Question 20N.3.SL.TZ0.1
Date | November 2020 | Marks available | [Maximum mark: 9] | Reference code | 20N.3.SL.TZ0.1 |
Level | SL | Paper | 3 | Time zone | TZ0 |
Command term | Comment, Identify, Show that, Sketch, State, Suggest | Question number | 1 | Adapted from | N/A |
A spherical soap bubble is made of a thin film of soapy water. The bubble has an internal air pressure and is formed in air of constant pressure . The theoretical prediction for the variation of is given by the equation
where is a constant for the thin film and is the radius of the bubble.
Data for and were collected under controlled conditions and plotted as a graph showing the variation of with .
Suggest whether the data are consistent with the theoretical prediction.
[2]
«theory suggests» is proportional to ✓
graph/line of best fit is straight/linear «so yes»
OR
graph/line of best fit passes through the origin «so yes» ✓
MP1: Accept ‘linear’
MP2 do not award if there is any contradiction
eg: graph not proportional, does not pass through origin.
Many students obtained full marks here although a significant number did not acknowledge that the graph was through the origin and lost a mark.

Show that the value of is about 0.03.
[2]
gradient «»
OR
use of equation with coordinates of a point ✓
✓
MP1 allow gradients in range to
MP2 allow a range to for
Very well answered either by obtaining the gradient or replacing with the coordinates of a point.

Identify the fundamental units of .
[1]
✓
Accept
Although the question was specifically about the fundamental units, several candidates lost the mark by answering Pa m.

In order to find the uncertainty for , a maximum gradient line would be drawn. On the graph, sketch the maximum gradient line for the data.
[1]
straight line, gradient greater than line of best fit, and within the error bars ✓
Almost all candidates were able to draw the correct maximum gradient line.
The percentage uncertainty for is . State , with its absolute uncertainty.
[2]
« of » =
OR
« of » = ✓
rounds uncertainty to 1sf
OR
✓
Allow ECF from (b)(i)
Award [2] marks for a bald correct answer
Well answered. A significant number did not round the uncertainty to match the value of gamma.

The expected value of is . Comment on your result.
[1]
Experimental value matches this/correct, as expected value within the range ✓
OR
experimental value does not match/incorrect, as it is not within range ✓
