DP Physics (last assessment 2024)

Question 18M.2.HL.TZ2.8a

Date	May 2018	Marks available	[Maximum mark: 1]	Reference code	18M.2.HL.TZ2.8a
Level	HL	Paper	2	Time zone	TZ2
Command term	Show that	Question number	a	Adapted from	N/A

[Maximum mark: 1]

18M.2.HL.TZ2.8a

A negatively charged thundercloud above the Earth’s surface may be modelled by a parallel plate capacitor.

M18/4/PHYSI/HP2/ENG/TZ2/08

The lower plate of the capacitor is the Earth’s surface and the upper plate is the base of the thundercloud.

The following data are available.

$\begin{array}{*{20}{l}} {{\text{Area of thundercloud base}}}&{ = 1.2 \times {{10}^8}{\text{ }}{{\text{m}}^2}} \\ {{\text{Charge on thundercloud base}}}&{ = -25{\text{ C}}} \\ {{\text{Distance of thundercloud base from Earth's surface}}}&{ = 1600{\text{ m}}} \\ {{\text{Permittivity of air}}}&{ = 8.8 \times {{10}^{ - 12}}{\text{ F }}{{\text{m}}^{ - 1}}} \end{array}$

(a)

Show that the capacitance of this arrangement is C = 6.6 × 10^–7 F.

[1]

Markscheme

C = «ε $\frac{A}{d}$ =» 8.8 × 10^–12 × $\frac{{1.2 \times {{10}^8}}}{{1600}}$

«C = 6.60 × 10^–7 F»

[1 mark]

Syllabus sections

Additional higher level (AHL)

Additional higher level (AHL) » Topic 11: Electromagnetic induction » 11.3 – Capacitance

Additional higher level (AHL) » Topic 11: Electromagnetic induction

Question 18M.2.HL.TZ2.8a

Select a Test

Syllabus sections

Confirm action