Question 22M.2.HL.TZ1.6
Date | May 2022 | Marks available | [Maximum mark: 11] | Reference code | 22M.2.HL.TZ1.6 |
Level | HL | Paper | 2 | Time zone | TZ1 |
Command term | Deduce, Draw, Explain, Show, State | Question number | 6 | Adapted from | N/A |
Nitric acid is usually produced by the oxidation of ammonia.
A mixture of nitric acid and sulfuric acid can be used to convert benzene to nitrobenzene, C6H5NO2.
Draw arrows in the boxes to represent the electron configuration of a nitrogen atom.
[1]
Accept all 2p electrons pointing downwards.
Accept half arrows instead of full arrows.
Drawing arrows in the boxes to represent the electron configuration of a nitrogen atom was done extremely well.

Deduce a Lewis (electron dot) structure of the nitric acid molecule, HNO3, that obeys the octet rule, showing any non-zero formal charges on the atoms.
[2]
bonds and non-bonding pairs correct ✔
formal charges correct ✔
Accept dots, crosses or lines to represent electron pairs.
Do not accept resonance structures with delocalised bonds/electrons.
Accept + and – sign respectively.
Do not accept a bond between nitrogen and hydrogen.
For an incorrect Lewis structure, allow ECF for non-zero formal charges.
Drawing the Lewis structure of HNO3 was performed extremely poorly with structures that included H bonded to N, no double bond or a combination of single, double and even a triple bond or incorrect structures with dotted lines to reflect resonance. Many did not calculate non-zero formal charges.

Explain the relative lengths of the three bonds between N and O in nitric acid.
[3]
Any three of:
two N-O same length/order ✔
delocalization/resonance ✔
N-OH longer «than N-O»
OR
N-OH bond order 1 AND N-O bond order 1½ ✔
Award [2 max] if bond strength, rather than bond length discussed.
Accept N-O between single and double bond AND N-OH single bond.
Poorly done; some explained relative bond strengths between N and O in HNO3, not relative lengths; others included generic answers such as triple bond is shortest, double bond is longer, single longest.

State a technique used to determine the length of the bonds between N and O in solid HNO3.
[1]
X-ray crystallography ✔
A majority could not state the technique to determine length of bonds; answers included NMR, IR, and such instead of X-ray crystallography.

Write an equation for the reaction between the acids to produce the electrophile, NO2+.
[1]
HNO3 + 2H2SO4 NO2+ + H3O+ + 2HSO4- ✔
Accept “HNO3 + H2SO4 NO2+ + H2O + HSO4-”.
Accept “HNO3 + H2SO4 H2NO3+ + HSO4-” AND “H2NO3+ NO2+ + H2O”.
Accept single arrows instead of equilibrium signs.
Many had difficulties writing the balanced equation(s) for the formation of the nitronium ion.

Draw the structural formula of the carbocation intermediate produced when this electrophile attacks benzene.
[1]
Accept any of the five structures.
Do not accept structures missing the positive charge.
Again, many had difficulty drawing the structural formula of the carbocation intermediate produced in the reaction.

Deduce the number of signals that you would expect in the 1H NMR spectrum of nitrobenzene and the relative areas of these.
[2]
Number of signals: three/3 ✔
Relative areas: 2 : 2 : 1 ✔
Deducing the number of signals in the 1H NMR spectrum of nitrobenzene, which depend on the number of different hydrogen environments, was done poorly. Also, instead of relative areas, the common answer included chemical shift (ppm) values.
