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Question 19N.2.HL.TZ0.9b(i)

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Date November 2019 Marks available [Maximum mark: 3] Reference code 19N.2.HL.TZ0.9b(i)
Level HL Paper 2 Time zone TZ0
Command term Calculate Question number b(i) Adapted from N/A
b(i).
[Maximum mark: 3]
19N.2.HL.TZ0.9b(i)

X has a capacitance of 18 μF. X is charged so that the one plate has a charge of 48 μC. X is then connected to an uncharged capacitor Y and a resistor via an open switch S.

The capacitance of Y is 12 μF. S is now closed.

(b(i))

Calculate the final charge on X and the final charge on Y.

[3]

Markscheme

ALTERNATIVE 1
QX+QY=48 ✔

QX18=QY12 ✔

solving to get QX=29 «μC»  QY=19 «μC» ✔

 

ALTERNATIVE 2

48=18 V+12 V⇒V=1.6 «V»✔

QX=«1.6×18=» 29 «QX=1.6×18=29 «μC» ✔

QY=«1.6×12=» 19 «μC» ✔

 

NOTE: Award [3] for bald correct answer

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