DP Physics (first assessment 2025)

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Question 22N.2.HL.TZ0.5

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Date November 2022 Marks available [Maximum mark: 9] Reference code 22N.2.HL.TZ0.5
Level HL Paper 2 Time zone TZ0
Command term Calculate, Explain, Identify, Show that, State Question number 5 Adapted from N/A
5.
[Maximum mark: 9]
22N.2.HL.TZ0.5

Resistor R is connected in a circuit with a cell that has internal resistance.

The ammeter and the voltmeter are ideal.

The resistance of R is 50.0 Ω. The voltmeter reads 1.47 V.

Resistor R is replaced by another of resistance 10.0 Ω. The ammeter now reads 139 mA.

One of the connecting wires is placed in a magnetic field. The direction of the current in the wire is shown.

(a)

State what is meant by an ideal voltmeter.

[1]

Markscheme

infinite resistance

OR

no current is flowing through it ✓

Examiners report

A majority of candidates scored a mark by simply stating infinite resistance. Several answers went the other way round, stating a resistance of zero.

(b.i)

Calculate, in mA, the current in the resistor.

[1]

Markscheme

1.4750.0=29.4 «mA» ✓

Examiners report

Very well answered, with most candidates successfully answering in the required unit of mA.

(b.ii)

Show that the internal resistance of the cell is about 0.7 Ω.

[2]

Markscheme

29.4 (50.0 + r) = 139 (10.0 + r) ✓


attempt to solve for r, e.g. 29.4 × 50.0 − 139 × 10.0 = r (139 − 29.4)

OR

0.73 «Ω» ✓

 

Do not allow working backwards from 0.7 Ω.

Examiners report

Many answers here produced a number that did not round to 0.7 but students claimed it did. The simultaneous equation approach was seen in the best candidates, getting the right answer. It is worthy of reminding about the need of showing one more decimal place when calculating a show that value type of question.

(b.iii)

Calculate the emf of the cell.

[2]

Markscheme

139 × 10−3 (10.0 + 0.73)

OR

29.4 × 10−3 (50.0 + 0.73)  ✓


1.49 «V» ✓

 

Watch for ECF from 5(b)(i).

Examiners report

Usually well answered, regardless of b(ii), by utilising the show that value given.

(c.i)

Explain, by reference to charge carriers in the wire, how the magnetic force on the wire arises.

[2]

Markscheme

charge/carriers are moving in a magnetic field ✓

 

there is a magnetic force on them / quote F = qvB

OR

this creates a magnetic field that interacts with the external magnetic field ✓

 

Accept electrons.

For MP2, the force must be identified as acting on charge / carriers.

Examiners report

Many scored MP1 here but did not get MP2 as they jumped straight to the wire rather than continuing with the explanation of what was going on with the charge carriers.

(c.ii)

Identify the direction of the magnetic force on the wire.

[1]

Markscheme

into the plane «of the paper» ✓

Examiners report

Generally, a well answered question although there was some confusion on how to communicate it, with some contradictory answers indicating into or out, and also North or South at the same time.