DP Physics (last assessment 2024)

Question 21N.2.HL.TZ0.3c.ii

Date	November 2021	Marks available	[Maximum mark: 2]	Reference code	21N.2.HL.TZ0.3c.ii
Level	HL	Paper	2	Time zone	TZ0
Command term	Determine	Question number	c.ii	Adapted from	N/A

c.ii.

[Maximum mark: 2]

21N.2.HL.TZ0.3c.ii

An uncharged parallel plate capacitor C is connected to a cell of emf 12 V, a resistor R and another resistor of resistance 20 MΩ.

(c.ii)

The switch is then connected to Y and C discharges through the 20 MΩ resistor. The voltage V_c drops to 50 % of its initial value in 5.0 s. Determine the capacitance of C.

[2]

Markscheme

$\frac{1}{2} = e^{- \frac{5.0}{20 \times 10^{6} C}}$ ✓

$C = 3.6 \times 10^{- 7}$ «F» ✓

Award [2] for a bald correct answer.

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Additional higher level (AHL)

Additional higher level (AHL) » Topic 11: Electromagnetic induction » 11.3 – Capacitance

Additional higher level (AHL) » Topic 11: Electromagnetic induction

Question 21N.2.HL.TZ0.3c.ii

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