Directly related questions
-
20N.1.hl.TZ0.11:
Which combination correctly describes the geometry of ?
-
20N.1.hl.TZ0.11:
Which combination correctly describes the geometry of ?
-
20N.2.hl.TZ0.2c:
State the number of sigma () and pi () bonds around the central carbon atom in molecule B.
-
20N.2.hl.TZ0.c:
State the number of sigma () and pi () bonds around the central carbon atom in molecule B.
-
20N.2.hl.TZ0.2c:
State the number of sigma () and pi () bonds around the central carbon atom in molecule B.
-
20N.2.hl.TZ0.2b:
State the type of hybridization shown by the central carbon atom in molecule B.
-
20N.2.hl.TZ0.b:
State the type of hybridization shown by the central carbon atom in molecule B.
-
20N.2.hl.TZ0.2b:
State the type of hybridization shown by the central carbon atom in molecule B.
- 17N.2.hl.TZ0.4c: State the type of hybridization shown by the phosphorus atom in PF3.
- 17N.2.hl.TZ0.4c: State the type of hybridization shown by the phosphorus atom in PF3.
- 17N.2.hl.TZ0.c: State the type of hybridization shown by the phosphorus atom in PF3.
-
17N.2.hl.TZ0.4a:
Draw the Lewis (electron dot) structures of PF3 and PF5 and use the VSEPR theory to deduce the molecular geometry of each species including bond angles.
-
17N.2.hl.TZ0.4a:
Draw the Lewis (electron dot) structures of PF3 and PF5 and use the VSEPR theory to deduce the molecular geometry of each species including bond angles.
-
17N.2.hl.TZ0.a:
Draw the Lewis (electron dot) structures of PF3 and PF5 and use the VSEPR theory to deduce the molecular geometry of each species including bond angles.
- 21M.1.hl.TZ1.13: In which series are all carbon atoms sp2 hybridized? A. C2H2 H2CO HCOOH B. C2H4 ...
- 21M.1.hl.TZ1.13: In which series are all carbon atoms sp2 hybridized? A. C2H2 H2CO HCOOH B. C2H4 ...
- 21M.1.hl.TZ2.13: What is the electron domain geometry of Si in SiO2? A. bent B. linear C. square planar D. ...
- 21M.1.hl.TZ2.13: What is the electron domain geometry of Si in SiO2? A. bent B. linear C. square planar D. ...
- 21M.2.hl.TZ2.4c: State the hybridization of the carbon I and II atoms in but-2-ene.
- 21M.2.hl.TZ2.4c: State the hybridization of the carbon I and II atoms in but-2-ene.
- 21M.2.hl.TZ2.c: State the hybridization of the carbon I and II atoms in but-2-ene.
-
21M.2.hl.TZ2.4d:
Draw diagrams to show how sigma (σ) and pi (π) bonds are formed between atoms.
-
21M.2.hl.TZ2.4d:
Draw diagrams to show how sigma (σ) and pi (π) bonds are formed between atoms.
-
21M.2.hl.TZ2.d:
Draw diagrams to show how sigma (σ) and pi (π) bonds are formed between atoms.
- 18M.1.hl.TZ1.12: Which molecules have at least one sp2 hybridized atom? I. CH3COOH II. ...
- 18M.1.hl.TZ1.12: Which molecules have at least one sp2 hybridized atom? I. CH3COOH II. ...
- 18M.1.hl.TZ1.13: Which can be represented with only one Lewis structure? A. CH2O B. C6H6 C. O3 D. ...
- 18M.1.hl.TZ1.13: Which can be represented with only one Lewis structure? A. CH2O B. C6H6 C. O3 D. ...
-
18M.2.hl.TZ1.2g.i:
Describe how sigma (σ) and pi () bonds are formed.
-
18M.2.hl.TZ1.2g.i:
Describe how sigma (σ) and pi () bonds are formed.
-
18M.2.hl.TZ1.g.i:
Describe how sigma (σ) and pi () bonds are formed.
-
18M.1.hl.TZ2.13:
Which overlap of atomic orbitals leads to the formation of only a sigma (σ) bond?
I. s − p
II. p − p
III. s − s
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
18M.1.hl.TZ2.13:
Which overlap of atomic orbitals leads to the formation of only a sigma (σ) bond?
I. s − p
II. p − p
III. s − s
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
18M.2.hl.TZ1.1i:
The C–N bonds in urea are shorter than might be expected for a single C–N bond. Suggest, in terms of electrons, how this could occur.
-
18M.2.hl.TZ1.1i:
The C–N bonds in urea are shorter than might be expected for a single C–N bond. Suggest, in terms of electrons, how this could occur.
-
18M.2.hl.TZ1.i:
The C–N bonds in urea are shorter than might be expected for a single C–N bond. Suggest, in terms of electrons, how this could occur.
-
18M.2.hl.TZ1.2g.ii:
Deduce the number of σ and bonds in a molecule of ethyne.
-
18M.2.hl.TZ1.2g.ii:
Deduce the number of σ and bonds in a molecule of ethyne.
-
18M.2.hl.TZ1.g.ii:
Deduce the number of σ and bonds in a molecule of ethyne.
- 18M.1.hl.TZ2.12: Which molecule has an expanded octet? A. CO B. CO2 C. SF2 D. SF4
- 18M.1.hl.TZ2.12: Which molecule has an expanded octet? A. CO B. CO2 C. SF2 D. SF4
-
18M.2.hl.TZ2.7d:
Absorption of UV light in the ozone layer causes the dissociation of oxygen and ozone.
Identify, in terms of bonding, the molecule that requires a longer wavelength to dissociate.
-
18M.2.hl.TZ2.7d:
Absorption of UV light in the ozone layer causes the dissociation of oxygen and ozone.
Identify, in terms of bonding, the molecule that requires a longer wavelength to dissociate.
-
18M.2.hl.TZ2.d:
Absorption of UV light in the ozone layer causes the dissociation of oxygen and ozone.
Identify, in terms of bonding, the molecule that requires a longer wavelength to dissociate.
-
18M.2.hl.TZ2.7c.i:
Carbon dioxide can be represented by at least two resonance structures, I and II.
Calculate the formal charge on each oxygen atom in the two structures.
-
18M.2.hl.TZ2.7c.i:
Carbon dioxide can be represented by at least two resonance structures, I and II.
Calculate the formal charge on each oxygen atom in the two structures.
-
18M.2.hl.TZ2.c.i:
Carbon dioxide can be represented by at least two resonance structures, I and II.
Calculate the formal charge on each oxygen atom in the two structures.
-
18M.2.hl.TZ2.7c.ii:
Deduce, giving a reason, the more likely structure.
-
18M.2.hl.TZ2.7c.ii:
Deduce, giving a reason, the more likely structure.
-
18M.2.hl.TZ2.c.ii:
Deduce, giving a reason, the more likely structure.
-
21N.1.hl.TZ0.12:
Which molecules contain two pi () bonds?
I. HCN
II. H2CO3
III. H2C2O4
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
-
21N.1.hl.TZ0.12:
Which molecules contain two pi () bonds?
I. HCN
II. H2CO3
III. H2C2O4
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
- 21N.1.hl.TZ0.13: What is the hybridization of nitrogen and chlorine in NCl3?
- 21N.1.hl.TZ0.13: What is the hybridization of nitrogen and chlorine in NCl3?
- 21N.2.hl.TZ0.3b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
- 21N.2.hl.TZ0.3b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
- 21N.2.hl.TZ0.b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
- 18N.1.hl.TZ0.13: What is the hybridization of the circled carbon, oxygen and nitrogen atoms?
- 18N.1.hl.TZ0.13: What is the hybridization of the circled carbon, oxygen and nitrogen atoms?
-
18N.1.hl.TZ0.12:
What is the number of sigma (σ) and pi (π) bonds in the molecule (NC)2C=C(CN)2?
-
18N.1.hl.TZ0.12:
What is the number of sigma (σ) and pi (π) bonds in the molecule (NC)2C=C(CN)2?
-
18N.2.hl.TZ0.3b.i:
Draw two Lewis (electron dot) structures for BrO3−.
-
18N.2.hl.TZ0.3b.i:
Draw two Lewis (electron dot) structures for BrO3−.
-
18N.2.hl.TZ0.b.i:
Draw two Lewis (electron dot) structures for BrO3−.
- 18N.2.hl.TZ0.6a.ii: Draw a diagram showing the delocalization of electrons in the conjugate base of butanoic acid.
- 18N.2.hl.TZ0.6a.ii: Draw a diagram showing the delocalization of electrons in the conjugate base of butanoic acid.
- 18N.2.hl.TZ0.a.ii: Draw a diagram showing the delocalization of electrons in the conjugate base of butanoic acid.
- 22M.1.hl.TZ1.12: In which compound are all carbon atoms sp3 hybridized? A. C2H2 B. C2H2Cl2 C. C2Cl4 D. C2Cl6
- 22M.1.hl.TZ1.12: In which compound are all carbon atoms sp3 hybridized? A. C2H2 B. C2H2Cl2 C. C2Cl4 D. C2Cl6
-
22M.1.hl.TZ2.11:
What is the formal charge of the oxygen atom in H3O+?
A. −2
B. −1
C. 0
D. +1
-
22M.1.hl.TZ2.11:
What is the formal charge of the oxygen atom in H3O+?
A. −2
B. −1
C. 0
D. +1
- 22M.1.hl.TZ2.12: What is the molecular geometry of SF4? A. Tetrahedral B. Trigonal bipyramidal C. ...
- 22M.1.hl.TZ2.12: What is the molecular geometry of SF4? A. Tetrahedral B. Trigonal bipyramidal C. ...
-
22M.2.hl.TZ1.6a(iii):
Explain the relative lengths of the three bonds between N and O in nitric acid.
-
22M.2.hl.TZ1.6a(iii):
Explain the relative lengths of the three bonds between N and O in nitric acid.
-
22M.2.hl.TZ1.a(iii):
Explain the relative lengths of the three bonds between N and O in nitric acid.
-
22M.2.hl.TZ2.7b(ii):
Identify the number of sigma and pi bonds in HCN.
-
22M.2.hl.TZ2.7b(ii):
Identify the number of sigma and pi bonds in HCN.
-
22M.2.hl.TZ2.b(ii):
Identify the number of sigma and pi bonds in HCN.
-
22M.2.hl.TZ2.7b(i):
Sketch the shape of one sigma () and one pi () bond.
-
22M.2.hl.TZ2.7b(i):
Sketch the shape of one sigma () and one pi () bond.
-
22M.2.hl.TZ2.b(i):
Sketch the shape of one sigma () and one pi () bond.
-
19M.2.hl.TZ1.2e:
Outline why both C to O bonds in the conjugate base are the same length and suggest a value for them. Use section 10 of the data booklet.
-
19M.2.hl.TZ1.2e:
Outline why both C to O bonds in the conjugate base are the same length and suggest a value for them. Use section 10 of the data booklet.
-
19M.2.hl.TZ1.e:
Outline why both C to O bonds in the conjugate base are the same length and suggest a value for them. Use section 10 of the data booklet.
-
19M.2.hl.TZ1.5c(ii):
State the hybridization of the nitrogen atom in chloramine.
-
19M.2.hl.TZ1.5c(ii):
State the hybridization of the nitrogen atom in chloramine.
-
19M.2.hl.TZ1.c(ii):
State the hybridization of the nitrogen atom in chloramine.
-
19M.2.hl.TZ2.3a(ii):
Dinitrogen monoxide in the stratosphere is converted to nitrogen monoxide, NO (g).
Write two equations to show how NO (g) catalyses the decomposition of ozone.
-
19M.2.hl.TZ2.3a(ii):
Dinitrogen monoxide in the stratosphere is converted to nitrogen monoxide, NO (g).
Write two equations to show how NO (g) catalyses the decomposition of ozone.
-
19M.2.hl.TZ2.a(ii):
Dinitrogen monoxide in the stratosphere is converted to nitrogen monoxide, NO (g).
Write two equations to show how NO (g) catalyses the decomposition of ozone.
-
19M.2.hl.TZ2.3d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
-
19M.2.hl.TZ2.3d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
-
19M.2.hl.TZ2.d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
-
19M.2.hl.TZ2.3d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
-
19M.2.hl.TZ2.3d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
-
19M.2.hl.TZ2.d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
- 19M.1.hl.TZ1.13: How many carbon atoms are sp3, sp2 and sp hybridized in the molecule?
- 19M.1.hl.TZ1.13: How many carbon atoms are sp3, sp2 and sp hybridized in the molecule?
- 19M.1.hl.TZ2.11: Which species has a square planar molecular geometry? A. SF4 B. XeF4 C. CF4 D. PF4+
- 19M.1.hl.TZ2.11: Which species has a square planar molecular geometry? A. SF4 B. XeF4 C. CF4 D. PF4+
- 19M.1.hl.TZ2.13: What is the hybridization of carbon and oxygen in methanol?
- 19M.1.hl.TZ2.13: What is the hybridization of carbon and oxygen in methanol?
- 19M.1.hl.TZ1.12: Which species has delocalized electrons? A. OH− B. H2CO C. CO2 D. CO32−
- 19M.1.hl.TZ1.12: Which species has delocalized electrons? A. OH− B. H2CO C. CO2 D. CO32−
- 19N.2.hl.TZ0.1e(i): Identify the steps which absorb ultraviolet light.
- 19N.2.hl.TZ0.1e(i): Identify the steps which absorb ultraviolet light.
- 19N.2.hl.TZ0.e(i): Identify the steps which absorb ultraviolet light.
- 19N.2.hl.TZ0.1f: Ozone depletion is catalysed by nitrogen monoxide, NO, which is produced in aircraft and motor...
- 19N.2.hl.TZ0.1f: Ozone depletion is catalysed by nitrogen monoxide, NO, which is produced in aircraft and motor...
- 19N.2.hl.TZ0.f: Ozone depletion is catalysed by nitrogen monoxide, NO, which is produced in aircraft and motor...
- 19N.1.hl.TZ0.12: Which atom is sp2 hybridized? A. C in H2CO B. C in CO2 C. N in CH3NH2 D. O in H2O
- 19N.1.hl.TZ0.12: Which atom is sp2 hybridized? A. C in H2CO B. C in CO2 C. N in CH3NH2 D. O in H2O
-
19N.2.hl.TZ0.6f(iii):
When excess ammonia is added to copper(II) chloride solution, the dark blue complex ion, [Cu(NH3)4(H2O)2]2+, forms.
State the molecular geometry of this complex ion, and the bond angles within it.
Molecular geometry:
Bond angles:
-
19N.2.hl.TZ0.6f(iii):
When excess ammonia is added to copper(II) chloride solution, the dark blue complex ion, [Cu(NH3)4(H2O)2]2+, forms.
State the molecular geometry of this complex ion, and the bond angles within it.
Molecular geometry:
Bond angles:
-
19N.2.hl.TZ0.f(iii):
When excess ammonia is added to copper(II) chloride solution, the dark blue complex ion, [Cu(NH3)4(H2O)2]2+, forms.
State the molecular geometry of this complex ion, and the bond angles within it.
Molecular geometry:
Bond angles:
- 19N.1.hl.TZ0.13: Which atom does not obey the octet rule? A. C in CO2 B. F in BF3 C. O in H2O D. S in SF6
- 19N.1.hl.TZ0.13: Which atom does not obey the octet rule? A. C in CO2 B. F in BF3 C. O in H2O D. S in SF6
- 22N.1.hl.TZ0.10: Which elements are capable of forming expanded octets? I. NitrogenII. PhosphorusIII....
- 22N.1.hl.TZ0.10: Which elements are capable of forming expanded octets? I. NitrogenII. PhosphorusIII....
- 22N.1.hl.TZ0.11: Which molecule has a tetrahedral molecular geometry? A. HNO3 B. SF4 C. XeF4 D. XeO4
- 22N.1.hl.TZ0.11: Which molecule has a tetrahedral molecular geometry? A. HNO3 B. SF4 C. XeF4 D. XeO4
-
22N.2.hl.TZ0.1f.v:
Deduce the Lewis (electron dot) structure, including formal charges, and shape for dinitrogen monoxide showing nitrogen as the central atom.
-
22N.2.hl.TZ0.1f.v:
Deduce the Lewis (electron dot) structure, including formal charges, and shape for dinitrogen monoxide showing nitrogen as the central atom.
-
22N.2.hl.TZ0.f.v:
Deduce the Lewis (electron dot) structure, including formal charges, and shape for dinitrogen monoxide showing nitrogen as the central atom.
- 22N.2.hl.TZ0.2b: State the number of sp2 hybridized carbons in chloroquine.
- 22N.2.hl.TZ0.2b: State the number of sp2 hybridized carbons in chloroquine.
- 22N.2.hl.TZ0.b: State the number of sp2 hybridized carbons in chloroquine.
-
22N.2.hl.TZ0.5c:
Deduce the Lewis (electron dot) structure for sulfur dioxide.
-
22N.2.hl.TZ0.5c:
Deduce the Lewis (electron dot) structure for sulfur dioxide.
-
22N.2.hl.TZ0.c:
Deduce the Lewis (electron dot) structure for sulfur dioxide.
- 22N.2.hl.TZ0.5f: SF4Cl2 can form two isomers, one which is polar and another non-polar. Deduce the 3-dimensional...
- 22N.2.hl.TZ0.5f: SF4Cl2 can form two isomers, one which is polar and another non-polar. Deduce the 3-dimensional...
- 22N.2.hl.TZ0.f: SF4Cl2 can form two isomers, one which is polar and another non-polar. Deduce the 3-dimensional...
- 17N.1.hl.TZ0.13: What is the hybridization state and electron domain geometry around the circled C, N and...
- 17N.1.hl.TZ0.13: What is the hybridization state and electron domain geometry around the circled C, N and...
-
17N.1.hl.TZ0.14:
How many sigma (σ) and pi (π) bonds are present in this molecule?
-
17N.1.hl.TZ0.14:
How many sigma (σ) and pi (π) bonds are present in this molecule?
- 18N.2.hl.TZ0.3b.ii: Determine the preferred Lewis structure based on the formal charge on the bromine atom, giving...
- 18N.2.hl.TZ0.3b.ii: Determine the preferred Lewis structure based on the formal charge on the bromine atom, giving...
- 18N.2.hl.TZ0.b.ii: Determine the preferred Lewis structure based on the formal charge on the bromine atom, giving...
-
19M.1.hl.TZ2.12:
How many sigma (σ) and pi (π) bonds are present in hydrogen cyanide, HCN?
-
19M.1.hl.TZ2.12:
How many sigma (σ) and pi (π) bonds are present in hydrogen cyanide, HCN?
-
20N.2.hl.TZ0.1e(iii):
s produce chlorine radicals. Write two successive propagation steps to show how chlorine radicals catalyse the depletion of ozone.
-
20N.2.hl.TZ0.e(iii):
s produce chlorine radicals. Write two successive propagation steps to show how chlorine radicals catalyse the depletion of ozone.
-
20N.2.hl.TZ0.1e(iii):
s produce chlorine radicals. Write two successive propagation steps to show how chlorine radicals catalyse the depletion of ozone.
- 21M.1.hl.TZ1.12: Which contain delocalised electrons? I. C6H5OHII. CH3COO−III. CO32− A. I and II only B. I...
- 21M.1.hl.TZ1.12: Which contain delocalised electrons? I. C6H5OHII. CH3COO−III. CO32− A. I and II only B. I...
-
21N.2.hl.TZ0.10a(i):
Distinguish between a sigma and pi bond.
-
21N.2.hl.TZ0.10a(i):
Distinguish between a sigma and pi bond.
-
21N.2.hl.TZ0.a(i):
Distinguish between a sigma and pi bond.
- 21N.2.hl.TZ0.10a(ii): Identify the hybridization of carbon in ethane, ethene and ethyne.
- 21N.2.hl.TZ0.10a(ii): Identify the hybridization of carbon in ethane, ethene and ethyne.
- 21N.2.hl.TZ0.a(ii): Identify the hybridization of carbon in ethane, ethene and ethyne.
-
22M.2.hl.TZ1.5a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
-
22M.2.hl.TZ1.5a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
-
22M.2.hl.TZ1.a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
- 22M.2.hl.TZ1.5a(iv): Deduce the hybridization of the central carbon atom in Compound A.
- 22M.2.hl.TZ1.5a(iv): Deduce the hybridization of the central carbon atom in Compound A.
- 22M.2.hl.TZ1.a(iv): Deduce the hybridization of the central carbon atom in Compound A.
-
22M.2.hl.TZ1.6a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
-
22M.2.hl.TZ1.6a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
-
22M.2.hl.TZ1.a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
- 22M.2.hl.TZ2.7b(iii): State the hybridization of the carbon atom in HCN.
- 22M.2.hl.TZ2.7b(iii): State the hybridization of the carbon atom in HCN.
- 22M.2.hl.TZ2.b(iii): State the hybridization of the carbon atom in HCN.
- 23M.1.HL.TZ1.13: Which types of hybridization are present in...
- 23M.1.HL.TZ1.13: Which types of hybridization are present in...
- 23M.1.HL.TZ1.33: Why does benzene undergo substitution more readily than addition? A. Benzene is unsaturated. B. ...
- 23M.1.HL.TZ1.33: Why does benzene undergo substitution more readily than addition? A. Benzene is unsaturated. B. ...
- 23M.1.HL.TZ1.34: What is the product of the reaction of but-2-ene with bromine? A. 1,2-dibromobutane B. ...
- 23M.1.HL.TZ1.34: What is the product of the reaction of but-2-ene with bromine? A. 1,2-dibromobutane B. ...
- 23M.1.HL.TZ1.35: Which molecule is optically active? A. 2,2-dichloropropane B. 1,2-dichloropropane C. ...
- 23M.1.HL.TZ1.35: Which molecule is optically active? A. 2,2-dichloropropane B. 1,2-dichloropropane C. ...
- 23M.1.HL.TZ1.36: Which pairs of reactants could produce the following intermediate? A. I and II only B. I...
- 23M.1.HL.TZ1.36: Which pairs of reactants could produce the following intermediate? A. I and II only B. I...
- 23M.1.HL.TZ1.37: Which terms describe the nitronium ion in the nitration of benzene? Type of...
- 23M.1.HL.TZ1.37: Which terms describe the nitronium ion in the nitration of benzene? Type of...
-
23M.1.HL.TZ1.39:
Which molecule produces this 1H-NMR spectrum?
[Source: SDBS, National Institute of Advanced Industrial Science and Technology.]
A. CH3COOCH3B. CH3COCH3
C. CH3CHO
D. CH3CH2CH3
-
23M.1.HL.TZ1.39:
Which molecule produces this 1H-NMR spectrum?
[Source: SDBS, National Institute of Advanced Industrial Science and Technology.]
A. CH3COOCH3B. CH3COCH3
C. CH3CHO
D. CH3CH2CH3
- 23M.1.SL.TZ1.21: Which change involves oxidation of N? A. NH3 to N2 B. NO2 to NO C. N2 to AlN D. NO2 to N2O4
- 23M.1.SL.TZ1.21: Which change involves oxidation of N? A. NH3 to N2 B. NO2 to NO C. N2 to AlN D. NO2 to N2O4
- 23M.2.HL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.SL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.i: Outline the meaning of homologous series.
- 23M.2.SL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.SL.TZ1.i: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.9a: Explain why a colorimeter set at a wavelength of 500 nm is not suitable to investigate reactions...
- 23M.2.HL.TZ1.9a: Explain why a colorimeter set at a wavelength of 500 nm is not suitable to investigate reactions...
- 23M.2.HL.TZ1.a: Explain why a colorimeter set at a wavelength of 500 nm is not suitable to investigate reactions...
-
23M.2.HL.TZ2.3a:
An electrolytic cell was set up using inert electrodes and a dilute aqueous solution of magnesium chloride, MgCl2 (aq).
-
23M.2.HL.TZ2.3a:
An electrolytic cell was set up using inert electrodes and a dilute aqueous solution of magnesium chloride, MgCl2 (aq).
-
23M.2.HL.TZ2.a:
An electrolytic cell was set up using inert electrodes and a dilute aqueous solution of magnesium chloride, MgCl2 (aq).
- 23M.2.HL.TZ2.7a: Identify the type of reaction.
- 23M.2.HL.TZ2.7a: Identify the type of reaction.
- 23M.2.HL.TZ2.a: Identify the type of reaction.
Sub sections and their related questions
14.1 Covalent bonding and electron domain and molecular geometries
-
17N.1.hl.TZ0.14:
How many sigma (σ) and pi (π) bonds are present in this molecule?
-
17N.2.hl.TZ0.4a:
Draw the Lewis (electron dot) structures of PF3 and PF5 and use the VSEPR theory to deduce the molecular geometry of each species including bond angles.
- 18M.1.hl.TZ1.13: Which can be represented with only one Lewis structure? A. CH2O B. C6H6 C. O3 D. ...
-
18M.2.hl.TZ1.1i:
The C–N bonds in urea are shorter than might be expected for a single C–N bond. Suggest, in terms of electrons, how this could occur.
-
18M.2.hl.TZ1.2g.i:
Describe how sigma (σ) and pi () bonds are formed.
-
18M.2.hl.TZ1.2g.ii:
Deduce the number of σ and bonds in a molecule of ethyne.
- 18M.1.hl.TZ2.12: Which molecule has an expanded octet? A. CO B. CO2 C. SF2 D. SF4
-
18M.1.hl.TZ2.13:
Which overlap of atomic orbitals leads to the formation of only a sigma (σ) bond?
I. s − p
II. p − p
III. s − s
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
18M.2.hl.TZ2.7c.i:
Carbon dioxide can be represented by at least two resonance structures, I and II.
Calculate the formal charge on each oxygen atom in the two structures.
-
18M.2.hl.TZ2.7c.ii:
Deduce, giving a reason, the more likely structure.
-
18M.2.hl.TZ2.7d:
Absorption of UV light in the ozone layer causes the dissociation of oxygen and ozone.
Identify, in terms of bonding, the molecule that requires a longer wavelength to dissociate.
-
18N.1.hl.TZ0.12:
What is the number of sigma (σ) and pi (π) bonds in the molecule (NC)2C=C(CN)2?
-
18N.2.hl.TZ0.3b.i:
Draw two Lewis (electron dot) structures for BrO3−.
- 18N.2.hl.TZ0.3b.ii: Determine the preferred Lewis structure based on the formal charge on the bromine atom, giving...
- 18N.2.hl.TZ0.6a.ii: Draw a diagram showing the delocalization of electrons in the conjugate base of butanoic acid.
-
19M.2.hl.TZ1.2e:
Outline why both C to O bonds in the conjugate base are the same length and suggest a value for them. Use section 10 of the data booklet.
-
19M.2.hl.TZ2.3a(ii):
Dinitrogen monoxide in the stratosphere is converted to nitrogen monoxide, NO (g).
Write two equations to show how NO (g) catalyses the decomposition of ozone.
-
19M.2.hl.TZ2.3d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
- 19M.1.hl.TZ1.12: Which species has delocalized electrons? A. OH− B. H2CO C. CO2 D. CO32−
- 19M.1.hl.TZ2.11: Which species has a square planar molecular geometry? A. SF4 B. XeF4 C. CF4 D. PF4+
-
19M.1.hl.TZ2.12:
How many sigma (σ) and pi (π) bonds are present in hydrogen cyanide, HCN?
- 19N.2.hl.TZ0.1e(i): Identify the steps which absorb ultraviolet light.
- 19N.2.hl.TZ0.1f: Ozone depletion is catalysed by nitrogen monoxide, NO, which is produced in aircraft and motor...
-
19N.2.hl.TZ0.6f(iii):
When excess ammonia is added to copper(II) chloride solution, the dark blue complex ion, [Cu(NH3)4(H2O)2]2+, forms.
State the molecular geometry of this complex ion, and the bond angles within it.
Molecular geometry:
Bond angles:
- 19N.1.hl.TZ0.13: Which atom does not obey the octet rule? A. C in CO2 B. F in BF3 C. O in H2O D. S in SF6
-
20N.1.hl.TZ0.11:
Which combination correctly describes the geometry of ?
-
20N.2.hl.TZ0.1e(iii):
s produce chlorine radicals. Write two successive propagation steps to show how chlorine radicals catalyse the depletion of ozone.
-
20N.2.hl.TZ0.2c:
State the number of sigma () and pi () bonds around the central carbon atom in molecule B.
- 21M.1.hl.TZ1.12: Which contain delocalised electrons? I. C6H5OHII. CH3COO−III. CO32− A. I and II only B. I...
- 21M.1.hl.TZ2.13: What is the electron domain geometry of Si in SiO2? A. bent B. linear C. square planar D. ...
-
21M.2.hl.TZ2.4d:
Draw diagrams to show how sigma (σ) and pi (π) bonds are formed between atoms.
-
21N.1.hl.TZ0.12:
Which molecules contain two pi () bonds?
I. HCN
II. H2CO3
III. H2C2O4
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
- 21N.2.hl.TZ0.3b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
-
21N.2.hl.TZ0.10a(i):
Distinguish between a sigma and pi bond.
-
22M.1.hl.TZ2.11:
What is the formal charge of the oxygen atom in H3O+?
A. −2
B. −1
C. 0
D. +1
- 22M.1.hl.TZ2.12: What is the molecular geometry of SF4? A. Tetrahedral B. Trigonal bipyramidal C. ...
-
22M.2.hl.TZ1.5a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
-
22M.2.hl.TZ1.6a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
-
22M.2.hl.TZ1.6a(iii):
Explain the relative lengths of the three bonds between N and O in nitric acid.
-
22M.2.hl.TZ2.7b(i):
Sketch the shape of one sigma () and one pi () bond.
-
22M.2.hl.TZ2.7b(ii):
Identify the number of sigma and pi bonds in HCN.
- 22N.1.hl.TZ0.10: Which elements are capable of forming expanded octets? I. NitrogenII. PhosphorusIII....
- 22N.1.hl.TZ0.11: Which molecule has a tetrahedral molecular geometry? A. HNO3 B. SF4 C. XeF4 D. XeO4
-
22N.2.hl.TZ0.1f.v:
Deduce the Lewis (electron dot) structure, including formal charges, and shape for dinitrogen monoxide showing nitrogen as the central atom.
-
22N.2.hl.TZ0.5c:
Deduce the Lewis (electron dot) structure for sulfur dioxide.
- 22N.2.hl.TZ0.5f: SF4Cl2 can form two isomers, one which is polar and another non-polar. Deduce the 3-dimensional...
- 23M.2.HL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.9a: Explain why a colorimeter set at a wavelength of 500 nm is not suitable to investigate reactions...
- 23M.2.HL.TZ2.7a: Identify the type of reaction.
- 23M.1.HL.TZ1.13: Which types of hybridization are present in...
- 23M.1.HL.TZ1.33: Why does benzene undergo substitution more readily than addition? A. Benzene is unsaturated. B. ...
- 23M.1.HL.TZ1.34: What is the product of the reaction of but-2-ene with bromine? A. 1,2-dibromobutane B. ...
- 23M.1.HL.TZ1.35: Which molecule is optically active? A. 2,2-dichloropropane B. 1,2-dichloropropane C. ...
- 23M.1.HL.TZ1.36: Which pairs of reactants could produce the following intermediate? A. I and II only B. I...
- 23M.1.HL.TZ1.37: Which terms describe the nitronium ion in the nitration of benzene? Type of...
-
23M.1.HL.TZ1.39:
Which molecule produces this 1H-NMR spectrum?
[Source: SDBS, National Institute of Advanced Industrial Science and Technology.]
A. CH3COOCH3B. CH3COCH3
C. CH3CHO
D. CH3CH2CH3
- 23M.2.SL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.1.SL.TZ1.21: Which change involves oxidation of N? A. NH3 to N2 B. NO2 to NO C. N2 to AlN D. NO2 to N2O4
-
19M.2.hl.TZ1.2e:
Outline why both C to O bonds in the conjugate base are the same length and suggest a value for them. Use section 10 of the data booklet.
-
19M.2.hl.TZ1.e:
Outline why both C to O bonds in the conjugate base are the same length and suggest a value for them. Use section 10 of the data booklet.
-
19M.2.hl.TZ2.3a(ii):
Dinitrogen monoxide in the stratosphere is converted to nitrogen monoxide, NO (g).
Write two equations to show how NO (g) catalyses the decomposition of ozone.
-
19M.2.hl.TZ2.3d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
-
19M.2.hl.TZ2.a(ii):
Dinitrogen monoxide in the stratosphere is converted to nitrogen monoxide, NO (g).
Write two equations to show how NO (g) catalyses the decomposition of ozone.
-
19M.2.hl.TZ2.d(i):
State what the presence of alternative Lewis structures shows about the nature of the bonding in the molecule.
- 19M.1.hl.TZ1.12: Which species has delocalized electrons? A. OH− B. H2CO C. CO2 D. CO32−
- 19M.1.hl.TZ2.11: Which species has a square planar molecular geometry? A. SF4 B. XeF4 C. CF4 D. PF4+
-
19M.1.hl.TZ2.12:
How many sigma (σ) and pi (π) bonds are present in hydrogen cyanide, HCN?
- 19N.2.hl.TZ0.1e(i): Identify the steps which absorb ultraviolet light.
- 19N.2.hl.TZ0.1f: Ozone depletion is catalysed by nitrogen monoxide, NO, which is produced in aircraft and motor...
- 19N.2.hl.TZ0.e(i): Identify the steps which absorb ultraviolet light.
- 19N.2.hl.TZ0.f: Ozone depletion is catalysed by nitrogen monoxide, NO, which is produced in aircraft and motor...
-
19N.2.hl.TZ0.6f(iii):
When excess ammonia is added to copper(II) chloride solution, the dark blue complex ion, [Cu(NH3)4(H2O)2]2+, forms.
State the molecular geometry of this complex ion, and the bond angles within it.
Molecular geometry:
Bond angles:
-
19N.2.hl.TZ0.f(iii):
When excess ammonia is added to copper(II) chloride solution, the dark blue complex ion, [Cu(NH3)4(H2O)2]2+, forms.
State the molecular geometry of this complex ion, and the bond angles within it.
Molecular geometry:
Bond angles:
- 19N.1.hl.TZ0.13: Which atom does not obey the octet rule? A. C in CO2 B. F in BF3 C. O in H2O D. S in SF6
-
20N.1.hl.TZ0.11:
Which combination correctly describes the geometry of ?
-
20N.2.hl.TZ0.1e(iii):
s produce chlorine radicals. Write two successive propagation steps to show how chlorine radicals catalyse the depletion of ozone.
-
20N.2.hl.TZ0.e(iii):
s produce chlorine radicals. Write two successive propagation steps to show how chlorine radicals catalyse the depletion of ozone.
-
20N.2.hl.TZ0.2c:
State the number of sigma () and pi () bonds around the central carbon atom in molecule B.
-
20N.2.hl.TZ0.c:
State the number of sigma () and pi () bonds around the central carbon atom in molecule B.
- 21M.1.hl.TZ1.12: Which contain delocalised electrons? I. C6H5OHII. CH3COO−III. CO32− A. I and II only B. I...
- 21M.1.hl.TZ2.13: What is the electron domain geometry of Si in SiO2? A. bent B. linear C. square planar D. ...
-
21M.2.hl.TZ2.4d:
Draw diagrams to show how sigma (σ) and pi (π) bonds are formed between atoms.
-
21M.2.hl.TZ2.d:
Draw diagrams to show how sigma (σ) and pi (π) bonds are formed between atoms.
-
21N.1.hl.TZ0.12:
Which molecules contain two pi () bonds?
I. HCN
II. H2CO3
III. H2C2O4
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
- 21N.2.hl.TZ0.3b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
- 21N.2.hl.TZ0.b(ii): Outline the reason why PCl5 is a non-polar molecule, while PCl4F is polar.
-
21N.2.hl.TZ0.10a(i):
Distinguish between a sigma and pi bond.
-
21N.2.hl.TZ0.a(i):
Distinguish between a sigma and pi bond.
-
22M.1.hl.TZ2.11:
What is the formal charge of the oxygen atom in H3O+?
A. −2
B. −1
C. 0
D. +1
- 22M.1.hl.TZ2.12: What is the molecular geometry of SF4? A. Tetrahedral B. Trigonal bipyramidal C. ...
-
22M.2.hl.TZ1.5a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
-
22M.2.hl.TZ1.a(iii):
State the number of (sigma) and (pi) bonds in Compound A.
-
22M.2.hl.TZ1.6a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
-
22M.2.hl.TZ1.6a(iii):
Explain the relative lengths of the three bonds between N and O in nitric acid.
-
22M.2.hl.TZ1.a(ii):
Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
-
22M.2.hl.TZ1.a(iii):
Explain the relative lengths of the three bonds between N and O in nitric acid.
-
22M.2.hl.TZ2.7b(i):
Sketch the shape of one sigma () and one pi () bond.
-
22M.2.hl.TZ2.7b(ii):
Identify the number of sigma and pi bonds in HCN.
-
22M.2.hl.TZ2.b(i):
Sketch the shape of one sigma () and one pi () bond.
-
22M.2.hl.TZ2.b(ii):
Identify the number of sigma and pi bonds in HCN.
- 22N.1.hl.TZ0.10: Which elements are capable of forming expanded octets? I. NitrogenII. PhosphorusIII....
- 22N.1.hl.TZ0.11: Which molecule has a tetrahedral molecular geometry? A. HNO3 B. SF4 C. XeF4 D. XeO4
-
22N.2.hl.TZ0.1f.v:
Deduce the Lewis (electron dot) structure, including formal charges, and shape for dinitrogen monoxide showing nitrogen as the central atom.
-
22N.2.hl.TZ0.f.v:
Deduce the Lewis (electron dot) structure, including formal charges, and shape for dinitrogen monoxide showing nitrogen as the central atom.
-
22N.2.hl.TZ0.5c:
Deduce the Lewis (electron dot) structure for sulfur dioxide.
- 22N.2.hl.TZ0.5f: SF4Cl2 can form two isomers, one which is polar and another non-polar. Deduce the 3-dimensional...
-
22N.2.hl.TZ0.c:
Deduce the Lewis (electron dot) structure for sulfur dioxide.
- 22N.2.hl.TZ0.f: SF4Cl2 can form two isomers, one which is polar and another non-polar. Deduce the 3-dimensional...
-
17N.1.hl.TZ0.14:
How many sigma (σ) and pi (π) bonds are present in this molecule?
-
17N.2.hl.TZ0.4a:
Draw the Lewis (electron dot) structures of PF3 and PF5 and use the VSEPR theory to deduce the molecular geometry of each species including bond angles.
-
17N.2.hl.TZ0.a:
Draw the Lewis (electron dot) structures of PF3 and PF5 and use the VSEPR theory to deduce the molecular geometry of each species including bond angles.
- 18M.1.hl.TZ1.13: Which can be represented with only one Lewis structure? A. CH2O B. C6H6 C. O3 D. ...
-
18M.2.hl.TZ1.1i:
The C–N bonds in urea are shorter than might be expected for a single C–N bond. Suggest, in terms of electrons, how this could occur.
-
18M.2.hl.TZ1.i:
The C–N bonds in urea are shorter than might be expected for a single C–N bond. Suggest, in terms of electrons, how this could occur.
-
18M.2.hl.TZ1.2g.i:
Describe how sigma (σ) and pi () bonds are formed.
-
18M.2.hl.TZ1.2g.ii:
Deduce the number of σ and bonds in a molecule of ethyne.
-
18M.2.hl.TZ1.g.i:
Describe how sigma (σ) and pi () bonds are formed.
-
18M.2.hl.TZ1.g.ii:
Deduce the number of σ and bonds in a molecule of ethyne.
- 18M.1.hl.TZ2.12: Which molecule has an expanded octet? A. CO B. CO2 C. SF2 D. SF4
-
18M.1.hl.TZ2.13:
Which overlap of atomic orbitals leads to the formation of only a sigma (σ) bond?
I. s − p
II. p − p
III. s − s
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
18M.2.hl.TZ2.7c.i:
Carbon dioxide can be represented by at least two resonance structures, I and II.
Calculate the formal charge on each oxygen atom in the two structures.
-
18M.2.hl.TZ2.7c.ii:
Deduce, giving a reason, the more likely structure.
-
18M.2.hl.TZ2.7d:
Absorption of UV light in the ozone layer causes the dissociation of oxygen and ozone.
Identify, in terms of bonding, the molecule that requires a longer wavelength to dissociate.
-
18M.2.hl.TZ2.c.i:
Carbon dioxide can be represented by at least two resonance structures, I and II.
Calculate the formal charge on each oxygen atom in the two structures.
-
18M.2.hl.TZ2.c.ii:
Deduce, giving a reason, the more likely structure.
-
18M.2.hl.TZ2.d:
Absorption of UV light in the ozone layer causes the dissociation of oxygen and ozone.
Identify, in terms of bonding, the molecule that requires a longer wavelength to dissociate.
- 23M.2.HL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.i: Outline the meaning of homologous series.
- 23M.2.HL.TZ1.9a: Explain why a colorimeter set at a wavelength of 500 nm is not suitable to investigate reactions...
- 23M.2.HL.TZ1.a: Explain why a colorimeter set at a wavelength of 500 nm is not suitable to investigate reactions...
- 23M.2.HL.TZ2.7a: Identify the type of reaction.
- 23M.2.HL.TZ2.a: Identify the type of reaction.
- 23M.1.HL.TZ1.13: Which types of hybridization are present in...
- 23M.1.HL.TZ1.33: Why does benzene undergo substitution more readily than addition? A. Benzene is unsaturated. B. ...
- 23M.1.HL.TZ1.34: What is the product of the reaction of but-2-ene with bromine? A. 1,2-dibromobutane B. ...
- 23M.1.HL.TZ1.35: Which molecule is optically active? A. 2,2-dichloropropane B. 1,2-dichloropropane C. ...
- 23M.1.HL.TZ1.36: Which pairs of reactants could produce the following intermediate? A. I and II only B. I...
- 23M.1.HL.TZ1.37: Which terms describe the nitronium ion in the nitration of benzene? Type of...
-
23M.1.HL.TZ1.39:
Which molecule produces this 1H-NMR spectrum?
[Source: SDBS, National Institute of Advanced Industrial Science and Technology.]
A. CH3COOCH3B. CH3COCH3
C. CH3CHO
D. CH3CH2CH3
- 23M.2.SL.TZ1.3ai: Outline the meaning of homologous series.
- 23M.2.SL.TZ1.i: Outline the meaning of homologous series.
- 23M.1.SL.TZ1.21: Which change involves oxidation of N? A. NH3 to N2 B. NO2 to NO C. N2 to AlN D. NO2 to N2O4
-
18N.1.hl.TZ0.12:
What is the number of sigma (σ) and pi (π) bonds in the molecule (NC)2C=C(CN)2?
-
18N.2.hl.TZ0.3b.i:
Draw two Lewis (electron dot) structures for BrO3−.
- 18N.2.hl.TZ0.3b.ii: Determine the preferred Lewis structure based on the formal charge on the bromine atom, giving...
-
18N.2.hl.TZ0.b.i:
Draw two Lewis (electron dot) structures for BrO3−.
- 18N.2.hl.TZ0.b.ii: Determine the preferred Lewis structure based on the formal charge on the bromine atom, giving...
- 18N.2.hl.TZ0.6a.ii: Draw a diagram showing the delocalization of electrons in the conjugate base of butanoic acid.
- 18N.2.hl.TZ0.a.ii: Draw a diagram showing the delocalization of electrons in the conjugate base of butanoic acid.
14.2 Hybridization
- 17N.1.hl.TZ0.13: What is the hybridization state and electron domain geometry around the circled C, N and...
- 17N.2.hl.TZ0.4c: State the type of hybridization shown by the phosphorus atom in PF3.
- 18M.1.hl.TZ1.12: Which molecules have at least one sp2 hybridized atom? I. CH3COOH II. ...
- 18N.1.hl.TZ0.13: What is the hybridization of the circled carbon, oxygen and nitrogen atoms?
-
19M.2.hl.TZ1.5c(ii):
State the hybridization of the nitrogen atom in chloramine.
-
19M.2.hl.TZ2.3d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
- 19M.1.hl.TZ1.13: How many carbon atoms are sp3, sp2 and sp hybridized in the molecule?
- 19M.1.hl.TZ2.13: What is the hybridization of carbon and oxygen in methanol?
- 19N.1.hl.TZ0.12: Which atom is sp2 hybridized? A. C in H2CO B. C in CO2 C. N in CH3NH2 D. O in H2O
-
20N.2.hl.TZ0.2b:
State the type of hybridization shown by the central carbon atom in molecule B.
- 21M.1.hl.TZ1.13: In which series are all carbon atoms sp2 hybridized? A. C2H2 H2CO HCOOH B. C2H4 ...
- 21M.2.hl.TZ2.4c: State the hybridization of the carbon I and II atoms in but-2-ene.
- 21N.1.hl.TZ0.13: What is the hybridization of nitrogen and chlorine in NCl3?
- 21N.2.hl.TZ0.10a(ii): Identify the hybridization of carbon in ethane, ethene and ethyne.
- 22M.1.hl.TZ1.12: In which compound are all carbon atoms sp3 hybridized? A. C2H2 B. C2H2Cl2 C. C2Cl4 D. C2Cl6
- 22M.2.hl.TZ1.5a(iv): Deduce the hybridization of the central carbon atom in Compound A.
- 22M.2.hl.TZ2.7b(iii): State the hybridization of the carbon atom in HCN.
- 22N.2.hl.TZ0.2b: State the number of sp2 hybridized carbons in chloroquine.
-
19M.2.hl.TZ1.5c(ii):
State the hybridization of the nitrogen atom in chloramine.
-
19M.2.hl.TZ1.c(ii):
State the hybridization of the nitrogen atom in chloramine.
-
19M.2.hl.TZ2.3d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
-
19M.2.hl.TZ2.d(iii):
Deduce the hybridization of the central nitrogen atom in the molecule.
- 19M.1.hl.TZ1.13: How many carbon atoms are sp3, sp2 and sp hybridized in the molecule?
- 19M.1.hl.TZ2.13: What is the hybridization of carbon and oxygen in methanol?
- 19N.1.hl.TZ0.12: Which atom is sp2 hybridized? A. C in H2CO B. C in CO2 C. N in CH3NH2 D. O in H2O
-
20N.2.hl.TZ0.2b:
State the type of hybridization shown by the central carbon atom in molecule B.
-
20N.2.hl.TZ0.b:
State the type of hybridization shown by the central carbon atom in molecule B.
- 21M.1.hl.TZ1.13: In which series are all carbon atoms sp2 hybridized? A. C2H2 H2CO HCOOH B. C2H4 ...
- 21M.2.hl.TZ2.4c: State the hybridization of the carbon I and II atoms in but-2-ene.
- 21M.2.hl.TZ2.c: State the hybridization of the carbon I and II atoms in but-2-ene.
- 21N.1.hl.TZ0.13: What is the hybridization of nitrogen and chlorine in NCl3?
- 21N.2.hl.TZ0.10a(ii): Identify the hybridization of carbon in ethane, ethene and ethyne.
- 21N.2.hl.TZ0.a(ii): Identify the hybridization of carbon in ethane, ethene and ethyne.
- 22M.1.hl.TZ1.12: In which compound are all carbon atoms sp3 hybridized? A. C2H2 B. C2H2Cl2 C. C2Cl4 D. C2Cl6
- 22M.2.hl.TZ1.5a(iv): Deduce the hybridization of the central carbon atom in Compound A.
- 22M.2.hl.TZ1.a(iv): Deduce the hybridization of the central carbon atom in Compound A.
- 22M.2.hl.TZ2.7b(iii): State the hybridization of the carbon atom in HCN.
- 22M.2.hl.TZ2.b(iii): State the hybridization of the carbon atom in HCN.
- 22N.2.hl.TZ0.2b: State the number of sp2 hybridized carbons in chloroquine.
- 22N.2.hl.TZ0.b: State the number of sp2 hybridized carbons in chloroquine.
- 17N.1.hl.TZ0.13: What is the hybridization state and electron domain geometry around the circled C, N and...
- 17N.2.hl.TZ0.4c: State the type of hybridization shown by the phosphorus atom in PF3.
- 17N.2.hl.TZ0.c: State the type of hybridization shown by the phosphorus atom in PF3.
- 18M.1.hl.TZ1.12: Which molecules have at least one sp2 hybridized atom? I. CH3COOH II. ...
- 18N.1.hl.TZ0.13: What is the hybridization of the circled carbon, oxygen and nitrogen atoms?