1.29:
A black body at temperature T emits radiation with peak wavelength and power P. What is the temperature of the black body and the power emitted for a peak wavelength of ?
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21M.1A.SL.TZ1.29:
A black body at temperature T emits radiation with peak wavelength and power P. What is the temperature of the black body and the power emitted for a peak wavelength of ?
- 21M.1A.SL.TZ1.30: In a simple climate model for a planet, the incoming intensity is 400 W m−2 and the...
- 21M.1A.SL.TZ1.30: In a simple climate model for a planet, the incoming intensity is 400 W m−2 and the...
- 21M.1A.SL.TZ2.30: What is the main role of carbon dioxide in the greenhouse effect? A. It absorbs incoming...
- 21M.1A.SL.TZ2.30: What is the main role of carbon dioxide in the greenhouse effect? A. It absorbs incoming...
- 21N.1A.SL.TZ0.25: The diagram shows a simple model of the energy balance in the Earth surface-atmosphere system....
- 21N.1A.SL.TZ0.25: The diagram shows a simple model of the energy balance in the Earth surface-atmosphere system....
- 21N.1A.SL.TZ0.30: Which is correct for a black-body radiator? A. The power it emits from a unit surface area...
- 21N.1A.SL.TZ0.30: Which is correct for a black-body radiator? A. The power it emits from a unit surface area...
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21N.2.SL.TZ0.6a.i:
Show that the intensity of the solar radiation at the location of Titan is 16 W m−2
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21N.2.SL.TZ0.6a.i:
Show that the intensity of the solar radiation at the location of Titan is 16 W m−2
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21N.2.SL.TZ0.a.i:
Show that the intensity of the solar radiation at the location of Titan is 16 W m−2
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21N.2.SL.TZ0.6a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2
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21N.2.SL.TZ0.6a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2
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21N.2.SL.TZ0.a.ii:
Titan has an atmosphere of nitrogen. The albedo of the atmosphere is 0.22. The surface of Titan may be assumed to be a black body. Explain why the average intensity of solar radiation absorbed by the whole surface of Titan is 3.1 W m−2
- 21N.2.SL.TZ0.6a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
- 21N.2.SL.TZ0.6a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
- 21N.2.SL.TZ0.a.iii: Show that the equilibrium surface temperature of Titan is about 90 K.
- 22M.1A.SL.TZ1.29: Three mechanisms that affect the composition of the atmosphere of the Earth are: I. Loss of...
- 22M.1A.SL.TZ1.29: Three mechanisms that affect the composition of the atmosphere of the Earth are: I. Loss of...
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22M.1A.SL.TZ1.30:
The diagram shows, for a region on the Earth’s surface, the incident, radiated and reflected intensities of the solar radiation.
What is the albedo of the region?
A.
B.
C.
D.
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22M.1A.SL.TZ1.30:
The diagram shows, for a region on the Earth’s surface, the incident, radiated and reflected intensities of the solar radiation.
What is the albedo of the region?
A.
B.
C.
D.
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22M.2.SL.TZ1.2d.ii:
The missing section of insulation is 0.56 m long and the external radius of the pipe is 0.067 m. The emissivity of the pipe surface is 0.40. Determine the energy lost every second from the pipe surface. Ignore any absorption of radiation by the pipe surface.
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22M.2.SL.TZ1.2d.ii:
The missing section of insulation is 0.56 m long and the external radius of the pipe is 0.067 m. The emissivity of the pipe surface is 0.40. Determine the energy lost every second from the pipe surface. Ignore any absorption of radiation by the pipe surface.
-
22M.2.SL.TZ1.d.ii:
The missing section of insulation is 0.56 m long and the external radius of the pipe is 0.067 m. The emissivity of the pipe surface is 0.40. Determine the energy lost every second from the pipe surface. Ignore any absorption of radiation by the pipe surface.
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23M.1A.SL.TZ1.29:
Two surfaces X and Y emit radiation of the same surface intensity. X emits a radiation of peak wavelength twice that of Y.
What is ?
A.B.
C. 2
D. 16
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23M.1A.SL.TZ1.25:
Two surfaces X and Y emit radiation of the same surface intensity. X emits a radiation of peak wavelength twice that of Y.
What is ?
A.B.
C. 2
D. 16
-
23M.1A.SL.TZ1.29:
Two surfaces X and Y emit radiation of the same surface intensity. X emits a radiation of peak wavelength twice that of Y.
What is ?
A.B.
C. 2
D. 16
-
23M.1A.SL.TZ1.25:
Two surfaces X and Y emit radiation of the same surface intensity. X emits a radiation of peak wavelength twice that of Y.
What is ?
A.B.
C. 2
D. 16
-
23M.1A.SL.TZ1.29:
Two surfaces X and Y emit radiation of the same surface intensity. X emits a radiation of peak wavelength twice that of Y.
What is ?
A.B.
C. 2
D. 16
-
23M.1A.SL.TZ1.25:
Two surfaces X and Y emit radiation of the same surface intensity. X emits a radiation of peak wavelength twice that of Y.
What is ?
A.B.
C. 2
D. 16
-
23M.1A.SL.TZ1.29:
Two surfaces X and Y emit radiation of the same surface intensity. X emits a radiation of peak wavelength twice that of Y.
What is ?
A.B.
C. 2
D. 16
-
23M.1A.SL.TZ1.25:
Two surfaces X and Y emit radiation of the same surface intensity. X emits a radiation of peak wavelength twice that of Y.
What is ?
A.B.
C. 2
D. 16
- 23M.1A.SL.TZ2.27: A planet has an albedo of 0.30. A simplified energy balance for the planet is shown. What is the...
- 23M.1A.SL.TZ2.27: A planet has an albedo of 0.30. A simplified energy balance for the planet is shown. What is the...
- 23M.1A.SL.TZ2.27: A planet has an albedo of 0.30. A simplified energy balance for the planet is shown. What is the...
- 23M.1A.SL.TZ2.27: A planet has an albedo of 0.30. A simplified energy balance for the planet is shown. What is the...
-
23M.1A.SL.TZ1.30:
Light of intensity 500 W m−2 is incident on concrete and on snow. 300 W m−2 is reflected from the
concrete and 400 W m−2 is reflected from the snow.What is ?
A.B.
C.
D. 2
-
23M.1A.SL.TZ1.30:
Light of intensity 500 W m−2 is incident on concrete and on snow. 300 W m−2 is reflected from the
concrete and 400 W m−2 is reflected from the snow.What is ?
A.B.
C.
D. 2
-
23M.1A.SL.TZ1.30:
Light of intensity 500 W m−2 is incident on concrete and on snow. 300 W m−2 is reflected from the
concrete and 400 W m−2 is reflected from the snow.What is ?
A.B.
C.
D. 2
-
23M.1A.SL.TZ1.30:
Light of intensity 500 W m−2 is incident on concrete and on snow. 300 W m−2 is reflected from the
concrete and 400 W m−2 is reflected from the snow.What is ?
A.B.
C.
D. 2
- 23M.1A.SL.TZ2.30: A planet has an albedo of 0.30. A simplified energy balance for the planet is shown. What is the...
- 23M.1A.SL.TZ2.30: A planet has an albedo of 0.30. A simplified energy balance for the planet is shown. What is the...
- 23M.1A.SL.TZ2.30: A planet has an albedo of 0.30. A simplified energy balance for the planet is shown. What is the...
- 23M.1A.SL.TZ2.30: A planet has an albedo of 0.30. A simplified energy balance for the planet is shown. What is the...