DP Chemistry (last assessment 2024)
Question 18M.2.hl.TZ2.9c
Date | May 2018 | Marks available | [Maximum mark: 2] | Reference code | 18M.2.hl.TZ2.9c |
Level | hl | Paper | 2 | Time zone | TZ2 |
Command term | Formulate | Question number | c | Adapted from | N/A |
c.
[Maximum mark: 2]
18M.2.hl.TZ2.9c
(c)
Nitrobenzene, C6H5NO2, can be converted to phenylamine via a two-stage reaction.
In the first stage, nitrobenzene is reduced with tin in an acidic solution to form an intermediate ion and tin(II) ions. In the second stage, the intermediate ion is converted to phenylamine in the presence of hydroxide ions.
Formulate the equation for each stage of the reaction.
[2]
Markscheme
Stage one:
C6H5NO2(l) + 3Sn(s) + 7H+(aq) → C6H5NH3+(aq) + 3Sn2+(aq) + 2H2O(l)
Stage two:
C6H5NH3+(aq) + OH–(aq) → C6H5NH2(l) + H2O(l)
[2 marks]