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Question 20N.2.hl.TZ0.1d(iii)

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Date November 2020 Marks available [Maximum mark: 3] Reference code 20N.2.hl.TZ0.1d(iii)
Level hl Paper 2 Time zone TZ0
Command term Explain Question number d(iii) Adapted from N/A
d(iii).
[Maximum mark: 3]
20N.2.hl.TZ0.1d(iii)

Chlorine undergoes many reactions.

(d(iii))

Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, NaOH(aq), using curly arrows to represent the movement of electron pairs.

[3]

Markscheme

curly arrow going from lone pair/negative charge on O in OH to C

curly arrow showing Cl leaving ✔

representation of transition state showing negative charge, square brackets and partial bonds ✔

 

Accept OH- with or without the lone pair.

Do not accept curly arrows originating on H in OH-.

Accept curly arrows in the transition state.

Do not penalize if HO and Cl are not at 180°.

Do not award M3 if OH-C bond is represented. 

Examiners report

Few earned full marks for the curly arrow mechanism of the reaction between sodium hydroxide and chloroethane. Mistakes being careless curly arrow drawing, inappropriate –OH notation, curly arrows from the hydrogen or from the carbon to the C–Cl bond, or a method that missed the transition state.