Directly related questions
-
20N.1.hl.TZ0.36:
What will be the major product in the reaction between but-1-ene and ?
A. 2-bromobut-1-ene
B. 1-bromobut-1-ene
C. 2-bromobutane
D. 1-bromobutane
-
20N.1.hl.TZ0.36:
What will be the major product in the reaction between but-1-ene and ?
A. 2-bromobut-1-ene
B. 1-bromobut-1-ene
C. 2-bromobutane
D. 1-bromobutane
-
20N.1.hl.TZ0.37:
Which molecule has an enantiomer?
A.
B.
C.
D.
-
20N.1.hl.TZ0.37:
Which molecule has an enantiomer?
A.
B.
C.
D.
-
20N.1.hl.TZ0.35:
Which is the electrophile in the nitration of benzene?
A.
B.
C.
D.
-
20N.1.hl.TZ0.35:
Which is the electrophile in the nitration of benzene?
A.
B.
C.
D.
-
20N.2.hl.TZ0.1d(iii):
Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, , using curly arrows to represent the movement of electron pairs.
-
20N.2.hl.TZ0.1d(iii):
Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, , using curly arrows to represent the movement of electron pairs.
-
20N.2.hl.TZ0.d(iii):
Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, , using curly arrows to represent the movement of electron pairs.
-
20N.2.hl.TZ0.2g(i):
Propanone can be synthesized in two steps from propene. Suggest the synthetic route including all the necessary reactants and steps.
-
20N.2.hl.TZ0.g(i):
Propanone can be synthesized in two steps from propene. Suggest the synthetic route including all the necessary reactants and steps.
-
20N.2.hl.TZ0.2g(i):
Propanone can be synthesized in two steps from propene. Suggest the synthetic route including all the necessary reactants and steps.
-
20N.2.hl.TZ0.2g(ii):
Propanone can be synthesized in two steps from propene.
Suggest why propanal is a minor product obtained from the synthetic route in (g)(i).
-
20N.2.hl.TZ0.2g(ii):
Propanone can be synthesized in two steps from propene.
Suggest why propanal is a minor product obtained from the synthetic route in (g)(i).
-
20N.2.hl.TZ0.g(ii):
Propanone can be synthesized in two steps from propene.
Suggest why propanal is a minor product obtained from the synthetic route in (g)(i).
- 17N.2.hl.TZ0.8a.iv: Deduce, giving a reason, which of the two compounds can show optical activity.
- 17N.2.hl.TZ0.8a.iv: Deduce, giving a reason, which of the two compounds can show optical activity.
- 17N.2.hl.TZ0.a.iv: Deduce, giving a reason, which of the two compounds can show optical activity.
- 17N.1.hl.TZ0.33: Propene reacts separately with H2O/H+ and H2/Ni to give products X and Z respectively. What...
- 17N.1.hl.TZ0.33: Propene reacts separately with H2O/H+ and H2/Ni to give products X and Z respectively. What...
- 17N.1.hl.TZ0.35: What is the product of the reaction between pentan-2-one and sodium borohydride, NaBH4? A....
- 17N.1.hl.TZ0.35: What is the product of the reaction between pentan-2-one and sodium borohydride, NaBH4? A....
-
17N.2.hl.TZ0.8e:
Explain the mechanism of the reaction between 2-bromo-2-methylpropane, (CH3)3CBr, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
17N.2.hl.TZ0.8e:
Explain the mechanism of the reaction between 2-bromo-2-methylpropane, (CH3)3CBr, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
17N.2.hl.TZ0.e:
Explain the mechanism of the reaction between 2-bromo-2-methylpropane, (CH3)3CBr, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
- 17N.2.hl.TZ0.8a.v: Draw three-dimensional representations of the two enantiomers.
- 17N.2.hl.TZ0.8a.v: Draw three-dimensional representations of the two enantiomers.
- 17N.2.hl.TZ0.a.v: Draw three-dimensional representations of the two enantiomers.
-
17N.2.hl.TZ0.8c:
State the reagents used in the nitration of benzene.
-
17N.2.hl.TZ0.8c:
State the reagents used in the nitration of benzene.
-
17N.2.hl.TZ0.c:
State the reagents used in the nitration of benzene.
-
17N.2.hl.TZ0.8d:
State an equation for the formation of NO2+.
-
17N.2.hl.TZ0.8d:
State an equation for the formation of NO2+.
-
17N.2.hl.TZ0.d:
State an equation for the formation of NO2+.
- 21M.1.hl.TZ1.36: What is the product of the reaction of benzene with a mixture of concentrated nitric and sulfuric...
- 21M.1.hl.TZ1.36: What is the product of the reaction of benzene with a mixture of concentrated nitric and sulfuric...
-
21M.1.hl.TZ2.36:
Which compound rotates the plane of plane-polarized light?
A. CH3C(CH3)ClCH3
B. CH3CH2CHClCH3
C. CH3C(Cl)2CH3
D. CH3CClBrCH3
-
21M.1.hl.TZ2.36:
Which compound rotates the plane of plane-polarized light?
A. CH3C(CH3)ClCH3
B. CH3CH2CHClCH3
C. CH3C(Cl)2CH3
D. CH3CClBrCH3
-
21M.2.hl.TZ1.5e(i):
Sketch the mechanism for the reaction of propene with hydrogen bromide using curly arrows.
-
21M.2.hl.TZ1.5e(i):
Sketch the mechanism for the reaction of propene with hydrogen bromide using curly arrows.
-
21M.2.hl.TZ1.e(i):
Sketch the mechanism for the reaction of propene with hydrogen bromide using curly arrows.
-
21M.2.hl.TZ1.5e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
-
21M.2.hl.TZ1.5e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
-
21M.2.hl.TZ1.e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
- 21M.2.hl.TZ2.4e: Sketch the mechanism for the reaction of 2-methylbut-2-ene with hydrogen bromide using curly...
- 21M.2.hl.TZ2.4e: Sketch the mechanism for the reaction of 2-methylbut-2-ene with hydrogen bromide using curly...
- 21M.2.hl.TZ2.e: Sketch the mechanism for the reaction of 2-methylbut-2-ene with hydrogen bromide using curly...
- 21M.2.hl.TZ2.4f: Explain why the major organic product is 2-bromo-2-methylbutane and not 2-bromo-3-methylbutane.
- 21M.2.hl.TZ2.4f: Explain why the major organic product is 2-bromo-2-methylbutane and not 2-bromo-3-methylbutane.
- 21M.2.hl.TZ2.f: Explain why the major organic product is 2-bromo-2-methylbutane and not 2-bromo-3-methylbutane.
- 21M.2.hl.TZ2.4h(i): Draw the stereoisomers of butan-2-ol using wedge-dash type representations.
- 21M.2.hl.TZ2.4h(i): Draw the stereoisomers of butan-2-ol using wedge-dash type representations.
- 21M.2.hl.TZ2.h(i): Draw the stereoisomers of butan-2-ol using wedge-dash type representations.
-
18M.1.hl.TZ2.36:
Propene is reacted first with hydrogen chloride to produce X which is then reacted with aqueous sodium hydroxide to give Y. Finally, Y is reacted with excess acidified potassium dichromate solution.
What is the major product, Z?
A. CH3CH(OH)CH3
B. CH3COCH3
C. CH3CH2CHO
D. CH3(CH2)2COOH
-
18M.1.hl.TZ2.36:
Propene is reacted first with hydrogen chloride to produce X which is then reacted with aqueous sodium hydroxide to give Y. Finally, Y is reacted with excess acidified potassium dichromate solution.
What is the major product, Z?
A. CH3CH(OH)CH3
B. CH3COCH3
C. CH3CH2CHO
D. CH3(CH2)2COOH
- 18M.1.hl.TZ2.37: Which isomers exist as non-superimposable mirror images? A. cis-trans isomers B. ...
- 18M.1.hl.TZ2.37: Which isomers exist as non-superimposable mirror images? A. cis-trans isomers B. ...
-
18M.1.hl.TZ1.36:
Which molecule contains a chiral carbon?
A. CH3CH2CHBrCH2CH3
B. CH3CH2CHBrCH3
C. CH2BrCH(CH3)CH2Br
D. CH3CH2CH2CH2CH2Br
-
18M.1.hl.TZ1.36:
Which molecule contains a chiral carbon?
A. CH3CH2CHBrCH2CH3
B. CH3CH2CHBrCH3
C. CH2BrCH(CH3)CH2Br
D. CH3CH2CH2CH2CH2Br
- 18M.1.hl.TZ1.37: Which reagents are needed to convert nitrobenzene to phenylamine in 2 steps?
- 18M.1.hl.TZ1.37: Which reagents are needed to convert nitrobenzene to phenylamine in 2 steps?
- 18M.1.hl.TZ1.35: What is name of this compound applying IUPAC rules? A. E 1-bromo-1-chlorobut-1-ene B. ...
- 18M.1.hl.TZ1.35: What is name of this compound applying IUPAC rules? A. E 1-bromo-1-chlorobut-1-ene B. ...
- 18M.1.hl.TZ2.35: Which is the correct combination of substitution reaction mechanisms?
- 18M.1.hl.TZ2.35: Which is the correct combination of substitution reaction mechanisms?
-
18M.2.hl.TZ1.7a:
Compare and contrast the mechanisms by which 1-chlorobutane, CH3CH2CH2CH2Cl, and 2-chloro-2-methylpropane, (CH3)3CCl, react with aqueous sodium hydroxide, giving two similarities and one difference.
-
18M.2.hl.TZ1.7a:
Compare and contrast the mechanisms by which 1-chlorobutane, CH3CH2CH2CH2Cl, and 2-chloro-2-methylpropane, (CH3)3CCl, react with aqueous sodium hydroxide, giving two similarities and one difference.
-
18M.2.hl.TZ1.a:
Compare and contrast the mechanisms by which 1-chlorobutane, CH3CH2CH2CH2Cl, and 2-chloro-2-methylpropane, (CH3)3CCl, react with aqueous sodium hydroxide, giving two similarities and one difference.
-
18M.2.hl.TZ1.7b:
Outline why the rate of reaction of the similar bromo-compounds is faster.
-
18M.2.hl.TZ1.7b:
Outline why the rate of reaction of the similar bromo-compounds is faster.
-
18M.2.hl.TZ1.b:
Outline why the rate of reaction of the similar bromo-compounds is faster.
-
18M.2.hl.TZ2.9b.iii:
Draw the structure of the intermediate formed stating its shape.
-
18M.2.hl.TZ2.b.iii:
Draw the structure of the intermediate formed stating its shape.
-
18M.2.hl.TZ2.9b.iii:
Draw the structure of the intermediate formed stating its shape.
-
18M.2.hl.TZ1.7c.ii:
Suggest how this product could be synthesized in one step from butanoic acid.
-
18M.2.hl.TZ1.7c.ii:
Suggest how this product could be synthesized in one step from butanoic acid.
-
18M.2.hl.TZ1.c.ii:
Suggest how this product could be synthesized in one step from butanoic acid.
-
18M.2.hl.TZ2.9b.i:
State the type of bond fission that takes place in a SN1 reaction.
-
18M.2.hl.TZ2.b.i:
State the type of bond fission that takes place in a SN1 reaction.
-
18M.2.hl.TZ2.9b.i:
State the type of bond fission that takes place in a SN1 reaction.
-
18M.2.hl.TZ2.9b.ii:
State the type of solvent most suitable for the reaction.
-
18M.2.hl.TZ2.b.ii:
State the type of solvent most suitable for the reaction.
-
18M.2.hl.TZ2.9b.ii:
State the type of solvent most suitable for the reaction.
-
18M.2.hl.TZ2.9b.iv:
Suggest, giving a reason, the percentage of each isomer from the SN1 reaction.
-
18M.2.hl.TZ2.b.iv:
Suggest, giving a reason, the percentage of each isomer from the SN1 reaction.
-
18M.2.hl.TZ2.9b.iv:
Suggest, giving a reason, the percentage of each isomer from the SN1 reaction.
-
18M.2.hl.TZ2.9c:
Nitrobenzene, C6H5NO2, can be converted to phenylamine via a two-stage reaction.
In the first stage, nitrobenzene is reduced with tin in an acidic solution to form an intermediate ion and tin(II) ions. In the second stage, the intermediate ion is converted to phenylamine in the presence of hydroxide ions.
Formulate the equation for each stage of the reaction.
-
18M.2.hl.TZ2.c:
Nitrobenzene, C6H5NO2, can be converted to phenylamine via a two-stage reaction.
In the first stage, nitrobenzene is reduced with tin in an acidic solution to form an intermediate ion and tin(II) ions. In the second stage, the intermediate ion is converted to phenylamine in the presence of hydroxide ions.
Formulate the equation for each stage of the reaction.
-
18M.2.hl.TZ2.9c:
Nitrobenzene, C6H5NO2, can be converted to phenylamine via a two-stage reaction.
In the first stage, nitrobenzene is reduced with tin in an acidic solution to form an intermediate ion and tin(II) ions. In the second stage, the intermediate ion is converted to phenylamine in the presence of hydroxide ions.
Formulate the equation for each stage of the reaction.
- 21N.1.hl.TZ0.35: Which statement is correct about configurational isomers? A. Configurational isomers can only...
- 21N.1.hl.TZ0.35: Which statement is correct about configurational isomers? A. Configurational isomers can only...
- 21N.1.hl.TZ0.37: Which attacking species is matched with its mechanism of reaction?
- 21N.1.hl.TZ0.37: Which attacking species is matched with its mechanism of reaction?
-
21N.1.hl.TZ0.36:
Which product is formed when CH3COCH2CH3 is reduced with sodium borohydride?
A. CH3CH2CH2CHOB. CH3CH2CH2CH2OH
C. CH3CH(OH)CH2CH3
D. CH3CH2CH2COOH
-
21N.1.hl.TZ0.36:
Which product is formed when CH3COCH2CH3 is reduced with sodium borohydride?
A. CH3CH2CH2CHOB. CH3CH2CH2CH2OH
C. CH3CH(OH)CH2CH3
D. CH3CH2CH2COOH
- 21N.2.hl.TZ0.10b(iii): Explain the mechanism of the reaction between but-1-ene with hydrogen iodide, using curly arrows...
- 21N.2.hl.TZ0.10b(iii): Explain the mechanism of the reaction between but-1-ene with hydrogen iodide, using curly arrows...
- 21N.2.hl.TZ0.b(iii): Explain the mechanism of the reaction between but-1-ene with hydrogen iodide, using curly arrows...
- 21N.2.hl.TZ0.10e: Discuss the reason benzene is more reactive with an electrophile than a nucleophile.
- 21N.2.hl.TZ0.10e: Discuss the reason benzene is more reactive with an electrophile than a nucleophile.
- 21N.2.hl.TZ0.e: Discuss the reason benzene is more reactive with an electrophile than a nucleophile.
- 21N.2.hl.TZ0.10b(i): State, giving a reason, if but-1-ene exhibits cis-trans isomerism.
- 21N.2.hl.TZ0.10b(i): State, giving a reason, if but-1-ene exhibits cis-trans isomerism.
- 21N.2.hl.TZ0.b(i): State, giving a reason, if but-1-ene exhibits cis-trans isomerism.
- 21N.2.hl.TZ0.10b(iv): State, giving a reason, if the product of this reaction exhibits stereoisomerism.
- 21N.2.hl.TZ0.10b(iv): State, giving a reason, if the product of this reaction exhibits stereoisomerism.
- 21N.2.hl.TZ0.b(iv): State, giving a reason, if the product of this reaction exhibits stereoisomerism.
-
18N.2.hl.TZ0.6e.ii:
Deduce the product of the complete reduction reaction in (e)(i).
-
18N.2.hl.TZ0.6e.ii:
Deduce the product of the complete reduction reaction in (e)(i).
-
18N.2.hl.TZ0.e.ii:
Deduce the product of the complete reduction reaction in (e)(i).
- 18N.2.hl.TZ0.9c: Explain the mechanism of the reaction between 1-bromopropane with aqueous sodium hydroxide using...
- 18N.2.hl.TZ0.9c: Explain the mechanism of the reaction between 1-bromopropane with aqueous sodium hydroxide using...
- 18N.2.hl.TZ0.c: Explain the mechanism of the reaction between 1-bromopropane with aqueous sodium hydroxide using...
- 18N.1.hl.TZ0.35: Which statement about the reaction of a hydroxide ion with the organic reagent is...
- 18N.1.hl.TZ0.35: Which statement about the reaction of a hydroxide ion with the organic reagent is...
- 18N.1.hl.TZ0.36: What is the major product of the reaction of HBr with but-1-ene? A. 1-bromobutane B. ...
- 18N.1.hl.TZ0.36: What is the major product of the reaction of HBr with but-1-ene? A. 1-bromobutane B. ...
- 18N.2.hl.TZ0.8b.ii: State, giving a reason, whether methyloxirane can form cis-trans isomers.
- 18N.2.hl.TZ0.8b.ii: State, giving a reason, whether methyloxirane can form cis-trans isomers.
- 18N.2.hl.TZ0.b.ii: State, giving a reason, whether methyloxirane can form cis-trans isomers.
- 18N.2.hl.TZ0.6e.i: State a suitable reagent for the reduction of butanoic acid.
- 18N.2.hl.TZ0.6e.i: State a suitable reagent for the reduction of butanoic acid.
- 18N.2.hl.TZ0.e.i: State a suitable reagent for the reduction of butanoic acid.
- 22M.1.hl.TZ1.37: What are the E/Z designations of these stereoisomers?
- 22M.1.hl.TZ1.37: What are the E/Z designations of these stereoisomers?
- 22M.1.hl.TZ1.35: What are the type of reaction and role of the nitronium ion, NO2+, in the following...
- 22M.1.hl.TZ1.35: What are the type of reaction and role of the nitronium ion, NO2+, in the following...
- 22M.1.hl.TZ1.36: What is molecule Z that is formed in step 1 of this synthetic route?
- 22M.1.hl.TZ1.36: What is molecule Z that is formed in step 1 of this synthetic route?
- 22M.1.hl.TZ2.37: What is the product of the reaction of propanal with lithium aluminium hydride, LiAlH4? A. ...
- 22M.1.hl.TZ2.37: What is the product of the reaction of propanal with lithium aluminium hydride, LiAlH4? A. ...
- 22M.1.hl.TZ2.32: Which sequence of reagents converts propene to propanone?
- 22M.1.hl.TZ2.32: Which sequence of reagents converts propene to propanone?
-
22M.2.hl.TZ1.5d(iii):
Explain the mechanism of the reaction using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ1.5d(iii):
Explain the mechanism of the reaction using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ1.d(iii):
Explain the mechanism of the reaction using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ1.5a(v):
Identify the isomer of Compound B that exists as optical isomers (enantiomers).
-
22M.2.hl.TZ1.5a(v):
Identify the isomer of Compound B that exists as optical isomers (enantiomers).
-
22M.2.hl.TZ1.a(v):
Identify the isomer of Compound B that exists as optical isomers (enantiomers).
-
22M.2.hl.TZ1.5b(ii):
Explain why the reaction produces more (CH3)3COH than (CH3)2CHCH2OH.
-
22M.2.hl.TZ1.5b(ii):
Explain why the reaction produces more (CH3)3COH than (CH3)2CHCH2OH.
-
22M.2.hl.TZ1.b(ii):
Explain why the reaction produces more (CH3)3COH than (CH3)2CHCH2OH.
- 22M.2.hl.TZ1.6b(ii): Draw the structural formula of the carbocation intermediate produced when this electrophile...
- 22M.2.hl.TZ1.6b(ii): Draw the structural formula of the carbocation intermediate produced when this electrophile...
- 22M.2.hl.TZ1.b(ii): Draw the structural formula of the carbocation intermediate produced when this electrophile...
-
22M.2.hl.TZ1.6b(i):
Write an equation for the reaction between the acids to produce the electrophile, NO2+.
-
22M.2.hl.TZ1.6b(i):
Write an equation for the reaction between the acids to produce the electrophile, NO2+.
-
22M.2.hl.TZ1.b(i):
Write an equation for the reaction between the acids to produce the electrophile, NO2+.
-
22M.2.hl.TZ2.8d(i):
Draw the full structural formula of (Z)-but-2-ene.
-
22M.2.hl.TZ2.8d(i):
Draw the full structural formula of (Z)-but-2-ene.
-
22M.2.hl.TZ2.d(i):
Draw the full structural formula of (Z)-but-2-ene.
-
22M.2.hl.TZ2.8e(i):
Explain the mechanism of the reaction between 1-bromopropane, CH3CH2CH2Br, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ2.8e(i):
Explain the mechanism of the reaction between 1-bromopropane, CH3CH2CH2Br, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ2.e(i):
Explain the mechanism of the reaction between 1-bromopropane, CH3CH2CH2Br, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
19M.2.hl.TZ1.2i:
State the reagent used to convert benzoic acid to phenylmethanol (benzyl alcohol), C6H5CH2OH.
-
19M.2.hl.TZ1.2i:
State the reagent used to convert benzoic acid to phenylmethanol (benzyl alcohol), C6H5CH2OH.
-
19M.2.hl.TZ1.i:
State the reagent used to convert benzoic acid to phenylmethanol (benzyl alcohol), C6H5CH2OH.
-
19M.2.hl.TZ1.1c(ii):
Explain the mechanism for the nitration of benzene, using curly arrows to indicate the movement of electron pairs.
-
19M.2.hl.TZ1.1c(ii):
Explain the mechanism for the nitration of benzene, using curly arrows to indicate the movement of electron pairs.
-
19M.2.hl.TZ1.c(ii):
Explain the mechanism for the nitration of benzene, using curly arrows to indicate the movement of electron pairs.
-
19M.2.hl.TZ1.1e:
The organic product is not optically active. Discuss whether or not the organic product is a racemic mixture.
-
19M.2.hl.TZ1.1e:
The organic product is not optically active. Discuss whether or not the organic product is a racemic mixture.
-
19M.2.hl.TZ1.e:
The organic product is not optically active. Discuss whether or not the organic product is a racemic mixture.
-
19M.2.hl.TZ2.6d(i):
Outline why the major product, C6H5–CHBr–CH3, can exist in two forms and state the relationship between these forms.
Two forms:
Relationship:
-
19M.2.hl.TZ2.6d(i):
Outline why the major product, C6H5–CHBr–CH3, can exist in two forms and state the relationship between these forms.
Two forms:
Relationship:
-
19M.2.hl.TZ2.d(i):
Outline why the major product, C6H5–CHBr–CH3, can exist in two forms and state the relationship between these forms.
Two forms:
Relationship:
-
19M.2.hl.TZ2.6d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
-
19M.2.hl.TZ2.6d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
-
19M.2.hl.TZ2.d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
-
19M.2.hl.TZ2.6c:
The benzene ring of phenylethene reacts with the nitronium ion, NO2+, and the C=C double bond reacts with hydrogen bromide, HBr.
Compare and contrast these two reactions in terms of their reaction mechanisms.
Similarity:
Difference:
-
19M.2.hl.TZ2.6c:
The benzene ring of phenylethene reacts with the nitronium ion, NO2+, and the C=C double bond reacts with hydrogen bromide, HBr.
Compare and contrast these two reactions in terms of their reaction mechanisms.
Similarity:
Difference:
-
19M.2.hl.TZ2.c:
The benzene ring of phenylethene reacts with the nitronium ion, NO2+, and the C=C double bond reacts with hydrogen bromide, HBr.
Compare and contrast these two reactions in terms of their reaction mechanisms.
Similarity:
Difference:
-
19M.2.hl.TZ2.6e:
The minor product, C6H5–CH2–CH2Br, can be directly converted to an intermediate compound, X, which can then be directly converted to the acid C6H5–CH2–COOH.
C6H5–CH2–CH2Br → X → C6H5–CH2–COOH
Identify X.
-
19M.2.hl.TZ2.6e:
The minor product, C6H5–CH2–CH2Br, can be directly converted to an intermediate compound, X, which can then be directly converted to the acid C6H5–CH2–COOH.
C6H5–CH2–CH2Br → X → C6H5–CH2–COOH
Identify X.
-
19M.2.hl.TZ2.e:
The minor product, C6H5–CH2–CH2Br, can be directly converted to an intermediate compound, X, which can then be directly converted to the acid C6H5–CH2–COOH.
C6H5–CH2–CH2Br → X → C6H5–CH2–COOH
Identify X.
-
19M.3.hl.TZ1.5a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.5a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.a:
Label with an asterisk, *, the chiral carbon atom.
- 19M.1.hl.TZ1.36: Which statement is not correct regarding benzene? A. It is planar. B. The ring contains...
- 19M.1.hl.TZ1.36: Which statement is not correct regarding benzene? A. It is planar. B. The ring contains...
- 19M.1.hl.TZ1.35: Which solvent is aprotic? A. H2O B. C6H5CH3 C. CH3OH D. CH3NH2
- 19M.1.hl.TZ1.35: Which solvent is aprotic? A. H2O B. C6H5CH3 C. CH3OH D. CH3NH2
- 19M.1.hl.TZ1.37: Which compound can exist as cis- and trans-isomers?
- 19M.1.hl.TZ1.37: Which compound can exist as cis- and trans-isomers?
-
19M.1.hl.TZ1.33:
Which is a major product of the electrophilic addition of hydrogen chloride to propene?
A. ClCH2CH=CH2
B. CH3CH(Cl)CH3
C. CH3CH2CH2Cl
D. CH3CH=CHCl
-
19M.1.hl.TZ1.33:
Which is a major product of the electrophilic addition of hydrogen chloride to propene?
A. ClCH2CH=CH2
B. CH3CH(Cl)CH3
C. CH3CH2CH2Cl
D. CH3CH=CHCl
-
19M.1.hl.TZ2.37:
Which class of compound is formed when a ketone is reduced?
A. primary alcohol
B. secondary alcohol
C. ether
D. carboxylic acid
-
19M.1.hl.TZ2.37:
Which class of compound is formed when a ketone is reduced?
A. primary alcohol
B. secondary alcohol
C. ether
D. carboxylic acid
-
19N.2.hl.TZ0.3a(iv):
Write an equation for the reaction of the major product with aqueous sodium hydroxide to produce a C3H8O compound, showing structural formulas.
-
19N.2.hl.TZ0.3a(iv):
Write an equation for the reaction of the major product with aqueous sodium hydroxide to produce a C3H8O compound, showing structural formulas.
-
19N.2.hl.TZ0.a(iv):
Write an equation for the reaction of the major product with aqueous sodium hydroxide to produce a C3H8O compound, showing structural formulas.
-
19N.2.hl.TZ0.3b(iii):
Sketch the mechanism using curly arrows to represent the movement of electrons.
-
19N.2.hl.TZ0.3b(iii):
Sketch the mechanism using curly arrows to represent the movement of electrons.
-
19N.2.hl.TZ0.b(iii):
Sketch the mechanism using curly arrows to represent the movement of electrons.
- 19N.2.hl.TZ0.3b(ii): Deduce the type of mechanism for the reaction of this isomer of C3H7Cl with aqueous sodium...
- 19N.2.hl.TZ0.3b(ii): Deduce the type of mechanism for the reaction of this isomer of C3H7Cl with aqueous sodium...
- 19N.2.hl.TZ0.b(ii): Deduce the type of mechanism for the reaction of this isomer of C3H7Cl with aqueous sodium...
- 19N.2.hl.TZ0.3a(iii): Outline why it is the major product.
- 19N.2.hl.TZ0.3a(iii): Outline why it is the major product.
- 19N.2.hl.TZ0.a(iii): Outline why it is the major product.
- 19N.1.hl.TZ0.37: Which can be reduced to an aldehyde? A. Butanone B. Butan-1-ol C. Butanoic acid D. Butan-2-ol
- 19N.1.hl.TZ0.37: Which can be reduced to an aldehyde? A. Butanone B. Butan-1-ol C. Butanoic acid D. Butan-2-ol
-
19N.1.hl.TZ0.36:
In which compound is the halogen substituted the most rapidly by aqueous hydroxide ions?
A. (CH3)3CCl
B. (CH3)3CI
C. CH3CH2CH2CH2Cl
D. CH3CH2CH2CH2I
-
19N.1.hl.TZ0.36:
In which compound is the halogen substituted the most rapidly by aqueous hydroxide ions?
A. (CH3)3CCl
B. (CH3)3CI
C. CH3CH2CH2CH2Cl
D. CH3CH2CH2CH2I
- 19N.3.hl.TZ0.26a: State the feature of Taxol that is a major challenge in its synthesis. Use section 37 of the data...
- 19N.3.hl.TZ0.26a: State the feature of Taxol that is a major challenge in its synthesis. Use section 37 of the data...
- 19N.3.hl.TZ0.a: State the feature of Taxol that is a major challenge in its synthesis. Use section 37 of the data...
- 22N.1.hl.TZ0.33: Which compound has a chiral carbon? A. Bromoethane B. 2-bromopropane C. 2-bromobutane D. ...
- 22N.1.hl.TZ0.33: Which compound has a chiral carbon? A. Bromoethane B. 2-bromopropane C. 2-bromobutane D. ...
-
22N.1.hl.TZ0.35:
Which statement best describes retrosynthesis?
A. The reaction conditions needed to convert the product of a reaction back to the starting materials.
B. Synthesizing a target molecule by working back from the target molecule to the starting materials.
C. A synthetic scheme using traditional methods rather than modern methods and materials.
D. A synthetic pathway which favours the equilibrium towards the products.
-
22N.1.hl.TZ0.35:
Which statement best describes retrosynthesis?
A. The reaction conditions needed to convert the product of a reaction back to the starting materials.
B. Synthesizing a target molecule by working back from the target molecule to the starting materials.
C. A synthetic scheme using traditional methods rather than modern methods and materials.
D. A synthetic pathway which favours the equilibrium towards the products.
-
22N.1.hl.TZ0.36:
What combination of reactants will convert nitrobenzene to phenylamine in two steps?
-
22N.1.hl.TZ0.36:
What combination of reactants will convert nitrobenzene to phenylamine in two steps?
- 22N.2.hl.TZ0.6e: State, with a reason, how the rate of reaction of cyanide with 2-chlorobutane differs from its...
- 22N.2.hl.TZ0.6e: State, with a reason, how the rate of reaction of cyanide with 2-chlorobutane differs from its...
- 22N.2.hl.TZ0.e: State, with a reason, how the rate of reaction of cyanide with 2-chlorobutane differs from its...
-
22N.2.hl.TZ0.6a:
This reaction could proceed through either SN1 or SN2 mechanisms depending on the reaction conditions. Sketch a graph of the rate versus nucleophile concentration, [CN−], for each of the mechanisms.
-
22N.2.hl.TZ0.6a:
This reaction could proceed through either SN1 or SN2 mechanisms depending on the reaction conditions. Sketch a graph of the rate versus nucleophile concentration, [CN−], for each of the mechanisms.
-
22N.2.hl.TZ0.a:
This reaction could proceed through either SN1 or SN2 mechanisms depending on the reaction conditions. Sketch a graph of the rate versus nucleophile concentration, [CN−], for each of the mechanisms.
-
22N.2.hl.TZ0.6f:
2-Bromobutane reacts with hydroxide via the same mechanism identified in (b). Explain this mechanism using curly arrows to represent the movement of electron pairs.
-
22N.2.hl.TZ0.6f:
2-Bromobutane reacts with hydroxide via the same mechanism identified in (b). Explain this mechanism using curly arrows to represent the movement of electron pairs.
-
22N.2.hl.TZ0.f:
2-Bromobutane reacts with hydroxide via the same mechanism identified in (b). Explain this mechanism using curly arrows to represent the movement of electron pairs.
- 22N.2.hl.TZ0.6b: Suggest, with a reason, whether the reaction follows an SN1 or SN2 mechanism if only one...
- 22N.2.hl.TZ0.6b: Suggest, with a reason, whether the reaction follows an SN1 or SN2 mechanism if only one...
- 22N.2.hl.TZ0.b: Suggest, with a reason, whether the reaction follows an SN1 or SN2 mechanism if only one...
- 22N.2.hl.TZ0.6c: State an instrument that could be used to determine whether the product was a single enantiomer...
- 22N.2.hl.TZ0.6c: State an instrument that could be used to determine whether the product was a single enantiomer...
- 22N.2.hl.TZ0.c: State an instrument that could be used to determine whether the product was a single enantiomer...
-
22N.2.hl.TZ0.6d:
SN1 and SN2 reactions are better conducted using different types of solvents. Identify two properties of a solvent most suited for the mechanism proposed in (b).
-
22N.2.hl.TZ0.6d:
SN1 and SN2 reactions are better conducted using different types of solvents. Identify two properties of a solvent most suited for the mechanism proposed in (b).
-
22N.2.hl.TZ0.d:
SN1 and SN2 reactions are better conducted using different types of solvents. Identify two properties of a solvent most suited for the mechanism proposed in (b).
- 17N.1.hl.TZ0.37: What is the number of optical isomers of isoleucine? A. 0 B. 2 C. 4 D. 8
- 17N.1.hl.TZ0.37: What is the number of optical isomers of isoleucine? A. 0 B. 2 C. 4 D. 8
-
18M.3.hl.TZ2.8e:
Sketch the wedge and dash (3-D) representations of alanine enantiomers.
-
18M.3.hl.TZ2.8e:
Sketch the wedge and dash (3-D) representations of alanine enantiomers.
-
18M.3.hl.TZ2.e:
Sketch the wedge and dash (3-D) representations of alanine enantiomers.
-
18N.1.hl.TZ0.37:
How many chiral carbon atoms are present in one molecule of (CH3)2CHCHClCHBrCH3?
A. 0
B. 1
C. 2
D. 3
-
18N.1.hl.TZ0.37:
How many chiral carbon atoms are present in one molecule of (CH3)2CHCHClCHBrCH3?
A. 0
B. 1
C. 2
D. 3
-
19M.2.hl.TZ1.1c(i):
Write the equation for the production of the active nitrating agent from concentrated sulfuric and nitric acids.
-
19M.2.hl.TZ1.1c(i):
Write the equation for the production of the active nitrating agent from concentrated sulfuric and nitric acids.
-
19M.2.hl.TZ1.c(i):
Write the equation for the production of the active nitrating agent from concentrated sulfuric and nitric acids.
- 19M.1.hl.TZ2.36: Which compound exists as two configurational isomers? A. CBr2=CH2 B. CH2=CHBr C....
- 19M.1.hl.TZ2.36: Which compound exists as two configurational isomers? A. CBr2=CH2 B. CH2=CHBr C....
-
19N.1.hl.TZ0.38:
Which can show optical activity?
A. CHBrCHCl
B. CH3CH2CHBrCH2CH3
C. (CH3)2CBrCl
D. CH3CH2CH(CH3)Br
-
19N.1.hl.TZ0.38:
Which can show optical activity?
A. CHBrCHCl
B. CH3CH2CHBrCH2CH3
C. (CH3)2CBrCl
D. CH3CH2CH(CH3)Br
-
21M.1.hl.TZ1.35:
Which is most likely to hydrolyse via a SN1 mechanism?
A. CH3CHBrCH2CH3
B. (CH3)2CHBr
C. (CH3)3CBr
D. CH3CH2CH2CH2Br
-
21M.1.hl.TZ1.35:
Which is most likely to hydrolyse via a SN1 mechanism?
A. CH3CHBrCH2CH3
B. (CH3)2CHBr
C. (CH3)3CBr
D. CH3CH2CH2CH2Br
- 21M.1.hl.TZ1.37: How many chiral centres are there in the following molecule? A. 2 B. 3 C. 4 D. 6
- 21M.1.hl.TZ1.37: How many chiral centres are there in the following molecule? A. 2 B. 3 C. 4 D. 6
- 21M.1.hl.TZ2.35: Which compound shows cis-trans isomerism? A. CH3CH=CCl2 B. CCl2=CH2 C. D.
- 21M.1.hl.TZ2.35: Which compound shows cis-trans isomerism? A. CH3CH=CCl2 B. CCl2=CH2 C. D.
-
21M.2.hl.TZ1.5e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
-
21M.2.hl.TZ1.5e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
-
21M.2.hl.TZ1.e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
- 21M.2.hl.TZ2.4h(ii): Outline how two enantiomers can be distinguished using a polarimeter.
- 21M.2.hl.TZ2.4h(ii): Outline how two enantiomers can be distinguished using a polarimeter.
- 21M.2.hl.TZ2.h(ii): Outline how two enantiomers can be distinguished using a polarimeter.
-
22M.2.hl.TZ2.8d(v):
Predict, giving a reason, the major product of reaction between but-1-ene and steam.
-
22M.2.hl.TZ2.8d(v):
Predict, giving a reason, the major product of reaction between but-1-ene and steam.
-
22M.2.hl.TZ2.d(v):
Predict, giving a reason, the major product of reaction between but-1-ene and steam.
-
23M.1.SL.TZ2.19:
Which reaction represents the neutralization of a Brønsted–Lowry acid and base?
A. 2HCl (aq) + Zn (s) → ZnCl2 (aq) + H2 (g)B. 2HCl (aq) + ZnO (s) → ZnCl2 (aq) + H2O (l)
C. 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (l)
D. C2H4 (g) + H2 (g) → C2H6 (g)
-
23M.1.SL.TZ2.19:
Which reaction represents the neutralization of a Brønsted–Lowry acid and base?
A. 2HCl (aq) + Zn (s) → ZnCl2 (aq) + H2 (g)B. 2HCl (aq) + ZnO (s) → ZnCl2 (aq) + H2O (l)
C. 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (l)
D. C2H4 (g) + H2 (g) → C2H6 (g)
- 23M.1.SL.TZ2.20: What is the hydroxide ion concentration in a solution of pH = 4 at 298 K? A. 4 B. 10 C. ...
- 23M.1.SL.TZ2.20: What is the hydroxide ion concentration in a solution of pH = 4 at 298 K? A. 4 B. 10 C. ...
Sub sections and their related questions
20.1 Types of organic reactions
- 17N.1.hl.TZ0.33: Propene reacts separately with H2O/H+ and H2/Ni to give products X and Z respectively. What...
- 17N.1.hl.TZ0.35: What is the product of the reaction between pentan-2-one and sodium borohydride, NaBH4? A....
-
17N.2.hl.TZ0.8c:
State the reagents used in the nitration of benzene.
-
17N.2.hl.TZ0.8d:
State an equation for the formation of NO2+.
-
17N.2.hl.TZ0.8e:
Explain the mechanism of the reaction between 2-bromo-2-methylpropane, (CH3)3CBr, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
- 18M.1.hl.TZ1.37: Which reagents are needed to convert nitrobenzene to phenylamine in 2 steps?
-
18M.2.hl.TZ1.7a:
Compare and contrast the mechanisms by which 1-chlorobutane, CH3CH2CH2CH2Cl, and 2-chloro-2-methylpropane, (CH3)3CCl, react with aqueous sodium hydroxide, giving two similarities and one difference.
-
18M.2.hl.TZ1.7b:
Outline why the rate of reaction of the similar bromo-compounds is faster.
-
18M.2.hl.TZ1.7c.ii:
Suggest how this product could be synthesized in one step from butanoic acid.
- 18M.1.hl.TZ2.35: Which is the correct combination of substitution reaction mechanisms?
-
18M.1.hl.TZ2.36:
Propene is reacted first with hydrogen chloride to produce X which is then reacted with aqueous sodium hydroxide to give Y. Finally, Y is reacted with excess acidified potassium dichromate solution.
What is the major product, Z?
A. CH3CH(OH)CH3
B. CH3COCH3
C. CH3CH2CHO
D. CH3(CH2)2COOH
-
18M.2.hl.TZ2.9b.i:
State the type of bond fission that takes place in a SN1 reaction.
-
18M.2.hl.TZ2.9b.ii:
State the type of solvent most suitable for the reaction.
-
18M.2.hl.TZ2.9b.iii:
Draw the structure of the intermediate formed stating its shape.
-
18M.2.hl.TZ2.9c:
Nitrobenzene, C6H5NO2, can be converted to phenylamine via a two-stage reaction.
In the first stage, nitrobenzene is reduced with tin in an acidic solution to form an intermediate ion and tin(II) ions. In the second stage, the intermediate ion is converted to phenylamine in the presence of hydroxide ions.
Formulate the equation for each stage of the reaction.
- 18N.1.hl.TZ0.35: Which statement about the reaction of a hydroxide ion with the organic reagent is...
- 18N.1.hl.TZ0.36: What is the major product of the reaction of HBr with but-1-ene? A. 1-bromobutane B. ...
- 18N.2.hl.TZ0.6e.i: State a suitable reagent for the reduction of butanoic acid.
-
18N.2.hl.TZ0.6e.ii:
Deduce the product of the complete reduction reaction in (e)(i).
- 18N.2.hl.TZ0.9c: Explain the mechanism of the reaction between 1-bromopropane with aqueous sodium hydroxide using...
-
19M.2.hl.TZ1.1c(i):
Write the equation for the production of the active nitrating agent from concentrated sulfuric and nitric acids.
-
19M.2.hl.TZ1.1c(ii):
Explain the mechanism for the nitration of benzene, using curly arrows to indicate the movement of electron pairs.
-
19M.2.hl.TZ1.2i:
State the reagent used to convert benzoic acid to phenylmethanol (benzyl alcohol), C6H5CH2OH.
-
19M.2.hl.TZ2.6c:
The benzene ring of phenylethene reacts with the nitronium ion, NO2+, and the C=C double bond reacts with hydrogen bromide, HBr.
Compare and contrast these two reactions in terms of their reaction mechanisms.
Similarity:
Difference:
-
19M.1.hl.TZ1.33:
Which is a major product of the electrophilic addition of hydrogen chloride to propene?
A. ClCH2CH=CH2
B. CH3CH(Cl)CH3
C. CH3CH2CH2Cl
D. CH3CH=CHCl
- 19M.1.hl.TZ1.35: Which solvent is aprotic? A. H2O B. C6H5CH3 C. CH3OH D. CH3NH2
- 19M.1.hl.TZ1.36: Which statement is not correct regarding benzene? A. It is planar. B. The ring contains...
-
19M.1.hl.TZ2.37:
Which class of compound is formed when a ketone is reduced?
A. primary alcohol
B. secondary alcohol
C. ether
D. carboxylic acid
- 19N.2.hl.TZ0.3a(iii): Outline why it is the major product.
-
19N.2.hl.TZ0.3a(iv):
Write an equation for the reaction of the major product with aqueous sodium hydroxide to produce a C3H8O compound, showing structural formulas.
- 19N.2.hl.TZ0.3b(ii): Deduce the type of mechanism for the reaction of this isomer of C3H7Cl with aqueous sodium...
-
19N.2.hl.TZ0.3b(iii):
Sketch the mechanism using curly arrows to represent the movement of electrons.
-
19N.1.hl.TZ0.36:
In which compound is the halogen substituted the most rapidly by aqueous hydroxide ions?
A. (CH3)3CCl
B. (CH3)3CI
C. CH3CH2CH2CH2Cl
D. CH3CH2CH2CH2I
- 19N.1.hl.TZ0.37: Which can be reduced to an aldehyde? A. Butanone B. Butan-1-ol C. Butanoic acid D. Butan-2-ol
-
20N.1.hl.TZ0.35:
Which is the electrophile in the nitration of benzene?
A.
B.
C.
D.
-
20N.1.hl.TZ0.36:
What will be the major product in the reaction between but-1-ene and ?
A. 2-bromobut-1-ene
B. 1-bromobut-1-ene
C. 2-bromobutane
D. 1-bromobutane
-
20N.2.hl.TZ0.1d(iii):
Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, , using curly arrows to represent the movement of electron pairs.
-
21M.1.hl.TZ1.35:
Which is most likely to hydrolyse via a SN1 mechanism?
A. CH3CHBrCH2CH3
B. (CH3)2CHBr
C. (CH3)3CBr
D. CH3CH2CH2CH2Br
- 21M.1.hl.TZ1.36: What is the product of the reaction of benzene with a mixture of concentrated nitric and sulfuric...
- 21M.2.hl.TZ2.4e: Sketch the mechanism for the reaction of 2-methylbut-2-ene with hydrogen bromide using curly...
- 21M.2.hl.TZ2.4f: Explain why the major organic product is 2-bromo-2-methylbutane and not 2-bromo-3-methylbutane.
-
21N.1.hl.TZ0.36:
Which product is formed when CH3COCH2CH3 is reduced with sodium borohydride?
A. CH3CH2CH2CHOB. CH3CH2CH2CH2OH
C. CH3CH(OH)CH2CH3
D. CH3CH2CH2COOH
- 21N.1.hl.TZ0.37: Which attacking species is matched with its mechanism of reaction?
- 21N.2.hl.TZ0.10b(iii): Explain the mechanism of the reaction between but-1-ene with hydrogen iodide, using curly arrows...
- 21N.2.hl.TZ0.10e: Discuss the reason benzene is more reactive with an electrophile than a nucleophile.
- 22M.1.hl.TZ1.35: What are the type of reaction and role of the nitronium ion, NO2+, in the following...
- 22M.1.hl.TZ1.36: What is molecule Z that is formed in step 1 of this synthetic route?
- 22M.1.hl.TZ2.37: What is the product of the reaction of propanal with lithium aluminium hydride, LiAlH4? A. ...
-
22M.2.hl.TZ1.5b(ii):
Explain why the reaction produces more (CH3)3COH than (CH3)2CHCH2OH.
-
22M.2.hl.TZ1.5d(iii):
Explain the mechanism of the reaction using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ1.6b(i):
Write an equation for the reaction between the acids to produce the electrophile, NO2+.
- 22M.2.hl.TZ1.6b(ii): Draw the structural formula of the carbocation intermediate produced when this electrophile...
-
22M.2.hl.TZ2.8d(v):
Predict, giving a reason, the major product of reaction between but-1-ene and steam.
-
22M.2.hl.TZ2.8e(i):
Explain the mechanism of the reaction between 1-bromopropane, CH3CH2CH2Br, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
22N.1.hl.TZ0.36:
What combination of reactants will convert nitrobenzene to phenylamine in two steps?
-
22N.2.hl.TZ0.6a:
This reaction could proceed through either SN1 or SN2 mechanisms depending on the reaction conditions. Sketch a graph of the rate versus nucleophile concentration, [CN−], for each of the mechanisms.
- 22N.2.hl.TZ0.6b: Suggest, with a reason, whether the reaction follows an SN1 or SN2 mechanism if only one...
-
22N.2.hl.TZ0.6d:
SN1 and SN2 reactions are better conducted using different types of solvents. Identify two properties of a solvent most suited for the mechanism proposed in (b).
- 22N.2.hl.TZ0.6e: State, with a reason, how the rate of reaction of cyanide with 2-chlorobutane differs from its...
-
22N.2.hl.TZ0.6f:
2-Bromobutane reacts with hydroxide via the same mechanism identified in (b). Explain this mechanism using curly arrows to represent the movement of electron pairs.
-
23M.1.SL.TZ2.19:
Which reaction represents the neutralization of a Brønsted–Lowry acid and base?
A. 2HCl (aq) + Zn (s) → ZnCl2 (aq) + H2 (g)B. 2HCl (aq) + ZnO (s) → ZnCl2 (aq) + H2O (l)
C. 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (l)
D. C2H4 (g) + H2 (g) → C2H6 (g)
- 23M.1.SL.TZ2.20: What is the hydroxide ion concentration in a solution of pH = 4 at 298 K? A. 4 B. 10 C. ...
-
19M.2.hl.TZ1.1c(i):
Write the equation for the production of the active nitrating agent from concentrated sulfuric and nitric acids.
-
19M.2.hl.TZ1.1c(ii):
Explain the mechanism for the nitration of benzene, using curly arrows to indicate the movement of electron pairs.
-
19M.2.hl.TZ1.c(i):
Write the equation for the production of the active nitrating agent from concentrated sulfuric and nitric acids.
-
19M.2.hl.TZ1.c(ii):
Explain the mechanism for the nitration of benzene, using curly arrows to indicate the movement of electron pairs.
-
19M.2.hl.TZ1.2i:
State the reagent used to convert benzoic acid to phenylmethanol (benzyl alcohol), C6H5CH2OH.
-
19M.2.hl.TZ1.i:
State the reagent used to convert benzoic acid to phenylmethanol (benzyl alcohol), C6H5CH2OH.
-
19M.2.hl.TZ2.6c:
The benzene ring of phenylethene reacts with the nitronium ion, NO2+, and the C=C double bond reacts with hydrogen bromide, HBr.
Compare and contrast these two reactions in terms of their reaction mechanisms.
Similarity:
Difference:
-
19M.2.hl.TZ2.c:
The benzene ring of phenylethene reacts with the nitronium ion, NO2+, and the C=C double bond reacts with hydrogen bromide, HBr.
Compare and contrast these two reactions in terms of their reaction mechanisms.
Similarity:
Difference:
-
19M.1.hl.TZ1.33:
Which is a major product of the electrophilic addition of hydrogen chloride to propene?
A. ClCH2CH=CH2
B. CH3CH(Cl)CH3
C. CH3CH2CH2Cl
D. CH3CH=CHCl
- 19M.1.hl.TZ1.35: Which solvent is aprotic? A. H2O B. C6H5CH3 C. CH3OH D. CH3NH2
- 19M.1.hl.TZ1.36: Which statement is not correct regarding benzene? A. It is planar. B. The ring contains...
-
19M.1.hl.TZ2.37:
Which class of compound is formed when a ketone is reduced?
A. primary alcohol
B. secondary alcohol
C. ether
D. carboxylic acid
- 19N.2.hl.TZ0.3a(iii): Outline why it is the major product.
-
19N.2.hl.TZ0.3a(iv):
Write an equation for the reaction of the major product with aqueous sodium hydroxide to produce a C3H8O compound, showing structural formulas.
- 19N.2.hl.TZ0.3b(ii): Deduce the type of mechanism for the reaction of this isomer of C3H7Cl with aqueous sodium...
-
19N.2.hl.TZ0.3b(iii):
Sketch the mechanism using curly arrows to represent the movement of electrons.
- 19N.2.hl.TZ0.a(iii): Outline why it is the major product.
-
19N.2.hl.TZ0.a(iv):
Write an equation for the reaction of the major product with aqueous sodium hydroxide to produce a C3H8O compound, showing structural formulas.
- 19N.2.hl.TZ0.b(ii): Deduce the type of mechanism for the reaction of this isomer of C3H7Cl with aqueous sodium...
-
19N.2.hl.TZ0.b(iii):
Sketch the mechanism using curly arrows to represent the movement of electrons.
-
19N.1.hl.TZ0.36:
In which compound is the halogen substituted the most rapidly by aqueous hydroxide ions?
A. (CH3)3CCl
B. (CH3)3CI
C. CH3CH2CH2CH2Cl
D. CH3CH2CH2CH2I
- 19N.1.hl.TZ0.37: Which can be reduced to an aldehyde? A. Butanone B. Butan-1-ol C. Butanoic acid D. Butan-2-ol
-
20N.1.hl.TZ0.35:
Which is the electrophile in the nitration of benzene?
A.
B.
C.
D.
-
20N.1.hl.TZ0.36:
What will be the major product in the reaction between but-1-ene and ?
A. 2-bromobut-1-ene
B. 1-bromobut-1-ene
C. 2-bromobutane
D. 1-bromobutane
-
20N.2.hl.TZ0.1d(iii):
Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, , using curly arrows to represent the movement of electron pairs.
-
20N.2.hl.TZ0.d(iii):
Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, , using curly arrows to represent the movement of electron pairs.
-
21M.1.hl.TZ1.35:
Which is most likely to hydrolyse via a SN1 mechanism?
A. CH3CHBrCH2CH3
B. (CH3)2CHBr
C. (CH3)3CBr
D. CH3CH2CH2CH2Br
- 21M.1.hl.TZ1.36: What is the product of the reaction of benzene with a mixture of concentrated nitric and sulfuric...
- 21M.2.hl.TZ2.4e: Sketch the mechanism for the reaction of 2-methylbut-2-ene with hydrogen bromide using curly...
- 21M.2.hl.TZ2.4f: Explain why the major organic product is 2-bromo-2-methylbutane and not 2-bromo-3-methylbutane.
- 21M.2.hl.TZ2.e: Sketch the mechanism for the reaction of 2-methylbut-2-ene with hydrogen bromide using curly...
- 21M.2.hl.TZ2.f: Explain why the major organic product is 2-bromo-2-methylbutane and not 2-bromo-3-methylbutane.
-
21N.1.hl.TZ0.36:
Which product is formed when CH3COCH2CH3 is reduced with sodium borohydride?
A. CH3CH2CH2CHOB. CH3CH2CH2CH2OH
C. CH3CH(OH)CH2CH3
D. CH3CH2CH2COOH
- 21N.1.hl.TZ0.37: Which attacking species is matched with its mechanism of reaction?
- 21N.2.hl.TZ0.10b(iii): Explain the mechanism of the reaction between but-1-ene with hydrogen iodide, using curly arrows...
- 21N.2.hl.TZ0.10e: Discuss the reason benzene is more reactive with an electrophile than a nucleophile.
- 21N.2.hl.TZ0.b(iii): Explain the mechanism of the reaction between but-1-ene with hydrogen iodide, using curly arrows...
- 21N.2.hl.TZ0.e: Discuss the reason benzene is more reactive with an electrophile than a nucleophile.
- 22M.1.hl.TZ1.35: What are the type of reaction and role of the nitronium ion, NO2+, in the following...
- 22M.1.hl.TZ1.36: What is molecule Z that is formed in step 1 of this synthetic route?
- 22M.1.hl.TZ2.37: What is the product of the reaction of propanal with lithium aluminium hydride, LiAlH4? A. ...
-
22M.2.hl.TZ1.5b(ii):
Explain why the reaction produces more (CH3)3COH than (CH3)2CHCH2OH.
-
22M.2.hl.TZ1.5d(iii):
Explain the mechanism of the reaction using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ1.b(ii):
Explain why the reaction produces more (CH3)3COH than (CH3)2CHCH2OH.
-
22M.2.hl.TZ1.d(iii):
Explain the mechanism of the reaction using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ1.6b(i):
Write an equation for the reaction between the acids to produce the electrophile, NO2+.
- 22M.2.hl.TZ1.6b(ii): Draw the structural formula of the carbocation intermediate produced when this electrophile...
-
22M.2.hl.TZ1.b(i):
Write an equation for the reaction between the acids to produce the electrophile, NO2+.
- 22M.2.hl.TZ1.b(ii): Draw the structural formula of the carbocation intermediate produced when this electrophile...
-
22M.2.hl.TZ2.8d(v):
Predict, giving a reason, the major product of reaction between but-1-ene and steam.
-
22M.2.hl.TZ2.8e(i):
Explain the mechanism of the reaction between 1-bromopropane, CH3CH2CH2Br, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
22M.2.hl.TZ2.d(v):
Predict, giving a reason, the major product of reaction between but-1-ene and steam.
-
22M.2.hl.TZ2.e(i):
Explain the mechanism of the reaction between 1-bromopropane, CH3CH2CH2Br, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
22N.1.hl.TZ0.36:
What combination of reactants will convert nitrobenzene to phenylamine in two steps?
-
22N.2.hl.TZ0.6a:
This reaction could proceed through either SN1 or SN2 mechanisms depending on the reaction conditions. Sketch a graph of the rate versus nucleophile concentration, [CN−], for each of the mechanisms.
- 22N.2.hl.TZ0.6b: Suggest, with a reason, whether the reaction follows an SN1 or SN2 mechanism if only one...
-
22N.2.hl.TZ0.6d:
SN1 and SN2 reactions are better conducted using different types of solvents. Identify two properties of a solvent most suited for the mechanism proposed in (b).
- 22N.2.hl.TZ0.6e: State, with a reason, how the rate of reaction of cyanide with 2-chlorobutane differs from its...
-
22N.2.hl.TZ0.6f:
2-Bromobutane reacts with hydroxide via the same mechanism identified in (b). Explain this mechanism using curly arrows to represent the movement of electron pairs.
-
22N.2.hl.TZ0.a:
This reaction could proceed through either SN1 or SN2 mechanisms depending on the reaction conditions. Sketch a graph of the rate versus nucleophile concentration, [CN−], for each of the mechanisms.
- 22N.2.hl.TZ0.b: Suggest, with a reason, whether the reaction follows an SN1 or SN2 mechanism if only one...
-
22N.2.hl.TZ0.d:
SN1 and SN2 reactions are better conducted using different types of solvents. Identify two properties of a solvent most suited for the mechanism proposed in (b).
- 22N.2.hl.TZ0.e: State, with a reason, how the rate of reaction of cyanide with 2-chlorobutane differs from its...
-
22N.2.hl.TZ0.f:
2-Bromobutane reacts with hydroxide via the same mechanism identified in (b). Explain this mechanism using curly arrows to represent the movement of electron pairs.
- 17N.1.hl.TZ0.33: Propene reacts separately with H2O/H+ and H2/Ni to give products X and Z respectively. What...
- 17N.1.hl.TZ0.35: What is the product of the reaction between pentan-2-one and sodium borohydride, NaBH4? A....
-
17N.2.hl.TZ0.8c:
State the reagents used in the nitration of benzene.
-
17N.2.hl.TZ0.8d:
State an equation for the formation of NO2+.
-
17N.2.hl.TZ0.8e:
Explain the mechanism of the reaction between 2-bromo-2-methylpropane, (CH3)3CBr, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
-
17N.2.hl.TZ0.c:
State the reagents used in the nitration of benzene.
-
17N.2.hl.TZ0.d:
State an equation for the formation of NO2+.
-
17N.2.hl.TZ0.e:
Explain the mechanism of the reaction between 2-bromo-2-methylpropane, (CH3)3CBr, and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.
- 18M.1.hl.TZ1.37: Which reagents are needed to convert nitrobenzene to phenylamine in 2 steps?
-
18M.2.hl.TZ1.7a:
Compare and contrast the mechanisms by which 1-chlorobutane, CH3CH2CH2CH2Cl, and 2-chloro-2-methylpropane, (CH3)3CCl, react with aqueous sodium hydroxide, giving two similarities and one difference.
-
18M.2.hl.TZ1.7b:
Outline why the rate of reaction of the similar bromo-compounds is faster.
-
18M.2.hl.TZ1.7c.ii:
Suggest how this product could be synthesized in one step from butanoic acid.
-
18M.2.hl.TZ1.a:
Compare and contrast the mechanisms by which 1-chlorobutane, CH3CH2CH2CH2Cl, and 2-chloro-2-methylpropane, (CH3)3CCl, react with aqueous sodium hydroxide, giving two similarities and one difference.
-
18M.2.hl.TZ1.b:
Outline why the rate of reaction of the similar bromo-compounds is faster.
-
18M.2.hl.TZ1.c.ii:
Suggest how this product could be synthesized in one step from butanoic acid.
- 18M.1.hl.TZ2.35: Which is the correct combination of substitution reaction mechanisms?
-
18M.1.hl.TZ2.36:
Propene is reacted first with hydrogen chloride to produce X which is then reacted with aqueous sodium hydroxide to give Y. Finally, Y is reacted with excess acidified potassium dichromate solution.
What is the major product, Z?
A. CH3CH(OH)CH3
B. CH3COCH3
C. CH3CH2CHO
D. CH3(CH2)2COOH
-
18M.2.hl.TZ2.9b.i:
State the type of bond fission that takes place in a SN1 reaction.
-
18M.2.hl.TZ2.9b.ii:
State the type of solvent most suitable for the reaction.
-
18M.2.hl.TZ2.9b.iii:
Draw the structure of the intermediate formed stating its shape.
-
18M.2.hl.TZ2.9c:
Nitrobenzene, C6H5NO2, can be converted to phenylamine via a two-stage reaction.
In the first stage, nitrobenzene is reduced with tin in an acidic solution to form an intermediate ion and tin(II) ions. In the second stage, the intermediate ion is converted to phenylamine in the presence of hydroxide ions.
Formulate the equation for each stage of the reaction.
-
18M.2.hl.TZ2.b.i:
State the type of bond fission that takes place in a SN1 reaction.
-
18M.2.hl.TZ2.b.ii:
State the type of solvent most suitable for the reaction.
-
18M.2.hl.TZ2.b.iii:
Draw the structure of the intermediate formed stating its shape.
-
18M.2.hl.TZ2.c:
Nitrobenzene, C6H5NO2, can be converted to phenylamine via a two-stage reaction.
In the first stage, nitrobenzene is reduced with tin in an acidic solution to form an intermediate ion and tin(II) ions. In the second stage, the intermediate ion is converted to phenylamine in the presence of hydroxide ions.
Formulate the equation for each stage of the reaction.
-
23M.1.SL.TZ2.19:
Which reaction represents the neutralization of a Brønsted–Lowry acid and base?
A. 2HCl (aq) + Zn (s) → ZnCl2 (aq) + H2 (g)B. 2HCl (aq) + ZnO (s) → ZnCl2 (aq) + H2O (l)
C. 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (l)
D. C2H4 (g) + H2 (g) → C2H6 (g)
- 23M.1.SL.TZ2.20: What is the hydroxide ion concentration in a solution of pH = 4 at 298 K? A. 4 B. 10 C. ...
- 18N.1.hl.TZ0.35: Which statement about the reaction of a hydroxide ion with the organic reagent is...
- 18N.1.hl.TZ0.36: What is the major product of the reaction of HBr with but-1-ene? A. 1-bromobutane B. ...
- 18N.2.hl.TZ0.6e.i: State a suitable reagent for the reduction of butanoic acid.
-
18N.2.hl.TZ0.6e.ii:
Deduce the product of the complete reduction reaction in (e)(i).
- 18N.2.hl.TZ0.e.i: State a suitable reagent for the reduction of butanoic acid.
-
18N.2.hl.TZ0.e.ii:
Deduce the product of the complete reduction reaction in (e)(i).
- 18N.2.hl.TZ0.9c: Explain the mechanism of the reaction between 1-bromopropane with aqueous sodium hydroxide using...
- 18N.2.hl.TZ0.c: Explain the mechanism of the reaction between 1-bromopropane with aqueous sodium hydroxide using...
20.2 Synthetic routes
-
18M.1.hl.TZ2.36:
Propene is reacted first with hydrogen chloride to produce X which is then reacted with aqueous sodium hydroxide to give Y. Finally, Y is reacted with excess acidified potassium dichromate solution.
What is the major product, Z?
A. CH3CH(OH)CH3
B. CH3COCH3
C. CH3CH2CHO
D. CH3(CH2)2COOH
-
19M.2.hl.TZ2.6e:
The minor product, C6H5–CH2–CH2Br, can be directly converted to an intermediate compound, X, which can then be directly converted to the acid C6H5–CH2–COOH.
C6H5–CH2–CH2Br → X → C6H5–CH2–COOH
Identify X.
-
20N.2.hl.TZ0.2g(i):
Propanone can be synthesized in two steps from propene. Suggest the synthetic route including all the necessary reactants and steps.
-
20N.2.hl.TZ0.2g(ii):
Propanone can be synthesized in two steps from propene.
Suggest why propanal is a minor product obtained from the synthetic route in (g)(i).
-
21M.2.hl.TZ1.5e(i):
Sketch the mechanism for the reaction of propene with hydrogen bromide using curly arrows.
-
21M.2.hl.TZ1.5e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
-
21M.2.hl.TZ1.5e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
- 22M.1.hl.TZ2.32: Which sequence of reagents converts propene to propanone?
-
22N.1.hl.TZ0.35:
Which statement best describes retrosynthesis?
A. The reaction conditions needed to convert the product of a reaction back to the starting materials.
B. Synthesizing a target molecule by working back from the target molecule to the starting materials.
C. A synthetic scheme using traditional methods rather than modern methods and materials.
D. A synthetic pathway which favours the equilibrium towards the products.
-
19M.2.hl.TZ2.6e:
The minor product, C6H5–CH2–CH2Br, can be directly converted to an intermediate compound, X, which can then be directly converted to the acid C6H5–CH2–COOH.
C6H5–CH2–CH2Br → X → C6H5–CH2–COOH
Identify X.
-
19M.2.hl.TZ2.e:
The minor product, C6H5–CH2–CH2Br, can be directly converted to an intermediate compound, X, which can then be directly converted to the acid C6H5–CH2–COOH.
C6H5–CH2–CH2Br → X → C6H5–CH2–COOH
Identify X.
-
20N.2.hl.TZ0.2g(i):
Propanone can be synthesized in two steps from propene. Suggest the synthetic route including all the necessary reactants and steps.
-
20N.2.hl.TZ0.2g(ii):
Propanone can be synthesized in two steps from propene.
Suggest why propanal is a minor product obtained from the synthetic route in (g)(i).
-
20N.2.hl.TZ0.g(i):
Propanone can be synthesized in two steps from propene. Suggest the synthetic route including all the necessary reactants and steps.
-
20N.2.hl.TZ0.g(ii):
Propanone can be synthesized in two steps from propene.
Suggest why propanal is a minor product obtained from the synthetic route in (g)(i).
-
21M.2.hl.TZ1.5e(i):
Sketch the mechanism for the reaction of propene with hydrogen bromide using curly arrows.
-
21M.2.hl.TZ1.5e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
-
21M.2.hl.TZ1.5e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
-
21M.2.hl.TZ1.e(i):
Sketch the mechanism for the reaction of propene with hydrogen bromide using curly arrows.
-
21M.2.hl.TZ1.e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
-
21M.2.hl.TZ1.e(ii):
Explain why the major organic product is 2-bromopropane and not 1-bromopropane.
- 22M.1.hl.TZ2.32: Which sequence of reagents converts propene to propanone?
-
22N.1.hl.TZ0.35:
Which statement best describes retrosynthesis?
A. The reaction conditions needed to convert the product of a reaction back to the starting materials.
B. Synthesizing a target molecule by working back from the target molecule to the starting materials.
C. A synthetic scheme using traditional methods rather than modern methods and materials.
D. A synthetic pathway which favours the equilibrium towards the products.
-
18M.1.hl.TZ2.36:
Propene is reacted first with hydrogen chloride to produce X which is then reacted with aqueous sodium hydroxide to give Y. Finally, Y is reacted with excess acidified potassium dichromate solution.
What is the major product, Z?
A. CH3CH(OH)CH3
B. CH3COCH3
C. CH3CH2CHO
D. CH3(CH2)2COOH
20.3 Stereoisomerism
- 17N.1.hl.TZ0.37: What is the number of optical isomers of isoleucine? A. 0 B. 2 C. 4 D. 8
- 17N.2.hl.TZ0.8a.iv: Deduce, giving a reason, which of the two compounds can show optical activity.
- 17N.2.hl.TZ0.8a.v: Draw three-dimensional representations of the two enantiomers.
- 18M.1.hl.TZ1.35: What is name of this compound applying IUPAC rules? A. E 1-bromo-1-chlorobut-1-ene B. ...
-
18M.1.hl.TZ1.36:
Which molecule contains a chiral carbon?
A. CH3CH2CHBrCH2CH3
B. CH3CH2CHBrCH3
C. CH2BrCH(CH3)CH2Br
D. CH3CH2CH2CH2CH2Br
- 18M.1.hl.TZ2.37: Which isomers exist as non-superimposable mirror images? A. cis-trans isomers B. ...
-
18M.2.hl.TZ2.9b.iv:
Suggest, giving a reason, the percentage of each isomer from the SN1 reaction.
-
18M.3.hl.TZ2.8e:
Sketch the wedge and dash (3-D) representations of alanine enantiomers.
-
18N.1.hl.TZ0.37:
How many chiral carbon atoms are present in one molecule of (CH3)2CHCHClCHBrCH3?
A. 0
B. 1
C. 2
D. 3
- 18N.2.hl.TZ0.8b.ii: State, giving a reason, whether methyloxirane can form cis-trans isomers.
-
19M.2.hl.TZ1.1e:
The organic product is not optically active. Discuss whether or not the organic product is a racemic mixture.
-
19M.2.hl.TZ2.6d(i):
Outline why the major product, C6H5–CHBr–CH3, can exist in two forms and state the relationship between these forms.
Two forms:
Relationship:
-
19M.2.hl.TZ2.6d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
-
19M.3.hl.TZ1.5a:
Label with an asterisk, *, the chiral carbon atom.
- 19M.1.hl.TZ1.37: Which compound can exist as cis- and trans-isomers?
- 19M.1.hl.TZ2.36: Which compound exists as two configurational isomers? A. CBr2=CH2 B. CH2=CHBr C....
- 19N.3.hl.TZ0.26a: State the feature of Taxol that is a major challenge in its synthesis. Use section 37 of the data...
-
19N.1.hl.TZ0.38:
Which can show optical activity?
A. CHBrCHCl
B. CH3CH2CHBrCH2CH3
C. (CH3)2CBrCl
D. CH3CH2CH(CH3)Br
-
20N.1.hl.TZ0.37:
Which molecule has an enantiomer?
A.
B.
C.
D.
- 21M.1.hl.TZ1.37: How many chiral centres are there in the following molecule? A. 2 B. 3 C. 4 D. 6
- 21M.1.hl.TZ2.35: Which compound shows cis-trans isomerism? A. CH3CH=CCl2 B. CCl2=CH2 C. D.
-
21M.1.hl.TZ2.36:
Which compound rotates the plane of plane-polarized light?
A. CH3C(CH3)ClCH3
B. CH3CH2CHClCH3
C. CH3C(Cl)2CH3
D. CH3CClBrCH3
- 21M.2.hl.TZ2.4h(i): Draw the stereoisomers of butan-2-ol using wedge-dash type representations.
- 21M.2.hl.TZ2.4h(ii): Outline how two enantiomers can be distinguished using a polarimeter.
- 21N.1.hl.TZ0.35: Which statement is correct about configurational isomers? A. Configurational isomers can only...
- 21N.2.hl.TZ0.10b(i): State, giving a reason, if but-1-ene exhibits cis-trans isomerism.
- 21N.2.hl.TZ0.10b(iv): State, giving a reason, if the product of this reaction exhibits stereoisomerism.
- 22M.1.hl.TZ1.37: What are the E/Z designations of these stereoisomers?
-
22M.2.hl.TZ1.5a(v):
Identify the isomer of Compound B that exists as optical isomers (enantiomers).
-
22M.2.hl.TZ2.8d(i):
Draw the full structural formula of (Z)-but-2-ene.
- 22N.1.hl.TZ0.33: Which compound has a chiral carbon? A. Bromoethane B. 2-bromopropane C. 2-bromobutane D. ...
- 22N.2.hl.TZ0.6c: State an instrument that could be used to determine whether the product was a single enantiomer...
-
19M.2.hl.TZ1.1e:
The organic product is not optically active. Discuss whether or not the organic product is a racemic mixture.
-
19M.2.hl.TZ1.e:
The organic product is not optically active. Discuss whether or not the organic product is a racemic mixture.
-
19M.2.hl.TZ2.6d(i):
Outline why the major product, C6H5–CHBr–CH3, can exist in two forms and state the relationship between these forms.
Two forms:
Relationship:
-
19M.2.hl.TZ2.6d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
-
19M.2.hl.TZ2.d(i):
Outline why the major product, C6H5–CHBr–CH3, can exist in two forms and state the relationship between these forms.
Two forms:
Relationship:
-
19M.2.hl.TZ2.d(ii):
The minor product, C6H5–CH2–CH2Br, can exist in different conformational forms (isomers).
Outline what this means.
-
19M.3.hl.TZ1.5a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.a:
Label with an asterisk, *, the chiral carbon atom.
- 19M.1.hl.TZ1.37: Which compound can exist as cis- and trans-isomers?
- 19M.1.hl.TZ2.36: Which compound exists as two configurational isomers? A. CBr2=CH2 B. CH2=CHBr C....
- 19N.3.hl.TZ0.26a: State the feature of Taxol that is a major challenge in its synthesis. Use section 37 of the data...
- 19N.3.hl.TZ0.a: State the feature of Taxol that is a major challenge in its synthesis. Use section 37 of the data...
-
19N.1.hl.TZ0.38:
Which can show optical activity?
A. CHBrCHCl
B. CH3CH2CHBrCH2CH3
C. (CH3)2CBrCl
D. CH3CH2CH(CH3)Br
-
20N.1.hl.TZ0.37:
Which molecule has an enantiomer?
A.
B.
C.
D.
- 21M.1.hl.TZ1.37: How many chiral centres are there in the following molecule? A. 2 B. 3 C. 4 D. 6
- 21M.1.hl.TZ2.35: Which compound shows cis-trans isomerism? A. CH3CH=CCl2 B. CCl2=CH2 C. D.
-
21M.1.hl.TZ2.36:
Which compound rotates the plane of plane-polarized light?
A. CH3C(CH3)ClCH3
B. CH3CH2CHClCH3
C. CH3C(Cl)2CH3
D. CH3CClBrCH3
- 21M.2.hl.TZ2.4h(i): Draw the stereoisomers of butan-2-ol using wedge-dash type representations.
- 21M.2.hl.TZ2.4h(ii): Outline how two enantiomers can be distinguished using a polarimeter.
- 21M.2.hl.TZ2.h(i): Draw the stereoisomers of butan-2-ol using wedge-dash type representations.
- 21M.2.hl.TZ2.h(ii): Outline how two enantiomers can be distinguished using a polarimeter.
- 21N.1.hl.TZ0.35: Which statement is correct about configurational isomers? A. Configurational isomers can only...
- 21N.2.hl.TZ0.10b(i): State, giving a reason, if but-1-ene exhibits cis-trans isomerism.
- 21N.2.hl.TZ0.10b(iv): State, giving a reason, if the product of this reaction exhibits stereoisomerism.
- 21N.2.hl.TZ0.b(i): State, giving a reason, if but-1-ene exhibits cis-trans isomerism.
- 21N.2.hl.TZ0.b(iv): State, giving a reason, if the product of this reaction exhibits stereoisomerism.
- 22M.1.hl.TZ1.37: What are the E/Z designations of these stereoisomers?
-
22M.2.hl.TZ1.5a(v):
Identify the isomer of Compound B that exists as optical isomers (enantiomers).
-
22M.2.hl.TZ1.a(v):
Identify the isomer of Compound B that exists as optical isomers (enantiomers).
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22M.2.hl.TZ2.8d(i):
Draw the full structural formula of (Z)-but-2-ene.
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22M.2.hl.TZ2.d(i):
Draw the full structural formula of (Z)-but-2-ene.
- 22N.1.hl.TZ0.33: Which compound has a chiral carbon? A. Bromoethane B. 2-bromopropane C. 2-bromobutane D. ...
- 22N.2.hl.TZ0.6c: State an instrument that could be used to determine whether the product was a single enantiomer...
- 22N.2.hl.TZ0.c: State an instrument that could be used to determine whether the product was a single enantiomer...
- 17N.1.hl.TZ0.37: What is the number of optical isomers of isoleucine? A. 0 B. 2 C. 4 D. 8
- 17N.2.hl.TZ0.8a.iv: Deduce, giving a reason, which of the two compounds can show optical activity.
- 17N.2.hl.TZ0.8a.v: Draw three-dimensional representations of the two enantiomers.
- 17N.2.hl.TZ0.a.iv: Deduce, giving a reason, which of the two compounds can show optical activity.
- 17N.2.hl.TZ0.a.v: Draw three-dimensional representations of the two enantiomers.
- 18M.1.hl.TZ1.35: What is name of this compound applying IUPAC rules? A. E 1-bromo-1-chlorobut-1-ene B. ...
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18M.1.hl.TZ1.36:
Which molecule contains a chiral carbon?
A. CH3CH2CHBrCH2CH3
B. CH3CH2CHBrCH3
C. CH2BrCH(CH3)CH2Br
D. CH3CH2CH2CH2CH2Br
- 18M.1.hl.TZ2.37: Which isomers exist as non-superimposable mirror images? A. cis-trans isomers B. ...
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18M.2.hl.TZ2.9b.iv:
Suggest, giving a reason, the percentage of each isomer from the SN1 reaction.
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18M.2.hl.TZ2.b.iv:
Suggest, giving a reason, the percentage of each isomer from the SN1 reaction.
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18M.3.hl.TZ2.8e:
Sketch the wedge and dash (3-D) representations of alanine enantiomers.
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18M.3.hl.TZ2.e:
Sketch the wedge and dash (3-D) representations of alanine enantiomers.
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18N.1.hl.TZ0.37:
How many chiral carbon atoms are present in one molecule of (CH3)2CHCHClCHBrCH3?
A. 0
B. 1
C. 2
D. 3
- 18N.2.hl.TZ0.8b.ii: State, giving a reason, whether methyloxirane can form cis-trans isomers.
- 18N.2.hl.TZ0.b.ii: State, giving a reason, whether methyloxirane can form cis-trans isomers.