DP Chemistry (last assessment 2024)

Test builder »

Question 19M.3.hl.TZ2.26

Select a Test
Date May 2019 Marks available [Maximum mark: 4] Reference code 19M.3.hl.TZ2.26
Level hl Paper 3 Time zone TZ2
Command term Calculate, Evaluate Question number 26 Adapted from N/A
26.
[Maximum mark: 4]
19M.3.hl.TZ2.26

Technetium-99m, Tc-99m, is a gamma-ray emitter commonly used as a medical tracer.

Its half-life is 6.0 hours.

(a)

Evaluate the suitability of technetium-99m for this use.

[2]

Markscheme

Any two of:
can be readily “tagged” to variety of biologically active carriers «which will deliver it to specific locations for imaging uses»  [✔]

frequency of radiation is compatible with existing X-ray detection apparatus [✔]

product of decay has low radioactivity/relatively short half-life/low total exposure to patient [✔]

«but small» increased risk of cancer to patient [✔]

must be made on site [✔]

 

Note: Accept other valid answers outlining advantages or limitations of Tc-99m, such as “produces only LLW”, “Tc is a transition element forming compounds in a variety of oxidation states”, “gamma-radiation «can escape the body and» be detected by external sensors”, “activity decreases quickly, so dose must be calculated prior to each injection”.

Examiners report

The most frequent response was the short half-life, followed by the emission and detection of gamma radiation.

(b)

Calculate the percentage of technetium-99m remaining after 10.0 hours. Use section 1 of the data booklet.

[2]

Markscheme

ALTERNATIVE 1

N ( t ) N 0 = ( 1 2 ) 10 6.0   [✔]
31 «% remaining» [✔]

 

ALTERNATIVE 2

λ « ln 2 t 1 2 »= 0.1155 hours–1 []

« N N 0  × 100 = eλt ×100 = 0.31498 × 100»

31 «% remaining» [✔]

 

NoteM1 is for correct substitution of values.

Award [2] for correct final answer.

 

Examiners report

Most candidates were able to calculate the percentage of technetium-99m correctly.