DP Chemistry (last assessment 2024)

Question 19M.3.hl.TZ2.b

Date	May 2019	Marks available	[Maximum mark: 2]	Reference code	19M.3.hl.TZ2.b
Level	hl	Paper	3	Time zone	TZ2
Command term	Determine	Question number	b	Adapted from	N/A

[Maximum mark: 2]

19M.3.hl.TZ2.b

Electricity can be generated in a variety of ways.

The cell potential for the spontaneous reaction when standard magnesium and silver half-cells are connected is +3.17 V.

Determine the cell potential at 298 K when:

[Mg²⁺] = 0.0500 mol dm⁻³
[Ag⁺] = 0.100 mol dm⁻³

Use sections 1 and 2 of the data booklet.

[2]

Markscheme

«E = Eᶱ $\frac{{RT}}{{nF}}$ × lnQ»

lnQ = « $\frac{{[{\text{M}}{{\text{g}}^{2 + }}]}}{{{{[{\text{A}}{{\text{g}}^ + }]}^2}}} = \frac{{0.0500}}{{{{0.100}^2}}} = \ln 5.00 =$ » 1.61 [✔]

E = «3.17 V $- \frac{{8.31{\text{ J }}{{\text{K}}^{ - 1}}{\text{ mo}}{{\text{l}}^{ - 1}} \times 298{\text{ K}}}}{{2 \times 96500{\text{ J }}{{\text{V}}^{ - 1}}{\text{ mo}}{{\text{l}}^{ - 1}}}} \times \ln \frac{{0.0500}}{{{{0.100}^2}}} = 3.17 - 0.021 = +$ »3.15 «V» [✔]

Note: Award [2] for correct final answer.

Examiners report

The cell potential was correctly calculated by several candidates with some candidates managed an ECF mark for an error in the calculation. Unfortunately, the ln Q part was frequently wrong due to candidates forgetting to square the denominator.

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Options » C: Energy » C.6 Electrochemistry, rechargeable batteries and fuel cells (HL only)

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Question 19M.3.hl.TZ2.b

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