DP Chemistry (last assessment 2024)

Question 18M.3.hl.TZ2.a.ii

Date	May 2018	Marks available	[Maximum mark: 2]	Reference code	18M.3.hl.TZ2.a.ii
Level	hl	Paper	3	Time zone	TZ2
Command term	Calculate	Question number	a.ii	Adapted from	N/A

a.ii.

[Maximum mark: 2]

18M.3.hl.TZ2.a.ii

Vanadium forms a body centred cubic (BCC) crystal structure with an edge length of 303 pm, (303 × 10⁻¹² m).

Calculate the expected first order diffraction pattern angle, in degrees, if x-rays of wavelength 150 pm are directed at a crystal of vanadium. Assume the edge length of the crystal to be the same as separation of layers of vanadium atoms found by x-ray diffraction. Use section 1 of the data booklet.

[2]

Markscheme

nλ = 2dsinθ

$\theta = {\sin ^{ - 1}}\left( {\frac{{n\lambda }}{{2d}}} \right)$

θ = « ${\sin ^{ - 1}}\left( {\frac{{150}}{{2 \times 303}}} \right) =$ » 14.3 «°»

Award [2] for correct final answer.

[2 marks]

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Options » A: Materials » A.8 Superconducting metals and X-ray crystallography (HL only)

Options » A: Materials

Question 18M.3.hl.TZ2.a.ii

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