Question 21N.2.SL.TZ0.4
| Date | November 2021 | Marks available | [Maximum mark: 8] | Reference code | 21N.2.SL.TZ0.4 |
| Level | SL | Paper | 2 | Time zone | TZ0 |
| Command term | Calculate, Describe, Determine, Draw | Question number | 4 | Adapted from | N/A |
A charged particle, P, of charge +68 μC is fixed in space. A second particle, Q, of charge +0.25 μC is held at a distance of 48 cm from P and is then released.
The diagram shows two parallel wires X and Y that carry equal currents into the page.
Point Q is equidistant from the two wires. The magnetic field at Q due to wire X alone is 15 mT.
The work done to move a particle of charge 0.25 μC from one point in an electric field to another is 4.5 μJ. Calculate the magnitude of the potential difference between the two points.
[1]
«» 18 «V» ✓
Determine the force on Q at the instant it is released.
[2]
✓
«N» ✓
Award [2] marks for a bald correct answer.
Allow symbolic k in substitutions for MP1.
Do not allow ECF from incorrect or not squared distance.
Describe the motion of Q after release.
[2]
Q moves to the right/away from P «along a straight line»
OR
Q is repelled from P ✓
with increasing speed/Q accelerates ✓
acceleration decreases ✓
On the diagram draw an arrow to show the direction of the magnetic field at Q due to wire X alone.
[1]
arrow of any length as shown ✓
Determine the magnitude and direction of the resultant magnetic field at Q.
[2]
«using components or Pythagoras to get» B = 21 «mT» ✓
directed «horizontally» to the right ✓
If no unit seen, assume mT.