Question 19N.3.sl.TZ0.b(ii)
Date | November 2019 | Marks available | [Maximum mark: 3] | Reference code | 19N.3.sl.TZ0.b(ii) |
Level | sl | Paper | 3 | Time zone | TZ0 |
Command term | Deduce, Formulate | Question number | b(ii) | Adapted from | N/A |
Metals are extracted from their ores by various means.
Aluminium is produced by the electrolysis of alumina (aluminium oxide) dissolved in cryolite.
Write half-equations for the electrolysis of molten alumina using graphite electrodes, deducing the state symbols of the products.
Anode (positive electrode):
Cathode (negative electrode):
[3]
Anode (positive electrode):
2O2− → 4e− + O2(g)
OR
2O2− + C → 4e− + CO2 (g) ✔
NOTE: Award [1 max] for M1 and M2 if correct half-equations are given at the wrong electrodes OR if incorrect reversed half-equations are given at the correct electrodes.
Cathode (negative electrode):
Al3+ + 3e− → Al (l) ✔
O2 gas AND Al liquid ✔
NOTE: Only state symbols of products required, which might be written as (g) and (l) in half-equations. Ignore any incorrect or missing state symbols for reactants.
