DP Physics (last assessment 2024)

Question 19N.2.HL.TZ0.a

Date	November 2019	Marks available	[Maximum mark: 2]	Reference code	19N.2.HL.TZ0.a
Level	HL	Paper	2	Time zone	TZ0
Command term	Calculate	Question number	a	Adapted from	N/A

[Maximum mark: 2]

19N.2.HL.TZ0.a

X has a capacitance of 18 μF. X is charged so that the one plate has a charge of 48 μC. X is then connected to an uncharged capacitor Y and a resistor via an open switch S.

Calculate, in J, the energy stored in X with the switch S open.

[2]

Markscheme

$E = \frac{1}{2} \frac{Q^{2}}{C}$ OR $V = \frac{Q}{C}$ ✔

$E = « \frac{1}{2} \frac{(48 \times 10^{- 6})}{18 \times 10^{- 6}} = » 6.4 \times 10^{- 5} « J »$ ✔

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Additional higher level (AHL)

Additional higher level (AHL) » Topic 11: Electromagnetic induction » 11.3 – Capacitance

Additional higher level (AHL) » Topic 11: Electromagnetic induction

Question 19N.2.HL.TZ0.a

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