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Question 22N.2.HL.TZ0.9b.i

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Date November 2022 Marks available [Maximum mark: 2] Reference code 22N.2.HL.TZ0.9b.i
Level HL Paper 2 Time zone TZ0
Command term Explain Question number b.i Adapted from N/A
b.i.
[Maximum mark: 2]
22N.2.HL.TZ0.9b.i

A parallel-plate capacitor of capacitance 1.5 × 10−10 F is made from two metal plates separated by an air gap of 1.0 mm. The capacitor is initially charged to a potential difference of 24 V.

The charged capacitor is disconnected from the voltage supply and the separation between the plates is increased to 4.0 mm.

(b.i)

Explain the change, if any, to the potential difference between the plates.

[2]

Markscheme

«from C=εAd» capacitance decreases «by factor 4 / to 3.8 × 10−11 F» ✓

«from V=qC» charge unchanged hence p.d. increases by factor 4 / to 96 «V» ✓

 

Award [1] max for a reasoning without numbers.

Examiners report

A well answered question though often lacking numerical detail.

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