Question 18M.2.SL.TZ2.6
| Date | May 2018 | Marks available | [Maximum mark: 6] | Reference code | 18M.2.SL.TZ2.6 |
| Level | SL | Paper | 2 | Time zone | TZ2 |
| Command term | Describe, Draw, Identify, Show that, State | Question number | 6 | Adapted from | N/A |
Rutherford constructed a model of the atom based on the results of the alpha particle scattering experiment. Describe this model.
[2]
«most of» the mass of the atom is confined within a very small volume/nucleus
«all» the positive charge is confined within a very small volume/nucleus
electrons orbit the nucleus «in circular orbits»
[2 marks]
Rhodium-106 () decays into palladium-106 () by beta minus (β–) decay.
The binding energy per nucleon of rhodium is 8.521 MeV and that of palladium is 8.550 MeV.
State what is meant by the binding energy of a nucleus.
[1]
the energy needed to separate the nucleons of a nucleus
OR
energy released when a nucleus is formed from its nucleons
Allow neutrons AND protons for nucleons
Don’t allow constituent parts
[1 mark]
Show that the energy released in the β– decay of rhodium is about 3 MeV.
[1]
Q = 106 × 8.550 − 106 × 8.521 = 3.07 «MeV»
«Q ≈ 3 Me V»
[1 mark]
β– decay is described by the following incomplete Feynman diagram.
Draw a labelled arrow to complete the Feynman diagram.
[1]
line with arrow as shown labelled anti-neutrino/
Correct direction of the “arrow” is essential
The line drawn must be “upwards” from the vertex in the time direction i.e. above the horizontal
[1 mark]
Identify particle V.
[1]
V = W–
[1 mark]