DP Chemistry (first assessment 2025)

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Question 19M.2.SL.TZ1.1

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Date May 2019 Marks available [Maximum mark: 7] Reference code 19M.2.SL.TZ1.1
Level SL Paper 2 Time zone TZ1
Command term Draw, Identify, State Question number 1 Adapted from N/A
1.
[Maximum mark: 7]
19M.2.SL.TZ1.1

Xylene is a derivative of benzene. One isomer is 1,4-dimethylbenzene.

Bromine reacts with alkanes.

(a)

State the number of 1H NMR signals for this isomer of xylene and the ratio in which they appear.

Number of signals:

Ratio:

[2]

Markscheme

Number of signals:
[✔]

Ratio:
3 : 2
OR
6 : 4 [✔]

 

Note: Accept any correct integer or fractional ratio.

Accept ratios in reverse order.

Examiners report

Most students gained M1 but very few gained M2, suggesting that the correct answer of 2 signals may have been a guess.

(b)

Draw the structure of one other isomer of xylene which retains the benzene ring.

[1]

Markscheme

  [✔]

Examiners report

Another isomer of xylene was generally correctly drawn, but some candidates drew the original compound.

(c(i))

Identify the initiation step of the reaction and its conditions.

[2]

Markscheme

Br2 → 2Br•  [✔]

«sun»light/UV/hv
OR
high temperature  [✔]

 

Note: Do not penalize missing radical symbol on Br.

Accept “homolytic fission of bromine” for M1.

Examiners report

Drawing or describing the homolytic fission of bromine was generally done well.

(c(ii))

1,4-dimethylbenzene reacts as a substituted alkane. Draw the structures of the two products of the overall reaction when one molecule of bromine reacts with one molecule of 1,4-dimethylbenzene.

[2]

Markscheme

  [✔]

HBr  [✔]

 

Note: Accept condensed formulae, such as CH3C6H4CH2Br.

Accept skeletal structures.

Examiners report

Very few students gained 2 marks finding hard to apply their knowledge of free radical substitution to a benzene containing compound. Many thought that the bromine will attach to the benzene ring or would substitute the alkyl group twice and not produce HBr.

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