Directly related questions
- 20N.3.sl.TZ0.3b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.sl.TZ0.3b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.sl.TZ0.b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.sl.TZ0.3c: Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.sl.TZ0.3c: Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.sl.TZ0.c: Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.sl.TZ0.4b(i): Alloying metals changes their properties. Suggest one property of magnesium that could be...
- 20N.3.sl.TZ0.4b(i): Alloying metals changes their properties. Suggest one property of magnesium that could be...
- 20N.3.sl.TZ0.b(i): Alloying metals changes their properties. Suggest one property of magnesium that could be...
- 20N.3.sl.TZ0.3b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.sl.TZ0.3b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.sl.TZ0.b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.sl.TZ0.4d: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.sl.TZ0.4d: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.sl.TZ0.d: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
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20N.3.sl.TZ0.4b(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020.
Write the half-equations for the reactions occurring in this electrolysis.
-
20N.3.sl.TZ0.4b(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020.
Write the half-equations for the reactions occurring in this electrolysis.
-
20N.3.sl.TZ0.b(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020.
Write the half-equations for the reactions occurring in this electrolysis.
-
20N.3.sl.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.3.sl.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.3.sl.TZ0.a:
Outline the two distinct phases of this composite.
-
20N.3.sl.TZ0.4b(iv):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
20N.3.sl.TZ0.4b(iv):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
20N.3.sl.TZ0.b(iv):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
- 20N.3.hl.TZ0.4d: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.hl.TZ0.4d: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.hl.TZ0.d: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.hl.TZ0.4b(i): CNT can act as Type 2 superconductors. Outline why Type 2 superconductors are generally more...
- 20N.3.hl.TZ0.4b(i): CNT can act as Type 2 superconductors. Outline why Type 2 superconductors are generally more...
- 20N.3.hl.TZ0.b(i): CNT can act as Type 2 superconductors. Outline why Type 2 superconductors are generally more...
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20N.3.hl.TZ0.5a:
Precipitation is one method used to treat waste water.
Phosphates, , in waste water can be removed by precipitation with magnesium ions. of magnesium phosphate is .
Calculate the maximum solubility of phosphate ions in a solution containing magnesium ions.
-
20N.3.hl.TZ0.5a:
Precipitation is one method used to treat waste water.
Phosphates, , in waste water can be removed by precipitation with magnesium ions. of magnesium phosphate is .
Calculate the maximum solubility of phosphate ions in a solution containing magnesium ions.
-
20N.3.hl.TZ0.a:
Precipitation is one method used to treat waste water.
Phosphates, , in waste water can be removed by precipitation with magnesium ions. of magnesium phosphate is .
Calculate the maximum solubility of phosphate ions in a solution containing magnesium ions.
- 20N.3.hl.TZ0.3b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.hl.TZ0.3b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.hl.TZ0.b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
-
20N.3.hl.TZ0.4c(iii):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
20N.3.hl.TZ0.4c(iii):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
20N.3.hl.TZ0.c(iii):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
17N.3.sl.TZ0.4a:
Outline the composition of an alloy and a composite.
-
17N.3.sl.TZ0.4a:
Outline the composition of an alloy and a composite.
-
17N.3.sl.TZ0.a:
Outline the composition of an alloy and a composite.
-
17N.3.sl.TZ0.6a:
State equations for the formation of iron nanoparticles and carbon atoms from Fe(CO)5 in the HIPCO process.
-
17N.3.sl.TZ0.6a:
State equations for the formation of iron nanoparticles and carbon atoms from Fe(CO)5 in the HIPCO process.
-
17N.3.sl.TZ0.a:
State equations for the formation of iron nanoparticles and carbon atoms from Fe(CO)5 in the HIPCO process.
- 17N.3.hl.TZ0.7b: Describe how the monomers of addition polymers and of condensation polymers differ.
- 17N.3.hl.TZ0.7b: Describe how the monomers of addition polymers and of condensation polymers differ.
- 17N.3.hl.TZ0.b: Describe how the monomers of addition polymers and of condensation polymers differ.
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17N.3.hl.TZ0.9b:
The solubility product, Ksp , of cadmium sulfide, CdS, is 8.0 × 10–27. Determine the concentration of cadmium ions in 1.0 dm3 of a saturated solution of cadmium sulfide to which 0.10 mol of solid sodium sulfide has been added, stating any assumption you make.
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17N.3.hl.TZ0.9b:
The solubility product, Ksp , of cadmium sulfide, CdS, is 8.0 × 10–27. Determine the concentration of cadmium ions in 1.0 dm3 of a saturated solution of cadmium sulfide to which 0.10 mol of solid sodium sulfide has been added, stating any assumption you make.
-
17N.3.hl.TZ0.b:
The solubility product, Ksp , of cadmium sulfide, CdS, is 8.0 × 10–27. Determine the concentration of cadmium ions in 1.0 dm3 of a saturated solution of cadmium sulfide to which 0.10 mol of solid sodium sulfide has been added, stating any assumption you make.
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17N.3.sl.TZ0.7b.ii:
One of the two infrared (IR) spectra is that of polyethene and the other of polytetrafluoroethene (PTFE).
Deduce, with a reason, which spectrum is that of PTFE. Infrared data is given in section 26 of the data booklet.
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17N.3.sl.TZ0.7b.ii:
One of the two infrared (IR) spectra is that of polyethene and the other of polytetrafluoroethene (PTFE).
Deduce, with a reason, which spectrum is that of PTFE. Infrared data is given in section 26 of the data booklet.
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17N.3.sl.TZ0.b.ii:
One of the two infrared (IR) spectra is that of polyethene and the other of polytetrafluoroethene (PTFE).
Deduce, with a reason, which spectrum is that of PTFE. Infrared data is given in section 26 of the data booklet.
-
17N.3.hl.TZ0.8a:
Calculate the total number of cobalt atoms within its unit cell.
-
17N.3.hl.TZ0.8a:
Calculate the total number of cobalt atoms within its unit cell.
-
17N.3.hl.TZ0.a:
Calculate the total number of cobalt atoms within its unit cell.
-
17N.3.hl.TZ0.6b:
Explain why Type 2 superconductors are generally more useful than Type 1.
-
17N.3.hl.TZ0.6b:
Explain why Type 2 superconductors are generally more useful than Type 1.
-
17N.3.hl.TZ0.b:
Explain why Type 2 superconductors are generally more useful than Type 1.
-
17N.3.hl.TZ0.7c:
Identify the type of intermolecular bonding that is responsible for Kevlar®’s strength.
-
17N.3.hl.TZ0.7c:
Identify the type of intermolecular bonding that is responsible for Kevlar®’s strength.
-
17N.3.hl.TZ0.c:
Identify the type of intermolecular bonding that is responsible for Kevlar®’s strength.
-
17N.3.hl.TZ0.8b.i:
The atomic radius, r, of cobalt is 1.18 × 10–8 cm. Determine the edge length, in cm, of the unit cell, a, using the second diagram.
-
17N.3.hl.TZ0.8b.i:
The atomic radius, r, of cobalt is 1.18 × 10–8 cm. Determine the edge length, in cm, of the unit cell, a, using the second diagram.
-
17N.3.hl.TZ0.b.i:
The atomic radius, r, of cobalt is 1.18 × 10–8 cm. Determine the edge length, in cm, of the unit cell, a, using the second diagram.
-
17N.3.hl.TZ0.8b.ii:
Determine a value for the density of cobalt, in g cm–3, using data from sections 2 and 6 of the data booklet and your answers from (a) and (b) (i).
If you did not obtain an answer to (b) (i), use 3.00 × 10–8 cm but this is not the correct answer.
-
17N.3.hl.TZ0.8b.ii:
Determine a value for the density of cobalt, in g cm–3, using data from sections 2 and 6 of the data booklet and your answers from (a) and (b) (i).
If you did not obtain an answer to (b) (i), use 3.00 × 10–8 cm but this is not the correct answer.
-
17N.3.hl.TZ0.b.ii:
Determine a value for the density of cobalt, in g cm–3, using data from sections 2 and 6 of the data booklet and your answers from (a) and (b) (i).
If you did not obtain an answer to (b) (i), use 3.00 × 10–8 cm but this is not the correct answer.
- 17N.3.hl.TZ0.9a: State the name of one method, other than precipitation, of removing heavy metal ions from...
- 17N.3.hl.TZ0.9a: State the name of one method, other than precipitation, of removing heavy metal ions from...
- 17N.3.hl.TZ0.a: State the name of one method, other than precipitation, of removing heavy metal ions from...
- 17N.3.sl.TZ0.4b.i: Outline why an alloy is usually harder than its components by referring to its structure.
- 17N.3.sl.TZ0.4b.i: Outline why an alloy is usually harder than its components by referring to its structure.
- 17N.3.sl.TZ0.b.i: Outline why an alloy is usually harder than its components by referring to its structure.
- 17N.3.sl.TZ0.4b.ii: At present, composite fillings are more expensive than amalgam fillings. Suggest why a patient...
- 17N.3.sl.TZ0.4b.ii: At present, composite fillings are more expensive than amalgam fillings. Suggest why a patient...
- 17N.3.sl.TZ0.b.ii: At present, composite fillings are more expensive than amalgam fillings. Suggest why a patient...
-
17N.3.sl.TZ0.4c:
Explain how Inductively Coupled Plasma (ICP) Spectroscopy could be used to determine the concentration of mercury in a sample of dental filling.
-
17N.3.sl.TZ0.4c:
Explain how Inductively Coupled Plasma (ICP) Spectroscopy could be used to determine the concentration of mercury in a sample of dental filling.
-
17N.3.sl.TZ0.c:
Explain how Inductively Coupled Plasma (ICP) Spectroscopy could be used to determine the concentration of mercury in a sample of dental filling.
-
17N.3.sl.TZ0.5:
Catalysts can take many forms and are used in many industrial processes.
Suggest two reasons why it might be worth using a more expensive catalyst to increase the rate of a reaction.
-
17N.3.sl.TZ0.5:
Catalysts can take many forms and are used in many industrial processes.
Suggest two reasons why it might be worth using a more expensive catalyst to increase the rate of a reaction.
-
17N.3.sl.TZ0.7a:
Outline two properties a substance should have to be used as liquid-crystal in a liquid-crystal display.
-
17N.3.sl.TZ0.7a:
Outline two properties a substance should have to be used as liquid-crystal in a liquid-crystal display.
-
17N.3.sl.TZ0.a:
Outline two properties a substance should have to be used as liquid-crystal in a liquid-crystal display.
-
17N.3.sl.TZ0.7c:
Many plastics used to be incinerated. Deduce an equation for the complete combustion of two repeating units of PVC, (–C2H3Cl–)2.
-
17N.3.sl.TZ0.7c:
Many plastics used to be incinerated. Deduce an equation for the complete combustion of two repeating units of PVC, (–C2H3Cl–)2.
-
17N.3.sl.TZ0.c:
Many plastics used to be incinerated. Deduce an equation for the complete combustion of two repeating units of PVC, (–C2H3Cl–)2.
- 17N.3.sl.TZ0.6c: Discuss one possible risk associated with the use of nanotechnology.
- 17N.3.sl.TZ0.6c: Discuss one possible risk associated with the use of nanotechnology.
- 17N.3.sl.TZ0.c: Discuss one possible risk associated with the use of nanotechnology.
-
17N.3.sl.TZ0.7b.i:
Describe how the structures of LDPE and HDPE affect one mechanical property of the plastics.
-
17N.3.sl.TZ0.7b.i:
Describe how the structures of LDPE and HDPE affect one mechanical property of the plastics.
-
17N.3.sl.TZ0.b.i:
Describe how the structures of LDPE and HDPE affect one mechanical property of the plastics.
-
18M.3.hl.TZ1.4c.i:
Draw the structure of the monomer from which nylon-6 is produced by a condensation reaction.
-
18M.3.hl.TZ1.4c.i:
Draw the structure of the monomer from which nylon-6 is produced by a condensation reaction.
-
18M.3.hl.TZ1.c.i:
Draw the structure of the monomer from which nylon-6 is produced by a condensation reaction.
-
18M.3.hl.TZ2.4a.i:
Deduce the number of atoms per unit cell in vanadium.
-
18M.3.hl.TZ2.4a.i:
Deduce the number of atoms per unit cell in vanadium.
-
18M.3.hl.TZ2.a.i:
Deduce the number of atoms per unit cell in vanadium.
-
18M.3.hl.TZ2.4b.i:
Vanadium and other transition metals can interfere with cell metabolism.
State and explain one process, other than by creating free radicals, by which transition metals interfere with cell metabolism.
-
18M.3.hl.TZ2.4b.i:
Vanadium and other transition metals can interfere with cell metabolism.
State and explain one process, other than by creating free radicals, by which transition metals interfere with cell metabolism.
-
18M.3.hl.TZ2.b.i:
Vanadium and other transition metals can interfere with cell metabolism.
State and explain one process, other than by creating free radicals, by which transition metals interfere with cell metabolism.
-
18M.3.hl.TZ1.5b:
The diagram illustrates the crystal structure of aluminium metal with the unit cell indicated. Outline the significance of the unit cell.
-
18M.3.hl.TZ1.5b:
The diagram illustrates the crystal structure of aluminium metal with the unit cell indicated. Outline the significance of the unit cell.
-
18M.3.hl.TZ1.b:
The diagram illustrates the crystal structure of aluminium metal with the unit cell indicated. Outline the significance of the unit cell.
-
18M.3.hl.TZ1.5e:
The concentration of aluminium in drinking water can be reduced by precipitating aluminium hydroxide. Calculate the maximum concentration of aluminium ions in water of pH 7 at 298 K. Solubility product of aluminium hydroxide = 3.3 × 10−34 at 298 K.
-
18M.3.hl.TZ1.5e:
The concentration of aluminium in drinking water can be reduced by precipitating aluminium hydroxide. Calculate the maximum concentration of aluminium ions in water of pH 7 at 298 K. Solubility product of aluminium hydroxide = 3.3 × 10−34 at 298 K.
-
18M.3.hl.TZ1.e:
The concentration of aluminium in drinking water can be reduced by precipitating aluminium hydroxide. Calculate the maximum concentration of aluminium ions in water of pH 7 at 298 K. Solubility product of aluminium hydroxide = 3.3 × 10−34 at 298 K.
-
18M.3.hl.TZ1.5c:
When X-rays of wavelength 0.154 nm are directed at a crystal of aluminium, the first order diffraction pattern is observed at 18°. Determine the separation of layers of aluminium atoms in the crystal, in m, using section 1 of the data booklet.
-
18M.3.hl.TZ1.5c:
When X-rays of wavelength 0.154 nm are directed at a crystal of aluminium, the first order diffraction pattern is observed at 18°. Determine the separation of layers of aluminium atoms in the crystal, in m, using section 1 of the data booklet.
-
18M.3.hl.TZ1.c:
When X-rays of wavelength 0.154 nm are directed at a crystal of aluminium, the first order diffraction pattern is observed at 18°. Determine the separation of layers of aluminium atoms in the crystal, in m, using section 1 of the data booklet.
-
18M.3.hl.TZ2.5c.i:
Distinguish between the manufacture of polyester and polyethene.
-
18M.3.hl.TZ2.5c.i:
Distinguish between the manufacture of polyester and polyethene.
-
18M.3.hl.TZ2.c.i:
Distinguish between the manufacture of polyester and polyethene.
-
18M.3.hl.TZ1.5d.i:
Deduce what the shape of the graph indicates about aluminium.
-
18M.3.hl.TZ1.5d.i:
Deduce what the shape of the graph indicates about aluminium.
-
18M.3.hl.TZ1.d.i:
Deduce what the shape of the graph indicates about aluminium.
-
18M.3.hl.TZ2.4a.iii:
Calculate the average mass, in g, of a vanadium atom by using sections 2 and 6 of the data booklet.
-
18M.3.hl.TZ2.4a.iii:
Calculate the average mass, in g, of a vanadium atom by using sections 2 and 6 of the data booklet.
-
18M.3.hl.TZ2.a.iii:
Calculate the average mass, in g, of a vanadium atom by using sections 2 and 6 of the data booklet.
-
18M.3.hl.TZ2.6b:
MWCNT are very small in size and can greatly increase switching speeds in a liquid crystal allowing the liquid crystal to change orientation quickly.
Discuss two other properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.hl.TZ2.6b:
MWCNT are very small in size and can greatly increase switching speeds in a liquid crystal allowing the liquid crystal to change orientation quickly.
Discuss two other properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.hl.TZ2.b:
MWCNT are very small in size and can greatly increase switching speeds in a liquid crystal allowing the liquid crystal to change orientation quickly.
Discuss two other properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.hl.TZ2.4a.ii:
Calculate the expected first order diffraction pattern angle, in degrees, if x-rays of wavelength 150 pm are directed at a crystal of vanadium. Assume the edge length of the crystal to be the same as separation of layers of vanadium atoms found by x-ray diffraction. Use section 1 of the data booklet.
-
18M.3.hl.TZ2.4a.ii:
Calculate the expected first order diffraction pattern angle, in degrees, if x-rays of wavelength 150 pm are directed at a crystal of vanadium. Assume the edge length of the crystal to be the same as separation of layers of vanadium atoms found by x-ray diffraction. Use section 1 of the data booklet.
-
18M.3.hl.TZ2.a.ii:
Calculate the expected first order diffraction pattern angle, in degrees, if x-rays of wavelength 150 pm are directed at a crystal of vanadium. Assume the edge length of the crystal to be the same as separation of layers of vanadium atoms found by x-ray diffraction. Use section 1 of the data booklet.
-
18M.3.hl.TZ2.4a.iv:
Determine the volume, in cm3, of a vanadium unit cell.
-
18M.3.hl.TZ2.4a.iv:
Determine the volume, in cm3, of a vanadium unit cell.
-
18M.3.hl.TZ2.a.iv:
Determine the volume, in cm3, of a vanadium unit cell.
-
18M.3.hl.TZ1.5d.ii:
Outline why the resistance of aluminium increases above 1.2 K.
-
18M.3.hl.TZ1.5d.ii:
Outline why the resistance of aluminium increases above 1.2 K.
-
18M.3.hl.TZ1.d.ii:
Outline why the resistance of aluminium increases above 1.2 K.
-
18M.3.hl.TZ2.4a.v:
Determine the density, in g cm−3, of vanadium by using your answers to (a)(i), (a)(iii) and (a)(iv).
-
18M.3.hl.TZ2.4a.v:
Determine the density, in g cm−3, of vanadium by using your answers to (a)(i), (a)(iii) and (a)(iv).
-
18M.3.hl.TZ2.a.v:
Determine the density, in g cm−3, of vanadium by using your answers to (a)(i), (a)(iii) and (a)(iv).
-
18M.3.hl.TZ2.4b.ii:
Vanadium(IV) ions can create free radicals by a Fenton reaction.
Deduce the equation for the reaction of V4+ with hydrogen peroxide.
-
18M.3.hl.TZ2.4b.ii:
Vanadium(IV) ions can create free radicals by a Fenton reaction.
Deduce the equation for the reaction of V4+ with hydrogen peroxide.
-
18M.3.hl.TZ2.b.ii:
Vanadium(IV) ions can create free radicals by a Fenton reaction.
Deduce the equation for the reaction of V4+ with hydrogen peroxide.
-
18M.3.sl.TZ1.3a:
Discuss, in terms of its structure, why an aluminium saucepan is impermeable to water.
-
18M.3.sl.TZ1.3a:
Discuss, in terms of its structure, why an aluminium saucepan is impermeable to water.
-
18M.3.sl.TZ1.a:
Discuss, in terms of its structure, why an aluminium saucepan is impermeable to water.
-
18M.3.sl.TZ1.3b.i:
State the name given to a material composed of two distinct solid phases.
-
18M.3.sl.TZ1.3b.i:
State the name given to a material composed of two distinct solid phases.
-
18M.3.sl.TZ1.b.i:
State the name given to a material composed of two distinct solid phases.
-
18M.3.sl.TZ1.3b.ii:
State one physical property of HDPE that will be affected by the incorporation of carbon nanotubes.
-
18M.3.sl.TZ1.3b.ii:
State one physical property of HDPE that will be affected by the incorporation of carbon nanotubes.
-
18M.3.sl.TZ1.b.ii:
State one physical property of HDPE that will be affected by the incorporation of carbon nanotubes.
-
18M.3.sl.TZ1.3b.iii:
Describe how carbon nanotubes are produced by chemical vapour deposition (CVD).
-
18M.3.sl.TZ1.3b.iii:
Describe how carbon nanotubes are produced by chemical vapour deposition (CVD).
-
18M.3.sl.TZ1.b.iii:
Describe how carbon nanotubes are produced by chemical vapour deposition (CVD).
-
18M.3.sl.TZ1.3b.iv:
State the property of carbon nanotubes that enables them to form a nematic liquid crystal phase.
-
18M.3.sl.TZ1.3b.iv:
State the property of carbon nanotubes that enables them to form a nematic liquid crystal phase.
-
18M.3.sl.TZ1.b.iv:
State the property of carbon nanotubes that enables them to form a nematic liquid crystal phase.
-
18M.3.sl.TZ1.4a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ1.4a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ1.a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ1.4b.i:
Compare and contrast the structures of HDPE and LDPE.
-
18M.3.sl.TZ1.4b.i:
Compare and contrast the structures of HDPE and LDPE.
-
18M.3.sl.TZ1.b.i:
Compare and contrast the structures of HDPE and LDPE.
-
18M.3.sl.TZ1.4b.ii:
State one way in which a physical property of HDPE, other than density, differs from that of LDPE as a result of this structural difference.
-
18M.3.sl.TZ1.4b.ii:
State one way in which a physical property of HDPE, other than density, differs from that of LDPE as a result of this structural difference.
-
18M.3.sl.TZ1.b.ii:
State one way in which a physical property of HDPE, other than density, differs from that of LDPE as a result of this structural difference.
-
18M.3.sl.TZ1.4c.i:
The production of HDPE involves the use of homogeneous catalysts. Outline how homogeneous catalysts reduce the activation energy of reactions.
-
18M.3.sl.TZ1.4c.i:
The production of HDPE involves the use of homogeneous catalysts. Outline how homogeneous catalysts reduce the activation energy of reactions.
-
18M.3.sl.TZ1.c.i:
The production of HDPE involves the use of homogeneous catalysts. Outline how homogeneous catalysts reduce the activation energy of reactions.
-
18M.3.sl.TZ1.4c.ii:
Trace amounts of metal from the catalysts used in the production of HDPE sometimes remain in the product. State a technique that could be used to measure the concentration of the metal.
-
18M.3.sl.TZ1.4c.ii:
Trace amounts of metal from the catalysts used in the production of HDPE sometimes remain in the product. State a technique that could be used to measure the concentration of the metal.
-
18M.3.sl.TZ1.c.ii:
Trace amounts of metal from the catalysts used in the production of HDPE sometimes remain in the product. State a technique that could be used to measure the concentration of the metal.
-
18M.3.sl.TZ1.4d:
Suggest two of the major obstacles, other than collection and economic factors, which have to be overcome in plastic recycling.
-
18M.3.sl.TZ1.4d:
Suggest two of the major obstacles, other than collection and economic factors, which have to be overcome in plastic recycling.
-
18M.3.sl.TZ1.d:
Suggest two of the major obstacles, other than collection and economic factors, which have to be overcome in plastic recycling.
-
18M.3.sl.TZ1.5:
Aluminium is produced by the electrolysis of a molten electrolyte containing bauxite.
Determine the mass, in g, of aluminium produced by the passage of a charge of 1.296 × 1013 C. Use sections 2 and 6 of the data booklet.
-
18M.3.sl.TZ1.5:
Aluminium is produced by the electrolysis of a molten electrolyte containing bauxite.
Determine the mass, in g, of aluminium produced by the passage of a charge of 1.296 × 1013 C. Use sections 2 and 6 of the data booklet.
-
18M.3.sl.TZ2.3a:
ICP-OES/MS can be used to analyse alloys and composites. Distinguish between alloys and composites.
-
18M.3.sl.TZ2.3a:
ICP-OES/MS can be used to analyse alloys and composites. Distinguish between alloys and composites.
-
18M.3.sl.TZ2.a:
ICP-OES/MS can be used to analyse alloys and composites. Distinguish between alloys and composites.
-
18M.3.sl.TZ2.3b:
ICP-MS is a reference mode for analysis. The following correlation graphs between ICP-OES and ICP-MS were produced for yttrium and nickel.
Each y-axis shows concentrations calculated by ICP-OES; each x-axis shows concentrations for the same sample as found by ICP-MS.
The line in each graph is y = x.
Discuss the effectiveness of ICP-OES for yttrium and nickel.
-
18M.3.sl.TZ2.3b:
ICP-MS is a reference mode for analysis. The following correlation graphs between ICP-OES and ICP-MS were produced for yttrium and nickel.
Each y-axis shows concentrations calculated by ICP-OES; each x-axis shows concentrations for the same sample as found by ICP-MS.
The line in each graph is y = x.
Discuss the effectiveness of ICP-OES for yttrium and nickel.
-
18M.3.sl.TZ2.b:
ICP-MS is a reference mode for analysis. The following correlation graphs between ICP-OES and ICP-MS were produced for yttrium and nickel.
Each y-axis shows concentrations calculated by ICP-OES; each x-axis shows concentrations for the same sample as found by ICP-MS.
The line in each graph is y = x.
Discuss the effectiveness of ICP-OES for yttrium and nickel.
-
18M.3.sl.TZ2.3c.i:
Identify the purpose of each graph.
-
18M.3.sl.TZ2.3c.i:
Identify the purpose of each graph.
-
18M.3.sl.TZ2.c.i:
Identify the purpose of each graph.
-
18M.3.sl.TZ2.3c.ii:
Calculate, to four significant figures, the concentration, in μg kg−1, of vanadium in oil giving a signal intensity of 14 950.
-
18M.3.sl.TZ2.3c.ii:
Calculate, to four significant figures, the concentration, in μg kg−1, of vanadium in oil giving a signal intensity of 14 950.
-
18M.3.sl.TZ2.c.ii:
Calculate, to four significant figures, the concentration, in μg kg−1, of vanadium in oil giving a signal intensity of 14 950.
-
18M.3.sl.TZ2.3c.iii:
Vanadium(V) oxide is used as the catalyst in the conversion of sulfur dioxide to sulfur trioxide.
SO2(g) + V2O5(s) → SO3(g) + 2VO2(s)
O2(g) + 2VO2(s) → V2O5(s)
Outline how vanadium(V) oxide acts as a catalyst.
-
18M.3.sl.TZ2.3c.iii:
Vanadium(V) oxide is used as the catalyst in the conversion of sulfur dioxide to sulfur trioxide.
SO2(g) + V2O5(s) → SO3(g) + 2VO2(s)
O2(g) + 2VO2(s) → V2O5(s)
Outline how vanadium(V) oxide acts as a catalyst.
-
18M.3.sl.TZ2.c.iii:
Vanadium(V) oxide is used as the catalyst in the conversion of sulfur dioxide to sulfur trioxide.
SO2(g) + V2O5(s) → SO3(g) + 2VO2(s)
O2(g) + 2VO2(s) → V2O5(s)
Outline how vanadium(V) oxide acts as a catalyst.
-
18M.3.sl.TZ2.4a:
Sketch four repeating units of the polymer to show atactic and isotactic polypropene.
-
18M.3.sl.TZ2.4a:
Sketch four repeating units of the polymer to show atactic and isotactic polypropene.
-
18M.3.sl.TZ2.a:
Sketch four repeating units of the polymer to show atactic and isotactic polypropene.
-
18M.3.sl.TZ2.4b.i:
State the chemical reason why plastics do not degrade easily.
-
18M.3.sl.TZ2.4b.i:
State the chemical reason why plastics do not degrade easily.
-
18M.3.sl.TZ2.b.i:
State the chemical reason why plastics do not degrade easily.
-
18M.3.sl.TZ2.5a:
State the source of carbon for MWCNT produced by arc discharge and by CVD.
-
18M.3.sl.TZ2.5a:
State the source of carbon for MWCNT produced by arc discharge and by CVD.
-
18M.3.sl.TZ2.a:
State the source of carbon for MWCNT produced by arc discharge and by CVD.
-
18M.3.sl.TZ2.5b:
Discuss three properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.sl.TZ2.5b:
Discuss three properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.sl.TZ2.b:
Discuss three properties a substance should have to be suitable for use in liquid crystal displays.
-
18N.3.hl.TZ0.2b:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.hl.TZ0.2b:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.hl.TZ0.b:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.sl.TZ0.2b.ii:
In an incomplete combustion of the polyvinyl chloride, PVC, it was found that hydrogen chloride, carbon monoxide, carbon dioxide, and water vapour were released.
Formulate an equation for this reaction using the formula of the PVC repeating unit.
-
18N.3.sl.TZ0.2b.ii:
In an incomplete combustion of the polyvinyl chloride, PVC, it was found that hydrogen chloride, carbon monoxide, carbon dioxide, and water vapour were released.
Formulate an equation for this reaction using the formula of the PVC repeating unit.
-
18N.3.sl.TZ0.b.ii:
In an incomplete combustion of the polyvinyl chloride, PVC, it was found that hydrogen chloride, carbon monoxide, carbon dioxide, and water vapour were released.
Formulate an equation for this reaction using the formula of the PVC repeating unit.
-
18N.3.sl.TZ0.3c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
-
18N.3.sl.TZ0.3c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
-
18N.3.sl.TZ0.c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
-
18N.3.sl.TZ0.3b:
An unknown antacid sample has a lead ion concentration of 0.50 μg dm‒3.
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.sl.TZ0.3b:
An unknown antacid sample has a lead ion concentration of 0.50 μg dm‒3.
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.sl.TZ0.b:
An unknown antacid sample has a lead ion concentration of 0.50 μg dm‒3.
Calculate the concentration of lead ions in the sample in mol dm‒3.
- 18N.3.sl.TZ0.2c.i: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.sl.TZ0.2c.i: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.sl.TZ0.c.i: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
-
18N.3.hl.TZ0.3d.ii:
An aqueous lead(II) ion reacts with three ethane-1,2-diamine molecules to form an octahedral chelate ion.
Outline why the chelate ion is more stable than the reactants.
-
18N.3.hl.TZ0.3d.ii:
An aqueous lead(II) ion reacts with three ethane-1,2-diamine molecules to form an octahedral chelate ion.
Outline why the chelate ion is more stable than the reactants.
-
18N.3.hl.TZ0.d.ii:
An aqueous lead(II) ion reacts with three ethane-1,2-diamine molecules to form an octahedral chelate ion.
Outline why the chelate ion is more stable than the reactants.
-
18N.3.sl.TZ0.2a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.sl.TZ0.2a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.sl.TZ0.a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.sl.TZ0.4c:
Arc discharge, consisting of two inert metal electrodes in a liquid solvent, is one method of producing carbon nanotubes (CNTs).
Predict, giving a reason, the electrode at which the solvent cyclohexane, C6H12, will decompose to form CNTs.
-
18N.3.sl.TZ0.4c:
Arc discharge, consisting of two inert metal electrodes in a liquid solvent, is one method of producing carbon nanotubes (CNTs).
Predict, giving a reason, the electrode at which the solvent cyclohexane, C6H12, will decompose to form CNTs.
-
18N.3.sl.TZ0.c:
Arc discharge, consisting of two inert metal electrodes in a liquid solvent, is one method of producing carbon nanotubes (CNTs).
Predict, giving a reason, the electrode at which the solvent cyclohexane, C6H12, will decompose to form CNTs.
-
18N.3.hl.TZ0.2a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.hl.TZ0.2a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.hl.TZ0.a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
- 18N.3.hl.TZ0.2d.i: State the names of the two terminal functional groups in X.
- 18N.3.hl.TZ0.2d.i: State the names of the two terminal functional groups in X.
- 18N.3.hl.TZ0.d.i: State the names of the two terminal functional groups in X.
- 18N.3.sl.TZ0.4a: Outline two observations that he could have made.
- 18N.3.sl.TZ0.4a: Outline two observations that he could have made.
- 18N.3.sl.TZ0.a: Outline two observations that he could have made.
-
18N.3.hl.TZ0.3c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
-
18N.3.hl.TZ0.3c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
-
18N.3.hl.TZ0.c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
-
18N.3.sl.TZ0.2d:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
-
18N.3.sl.TZ0.2d:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
-
18N.3.sl.TZ0.d:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
- 18N.3.hl.TZ0.2c: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.hl.TZ0.2c: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.hl.TZ0.c: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.sl.TZ0.3a: State the type of particle present in the plasma formed.
- 18N.3.sl.TZ0.3a: State the type of particle present in the plasma formed.
- 18N.3.sl.TZ0.a: State the type of particle present in the plasma formed.
- 18N.3.hl.TZ0.2d.ii: Deduce the repeating unit of the polymer of X.
- 18N.3.hl.TZ0.2d.ii: Deduce the repeating unit of the polymer of X.
- 18N.3.hl.TZ0.d.ii: Deduce the repeating unit of the polymer of X.
-
18N.3.hl.TZ0.3b.i:
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.hl.TZ0.3b.i:
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.hl.TZ0.b.i:
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.hl.TZ0.3b.ii:
Lead ions are toxic and can be precipitated using hydroxide ions.
Pb2+ (aq) + 2OH‒ (aq) Pb(OH)2 (s)
Sufficient sodium hydroxide solid is added to the antacid sample to produce a 1.0 × 10‒2 mol dm‒3 hydroxide ion solution at 298 K.
Deduce if a precipitate will be formed, using section 32 of the data booklet.
If you did not calculate the concentration of lead ions in (b)(i), use the value of 2.4 × 10−4 mol dm‒3, but this is not the correct value.
-
18N.3.hl.TZ0.3b.ii:
Lead ions are toxic and can be precipitated using hydroxide ions.
Pb2+ (aq) + 2OH‒ (aq) Pb(OH)2 (s)
Sufficient sodium hydroxide solid is added to the antacid sample to produce a 1.0 × 10‒2 mol dm‒3 hydroxide ion solution at 298 K.
Deduce if a precipitate will be formed, using section 32 of the data booklet.
If you did not calculate the concentration of lead ions in (b)(i), use the value of 2.4 × 10−4 mol dm‒3, but this is not the correct value.
-
18N.3.hl.TZ0.b.ii:
Lead ions are toxic and can be precipitated using hydroxide ions.
Pb2+ (aq) + 2OH‒ (aq) Pb(OH)2 (s)
Sufficient sodium hydroxide solid is added to the antacid sample to produce a 1.0 × 10‒2 mol dm‒3 hydroxide ion solution at 298 K.
Deduce if a precipitate will be formed, using section 32 of the data booklet.
If you did not calculate the concentration of lead ions in (b)(i), use the value of 2.4 × 10−4 mol dm‒3, but this is not the correct value.
- 18N.3.sl.TZ0.4b: The structure of biphenyl nitrile is shown. Describe, giving a reason, a feature of the...
- 18N.3.sl.TZ0.4b: The structure of biphenyl nitrile is shown. Describe, giving a reason, a feature of the...
- 18N.3.sl.TZ0.b: The structure of biphenyl nitrile is shown. Describe, giving a reason, a feature of the...
- 18N.3.hl.TZ0.3a: State the type of particle present in the plasma formed.
- 18N.3.hl.TZ0.3a: State the type of particle present in the plasma formed.
- 18N.3.hl.TZ0.a: State the type of particle present in the plasma formed.
-
18N.3.hl.TZ0.5a.ii:
Calculate the number of atoms per unit cell of gold, showing your working.
-
18N.3.hl.TZ0.5a.ii:
Calculate the number of atoms per unit cell of gold, showing your working.
-
18N.3.hl.TZ0.a.ii:
Calculate the number of atoms per unit cell of gold, showing your working.
- 18N.3.hl.TZ0.5a.i: State the name of the crystal structure of gold.
- 18N.3.hl.TZ0.5a.i: State the name of the crystal structure of gold.
- 18N.3.hl.TZ0.a.i: State the name of the crystal structure of gold.
-
18N.3.hl.TZ0.5b:
The edge length of the gold unit cell is 4.08 × 10‒8 cm.
Determine the density of gold in g cm‒3, using sections 2 and 6 of the data booklet.
-
18N.3.hl.TZ0.5b:
The edge length of the gold unit cell is 4.08 × 10‒8 cm.
Determine the density of gold in g cm‒3, using sections 2 and 6 of the data booklet.
-
18N.3.hl.TZ0.b:
The edge length of the gold unit cell is 4.08 × 10‒8 cm.
Determine the density of gold in g cm‒3, using sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ1.4e:
State one factor considered when making green chemistry polymers.
-
19M.3.hl.TZ1.4e:
State one factor considered when making green chemistry polymers.
-
19M.3.hl.TZ1.e:
State one factor considered when making green chemistry polymers.
-
19M.3.hl.TZ1.3e:
Lithium forms a crystalline lattice with the unit cell structure shown below.
X-ray diffraction shows that the length of the edge of the unit cell is 3.51 × 10−8 cm.
Determine the density of lithium, in g cm−3, using sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ1.3e:
Lithium forms a crystalline lattice with the unit cell structure shown below.
X-ray diffraction shows that the length of the edge of the unit cell is 3.51 × 10−8 cm.
Determine the density of lithium, in g cm−3, using sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ1.e:
Lithium forms a crystalline lattice with the unit cell structure shown below.
X-ray diffraction shows that the length of the edge of the unit cell is 3.51 × 10−8 cm.
Determine the density of lithium, in g cm−3, using sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ1.5b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.hl.TZ1.5b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.hl.TZ1.b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.hl.TZ1.4c:
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.hl.TZ1.4c:
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.hl.TZ1.c:
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.hl.TZ1.3b(i):
Identify the colour of the emission spectrum of lithium using section 17 of the data booklet.
-
19M.3.hl.TZ1.3b(i):
Identify the colour of the emission spectrum of lithium using section 17 of the data booklet.
-
19M.3.hl.TZ1.b(i):
Identify the colour of the emission spectrum of lithium using section 17 of the data booklet.
-
19M.3.hl.TZ1.6b:
Suggest one application for carbon nanotubes.
-
19M.3.hl.TZ1.6b:
Suggest one application for carbon nanotubes.
-
19M.3.hl.TZ1.b:
Suggest one application for carbon nanotubes.
-
19M.3.hl.TZ1.4d:
Classify polybutadiene as either an addition or condensation polymer, giving a reason.
-
19M.3.hl.TZ1.4d:
Classify polybutadiene as either an addition or condensation polymer, giving a reason.
-
19M.3.hl.TZ1.d:
Classify polybutadiene as either an addition or condensation polymer, giving a reason.
-
19M.3.hl.TZ1.3b(iii):
Suggest a better method.
-
19M.3.hl.TZ1.3b(iii):
Suggest a better method.
-
19M.3.hl.TZ1.b(iii):
Suggest a better method.
-
19M.3.hl.TZ1.3c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.hl.TZ1.3c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.hl.TZ1.c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.hl.TZ1.3a:
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.hl.TZ1.3a:
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.hl.TZ1.a:
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.hl.TZ1.4b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.hl.TZ1.4b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.hl.TZ1.b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.hl.TZ1.3d(i):
Lithium has shown some superconductive properties when doped into graphene or when under high pressure. Under high pressure, however, the Meissner effect is absent.
Describe the Meissner effect.
-
19M.3.hl.TZ1.3d(i):
Lithium has shown some superconductive properties when doped into graphene or when under high pressure. Under high pressure, however, the Meissner effect is absent.
Describe the Meissner effect.
-
19M.3.hl.TZ1.d(i):
Lithium has shown some superconductive properties when doped into graphene or when under high pressure. Under high pressure, however, the Meissner effect is absent.
Describe the Meissner effect.
-
19M.3.hl.TZ1.4a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.hl.TZ1.4a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.hl.TZ1.a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.hl.TZ1.6a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.hl.TZ1.6a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.hl.TZ1.a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.hl.TZ1.7b:
State the number of coordinate covalent bonds EDTA forms with Ni2+.
-
19M.3.hl.TZ1.7b:
State the number of coordinate covalent bonds EDTA forms with Ni2+.
-
19M.3.hl.TZ1.b:
State the number of coordinate covalent bonds EDTA forms with Ni2+.
-
19M.3.hl.TZ1.3b(ii):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.hl.TZ1.3b(ii):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.hl.TZ1.b(ii):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.hl.TZ1.3d(ii):
At very low temperatures, lithium atoms enhance the phonon binding of electrons in graphene suggesting the formation of Cooper pairs.
Explain how Cooper pairs are formed.
-
19M.3.hl.TZ1.3d(ii):
At very low temperatures, lithium atoms enhance the phonon binding of electrons in graphene suggesting the formation of Cooper pairs.
Explain how Cooper pairs are formed.
-
19M.3.hl.TZ1.d(ii):
At very low temperatures, lithium atoms enhance the phonon binding of electrons in graphene suggesting the formation of Cooper pairs.
Explain how Cooper pairs are formed.
-
19M.3.hl.TZ1.5a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.5a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.7a:
Explain how entropy affects this equilibrium.
-
19M.3.hl.TZ1.7a:
Explain how entropy affects this equilibrium.
-
19M.3.hl.TZ1.a:
Explain how entropy affects this equilibrium.
-
19M.3.hl.TZ2.4c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.hl.TZ2.4c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.hl.TZ2.c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.hl.TZ2.3:
Describe the characteristics of the nematic liquid crystal phase.
Shape of molecules:
Distribution:
-
19M.3.hl.TZ2.3:
Describe the characteristics of the nematic liquid crystal phase.
Shape of molecules:
Distribution:
-
19M.3.hl.TZ2.5f:
Draw the full structural formula of the organic functional group formed during the polymerization of the two reactants below.
-
19M.3.hl.TZ2.5f:
Draw the full structural formula of the organic functional group formed during the polymerization of the two reactants below.
-
19M.3.hl.TZ2.f:
Draw the full structural formula of the organic functional group formed during the polymerization of the two reactants below.
-
19M.3.hl.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.hl.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.hl.TZ2.d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.hl.TZ2.5d:
Suggest why the addition of plasticizers is controversial.
-
19M.3.hl.TZ2.5d:
Suggest why the addition of plasticizers is controversial.
-
19M.3.hl.TZ2.d:
Suggest why the addition of plasticizers is controversial.
-
19M.3.hl.TZ2.4a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48 250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ2.4a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48 250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ2.a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48 250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ2.18b:
Outline one approach to controlling industrial emissions of carbon dioxide.
-
19M.3.hl.TZ2.18b:
Outline one approach to controlling industrial emissions of carbon dioxide.
-
19M.3.hl.TZ2.b:
Outline one approach to controlling industrial emissions of carbon dioxide.
-
19M.3.hl.TZ2.8a:
Outline why heavy metals are toxic.
-
19M.3.hl.TZ2.8a:
Outline why heavy metals are toxic.
-
19M.3.hl.TZ2.a:
Outline why heavy metals are toxic.
-
19M.3.hl.TZ2.8b:
Determine the maximum concentration of lead(II) ions at 298 K in a solution in which the concentration of carbonate ions is maintained at 1.10 × 10−4 mol dm−3. Use section 32 of the data booklet.
-
19M.3.hl.TZ2.8b:
Determine the maximum concentration of lead(II) ions at 298 K in a solution in which the concentration of carbonate ions is maintained at 1.10 × 10−4 mol dm−3. Use section 32 of the data booklet.
-
19M.3.hl.TZ2.b:
Determine the maximum concentration of lead(II) ions at 298 K in a solution in which the concentration of carbonate ions is maintained at 1.10 × 10−4 mol dm−3. Use section 32 of the data booklet.
-
19M.3.sl.TZ1.6b:
Suggest one application for carbon nanotubes.
-
19M.3.sl.TZ1.6b:
Suggest one application for carbon nanotubes.
-
19M.3.sl.TZ1.b:
Suggest one application for carbon nanotubes.
-
19M.3.sl.TZ1.4c(i):
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.sl.TZ1.4c(i):
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.sl.TZ1.c(i):
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.sl.TZ1.6a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.sl.TZ1.6a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.sl.TZ1.a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.sl.TZ1.5b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.sl.TZ1.5b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.sl.TZ1.b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.sl.TZ1.3c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.sl.TZ1.3c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.sl.TZ1.c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.sl.TZ1.5a:
State the name of the functional group which allows the molecule to be responsive to applied electric fields.
-
19M.3.sl.TZ1.5a:
State the name of the functional group which allows the molecule to be responsive to applied electric fields.
-
19M.3.sl.TZ1.a:
State the name of the functional group which allows the molecule to be responsive to applied electric fields.
-
19M.3.sl.TZ1.3a(i):
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.sl.TZ1.3a(i):
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.sl.TZ1.a(i):
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.sl.TZ2.4a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.sl.TZ2.4a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.sl.TZ2.a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.sl.TZ2.4c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.sl.TZ2.4c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.sl.TZ2.c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.sl.TZ2.5a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.sl.TZ2.5a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.sl.TZ2.a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.sl.TZ2.4b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.sl.TZ2.4b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.sl.TZ2.b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.sl.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.sl.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.sl.TZ2.d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.sl.TZ2.5c:
Identify a hazardous product of the incineration of polychloroethene.
-
19M.3.sl.TZ2.5c:
Identify a hazardous product of the incineration of polychloroethene.
-
19M.3.sl.TZ2.c:
Identify a hazardous product of the incineration of polychloroethene.
-
19M.3.sl.TZ2.5d:
Explain how plasticizers affect the properties of plastics.
-
19M.3.sl.TZ2.5d:
Explain how plasticizers affect the properties of plastics.
-
19M.3.sl.TZ2.d:
Explain how plasticizers affect the properties of plastics.
-
19M.3.sl.TZ2.5e:
Suggest why the addition of plasticizers is controversial.
-
19M.3.sl.TZ2.5e:
Suggest why the addition of plasticizers is controversial.
-
19M.3.sl.TZ2.e:
Suggest why the addition of plasticizers is controversial.
-
19M.3.sl.TZ2.3:
Describe the characteristics of the nematic liquid crystal phase and the effect that an electric field has on it.
Shape of molecules:Distribution:
Effect of electric field:
-
19M.3.sl.TZ2.3:
Describe the characteristics of the nematic liquid crystal phase and the effect that an electric field has on it.
Shape of molecules:Distribution:
Effect of electric field:
- 19N.3.hl.TZ0.5c: Discuss why the recycling of plastics is an energy intensive process.
- 19N.3.hl.TZ0.5c: Discuss why the recycling of plastics is an energy intensive process.
- 19N.3.hl.TZ0.c: Discuss why the recycling of plastics is an energy intensive process.
- 19N.3.sl.TZ0.4c: Polypropene is a thermoplastic. Outline what is meant by thermoplastic.
- 19N.3.sl.TZ0.4c: Polypropene is a thermoplastic. Outline what is meant by thermoplastic.
- 19N.3.sl.TZ0.c: Polypropene is a thermoplastic. Outline what is meant by thermoplastic.
-
19N.3.sl.TZ0.5a:
Discuss why different methods of reduction are needed to extract metals.
-
19N.3.sl.TZ0.5a:
Discuss why different methods of reduction are needed to extract metals.
-
19N.3.sl.TZ0.a:
Discuss why different methods of reduction are needed to extract metals.
- 19N.3.sl.TZ0.6b: State how liquid crystals are affected by an electric field.
- 19N.3.sl.TZ0.6b: State how liquid crystals are affected by an electric field.
- 19N.3.sl.TZ0.b: State how liquid crystals are affected by an electric field.
- 19N.3.sl.TZ0.4d: Discuss why the recycling of plastics is an energy intensive process.
- 19N.3.sl.TZ0.4d: Discuss why the recycling of plastics is an energy intensive process.
- 19N.3.sl.TZ0.d: Discuss why the recycling of plastics is an energy intensive process.
- 19N.3.hl.TZ0.4b: State two differences between Type I and Type II superconductors.
- 19N.3.hl.TZ0.4b: State two differences between Type I and Type II superconductors.
- 19N.3.hl.TZ0.b: State two differences between Type I and Type II superconductors.
- 19N.3.sl.TZ0.6a: Describe the arrangement of soap molecules in the nematic liquid crystal phase.
- 19N.3.sl.TZ0.6a: Describe the arrangement of soap molecules in the nematic liquid crystal phase.
- 19N.3.sl.TZ0.a: Describe the arrangement of soap molecules in the nematic liquid crystal phase.
-
19N.3.sl.TZ0.4a:
Draw a section of an isotactic polypropene polymer chain containing four repeating units.
-
19N.3.sl.TZ0.4a:
Draw a section of an isotactic polypropene polymer chain containing four repeating units.
-
19N.3.sl.TZ0.a:
Draw a section of an isotactic polypropene polymer chain containing four repeating units.
- 19N.3.sl.TZ0.3b: Distinguish between heterogeneous and homogeneous catalysts, giving one difference.
- 19N.3.sl.TZ0.3b: Distinguish between heterogeneous and homogeneous catalysts, giving one difference.
- 19N.3.sl.TZ0.b: Distinguish between heterogeneous and homogeneous catalysts, giving one difference.
- 19N.3.sl.TZ0.4b: Predict, with a reason, whether isotactic or atactic polypropene has the higher melting point.
- 19N.3.sl.TZ0.4b: Predict, with a reason, whether isotactic or atactic polypropene has the higher melting point.
- 19N.3.sl.TZ0.b: Predict, with a reason, whether isotactic or atactic polypropene has the higher melting point.
- 19N.3.hl.TZ0.4a(ii): Suggest why the resistance of metals increases with temperature.
- 19N.3.hl.TZ0.4a(ii): Suggest why the resistance of metals increases with temperature.
- 19N.3.hl.TZ0.a(ii): Suggest why the resistance of metals increases with temperature.
-
19N.3.sl.TZ0.5b(i):
Determine the percentage of ionic bonding in alumina using sections 8 and 29 of the data booklet.
-
19N.3.sl.TZ0.5b(i):
Determine the percentage of ionic bonding in alumina using sections 8 and 29 of the data booklet.
-
19N.3.sl.TZ0.b(i):
Determine the percentage of ionic bonding in alumina using sections 8 and 29 of the data booklet.
-
19N.3.sl.TZ0.3a:
Describe how a heterogeneous catalyst provides an alternative pathway for a reaction.
-
19N.3.sl.TZ0.3a:
Describe how a heterogeneous catalyst provides an alternative pathway for a reaction.
-
19N.3.sl.TZ0.a:
Describe how a heterogeneous catalyst provides an alternative pathway for a reaction.
- 19N.3.hl.TZ0.4a(i): Outline how resistance to electric currents occurs in metals.
- 19N.3.hl.TZ0.4a(i): Outline how resistance to electric currents occurs in metals.
- 19N.3.hl.TZ0.a(i): Outline how resistance to electric currents occurs in metals.
-
19N.3.hl.TZ0.5a:
Draw the structure of the monomers of Kevlar® if the by-product of the condensation polymerization is hydrogen chloride.
-
19N.3.hl.TZ0.5a:
Draw the structure of the monomers of Kevlar® if the by-product of the condensation polymerization is hydrogen chloride.
-
19N.3.hl.TZ0.a:
Draw the structure of the monomers of Kevlar® if the by-product of the condensation polymerization is hydrogen chloride.
-
19N.3.hl.TZ0.7:
X-ray crystallography of a metal crystal produces a diffraction pattern of bright spots.
Using X-rays of wavelength 1.54 × 10−10 m, the first bright spots were produced at an angle θ of 22.3° from the centre.
Calculate the separation between planes of atoms in the lattice, in meters, using section 1 of the data booklet.
-
19N.3.hl.TZ0.7:
X-ray crystallography of a metal crystal produces a diffraction pattern of bright spots.
Using X-rays of wavelength 1.54 × 10−10 m, the first bright spots were produced at an angle θ of 22.3° from the centre.
Calculate the separation between planes of atoms in the lattice, in meters, using section 1 of the data booklet.
-
19N.3.hl.TZ0.8:
1.40 × 10−3 g of NaOH (s) are dissolved in 250.0 cm3 of 1.00 × 10−11 mol dm−3 Pb(OH)2 (aq) solution.
Determine the change in lead ion concentration in the solution, using section 32 of the data booklet.
-
19N.3.hl.TZ0.8:
1.40 × 10−3 g of NaOH (s) are dissolved in 250.0 cm3 of 1.00 × 10−11 mol dm−3 Pb(OH)2 (aq) solution.
Determine the change in lead ion concentration in the solution, using section 32 of the data booklet.
-
19N.3.sl.TZ0.5b(ii):
Write half-equations for the electrolysis of molten alumina using graphite electrodes, deducing the state symbols of the products.
Anode (positive electrode):
Cathode (negative electrode):
-
19N.3.sl.TZ0.5b(ii):
Write half-equations for the electrolysis of molten alumina using graphite electrodes, deducing the state symbols of the products.
Anode (positive electrode):
Cathode (negative electrode):
-
19N.3.sl.TZ0.b(ii):
Write half-equations for the electrolysis of molten alumina using graphite electrodes, deducing the state symbols of the products.
Anode (positive electrode):
Cathode (negative electrode):
- 19N.3.hl.TZ0.5b: State and explain why plasticizers are added to polymers.
- 19N.3.hl.TZ0.5b: State and explain why plasticizers are added to polymers.
- 19N.3.hl.TZ0.b: State and explain why plasticizers are added to polymers.
- 17N.3.sl.TZ0.6b: Outline why the iron nanoparticle catalysts produced by the HIPCO process are more efficient than...
- 17N.3.sl.TZ0.6b: Outline why the iron nanoparticle catalysts produced by the HIPCO process are more efficient than...
- 17N.3.sl.TZ0.b: Outline why the iron nanoparticle catalysts produced by the HIPCO process are more efficient than...
-
18M.3.hl.TZ1.4c.ii:
Deduce, giving a reason, whether the atom economy of a condensation polymerization, such as this, would be greater or less than an addition polymerization, such as the formation of HDPE.
-
18M.3.hl.TZ1.4c.ii:
Deduce, giving a reason, whether the atom economy of a condensation polymerization, such as this, would be greater or less than an addition polymerization, such as the formation of HDPE.
-
18M.3.hl.TZ1.c.ii:
Deduce, giving a reason, whether the atom economy of a condensation polymerization, such as this, would be greater or less than an addition polymerization, such as the formation of HDPE.
-
18M.3.sl.TZ1.4e:
Suggest why there are so many different ways in which plastics can be classified. HDPE can, for example, be categorized thermoplastic, an addition polymer, having Resin Identification Code (RIC) 2, etc.
-
18M.3.sl.TZ1.4e:
Suggest why there are so many different ways in which plastics can be classified. HDPE can, for example, be categorized thermoplastic, an addition polymer, having Resin Identification Code (RIC) 2, etc.
-
18M.3.sl.TZ1.e:
Suggest why there are so many different ways in which plastics can be classified. HDPE can, for example, be categorized thermoplastic, an addition polymer, having Resin Identification Code (RIC) 2, etc.
-
18M.3.sl.TZ2.4b.ii:
Compare two ways in which recycling differs from reusing plastics.
-
18M.3.sl.TZ2.4b.ii:
Compare two ways in which recycling differs from reusing plastics.
-
18M.3.sl.TZ2.b.ii:
Compare two ways in which recycling differs from reusing plastics.
-
18M.3.sl.TZ2.4c:
Civilizations are often characterized by the materials they use.
Suggest an advantage polymers have over materials from the iron age.
-
18M.3.sl.TZ2.4c:
Civilizations are often characterized by the materials they use.
Suggest an advantage polymers have over materials from the iron age.
-
18M.3.sl.TZ2.c:
Civilizations are often characterized by the materials they use.
Suggest an advantage polymers have over materials from the iron age.
-
18N.3.sl.TZ0.2b.i:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.sl.TZ0.2b.i:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.sl.TZ0.b.i:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
- 18N.3.sl.TZ0.2c.ii: Identify another advantage of using a zeolite instead of concentrated sulfuric acid.
- 18N.3.sl.TZ0.2c.ii: Identify another advantage of using a zeolite instead of concentrated sulfuric acid.
- 18N.3.sl.TZ0.c.ii: Identify another advantage of using a zeolite instead of concentrated sulfuric acid.
-
18N.3.hl.TZ0.2d.iii:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
-
18N.3.hl.TZ0.2d.iii:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
-
18N.3.hl.TZ0.d.iii:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
- 18N.3.hl.TZ0.3d.i: State one feature of a chelating agent.
- 18N.3.hl.TZ0.3d.i: State one feature of a chelating agent.
- 18N.3.hl.TZ0.d.i: State one feature of a chelating agent.
-
19M.3.hl.TZ2.4b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.hl.TZ2.4b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.hl.TZ2.b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.hl.TZ2.4e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.hl.TZ2.4e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.hl.TZ2.e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.hl.TZ2.5a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.hl.TZ2.5a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.hl.TZ2.a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.hl.TZ2.5c:
Explain how plasticizers affect the properties of plastics.
-
19M.3.hl.TZ2.5c:
Explain how plasticizers affect the properties of plastics.
-
19M.3.hl.TZ2.c:
Explain how plasticizers affect the properties of plastics.
-
19M.3.hl.TZ2.5e:
Outline, giving a reason, how addition and condensation polymerization compare with regard to green chemistry.
-
19M.3.hl.TZ2.5e:
Outline, giving a reason, how addition and condensation polymerization compare with regard to green chemistry.
-
19M.3.hl.TZ2.e:
Outline, giving a reason, how addition and condensation polymerization compare with regard to green chemistry.
-
19M.3.hl.TZ2.6a:
State the number of atoms in the unit cell.
-
19M.3.hl.TZ2.6a:
State the number of atoms in the unit cell.
-
19M.3.hl.TZ2.a:
State the number of atoms in the unit cell.
-
19M.3.hl.TZ2.6b:
Determine the density of calcium, in g cm−3, using section 2 of the data booklet.
Ar = 40.08; metallic radius (r) = 1.97 × 10−10 m
-
19M.3.hl.TZ2.6b:
Determine the density of calcium, in g cm−3, using section 2 of the data booklet.
Ar = 40.08; metallic radius (r) = 1.97 × 10−10 m
-
19M.3.hl.TZ2.b:
Determine the density of calcium, in g cm−3, using section 2 of the data booklet.
Ar = 40.08; metallic radius (r) = 1.97 × 10−10 m
-
19M.3.hl.TZ2.7a:
State what is meant by a superconductor.
-
19M.3.hl.TZ2.7a:
State what is meant by a superconductor.
-
19M.3.hl.TZ2.a:
State what is meant by a superconductor.
-
19M.3.hl.TZ2.8c:
State a method, other than precipitation, of removing heavy metal ions from solution.
-
19M.3.hl.TZ2.8c:
State a method, other than precipitation, of removing heavy metal ions from solution.
-
19M.3.hl.TZ2.c:
State a method, other than precipitation, of removing heavy metal ions from solution.
-
19M.3.sl.TZ1.3a(ii):
Explain why lithium is paramagnetic while lithium hydride is diamagnetic by referring to electron configurations.
-
19M.3.sl.TZ1.3a(ii):
Explain why lithium is paramagnetic while lithium hydride is diamagnetic by referring to electron configurations.
-
19M.3.sl.TZ1.a(ii):
Explain why lithium is paramagnetic while lithium hydride is diamagnetic by referring to electron configurations.
-
19M.3.sl.TZ1.3b(i):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.sl.TZ1.3b(i):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.sl.TZ1.b(i):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.sl.TZ1.3b(ii):
Suggest a better method.
-
19M.3.sl.TZ1.3b(ii):
Suggest a better method.
-
19M.3.sl.TZ1.b(ii):
Suggest a better method.
-
19M.3.sl.TZ1.4a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.sl.TZ1.4a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.sl.TZ1.a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.sl.TZ1.4b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.sl.TZ1.4b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.sl.TZ1.b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.sl.TZ1.4c(ii):
The trace quantities of dioxins from tyre fires are rarely inhaled and instead settle on the ground.
Describe why this is a health concern.
-
19M.3.sl.TZ1.4c(ii):
The trace quantities of dioxins from tyre fires are rarely inhaled and instead settle on the ground.
Describe why this is a health concern.
-
19M.3.sl.TZ1.c(ii):
The trace quantities of dioxins from tyre fires are rarely inhaled and instead settle on the ground.
Describe why this is a health concern.
-
19M.3.sl.TZ2.4e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.sl.TZ2.4e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.sl.TZ2.e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19N.3.sl.TZ0.3c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
-
19N.3.sl.TZ0.3c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
-
19N.3.sl.TZ0.c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
- 20N.3.sl.TZ0.4a: Explain these properties of carbon nanotubes.
- 20N.3.sl.TZ0.4a: Explain these properties of carbon nanotubes.
- 20N.3.sl.TZ0.a: Explain these properties of carbon nanotubes.
-
20N.3.sl.TZ0.4b(iii):
Calculate the theoretical mass of magnesium obtained if a current of is used for hours. Use charge and section 2 of the data booklet
-
20N.3.sl.TZ0.4b(iii):
Calculate the theoretical mass of magnesium obtained if a current of is used for hours. Use charge and section 2 of the data booklet
-
20N.3.sl.TZ0.b(iii):
Calculate the theoretical mass of magnesium obtained if a current of is used for hours. Use charge and section 2 of the data booklet
- 20N.3.sl.TZ0.4c: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.sl.TZ0.4c: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.sl.TZ0.c: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.sl.TZ0.4e: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
-
20N.3.hl.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.3.hl.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.3.hl.TZ0.a:
Outline the two distinct phases of this composite.
- 20N.3.hl.TZ0.3b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.hl.TZ0.3b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.hl.TZ0.b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.hl.TZ0.3b(iii): Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.hl.TZ0.3b(iii): Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.hl.TZ0.b(iii): Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.hl.TZ0.3c: Classify PVC and polyethene terephthalate, PET, as addition or condensation polymers and deduce...
- 20N.3.hl.TZ0.3c: Classify PVC and polyethene terephthalate, PET, as addition or condensation polymers and deduce...
- 20N.3.hl.TZ0.c: Classify PVC and polyethene terephthalate, PET, as addition or condensation polymers and deduce...
- 20N.3.hl.TZ0.4a: Explain these properties of carbon nanotubes.
- 20N.3.hl.TZ0.4a: Explain these properties of carbon nanotubes.
- 20N.3.hl.TZ0.a: Explain these properties of carbon nanotubes.
-
20N.3.hl.TZ0.4b(ii):
Explain the role of electrons in superconducting materials in terms of the Bardeen–Cooper–Schrieffer (BCS) theory.
-
20N.3.hl.TZ0.4b(ii):
Explain the role of electrons in superconducting materials in terms of the Bardeen–Cooper–Schrieffer (BCS) theory.
-
20N.3.hl.TZ0.b(ii):
Explain the role of electrons in superconducting materials in terms of the Bardeen–Cooper–Schrieffer (BCS) theory.
-
20N.3.hl.TZ0.4c(i):
Alloying metals changes their properties. Suggest one property of magnesium that could be improved by making a magnesium–CNT alloy.
-
20N.3.hl.TZ0.4c(i):
Alloying metals changes their properties. Suggest one property of magnesium that could be improved by making a magnesium–CNT alloy.
-
20N.3.hl.TZ0.c(i):
Alloying metals changes their properties. Suggest one property of magnesium that could be improved by making a magnesium–CNT alloy.
-
20N.3.hl.TZ0.4c(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020
Calculate the theoretical mass of magnesium obtained if a current of 3.00 A is used for hours. Use charge :(Q) = current (I) × time (t) and section 2 of the data booklet.
-
20N.3.hl.TZ0.4c(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020
Calculate the theoretical mass of magnesium obtained if a current of 3.00 A is used for hours. Use charge :(Q) = current (I) × time (t) and section 2 of the data booklet.
-
20N.3.hl.TZ0.c(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020
Calculate the theoretical mass of magnesium obtained if a current of 3.00 A is used for hours. Use charge :(Q) = current (I) × time (t) and section 2 of the data booklet.
- 20N.3.hl.TZ0.4e: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.hl.TZ0.4e: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.hl.TZ0.e: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
-
20N.3.hl.TZ0.5b:
Precipitation is one method used to treat waste water.
Zinc, cadmium, nickel, and lead are metal ions which can be removed by precipitation. Explain why waste water is adjusted to a pH of 9−10 to remove these ions by referring to section 32 of the data booklet.
-
20N.3.hl.TZ0.5b:
Precipitation is one method used to treat waste water.
Zinc, cadmium, nickel, and lead are metal ions which can be removed by precipitation. Explain why waste water is adjusted to a pH of 9−10 to remove these ions by referring to section 32 of the data booklet.
-
20N.3.hl.TZ0.b:
Precipitation is one method used to treat waste water.
Zinc, cadmium, nickel, and lead are metal ions which can be removed by precipitation. Explain why waste water is adjusted to a pH of 9−10 to remove these ions by referring to section 32 of the data booklet.
- 23M.2.HL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.SL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.i: Outline the meaning of homologous series.
- 23M.2.SL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.SL.TZ1.i: Outline the meaning of homologous series.
- 23M.2.HL.TZ2.7a: Identify the type of reaction.
- 23M.2.HL.TZ2.7a: Identify the type of reaction.
- 23M.2.HL.TZ2.a: Identify the type of reaction.
Sub sections and their related questions
A.1 Materials science introduction
-
17N.3.sl.TZ0.4a:
Outline the composition of an alloy and a composite.
- 17N.3.sl.TZ0.4b.ii: At present, composite fillings are more expensive than amalgam fillings. Suggest why a patient...
-
18M.3.sl.TZ1.3a:
Discuss, in terms of its structure, why an aluminium saucepan is impermeable to water.
-
18M.3.sl.TZ1.3b.i:
State the name given to a material composed of two distinct solid phases.
-
18M.3.sl.TZ1.4e:
Suggest why there are so many different ways in which plastics can be classified. HDPE can, for example, be categorized thermoplastic, an addition polymer, having Resin Identification Code (RIC) 2, etc.
-
18M.3.sl.TZ2.3a:
ICP-OES/MS can be used to analyse alloys and composites. Distinguish between alloys and composites.
-
18M.3.sl.TZ2.4c:
Civilizations are often characterized by the materials they use.
Suggest an advantage polymers have over materials from the iron age.
-
18N.3.sl.TZ0.2a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.hl.TZ0.2a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
19M.3.hl.TZ1.3a:
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.hl.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.sl.TZ1.3a(i):
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.sl.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19N.3.sl.TZ0.5b(i):
Determine the percentage of ionic bonding in alumina using sections 8 and 29 of the data booklet.
-
20N.3.sl.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.3.hl.TZ0.3a:
Outline the two distinct phases of this composite.
-
19M.3.hl.TZ1.3a:
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.hl.TZ1.a:
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.hl.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.hl.TZ2.d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.sl.TZ1.3a(i):
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.sl.TZ1.a(i):
Identify the type of bonding in lithium hydride, using sections 8 and 29 of the data booklet.
-
19M.3.sl.TZ2.4d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19M.3.sl.TZ2.d:
Outline how alloys conduct electricity and why they are often harder than pure metals.
Conduct electricity:
Harder than pure metals:
-
19N.3.sl.TZ0.5b(i):
Determine the percentage of ionic bonding in alumina using sections 8 and 29 of the data booklet.
-
19N.3.sl.TZ0.b(i):
Determine the percentage of ionic bonding in alumina using sections 8 and 29 of the data booklet.
-
20N.3.sl.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.3.sl.TZ0.a:
Outline the two distinct phases of this composite.
-
20N.3.hl.TZ0.3a:
Outline the two distinct phases of this composite.
-
20N.3.hl.TZ0.a:
Outline the two distinct phases of this composite.
-
17N.3.sl.TZ0.4a:
Outline the composition of an alloy and a composite.
- 17N.3.sl.TZ0.4b.ii: At present, composite fillings are more expensive than amalgam fillings. Suggest why a patient...
-
17N.3.sl.TZ0.a:
Outline the composition of an alloy and a composite.
- 17N.3.sl.TZ0.b.ii: At present, composite fillings are more expensive than amalgam fillings. Suggest why a patient...
-
18M.3.sl.TZ1.3a:
Discuss, in terms of its structure, why an aluminium saucepan is impermeable to water.
-
18M.3.sl.TZ1.3b.i:
State the name given to a material composed of two distinct solid phases.
-
18M.3.sl.TZ1.a:
Discuss, in terms of its structure, why an aluminium saucepan is impermeable to water.
-
18M.3.sl.TZ1.b.i:
State the name given to a material composed of two distinct solid phases.
-
18M.3.sl.TZ1.4e:
Suggest why there are so many different ways in which plastics can be classified. HDPE can, for example, be categorized thermoplastic, an addition polymer, having Resin Identification Code (RIC) 2, etc.
-
18M.3.sl.TZ1.e:
Suggest why there are so many different ways in which plastics can be classified. HDPE can, for example, be categorized thermoplastic, an addition polymer, having Resin Identification Code (RIC) 2, etc.
-
18M.3.sl.TZ2.3a:
ICP-OES/MS can be used to analyse alloys and composites. Distinguish between alloys and composites.
-
18M.3.sl.TZ2.a:
ICP-OES/MS can be used to analyse alloys and composites. Distinguish between alloys and composites.
-
18M.3.sl.TZ2.4c:
Civilizations are often characterized by the materials they use.
Suggest an advantage polymers have over materials from the iron age.
-
18M.3.sl.TZ2.c:
Civilizations are often characterized by the materials they use.
Suggest an advantage polymers have over materials from the iron age.
-
18N.3.sl.TZ0.2a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.sl.TZ0.a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.hl.TZ0.2a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
-
18N.3.hl.TZ0.a:
Outline why this type of classification is not entirely satisfactory by using magnesium diboride, MgB2, as an example. Refer to sections 8 and 29 of the data booklet.
A.2 Metals and inductively coupled plasma (ICP) spectroscopy
- 17N.3.sl.TZ0.4b.i: Outline why an alloy is usually harder than its components by referring to its structure.
-
17N.3.sl.TZ0.4c:
Explain how Inductively Coupled Plasma (ICP) Spectroscopy could be used to determine the concentration of mercury in a sample of dental filling.
-
18M.3.sl.TZ1.4c.ii:
Trace amounts of metal from the catalysts used in the production of HDPE sometimes remain in the product. State a technique that could be used to measure the concentration of the metal.
-
18M.3.sl.TZ1.5:
Aluminium is produced by the electrolysis of a molten electrolyte containing bauxite.
Determine the mass, in g, of aluminium produced by the passage of a charge of 1.296 × 1013 C. Use sections 2 and 6 of the data booklet.
-
18M.3.sl.TZ2.3b:
ICP-MS is a reference mode for analysis. The following correlation graphs between ICP-OES and ICP-MS were produced for yttrium and nickel.
Each y-axis shows concentrations calculated by ICP-OES; each x-axis shows concentrations for the same sample as found by ICP-MS.
The line in each graph is y = x.
Discuss the effectiveness of ICP-OES for yttrium and nickel.
-
18M.3.sl.TZ2.3c.i:
Identify the purpose of each graph.
-
18M.3.sl.TZ2.3c.ii:
Calculate, to four significant figures, the concentration, in μg kg−1, of vanadium in oil giving a signal intensity of 14 950.
- 18N.3.sl.TZ0.3a: State the type of particle present in the plasma formed.
-
18N.3.sl.TZ0.3b:
An unknown antacid sample has a lead ion concentration of 0.50 μg dm‒3.
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.sl.TZ0.3c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
- 18N.3.hl.TZ0.3a: State the type of particle present in the plasma formed.
-
18N.3.hl.TZ0.3b.i:
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.hl.TZ0.3c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
-
19M.3.hl.TZ1.3b(i):
Identify the colour of the emission spectrum of lithium using section 17 of the data booklet.
-
19M.3.hl.TZ1.3b(ii):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.hl.TZ1.3b(iii):
Suggest a better method.
-
19M.3.hl.TZ1.3c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.hl.TZ2.4a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48 250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ2.4b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.sl.TZ1.3a(ii):
Explain why lithium is paramagnetic while lithium hydride is diamagnetic by referring to electron configurations.
-
19M.3.sl.TZ1.3b(i):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.sl.TZ1.3b(ii):
Suggest a better method.
-
19M.3.sl.TZ1.3c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.sl.TZ2.4a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.sl.TZ2.4b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19N.3.sl.TZ0.5a:
Discuss why different methods of reduction are needed to extract metals.
-
19N.3.sl.TZ0.5b(ii):
Write half-equations for the electrolysis of molten alumina using graphite electrodes, deducing the state symbols of the products.
Anode (positive electrode):
Cathode (negative electrode):
- 20N.3.sl.TZ0.4b(i): Alloying metals changes their properties. Suggest one property of magnesium that could be...
-
20N.3.sl.TZ0.4b(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020.
Write the half-equations for the reactions occurring in this electrolysis.
-
20N.3.sl.TZ0.4b(iii):
Calculate the theoretical mass of magnesium obtained if a current of is used for hours. Use charge and section 2 of the data booklet
-
20N.3.sl.TZ0.4b(iv):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
20N.3.hl.TZ0.4c(i):
Alloying metals changes their properties. Suggest one property of magnesium that could be improved by making a magnesium–CNT alloy.
-
20N.3.hl.TZ0.4c(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020
Calculate the theoretical mass of magnesium obtained if a current of 3.00 A is used for hours. Use charge :(Q) = current (I) × time (t) and section 2 of the data booklet.
-
20N.3.hl.TZ0.4c(iii):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
19M.3.hl.TZ1.3b(i):
Identify the colour of the emission spectrum of lithium using section 17 of the data booklet.
-
19M.3.hl.TZ1.3b(ii):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.hl.TZ1.3b(iii):
Suggest a better method.
-
19M.3.hl.TZ1.3c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.hl.TZ1.b(i):
Identify the colour of the emission spectrum of lithium using section 17 of the data booklet.
-
19M.3.hl.TZ1.b(ii):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.hl.TZ1.b(iii):
Suggest a better method.
-
19M.3.hl.TZ1.c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.hl.TZ2.4a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48 250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ2.4b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.hl.TZ2.a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48 250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ2.b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.sl.TZ1.3a(ii):
Explain why lithium is paramagnetic while lithium hydride is diamagnetic by referring to electron configurations.
-
19M.3.sl.TZ1.3b(i):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.sl.TZ1.3b(ii):
Suggest a better method.
-
19M.3.sl.TZ1.3c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.sl.TZ1.a(ii):
Explain why lithium is paramagnetic while lithium hydride is diamagnetic by referring to electron configurations.
-
19M.3.sl.TZ1.b(i):
Suggest why ICP-OES does not give good quantitative results for distinguishing 6Li from naturally occurring lithium.
-
19M.3.sl.TZ1.b(ii):
Suggest a better method.
-
19M.3.sl.TZ1.c:
Lithium is obtained by electrolysis of molten lithium chloride. Calculate the time, in seconds, taken to deposit 0.694 g Li using a current of 2.00 A.
Q (charge) = I (current) × t (time)
-
19M.3.sl.TZ2.4a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.sl.TZ2.4b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19M.3.sl.TZ2.a:
Determine the mass of aluminium, in g, that could be extracted from an appropriate solution by a charge of 48250 C. Use sections 2 and 6 of the data booklet.
-
19M.3.sl.TZ2.b:
Once extracted, the purity of the metal can be assessed using ICP-MS. Suggest two advantages of using plasma technology rather than regular mass spectrometry.
-
19N.3.sl.TZ0.5a:
Discuss why different methods of reduction are needed to extract metals.
-
19N.3.sl.TZ0.5b(ii):
Write half-equations for the electrolysis of molten alumina using graphite electrodes, deducing the state symbols of the products.
Anode (positive electrode):
Cathode (negative electrode):
-
19N.3.sl.TZ0.a:
Discuss why different methods of reduction are needed to extract metals.
-
19N.3.sl.TZ0.b(ii):
Write half-equations for the electrolysis of molten alumina using graphite electrodes, deducing the state symbols of the products.
Anode (positive electrode):
Cathode (negative electrode):
- 20N.3.sl.TZ0.4b(i): Alloying metals changes their properties. Suggest one property of magnesium that could be...
-
20N.3.sl.TZ0.4b(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020.
Write the half-equations for the reactions occurring in this electrolysis.
-
20N.3.sl.TZ0.4b(iii):
Calculate the theoretical mass of magnesium obtained if a current of is used for hours. Use charge and section 2 of the data booklet
-
20N.3.sl.TZ0.4b(iv):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
- 20N.3.sl.TZ0.b(i): Alloying metals changes their properties. Suggest one property of magnesium that could be...
-
20N.3.sl.TZ0.b(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020.
Write the half-equations for the reactions occurring in this electrolysis.
-
20N.3.sl.TZ0.b(iii):
Calculate the theoretical mass of magnesium obtained if a current of is used for hours. Use charge and section 2 of the data booklet
-
20N.3.sl.TZ0.b(iv):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
20N.3.hl.TZ0.4c(i):
Alloying metals changes their properties. Suggest one property of magnesium that could be improved by making a magnesium–CNT alloy.
-
20N.3.hl.TZ0.4c(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020
Calculate the theoretical mass of magnesium obtained if a current of 3.00 A is used for hours. Use charge :(Q) = current (I) × time (t) and section 2 of the data booklet.
-
20N.3.hl.TZ0.4c(iii):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
-
20N.3.hl.TZ0.c(i):
Alloying metals changes their properties. Suggest one property of magnesium that could be improved by making a magnesium–CNT alloy.
-
20N.3.hl.TZ0.c(ii):
Pure magnesium needed for making alloys can be obtained by electrolysis of molten magnesium chloride.
© International Baccalaureate Organization 2020
Calculate the theoretical mass of magnesium obtained if a current of 3.00 A is used for hours. Use charge :(Q) = current (I) × time (t) and section 2 of the data booklet.
-
20N.3.hl.TZ0.c(iii):
Suggest a gas which should be continuously passed over the molten magnesium in the electrolytic cell.
- 17N.3.sl.TZ0.4b.i: Outline why an alloy is usually harder than its components by referring to its structure.
-
17N.3.sl.TZ0.4c:
Explain how Inductively Coupled Plasma (ICP) Spectroscopy could be used to determine the concentration of mercury in a sample of dental filling.
- 17N.3.sl.TZ0.b.i: Outline why an alloy is usually harder than its components by referring to its structure.
-
17N.3.sl.TZ0.c:
Explain how Inductively Coupled Plasma (ICP) Spectroscopy could be used to determine the concentration of mercury in a sample of dental filling.
-
18M.3.sl.TZ1.4c.ii:
Trace amounts of metal from the catalysts used in the production of HDPE sometimes remain in the product. State a technique that could be used to measure the concentration of the metal.
-
18M.3.sl.TZ1.c.ii:
Trace amounts of metal from the catalysts used in the production of HDPE sometimes remain in the product. State a technique that could be used to measure the concentration of the metal.
-
18M.3.sl.TZ1.5:
Aluminium is produced by the electrolysis of a molten electrolyte containing bauxite.
Determine the mass, in g, of aluminium produced by the passage of a charge of 1.296 × 1013 C. Use sections 2 and 6 of the data booklet.
-
18M.3.sl.TZ2.3b:
ICP-MS is a reference mode for analysis. The following correlation graphs between ICP-OES and ICP-MS were produced for yttrium and nickel.
Each y-axis shows concentrations calculated by ICP-OES; each x-axis shows concentrations for the same sample as found by ICP-MS.
The line in each graph is y = x.
Discuss the effectiveness of ICP-OES for yttrium and nickel.
-
18M.3.sl.TZ2.3c.i:
Identify the purpose of each graph.
-
18M.3.sl.TZ2.3c.ii:
Calculate, to four significant figures, the concentration, in μg kg−1, of vanadium in oil giving a signal intensity of 14 950.
-
18M.3.sl.TZ2.b:
ICP-MS is a reference mode for analysis. The following correlation graphs between ICP-OES and ICP-MS were produced for yttrium and nickel.
Each y-axis shows concentrations calculated by ICP-OES; each x-axis shows concentrations for the same sample as found by ICP-MS.
The line in each graph is y = x.
Discuss the effectiveness of ICP-OES for yttrium and nickel.
-
18M.3.sl.TZ2.c.i:
Identify the purpose of each graph.
-
18M.3.sl.TZ2.c.ii:
Calculate, to four significant figures, the concentration, in μg kg−1, of vanadium in oil giving a signal intensity of 14 950.
- 18N.3.sl.TZ0.3a: State the type of particle present in the plasma formed.
-
18N.3.sl.TZ0.3b:
An unknown antacid sample has a lead ion concentration of 0.50 μg dm‒3.
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.sl.TZ0.3c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
- 18N.3.sl.TZ0.a: State the type of particle present in the plasma formed.
-
18N.3.sl.TZ0.b:
An unknown antacid sample has a lead ion concentration of 0.50 μg dm‒3.
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.sl.TZ0.c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
- 18N.3.hl.TZ0.3a: State the type of particle present in the plasma formed.
-
18N.3.hl.TZ0.3b.i:
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.hl.TZ0.3c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
- 18N.3.hl.TZ0.a: State the type of particle present in the plasma formed.
-
18N.3.hl.TZ0.b.i:
Calculate the concentration of lead ions in the sample in mol dm‒3.
-
18N.3.hl.TZ0.c:
Electrolysis is used to obtain lead from Pb2+ (aq) solution.
Determine the time, in hours, required to produce 0.0500 mol lead using a current (I) of 1.34 A. Use section 2 of the data booklet and the equation, charge (Q) = current (I) × time (t, in seconds).
A.3 Catalysts
-
17N.3.sl.TZ0.5:
Catalysts can take many forms and are used in many industrial processes.
Suggest two reasons why it might be worth using a more expensive catalyst to increase the rate of a reaction.
-
18M.3.sl.TZ1.4c.i:
The production of HDPE involves the use of homogeneous catalysts. Outline how homogeneous catalysts reduce the activation energy of reactions.
-
18M.3.sl.TZ2.3c.iii:
Vanadium(V) oxide is used as the catalyst in the conversion of sulfur dioxide to sulfur trioxide.
SO2(g) + V2O5(s) → SO3(g) + 2VO2(s)
O2(g) + 2VO2(s) → V2O5(s)
Outline how vanadium(V) oxide acts as a catalyst.
- 18N.3.sl.TZ0.2c.i: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.sl.TZ0.2c.ii: Identify another advantage of using a zeolite instead of concentrated sulfuric acid.
- 18N.3.hl.TZ0.2c: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
-
19M.3.hl.TZ1.4a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.hl.TZ2.4c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.sl.TZ1.4a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.sl.TZ2.4c:
Explain the action of metals as heterogeneous catalysts.
-
19N.3.sl.TZ0.3a:
Describe how a heterogeneous catalyst provides an alternative pathway for a reaction.
- 19N.3.sl.TZ0.3b: Distinguish between heterogeneous and homogeneous catalysts, giving one difference.
-
19N.3.sl.TZ0.3c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
- 20N.3.sl.TZ0.4c: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.hl.TZ0.4d: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
-
19M.3.hl.TZ1.4a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.hl.TZ1.a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.hl.TZ2.4c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.hl.TZ2.c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.sl.TZ1.4a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.sl.TZ1.a:
Outline two differences between heterogeneous and homogeneous catalysts.
-
19M.3.sl.TZ2.4c:
Explain the action of metals as heterogeneous catalysts.
-
19M.3.sl.TZ2.c:
Explain the action of metals as heterogeneous catalysts.
-
19N.3.sl.TZ0.3a:
Describe how a heterogeneous catalyst provides an alternative pathway for a reaction.
- 19N.3.sl.TZ0.3b: Distinguish between heterogeneous and homogeneous catalysts, giving one difference.
-
19N.3.sl.TZ0.3c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
-
19N.3.sl.TZ0.a:
Describe how a heterogeneous catalyst provides an alternative pathway for a reaction.
- 19N.3.sl.TZ0.b: Distinguish between heterogeneous and homogeneous catalysts, giving one difference.
-
19N.3.sl.TZ0.c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
- 20N.3.sl.TZ0.4c: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.sl.TZ0.c: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.hl.TZ0.4d: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
- 20N.3.hl.TZ0.d: Zeolites can be used as catalysts in the manufacture of CNT. Explain, with reference to their...
-
17N.3.sl.TZ0.5:
Catalysts can take many forms and are used in many industrial processes.
Suggest two reasons why it might be worth using a more expensive catalyst to increase the rate of a reaction.
-
18M.3.sl.TZ1.4c.i:
The production of HDPE involves the use of homogeneous catalysts. Outline how homogeneous catalysts reduce the activation energy of reactions.
-
18M.3.sl.TZ1.c.i:
The production of HDPE involves the use of homogeneous catalysts. Outline how homogeneous catalysts reduce the activation energy of reactions.
-
18M.3.sl.TZ2.3c.iii:
Vanadium(V) oxide is used as the catalyst in the conversion of sulfur dioxide to sulfur trioxide.
SO2(g) + V2O5(s) → SO3(g) + 2VO2(s)
O2(g) + 2VO2(s) → V2O5(s)
Outline how vanadium(V) oxide acts as a catalyst.
-
18M.3.sl.TZ2.c.iii:
Vanadium(V) oxide is used as the catalyst in the conversion of sulfur dioxide to sulfur trioxide.
SO2(g) + V2O5(s) → SO3(g) + 2VO2(s)
O2(g) + 2VO2(s) → V2O5(s)
Outline how vanadium(V) oxide acts as a catalyst.
- 18N.3.sl.TZ0.2c.i: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.sl.TZ0.2c.ii: Identify another advantage of using a zeolite instead of concentrated sulfuric acid.
- 18N.3.sl.TZ0.c.i: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.sl.TZ0.c.ii: Identify another advantage of using a zeolite instead of concentrated sulfuric acid.
- 18N.3.hl.TZ0.2c: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
- 18N.3.hl.TZ0.c: A zeolite is an alternative catalyst for this reaction. Explain how zeolites act as selective...
A.4 Liquid crystals
-
17N.3.sl.TZ0.7a:
Outline two properties a substance should have to be used as liquid-crystal in a liquid-crystal display.
-
18M.3.hl.TZ2.6b:
MWCNT are very small in size and can greatly increase switching speeds in a liquid crystal allowing the liquid crystal to change orientation quickly.
Discuss two other properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.sl.TZ1.3b.iv:
State the property of carbon nanotubes that enables them to form a nematic liquid crystal phase.
-
18M.3.sl.TZ1.4a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ2.5b:
Discuss three properties a substance should have to be suitable for use in liquid crystal displays.
- 18N.3.sl.TZ0.4a: Outline two observations that he could have made.
- 18N.3.sl.TZ0.4b: The structure of biphenyl nitrile is shown. Describe, giving a reason, a feature of the...
-
19M.3.hl.TZ1.5a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.5b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.hl.TZ2.3:
Describe the characteristics of the nematic liquid crystal phase.
Shape of molecules:
Distribution:
-
19M.3.sl.TZ1.5a:
State the name of the functional group which allows the molecule to be responsive to applied electric fields.
-
19M.3.sl.TZ1.5b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.sl.TZ2.3:
Describe the characteristics of the nematic liquid crystal phase and the effect that an electric field has on it.
Shape of molecules:Distribution:
Effect of electric field:
- 19N.3.sl.TZ0.6a: Describe the arrangement of soap molecules in the nematic liquid crystal phase.
- 19N.3.sl.TZ0.6b: State how liquid crystals are affected by an electric field.
- 20N.3.sl.TZ0.4d: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.hl.TZ0.4e: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
-
19M.3.hl.TZ1.5a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.5b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.hl.TZ1.a:
Label with an asterisk, *, the chiral carbon atom.
-
19M.3.hl.TZ1.b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.hl.TZ2.3:
Describe the characteristics of the nematic liquid crystal phase.
Shape of molecules:
Distribution:
-
19M.3.sl.TZ1.5a:
State the name of the functional group which allows the molecule to be responsive to applied electric fields.
-
19M.3.sl.TZ1.5b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.sl.TZ1.a:
State the name of the functional group which allows the molecule to be responsive to applied electric fields.
-
19M.3.sl.TZ1.b:
Explain the effects of very low and high temperatures on the liquid-crystal behaviour of this molecule.
Low temperature:
High temperature:
-
19M.3.sl.TZ2.3:
Describe the characteristics of the nematic liquid crystal phase and the effect that an electric field has on it.
Shape of molecules:Distribution:
Effect of electric field:
- 19N.3.sl.TZ0.6a: Describe the arrangement of soap molecules in the nematic liquid crystal phase.
- 19N.3.sl.TZ0.6b: State how liquid crystals are affected by an electric field.
- 19N.3.sl.TZ0.a: Describe the arrangement of soap molecules in the nematic liquid crystal phase.
- 19N.3.sl.TZ0.b: State how liquid crystals are affected by an electric field.
- 20N.3.sl.TZ0.4d: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.sl.TZ0.4e: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.sl.TZ0.d: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.hl.TZ0.4e: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
- 20N.3.hl.TZ0.e: Experiments have been done to explore the nematic liquid crystal behaviour of CNT. Justify how...
-
17N.3.sl.TZ0.7a:
Outline two properties a substance should have to be used as liquid-crystal in a liquid-crystal display.
-
17N.3.sl.TZ0.a:
Outline two properties a substance should have to be used as liquid-crystal in a liquid-crystal display.
-
18M.3.hl.TZ2.6b:
MWCNT are very small in size and can greatly increase switching speeds in a liquid crystal allowing the liquid crystal to change orientation quickly.
Discuss two other properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.hl.TZ2.b:
MWCNT are very small in size and can greatly increase switching speeds in a liquid crystal allowing the liquid crystal to change orientation quickly.
Discuss two other properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.sl.TZ1.3b.iv:
State the property of carbon nanotubes that enables them to form a nematic liquid crystal phase.
-
18M.3.sl.TZ1.b.iv:
State the property of carbon nanotubes that enables them to form a nematic liquid crystal phase.
-
18M.3.sl.TZ1.4a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ1.a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ2.5b:
Discuss three properties a substance should have to be suitable for use in liquid crystal displays.
-
18M.3.sl.TZ2.b:
Discuss three properties a substance should have to be suitable for use in liquid crystal displays.
- 18N.3.sl.TZ0.4a: Outline two observations that he could have made.
- 18N.3.sl.TZ0.4b: The structure of biphenyl nitrile is shown. Describe, giving a reason, a feature of the...
- 18N.3.sl.TZ0.a: Outline two observations that he could have made.
- 18N.3.sl.TZ0.b: The structure of biphenyl nitrile is shown. Describe, giving a reason, a feature of the...
A.5 Polymers
-
17N.3.sl.TZ0.7b.i:
Describe how the structures of LDPE and HDPE affect one mechanical property of the plastics.
-
18M.3.hl.TZ1.4c.ii:
Deduce, giving a reason, whether the atom economy of a condensation polymerization, such as this, would be greater or less than an addition polymerization, such as the formation of HDPE.
-
18M.3.sl.TZ1.4a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ1.4b.i:
Compare and contrast the structures of HDPE and LDPE.
-
18M.3.sl.TZ1.4b.ii:
State one way in which a physical property of HDPE, other than density, differs from that of LDPE as a result of this structural difference.
-
18M.3.sl.TZ2.4a:
Sketch four repeating units of the polymer to show atactic and isotactic polypropene.
-
18N.3.sl.TZ0.2b.i:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.hl.TZ0.2b:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
19M.3.hl.TZ1.4b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.hl.TZ2.5a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.hl.TZ2.5c:
Explain how plasticizers affect the properties of plastics.
-
19M.3.sl.TZ1.4b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.sl.TZ2.5a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.sl.TZ2.5d:
Explain how plasticizers affect the properties of plastics.
- 19N.3.hl.TZ0.5b: State and explain why plasticizers are added to polymers.
-
19N.3.sl.TZ0.4a:
Draw a section of an isotactic polypropene polymer chain containing four repeating units.
- 19N.3.sl.TZ0.4b: Predict, with a reason, whether isotactic or atactic polypropene has the higher melting point.
- 19N.3.sl.TZ0.4c: Polypropene is a thermoplastic. Outline what is meant by thermoplastic.
- 19N.3.sl.TZ0.4d: Discuss why the recycling of plastics is an energy intensive process.
- 20N.3.sl.TZ0.3b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.sl.TZ0.3b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.sl.TZ0.3c: Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.hl.TZ0.3b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.hl.TZ0.3b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.hl.TZ0.3b(iii): Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 23M.2.HL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.HL.TZ2.7a: Identify the type of reaction.
- 23M.2.SL.TZ1.3ai: Outline the meaning of homologous series.
-
19M.3.hl.TZ1.4b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.hl.TZ1.b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.hl.TZ2.5a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.hl.TZ2.5c:
Explain how plasticizers affect the properties of plastics.
-
19M.3.hl.TZ2.a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.hl.TZ2.c:
Explain how plasticizers affect the properties of plastics.
-
19M.3.sl.TZ1.4b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.sl.TZ1.b:
Suggest, giving a reason, how elastomers used for the tyre tread can increase the traction between the tyre and the road.
-
19M.3.sl.TZ2.5a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.sl.TZ2.5d:
Explain how plasticizers affect the properties of plastics.
-
19M.3.sl.TZ2.a:
Draw a section of isotactic polychloroethene (polyvinylchloride, PVC) showing all the atoms and all the bonds of four monomer units.
-
19M.3.sl.TZ2.d:
Explain how plasticizers affect the properties of plastics.
- 19N.3.hl.TZ0.5b: State and explain why plasticizers are added to polymers.
- 19N.3.hl.TZ0.b: State and explain why plasticizers are added to polymers.
-
19N.3.sl.TZ0.4a:
Draw a section of an isotactic polypropene polymer chain containing four repeating units.
- 19N.3.sl.TZ0.4b: Predict, with a reason, whether isotactic or atactic polypropene has the higher melting point.
- 19N.3.sl.TZ0.4c: Polypropene is a thermoplastic. Outline what is meant by thermoplastic.
- 19N.3.sl.TZ0.4d: Discuss why the recycling of plastics is an energy intensive process.
-
19N.3.sl.TZ0.a:
Draw a section of an isotactic polypropene polymer chain containing four repeating units.
- 19N.3.sl.TZ0.b: Predict, with a reason, whether isotactic or atactic polypropene has the higher melting point.
- 19N.3.sl.TZ0.c: Polypropene is a thermoplastic. Outline what is meant by thermoplastic.
- 19N.3.sl.TZ0.d: Discuss why the recycling of plastics is an energy intensive process.
- 20N.3.sl.TZ0.3b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.sl.TZ0.3b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.sl.TZ0.3c: Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.sl.TZ0.b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.sl.TZ0.b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.sl.TZ0.c: Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.hl.TZ0.3b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.hl.TZ0.3b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.hl.TZ0.3b(iii): Explain why phthalates are replaced by other plasticizers in the production of plastics.
- 20N.3.hl.TZ0.b(i): Thermoplastic composites are increasingly replacing thermosets. Suggest one advantage of...
- 20N.3.hl.TZ0.b(ii): Explain how thermoplastics, such as polyvinylchloride, PVC, can be made more flexible by the...
- 20N.3.hl.TZ0.b(iii): Explain why phthalates are replaced by other plasticizers in the production of plastics.
-
17N.3.sl.TZ0.7b.i:
Describe how the structures of LDPE and HDPE affect one mechanical property of the plastics.
-
17N.3.sl.TZ0.b.i:
Describe how the structures of LDPE and HDPE affect one mechanical property of the plastics.
-
18M.3.hl.TZ1.4c.ii:
Deduce, giving a reason, whether the atom economy of a condensation polymerization, such as this, would be greater or less than an addition polymerization, such as the formation of HDPE.
-
18M.3.hl.TZ1.c.ii:
Deduce, giving a reason, whether the atom economy of a condensation polymerization, such as this, would be greater or less than an addition polymerization, such as the formation of HDPE.
- 23M.2.HL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.i: Outline the meaning of homologous series.
- 23M.2.HL.TZ2.7a: Identify the type of reaction.
- 23M.2.HL.TZ2.a: Identify the type of reaction.
- 23M.2.SL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.SL.TZ1.i: Outline the meaning of homologous series.
-
18M.3.sl.TZ1.4a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ1.4b.i:
Compare and contrast the structures of HDPE and LDPE.
-
18M.3.sl.TZ1.4b.ii:
State one way in which a physical property of HDPE, other than density, differs from that of LDPE as a result of this structural difference.
-
18M.3.sl.TZ1.a:
Both of these are thermoplastic polymers. Outline what this term means.
-
18M.3.sl.TZ1.b.i:
Compare and contrast the structures of HDPE and LDPE.
-
18M.3.sl.TZ1.b.ii:
State one way in which a physical property of HDPE, other than density, differs from that of LDPE as a result of this structural difference.
-
18M.3.sl.TZ2.4a:
Sketch four repeating units of the polymer to show atactic and isotactic polypropene.
-
18M.3.sl.TZ2.a:
Sketch four repeating units of the polymer to show atactic and isotactic polypropene.
-
18N.3.sl.TZ0.2b.i:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.sl.TZ0.b.i:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.hl.TZ0.2b:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
-
18N.3.hl.TZ0.b:
Structures of poly(methyl acrylate), PMA, and Bakelite® are shown.
Suggest, giving reasons, which is the thermoplastic polymer and which is the thermosetting polymer.
A.6 Nanotechnology
-
17N.3.sl.TZ0.6a:
State equations for the formation of iron nanoparticles and carbon atoms from Fe(CO)5 in the HIPCO process.
- 17N.3.sl.TZ0.6b: Outline why the iron nanoparticle catalysts produced by the HIPCO process are more efficient than...
- 17N.3.sl.TZ0.6c: Discuss one possible risk associated with the use of nanotechnology.
-
18M.3.sl.TZ1.3b.ii:
State one physical property of HDPE that will be affected by the incorporation of carbon nanotubes.
-
18M.3.sl.TZ1.3b.iii:
Describe how carbon nanotubes are produced by chemical vapour deposition (CVD).
-
18M.3.sl.TZ2.5a:
State the source of carbon for MWCNT produced by arc discharge and by CVD.
-
18N.3.sl.TZ0.4c:
Arc discharge, consisting of two inert metal electrodes in a liquid solvent, is one method of producing carbon nanotubes (CNTs).
Predict, giving a reason, the electrode at which the solvent cyclohexane, C6H12, will decompose to form CNTs.
-
19M.3.hl.TZ1.6a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.hl.TZ1.6b:
Suggest one application for carbon nanotubes.
-
19M.3.hl.TZ2.4e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.sl.TZ1.6a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.sl.TZ1.6b:
Suggest one application for carbon nanotubes.
-
19M.3.sl.TZ2.4e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19N.3.sl.TZ0.3c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
- 20N.3.sl.TZ0.4a: Explain these properties of carbon nanotubes.
- 20N.3.hl.TZ0.4a: Explain these properties of carbon nanotubes.
-
19M.3.hl.TZ1.6a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.hl.TZ1.6b:
Suggest one application for carbon nanotubes.
-
19M.3.hl.TZ1.a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.hl.TZ1.b:
Suggest one application for carbon nanotubes.
-
19M.3.hl.TZ2.4e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.hl.TZ2.e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.sl.TZ1.6a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.sl.TZ1.6b:
Suggest one application for carbon nanotubes.
-
19M.3.sl.TZ1.a:
Describe the structure and bonding of a carbon nanotube.
Structure:
Bonding:
-
19M.3.sl.TZ1.b:
Suggest one application for carbon nanotubes.
-
19M.3.sl.TZ2.4e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19M.3.sl.TZ2.e:
Carbon nanotubes are added to metals to increase tensile strength.
Write an equation for the formation of carbon nanotubes from carbon monoxide.
-
19N.3.sl.TZ0.3c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
-
19N.3.sl.TZ0.c:
Nanotubes are used to support the active material in nanocatalysts.
Explain why oxygen cannot be used for the chemical vapour deposition (CVD) preparation of carbon nanotubes.
- 20N.3.sl.TZ0.4a: Explain these properties of carbon nanotubes.
- 20N.3.sl.TZ0.a: Explain these properties of carbon nanotubes.
- 20N.3.hl.TZ0.4a: Explain these properties of carbon nanotubes.
- 20N.3.hl.TZ0.a: Explain these properties of carbon nanotubes.
-
17N.3.sl.TZ0.6a:
State equations for the formation of iron nanoparticles and carbon atoms from Fe(CO)5 in the HIPCO process.
- 17N.3.sl.TZ0.6b: Outline why the iron nanoparticle catalysts produced by the HIPCO process are more efficient than...
- 17N.3.sl.TZ0.6c: Discuss one possible risk associated with the use of nanotechnology.
-
17N.3.sl.TZ0.a:
State equations for the formation of iron nanoparticles and carbon atoms from Fe(CO)5 in the HIPCO process.
- 17N.3.sl.TZ0.b: Outline why the iron nanoparticle catalysts produced by the HIPCO process are more efficient than...
- 17N.3.sl.TZ0.c: Discuss one possible risk associated with the use of nanotechnology.
-
18M.3.sl.TZ1.3b.ii:
State one physical property of HDPE that will be affected by the incorporation of carbon nanotubes.
-
18M.3.sl.TZ1.3b.iii:
Describe how carbon nanotubes are produced by chemical vapour deposition (CVD).
-
18M.3.sl.TZ1.b.ii:
State one physical property of HDPE that will be affected by the incorporation of carbon nanotubes.
-
18M.3.sl.TZ1.b.iii:
Describe how carbon nanotubes are produced by chemical vapour deposition (CVD).
-
18M.3.sl.TZ2.5a:
State the source of carbon for MWCNT produced by arc discharge and by CVD.
-
18M.3.sl.TZ2.a:
State the source of carbon for MWCNT produced by arc discharge and by CVD.
-
18N.3.sl.TZ0.4c:
Arc discharge, consisting of two inert metal electrodes in a liquid solvent, is one method of producing carbon nanotubes (CNTs).
Predict, giving a reason, the electrode at which the solvent cyclohexane, C6H12, will decompose to form CNTs.
-
18N.3.sl.TZ0.c:
Arc discharge, consisting of two inert metal electrodes in a liquid solvent, is one method of producing carbon nanotubes (CNTs).
Predict, giving a reason, the electrode at which the solvent cyclohexane, C6H12, will decompose to form CNTs.
A.7 Environmental impact—plastics
-
17N.3.sl.TZ0.7b.ii:
One of the two infrared (IR) spectra is that of polyethene and the other of polytetrafluoroethene (PTFE).
Deduce, with a reason, which spectrum is that of PTFE. Infrared data is given in section 26 of the data booklet.
-
17N.3.sl.TZ0.7c:
Many plastics used to be incinerated. Deduce an equation for the complete combustion of two repeating units of PVC, (–C2H3Cl–)2.
-
18M.3.sl.TZ1.4d:
Suggest two of the major obstacles, other than collection and economic factors, which have to be overcome in plastic recycling.
-
18M.3.sl.TZ2.4b.i:
State the chemical reason why plastics do not degrade easily.
-
18M.3.sl.TZ2.4b.ii:
Compare two ways in which recycling differs from reusing plastics.
-
18N.3.sl.TZ0.2b.ii:
In an incomplete combustion of the polyvinyl chloride, PVC, it was found that hydrogen chloride, carbon monoxide, carbon dioxide, and water vapour were released.
Formulate an equation for this reaction using the formula of the PVC repeating unit.
-
18N.3.sl.TZ0.2d:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
-
19M.3.hl.TZ1.4c:
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.hl.TZ2.5d:
Suggest why the addition of plasticizers is controversial.
-
19M.3.sl.TZ1.4c(i):
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.sl.TZ1.4c(ii):
The trace quantities of dioxins from tyre fires are rarely inhaled and instead settle on the ground.
Describe why this is a health concern.
-
19M.3.sl.TZ2.5c:
Identify a hazardous product of the incineration of polychloroethene.
-
19M.3.sl.TZ2.5e:
Suggest why the addition of plasticizers is controversial.
- 19N.3.hl.TZ0.5c: Discuss why the recycling of plastics is an energy intensive process.
-
19M.3.hl.TZ1.4c:
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.hl.TZ1.c:
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.hl.TZ2.5d:
Suggest why the addition of plasticizers is controversial.
-
19M.3.hl.TZ2.d:
Suggest why the addition of plasticizers is controversial.
-
19M.3.sl.TZ1.4c(i):
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.sl.TZ1.4c(ii):
The trace quantities of dioxins from tyre fires are rarely inhaled and instead settle on the ground.
Describe why this is a health concern.
-
19M.3.sl.TZ1.c(i):
Tyre fires emit trace quantities of polychlorinated dibenzofurans and polychlorinated dibenzo-p-dioxin.
Outline, using section 31 of the data booklet, why polychlorinated dibenzofuran is not classed chemically as a dioxin but considered “dioxin-like”.
-
19M.3.sl.TZ1.c(ii):
The trace quantities of dioxins from tyre fires are rarely inhaled and instead settle on the ground.
Describe why this is a health concern.
-
19M.3.sl.TZ2.5c:
Identify a hazardous product of the incineration of polychloroethene.
-
19M.3.sl.TZ2.5e:
Suggest why the addition of plasticizers is controversial.
-
19M.3.sl.TZ2.c:
Identify a hazardous product of the incineration of polychloroethene.
-
19M.3.sl.TZ2.e:
Suggest why the addition of plasticizers is controversial.
- 19N.3.hl.TZ0.5c: Discuss why the recycling of plastics is an energy intensive process.
- 19N.3.hl.TZ0.c: Discuss why the recycling of plastics is an energy intensive process.
-
17N.3.sl.TZ0.7b.ii:
One of the two infrared (IR) spectra is that of polyethene and the other of polytetrafluoroethene (PTFE).
Deduce, with a reason, which spectrum is that of PTFE. Infrared data is given in section 26 of the data booklet.
-
17N.3.sl.TZ0.7c:
Many plastics used to be incinerated. Deduce an equation for the complete combustion of two repeating units of PVC, (–C2H3Cl–)2.
-
17N.3.sl.TZ0.b.ii:
One of the two infrared (IR) spectra is that of polyethene and the other of polytetrafluoroethene (PTFE).
Deduce, with a reason, which spectrum is that of PTFE. Infrared data is given in section 26 of the data booklet.
-
17N.3.sl.TZ0.c:
Many plastics used to be incinerated. Deduce an equation for the complete combustion of two repeating units of PVC, (–C2H3Cl–)2.
-
18M.3.sl.TZ1.4d:
Suggest two of the major obstacles, other than collection and economic factors, which have to be overcome in plastic recycling.
-
18M.3.sl.TZ1.d:
Suggest two of the major obstacles, other than collection and economic factors, which have to be overcome in plastic recycling.
-
18M.3.sl.TZ2.4b.i:
State the chemical reason why plastics do not degrade easily.
-
18M.3.sl.TZ2.4b.ii:
Compare two ways in which recycling differs from reusing plastics.
-
18M.3.sl.TZ2.b.i:
State the chemical reason why plastics do not degrade easily.
-
18M.3.sl.TZ2.b.ii:
Compare two ways in which recycling differs from reusing plastics.
-
18N.3.sl.TZ0.2b.ii:
In an incomplete combustion of the polyvinyl chloride, PVC, it was found that hydrogen chloride, carbon monoxide, carbon dioxide, and water vapour were released.
Formulate an equation for this reaction using the formula of the PVC repeating unit.
-
18N.3.sl.TZ0.2d:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
-
18N.3.sl.TZ0.b.ii:
In an incomplete combustion of the polyvinyl chloride, PVC, it was found that hydrogen chloride, carbon monoxide, carbon dioxide, and water vapour were released.
Formulate an equation for this reaction using the formula of the PVC repeating unit.
-
18N.3.sl.TZ0.d:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
A.8 Superconducting metals and X-ray crystallography (HL only)
-
17N.3.hl.TZ0.6b:
Explain why Type 2 superconductors are generally more useful than Type 1.
-
17N.3.hl.TZ0.8a:
Calculate the total number of cobalt atoms within its unit cell.
-
17N.3.hl.TZ0.8b.i:
The atomic radius, r, of cobalt is 1.18 × 10–8 cm. Determine the edge length, in cm, of the unit cell, a, using the second diagram.
-
17N.3.hl.TZ0.8b.ii:
Determine a value for the density of cobalt, in g cm–3, using data from sections 2 and 6 of the data booklet and your answers from (a) and (b) (i).
If you did not obtain an answer to (b) (i), use 3.00 × 10–8 cm but this is not the correct answer.
-
18M.3.hl.TZ1.5b:
The diagram illustrates the crystal structure of aluminium metal with the unit cell indicated. Outline the significance of the unit cell.
-
18M.3.hl.TZ1.5c:
When X-rays of wavelength 0.154 nm are directed at a crystal of aluminium, the first order diffraction pattern is observed at 18°. Determine the separation of layers of aluminium atoms in the crystal, in m, using section 1 of the data booklet.
-
18M.3.hl.TZ1.5d.i:
Deduce what the shape of the graph indicates about aluminium.
-
18M.3.hl.TZ1.5d.ii:
Outline why the resistance of aluminium increases above 1.2 K.
-
18M.3.hl.TZ2.4a.i:
Deduce the number of atoms per unit cell in vanadium.
-
18M.3.hl.TZ2.4a.ii:
Calculate the expected first order diffraction pattern angle, in degrees, if x-rays of wavelength 150 pm are directed at a crystal of vanadium. Assume the edge length of the crystal to be the same as separation of layers of vanadium atoms found by x-ray diffraction. Use section 1 of the data booklet.
-
18M.3.hl.TZ2.4a.iii:
Calculate the average mass, in g, of a vanadium atom by using sections 2 and 6 of the data booklet.
-
18M.3.hl.TZ2.4a.iv:
Determine the volume, in cm3, of a vanadium unit cell.
-
18M.3.hl.TZ2.4a.v:
Determine the density, in g cm−3, of vanadium by using your answers to (a)(i), (a)(iii) and (a)(iv).
- 18N.3.hl.TZ0.5a.i: State the name of the crystal structure of gold.
-
18N.3.hl.TZ0.5a.ii:
Calculate the number of atoms per unit cell of gold, showing your working.
-
18N.3.hl.TZ0.5b:
The edge length of the gold unit cell is 4.08 × 10‒8 cm.
Determine the density of gold in g cm‒3, using sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ1.3d(i):
Lithium has shown some superconductive properties when doped into graphene or when under high pressure. Under high pressure, however, the Meissner effect is absent.
Describe the Meissner effect.
-
19M.3.hl.TZ1.3d(ii):
At very low temperatures, lithium atoms enhance the phonon binding of electrons in graphene suggesting the formation of Cooper pairs.
Explain how Cooper pairs are formed.
-
19M.3.hl.TZ1.3e:
Lithium forms a crystalline lattice with the unit cell structure shown below.
X-ray diffraction shows that the length of the edge of the unit cell is 3.51 × 10−8 cm.
Determine the density of lithium, in g cm−3, using sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ2.6a:
State the number of atoms in the unit cell.
-
19M.3.hl.TZ2.6b:
Determine the density of calcium, in g cm−3, using section 2 of the data booklet.
Ar = 40.08; metallic radius (r) = 1.97 × 10−10 m
-
19M.3.hl.TZ2.7a:
State what is meant by a superconductor.
-
19M.3.hl.TZ2.18b:
Outline one approach to controlling industrial emissions of carbon dioxide.
- 19N.3.hl.TZ0.4a(i): Outline how resistance to electric currents occurs in metals.
- 19N.3.hl.TZ0.4a(ii): Suggest why the resistance of metals increases with temperature.
- 19N.3.hl.TZ0.4b: State two differences between Type I and Type II superconductors.
-
19N.3.hl.TZ0.7:
X-ray crystallography of a metal crystal produces a diffraction pattern of bright spots.
Using X-rays of wavelength 1.54 × 10−10 m, the first bright spots were produced at an angle θ of 22.3° from the centre.
Calculate the separation between planes of atoms in the lattice, in meters, using section 1 of the data booklet.
- 20N.3.hl.TZ0.4b(i): CNT can act as Type 2 superconductors. Outline why Type 2 superconductors are generally more...
-
20N.3.hl.TZ0.4b(ii):
Explain the role of electrons in superconducting materials in terms of the Bardeen–Cooper–Schrieffer (BCS) theory.
-
19M.3.hl.TZ1.3d(i):
Lithium has shown some superconductive properties when doped into graphene or when under high pressure. Under high pressure, however, the Meissner effect is absent.
Describe the Meissner effect.
-
19M.3.hl.TZ1.3d(ii):
At very low temperatures, lithium atoms enhance the phonon binding of electrons in graphene suggesting the formation of Cooper pairs.
Explain how Cooper pairs are formed.
-
19M.3.hl.TZ1.3e:
Lithium forms a crystalline lattice with the unit cell structure shown below.
X-ray diffraction shows that the length of the edge of the unit cell is 3.51 × 10−8 cm.
Determine the density of lithium, in g cm−3, using sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ1.d(i):
Lithium has shown some superconductive properties when doped into graphene or when under high pressure. Under high pressure, however, the Meissner effect is absent.
Describe the Meissner effect.
-
19M.3.hl.TZ1.d(ii):
At very low temperatures, lithium atoms enhance the phonon binding of electrons in graphene suggesting the formation of Cooper pairs.
Explain how Cooper pairs are formed.
-
19M.3.hl.TZ1.e:
Lithium forms a crystalline lattice with the unit cell structure shown below.
X-ray diffraction shows that the length of the edge of the unit cell is 3.51 × 10−8 cm.
Determine the density of lithium, in g cm−3, using sections 2 and 6 of the data booklet.
-
19M.3.hl.TZ2.6a:
State the number of atoms in the unit cell.
-
19M.3.hl.TZ2.6b:
Determine the density of calcium, in g cm−3, using section 2 of the data booklet.
Ar = 40.08; metallic radius (r) = 1.97 × 10−10 m
-
19M.3.hl.TZ2.a:
State the number of atoms in the unit cell.
-
19M.3.hl.TZ2.b:
Determine the density of calcium, in g cm−3, using section 2 of the data booklet.
Ar = 40.08; metallic radius (r) = 1.97 × 10−10 m
-
19M.3.hl.TZ2.7a:
State what is meant by a superconductor.
-
19M.3.hl.TZ2.a:
State what is meant by a superconductor.
-
19M.3.hl.TZ2.18b:
Outline one approach to controlling industrial emissions of carbon dioxide.
-
19M.3.hl.TZ2.b:
Outline one approach to controlling industrial emissions of carbon dioxide.
- 19N.3.hl.TZ0.4a(i): Outline how resistance to electric currents occurs in metals.
- 19N.3.hl.TZ0.4a(ii): Suggest why the resistance of metals increases with temperature.
- 19N.3.hl.TZ0.4b: State two differences between Type I and Type II superconductors.
- 19N.3.hl.TZ0.a(i): Outline how resistance to electric currents occurs in metals.
- 19N.3.hl.TZ0.a(ii): Suggest why the resistance of metals increases with temperature.
- 19N.3.hl.TZ0.b: State two differences between Type I and Type II superconductors.
-
19N.3.hl.TZ0.7:
X-ray crystallography of a metal crystal produces a diffraction pattern of bright spots.
Using X-rays of wavelength 1.54 × 10−10 m, the first bright spots were produced at an angle θ of 22.3° from the centre.
Calculate the separation between planes of atoms in the lattice, in meters, using section 1 of the data booklet.
- 20N.3.hl.TZ0.4b(i): CNT can act as Type 2 superconductors. Outline why Type 2 superconductors are generally more...
-
20N.3.hl.TZ0.4b(ii):
Explain the role of electrons in superconducting materials in terms of the Bardeen–Cooper–Schrieffer (BCS) theory.
- 20N.3.hl.TZ0.b(i): CNT can act as Type 2 superconductors. Outline why Type 2 superconductors are generally more...
-
20N.3.hl.TZ0.b(ii):
Explain the role of electrons in superconducting materials in terms of the Bardeen–Cooper–Schrieffer (BCS) theory.
-
17N.3.hl.TZ0.6b:
Explain why Type 2 superconductors are generally more useful than Type 1.
-
17N.3.hl.TZ0.b:
Explain why Type 2 superconductors are generally more useful than Type 1.
-
17N.3.hl.TZ0.8a:
Calculate the total number of cobalt atoms within its unit cell.
-
17N.3.hl.TZ0.8b.i:
The atomic radius, r, of cobalt is 1.18 × 10–8 cm. Determine the edge length, in cm, of the unit cell, a, using the second diagram.
-
17N.3.hl.TZ0.8b.ii:
Determine a value for the density of cobalt, in g cm–3, using data from sections 2 and 6 of the data booklet and your answers from (a) and (b) (i).
If you did not obtain an answer to (b) (i), use 3.00 × 10–8 cm but this is not the correct answer.
-
17N.3.hl.TZ0.a:
Calculate the total number of cobalt atoms within its unit cell.
-
17N.3.hl.TZ0.b.i:
The atomic radius, r, of cobalt is 1.18 × 10–8 cm. Determine the edge length, in cm, of the unit cell, a, using the second diagram.
-
17N.3.hl.TZ0.b.ii:
Determine a value for the density of cobalt, in g cm–3, using data from sections 2 and 6 of the data booklet and your answers from (a) and (b) (i).
If you did not obtain an answer to (b) (i), use 3.00 × 10–8 cm but this is not the correct answer.
-
18M.3.hl.TZ1.5b:
The diagram illustrates the crystal structure of aluminium metal with the unit cell indicated. Outline the significance of the unit cell.
-
18M.3.hl.TZ1.5c:
When X-rays of wavelength 0.154 nm are directed at a crystal of aluminium, the first order diffraction pattern is observed at 18°. Determine the separation of layers of aluminium atoms in the crystal, in m, using section 1 of the data booklet.
-
18M.3.hl.TZ1.5d.i:
Deduce what the shape of the graph indicates about aluminium.
-
18M.3.hl.TZ1.5d.ii:
Outline why the resistance of aluminium increases above 1.2 K.
-
18M.3.hl.TZ1.b:
The diagram illustrates the crystal structure of aluminium metal with the unit cell indicated. Outline the significance of the unit cell.
-
18M.3.hl.TZ1.c:
When X-rays of wavelength 0.154 nm are directed at a crystal of aluminium, the first order diffraction pattern is observed at 18°. Determine the separation of layers of aluminium atoms in the crystal, in m, using section 1 of the data booklet.
-
18M.3.hl.TZ1.d.i:
Deduce what the shape of the graph indicates about aluminium.
-
18M.3.hl.TZ1.d.ii:
Outline why the resistance of aluminium increases above 1.2 K.
-
18M.3.hl.TZ2.4a.i:
Deduce the number of atoms per unit cell in vanadium.
-
18M.3.hl.TZ2.4a.ii:
Calculate the expected first order diffraction pattern angle, in degrees, if x-rays of wavelength 150 pm are directed at a crystal of vanadium. Assume the edge length of the crystal to be the same as separation of layers of vanadium atoms found by x-ray diffraction. Use section 1 of the data booklet.
-
18M.3.hl.TZ2.4a.iii:
Calculate the average mass, in g, of a vanadium atom by using sections 2 and 6 of the data booklet.
-
18M.3.hl.TZ2.4a.iv:
Determine the volume, in cm3, of a vanadium unit cell.
-
18M.3.hl.TZ2.4a.v:
Determine the density, in g cm−3, of vanadium by using your answers to (a)(i), (a)(iii) and (a)(iv).
-
18M.3.hl.TZ2.a.i:
Deduce the number of atoms per unit cell in vanadium.
-
18M.3.hl.TZ2.a.ii:
Calculate the expected first order diffraction pattern angle, in degrees, if x-rays of wavelength 150 pm are directed at a crystal of vanadium. Assume the edge length of the crystal to be the same as separation of layers of vanadium atoms found by x-ray diffraction. Use section 1 of the data booklet.
-
18M.3.hl.TZ2.a.iii:
Calculate the average mass, in g, of a vanadium atom by using sections 2 and 6 of the data booklet.
-
18M.3.hl.TZ2.a.iv:
Determine the volume, in cm3, of a vanadium unit cell.
-
18M.3.hl.TZ2.a.v:
Determine the density, in g cm−3, of vanadium by using your answers to (a)(i), (a)(iii) and (a)(iv).
- 18N.3.hl.TZ0.5a.i: State the name of the crystal structure of gold.
-
18N.3.hl.TZ0.5a.ii:
Calculate the number of atoms per unit cell of gold, showing your working.
-
18N.3.hl.TZ0.5b:
The edge length of the gold unit cell is 4.08 × 10‒8 cm.
Determine the density of gold in g cm‒3, using sections 2 and 6 of the data booklet.
- 18N.3.hl.TZ0.a.i: State the name of the crystal structure of gold.
-
18N.3.hl.TZ0.a.ii:
Calculate the number of atoms per unit cell of gold, showing your working.
-
18N.3.hl.TZ0.b:
The edge length of the gold unit cell is 4.08 × 10‒8 cm.
Determine the density of gold in g cm‒3, using sections 2 and 6 of the data booklet.
A.9 Condensation polymers (HL only)
- 17N.3.hl.TZ0.7b: Describe how the monomers of addition polymers and of condensation polymers differ.
-
17N.3.hl.TZ0.7c:
Identify the type of intermolecular bonding that is responsible for Kevlar®’s strength.
-
18M.3.hl.TZ1.4c.i:
Draw the structure of the monomer from which nylon-6 is produced by a condensation reaction.
-
18M.3.hl.TZ2.5c.i:
Distinguish between the manufacture of polyester and polyethene.
- 18N.3.hl.TZ0.2d.i: State the names of the two terminal functional groups in X.
- 18N.3.hl.TZ0.2d.ii: Deduce the repeating unit of the polymer of X.
-
18N.3.hl.TZ0.2d.iii:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
-
19M.3.hl.TZ1.4d:
Classify polybutadiene as either an addition or condensation polymer, giving a reason.
-
19M.3.hl.TZ1.4e:
State one factor considered when making green chemistry polymers.
-
19M.3.hl.TZ2.5e:
Outline, giving a reason, how addition and condensation polymerization compare with regard to green chemistry.
-
19M.3.hl.TZ2.5f:
Draw the full structural formula of the organic functional group formed during the polymerization of the two reactants below.
-
19N.3.hl.TZ0.5a:
Draw the structure of the monomers of Kevlar® if the by-product of the condensation polymerization is hydrogen chloride.
- 20N.3.hl.TZ0.3c: Classify PVC and polyethene terephthalate, PET, as addition or condensation polymers and deduce...
-
19M.3.hl.TZ1.4d:
Classify polybutadiene as either an addition or condensation polymer, giving a reason.
-
19M.3.hl.TZ1.4e:
State one factor considered when making green chemistry polymers.
-
19M.3.hl.TZ1.d:
Classify polybutadiene as either an addition or condensation polymer, giving a reason.
-
19M.3.hl.TZ1.e:
State one factor considered when making green chemistry polymers.
-
19M.3.hl.TZ2.5e:
Outline, giving a reason, how addition and condensation polymerization compare with regard to green chemistry.
-
19M.3.hl.TZ2.5f:
Draw the full structural formula of the organic functional group formed during the polymerization of the two reactants below.
-
19M.3.hl.TZ2.e:
Outline, giving a reason, how addition and condensation polymerization compare with regard to green chemistry.
-
19M.3.hl.TZ2.f:
Draw the full structural formula of the organic functional group formed during the polymerization of the two reactants below.
-
19N.3.hl.TZ0.5a:
Draw the structure of the monomers of Kevlar® if the by-product of the condensation polymerization is hydrogen chloride.
-
19N.3.hl.TZ0.a:
Draw the structure of the monomers of Kevlar® if the by-product of the condensation polymerization is hydrogen chloride.
- 20N.3.hl.TZ0.3c: Classify PVC and polyethene terephthalate, PET, as addition or condensation polymers and deduce...
- 20N.3.hl.TZ0.c: Classify PVC and polyethene terephthalate, PET, as addition or condensation polymers and deduce...
- 17N.3.hl.TZ0.7b: Describe how the monomers of addition polymers and of condensation polymers differ.
-
17N.3.hl.TZ0.7c:
Identify the type of intermolecular bonding that is responsible for Kevlar®’s strength.
- 17N.3.hl.TZ0.b: Describe how the monomers of addition polymers and of condensation polymers differ.
-
17N.3.hl.TZ0.c:
Identify the type of intermolecular bonding that is responsible for Kevlar®’s strength.
-
18M.3.hl.TZ1.4c.i:
Draw the structure of the monomer from which nylon-6 is produced by a condensation reaction.
-
18M.3.hl.TZ1.c.i:
Draw the structure of the monomer from which nylon-6 is produced by a condensation reaction.
-
18M.3.hl.TZ2.5c.i:
Distinguish between the manufacture of polyester and polyethene.
-
18M.3.hl.TZ2.c.i:
Distinguish between the manufacture of polyester and polyethene.
- 18N.3.hl.TZ0.2d.i: State the names of the two terminal functional groups in X.
- 18N.3.hl.TZ0.2d.ii: Deduce the repeating unit of the polymer of X.
-
18N.3.hl.TZ0.2d.iii:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
- 18N.3.hl.TZ0.d.i: State the names of the two terminal functional groups in X.
- 18N.3.hl.TZ0.d.ii: Deduce the repeating unit of the polymer of X.
-
18N.3.hl.TZ0.d.iii:
Repeating units of several polymers are listed.
The infrared (IR) spectrum of one of these polymers is shown.
Deduce, giving a reason, the name of this polymer and its Resin Identification Code (RIC), using sections 26 and 30 in the data booklet.
A.10 Environmental impact—heavy metals (HL only)
- 17N.3.hl.TZ0.9a: State the name of one method, other than precipitation, of removing heavy metal ions from...
-
17N.3.hl.TZ0.9b:
The solubility product, Ksp , of cadmium sulfide, CdS, is 8.0 × 10–27. Determine the concentration of cadmium ions in 1.0 dm3 of a saturated solution of cadmium sulfide to which 0.10 mol of solid sodium sulfide has been added, stating any assumption you make.
-
18M.3.hl.TZ1.5e:
The concentration of aluminium in drinking water can be reduced by precipitating aluminium hydroxide. Calculate the maximum concentration of aluminium ions in water of pH 7 at 298 K. Solubility product of aluminium hydroxide = 3.3 × 10−34 at 298 K.
-
18M.3.hl.TZ2.4b.i:
Vanadium and other transition metals can interfere with cell metabolism.
State and explain one process, other than by creating free radicals, by which transition metals interfere with cell metabolism.
-
18M.3.hl.TZ2.4b.ii:
Vanadium(IV) ions can create free radicals by a Fenton reaction.
Deduce the equation for the reaction of V4+ with hydrogen peroxide.
-
18N.3.hl.TZ0.3b.ii:
Lead ions are toxic and can be precipitated using hydroxide ions.
Pb2+ (aq) + 2OH‒ (aq) Pb(OH)2 (s)
Sufficient sodium hydroxide solid is added to the antacid sample to produce a 1.0 × 10‒2 mol dm‒3 hydroxide ion solution at 298 K.
Deduce if a precipitate will be formed, using section 32 of the data booklet.
If you did not calculate the concentration of lead ions in (b)(i), use the value of 2.4 × 10−4 mol dm‒3, but this is not the correct value.
- 18N.3.hl.TZ0.3d.i: State one feature of a chelating agent.
-
18N.3.hl.TZ0.3d.ii:
An aqueous lead(II) ion reacts with three ethane-1,2-diamine molecules to form an octahedral chelate ion.
Outline why the chelate ion is more stable than the reactants.
-
19M.3.hl.TZ1.7a:
Explain how entropy affects this equilibrium.
-
19M.3.hl.TZ1.7b:
State the number of coordinate covalent bonds EDTA forms with Ni2+.
-
19M.3.hl.TZ2.8a:
Outline why heavy metals are toxic.
-
19M.3.hl.TZ2.8b:
Determine the maximum concentration of lead(II) ions at 298 K in a solution in which the concentration of carbonate ions is maintained at 1.10 × 10−4 mol dm−3. Use section 32 of the data booklet.
-
19M.3.hl.TZ2.8c:
State a method, other than precipitation, of removing heavy metal ions from solution.
-
19N.3.hl.TZ0.8:
1.40 × 10−3 g of NaOH (s) are dissolved in 250.0 cm3 of 1.00 × 10−11 mol dm−3 Pb(OH)2 (aq) solution.
Determine the change in lead ion concentration in the solution, using section 32 of the data booklet.
-
20N.3.hl.TZ0.5a:
Precipitation is one method used to treat waste water.
Phosphates, , in waste water can be removed by precipitation with magnesium ions. of magnesium phosphate is .
Calculate the maximum solubility of phosphate ions in a solution containing magnesium ions.
-
20N.3.hl.TZ0.5b:
Precipitation is one method used to treat waste water.
Zinc, cadmium, nickel, and lead are metal ions which can be removed by precipitation. Explain why waste water is adjusted to a pH of 9−10 to remove these ions by referring to section 32 of the data booklet.
-
19M.3.hl.TZ1.7a:
Explain how entropy affects this equilibrium.
-
19M.3.hl.TZ1.7b:
State the number of coordinate covalent bonds EDTA forms with Ni2+.
-
19M.3.hl.TZ1.a:
Explain how entropy affects this equilibrium.
-
19M.3.hl.TZ1.b:
State the number of coordinate covalent bonds EDTA forms with Ni2+.
-
19M.3.hl.TZ2.8a:
Outline why heavy metals are toxic.
-
19M.3.hl.TZ2.8b:
Determine the maximum concentration of lead(II) ions at 298 K in a solution in which the concentration of carbonate ions is maintained at 1.10 × 10−4 mol dm−3. Use section 32 of the data booklet.
-
19M.3.hl.TZ2.8c:
State a method, other than precipitation, of removing heavy metal ions from solution.
-
19M.3.hl.TZ2.a:
Outline why heavy metals are toxic.
-
19M.3.hl.TZ2.b:
Determine the maximum concentration of lead(II) ions at 298 K in a solution in which the concentration of carbonate ions is maintained at 1.10 × 10−4 mol dm−3. Use section 32 of the data booklet.
-
19M.3.hl.TZ2.c:
State a method, other than precipitation, of removing heavy metal ions from solution.
-
19N.3.hl.TZ0.8:
1.40 × 10−3 g of NaOH (s) are dissolved in 250.0 cm3 of 1.00 × 10−11 mol dm−3 Pb(OH)2 (aq) solution.
Determine the change in lead ion concentration in the solution, using section 32 of the data booklet.
-
20N.3.hl.TZ0.5a:
Precipitation is one method used to treat waste water.
Phosphates, , in waste water can be removed by precipitation with magnesium ions. of magnesium phosphate is .
Calculate the maximum solubility of phosphate ions in a solution containing magnesium ions.
-
20N.3.hl.TZ0.5b:
Precipitation is one method used to treat waste water.
Zinc, cadmium, nickel, and lead are metal ions which can be removed by precipitation. Explain why waste water is adjusted to a pH of 9−10 to remove these ions by referring to section 32 of the data booklet.
-
20N.3.hl.TZ0.a:
Precipitation is one method used to treat waste water.
Phosphates, , in waste water can be removed by precipitation with magnesium ions. of magnesium phosphate is .
Calculate the maximum solubility of phosphate ions in a solution containing magnesium ions.
-
20N.3.hl.TZ0.b:
Precipitation is one method used to treat waste water.
Zinc, cadmium, nickel, and lead are metal ions which can be removed by precipitation. Explain why waste water is adjusted to a pH of 9−10 to remove these ions by referring to section 32 of the data booklet.
- 17N.3.hl.TZ0.9a: State the name of one method, other than precipitation, of removing heavy metal ions from...
-
17N.3.hl.TZ0.9b:
The solubility product, Ksp , of cadmium sulfide, CdS, is 8.0 × 10–27. Determine the concentration of cadmium ions in 1.0 dm3 of a saturated solution of cadmium sulfide to which 0.10 mol of solid sodium sulfide has been added, stating any assumption you make.
- 17N.3.hl.TZ0.a: State the name of one method, other than precipitation, of removing heavy metal ions from...
-
17N.3.hl.TZ0.b:
The solubility product, Ksp , of cadmium sulfide, CdS, is 8.0 × 10–27. Determine the concentration of cadmium ions in 1.0 dm3 of a saturated solution of cadmium sulfide to which 0.10 mol of solid sodium sulfide has been added, stating any assumption you make.
-
18M.3.hl.TZ1.5e:
The concentration of aluminium in drinking water can be reduced by precipitating aluminium hydroxide. Calculate the maximum concentration of aluminium ions in water of pH 7 at 298 K. Solubility product of aluminium hydroxide = 3.3 × 10−34 at 298 K.
-
18M.3.hl.TZ1.e:
The concentration of aluminium in drinking water can be reduced by precipitating aluminium hydroxide. Calculate the maximum concentration of aluminium ions in water of pH 7 at 298 K. Solubility product of aluminium hydroxide = 3.3 × 10−34 at 298 K.
-
18M.3.hl.TZ2.4b.i:
Vanadium and other transition metals can interfere with cell metabolism.
State and explain one process, other than by creating free radicals, by which transition metals interfere with cell metabolism.
-
18M.3.hl.TZ2.4b.ii:
Vanadium(IV) ions can create free radicals by a Fenton reaction.
Deduce the equation for the reaction of V4+ with hydrogen peroxide.
-
18M.3.hl.TZ2.b.i:
Vanadium and other transition metals can interfere with cell metabolism.
State and explain one process, other than by creating free radicals, by which transition metals interfere with cell metabolism.
-
18M.3.hl.TZ2.b.ii:
Vanadium(IV) ions can create free radicals by a Fenton reaction.
Deduce the equation for the reaction of V4+ with hydrogen peroxide.
-
18N.3.hl.TZ0.3b.ii:
Lead ions are toxic and can be precipitated using hydroxide ions.
Pb2+ (aq) + 2OH‒ (aq) Pb(OH)2 (s)
Sufficient sodium hydroxide solid is added to the antacid sample to produce a 1.0 × 10‒2 mol dm‒3 hydroxide ion solution at 298 K.
Deduce if a precipitate will be formed, using section 32 of the data booklet.
If you did not calculate the concentration of lead ions in (b)(i), use the value of 2.4 × 10−4 mol dm‒3, but this is not the correct value.
- 18N.3.hl.TZ0.3d.i: State one feature of a chelating agent.
-
18N.3.hl.TZ0.3d.ii:
An aqueous lead(II) ion reacts with three ethane-1,2-diamine molecules to form an octahedral chelate ion.
Outline why the chelate ion is more stable than the reactants.
-
18N.3.hl.TZ0.b.ii:
Lead ions are toxic and can be precipitated using hydroxide ions.
Pb2+ (aq) + 2OH‒ (aq) Pb(OH)2 (s)
Sufficient sodium hydroxide solid is added to the antacid sample to produce a 1.0 × 10‒2 mol dm‒3 hydroxide ion solution at 298 K.
Deduce if a precipitate will be formed, using section 32 of the data booklet.
If you did not calculate the concentration of lead ions in (b)(i), use the value of 2.4 × 10−4 mol dm‒3, but this is not the correct value.
- 18N.3.hl.TZ0.d.i: State one feature of a chelating agent.
-
18N.3.hl.TZ0.d.ii:
An aqueous lead(II) ion reacts with three ethane-1,2-diamine molecules to form an octahedral chelate ion.
Outline why the chelate ion is more stable than the reactants.