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Question 19N.2.hl.TZ0.a(iv)

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Date November 2019 Marks available [Maximum mark: 1] Reference code 19N.2.hl.TZ0.a(iv)
Level hl Paper 2 Time zone TZ0
Command term Write Question number a(iv) Adapted from N/A
a(iv).
[Maximum mark: 1]
19N.2.hl.TZ0.a(iv)

Propene is an important starting material for many products. The following shows some compounds which can be made from propene, C3H6.


Propene (C3H6) → C3H7Cl → C3H8O → C3H6O

Consider the conversion of propene to C3H7Cl.

Write an equation for the reaction of the major product with aqueous sodium hydroxide to produce a C3H8O compound, showing structural formulas.

[1]

Markscheme

CH3CHClCH3 (l) + OH (aq) → CH3CH(OH)CH3 (aq) + Cl (aq)
OR
CH3CHClCH3 (l) + NaOH (aq) → CH3CH(OH)CH3 (aq) + NaCl (aq) ✔