Reactivity 1.4.4—As a reaction approaches equilibrium, ΔG becomes less negative and finally reaches zero. Perform calculations using the equation ΔG = ΔG⦵ + RT lnQ and its application to a system at equilibrium ΔG⦵ = −RT lnK.
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[N/A]Directly related questions
- 21N.1A.HL.TZ0.17: In which of the following situations is the forward reaction spontaneous? A. The equilibrium...
- 21N.1A.HL.TZ0.17: In which of the following situations is the forward reaction spontaneous? A. The equilibrium...
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21N.1A.HL.TZ0.23:
The graph shows Gibbs free energy of a mixture of N2O4 (g) and NO2 (g) in different proportions.
N2O4 (g) 2NO2 (g)
Which point shows the system at equilibrium?
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21N.1A.HL.TZ0.23:
The graph shows Gibbs free energy of a mixture of N2O4 (g) and NO2 (g) in different proportions.
N2O4 (g) 2NO2 (g)
Which point shows the system at equilibrium?
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21N.1A.HL.TZ0.23:
The graph shows Gibbs free energy of a mixture of N2O4 (g) and NO2 (g) in different proportions.
N2O4 (g) 2NO2 (g)
Which point shows the system at equilibrium?
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21N.1A.HL.TZ0.23:
The graph shows Gibbs free energy of a mixture of N2O4 (g) and NO2 (g) in different proportions.
N2O4 (g) 2NO2 (g)
Which point shows the system at equilibrium?
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21N.2.HL.TZ0.3c(iv):
Determine the equilibrium constant, K, for this reaction at 25 °C, referring to section 1 of the data booklet.
If you did not obtain an answer in (c)(iii), use ΔG = –43.5 kJ mol−1, but this is not the correct answer.
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21N.2.HL.TZ0.3c(iv):
Determine the equilibrium constant, K, for this reaction at 25 °C, referring to section 1 of the data booklet.
If you did not obtain an answer in (c)(iii), use ΔG = –43.5 kJ mol−1, but this is not the correct answer.
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21N.2.HL.TZ0.c(iv):
Determine the equilibrium constant, K, for this reaction at 25 °C, referring to section 1 of the data booklet.
If you did not obtain an answer in (c)(iii), use ΔG = –43.5 kJ mol−1, but this is not the correct answer.
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21N.2.HL.TZ0.3c(iv):
Determine the equilibrium constant, K, for this reaction at 25 °C, referring to section 1 of the data booklet.
If you did not obtain an answer in (c)(iii), use ΔG = –43.5 kJ mol−1, but this is not the correct answer.
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21N.2.HL.TZ0.3c(iv):
Determine the equilibrium constant, K, for this reaction at 25 °C, referring to section 1 of the data booklet.
If you did not obtain an answer in (c)(iii), use ΔG = –43.5 kJ mol−1, but this is not the correct answer.
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21N.2.HL.TZ0.c(iv):
Determine the equilibrium constant, K, for this reaction at 25 °C, referring to section 1 of the data booklet.
If you did not obtain an answer in (c)(iii), use ΔG = –43.5 kJ mol−1, but this is not the correct answer.
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22M.2.HL.TZ2.4d(iv):
Calculate the equilibrium constant, Kc, for this reaction at 298 K. Use your answer to (d)(iii) and sections 1 and 2 of the data booklet.
(If you did not obtain an answer to (d)(iii) use a value of 2.0 kJ mol−1, although this is not the correct answer).
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22M.2.HL.TZ2.4d(iv):
Calculate the equilibrium constant, Kc, for this reaction at 298 K. Use your answer to (d)(iii) and sections 1 and 2 of the data booklet.
(If you did not obtain an answer to (d)(iii) use a value of 2.0 kJ mol−1, although this is not the correct answer).
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22M.2.HL.TZ2.d(iv):
Calculate the equilibrium constant, Kc, for this reaction at 298 K. Use your answer to (d)(iii) and sections 1 and 2 of the data booklet.
(If you did not obtain an answer to (d)(iii) use a value of 2.0 kJ mol−1, although this is not the correct answer).
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22M.2.HL.TZ2.4d(iv):
Calculate the equilibrium constant, Kc, for this reaction at 298 K. Use your answer to (d)(iii) and sections 1 and 2 of the data booklet.
(If you did not obtain an answer to (d)(iii) use a value of 2.0 kJ mol−1, although this is not the correct answer).
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22M.2.HL.TZ2.4d(iv):
Calculate the equilibrium constant, Kc, for this reaction at 298 K. Use your answer to (d)(iii) and sections 1 and 2 of the data booklet.
(If you did not obtain an answer to (d)(iii) use a value of 2.0 kJ mol−1, although this is not the correct answer).
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22M.2.HL.TZ2.d(iv):
Calculate the equilibrium constant, Kc, for this reaction at 298 K. Use your answer to (d)(iii) and sections 1 and 2 of the data booklet.
(If you did not obtain an answer to (d)(iii) use a value of 2.0 kJ mol−1, although this is not the correct answer).