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5.2 Further Differentiation

Question 1a

Marks: 2

Find an expression for the derivative of each of the following functions:

a)
f open parentheses x close parentheses equals open parentheses 12 x squared minus 7 close parentheses e to the power of negative 2 x end exponent
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    Question 1b

    Marks: 3
    b)
    g open parentheses x close parentheses equals fraction numerator tan 3 x over denominator 4 minus 5 x cubed end fraction
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      Question 1c

      Marks: 3
      c)
      h open parentheses x close parentheses equals open parentheses ln open parentheses 2 x squared minus x minus 2 close parentheses close parentheses to the power of 5
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        Question 1d

        Marks: 4
        d)
        j open parentheses x close parentheses equals fraction numerator 2 x to the power of negative 3 over 4 end exponent over denominator 1 minus x to the power of 3 over 5 end exponent end fraction
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          Question 2a

          Marks: 3

          Find an expression for the derivative of each of the following functions:

          a)
          f open parentheses x close parentheses equals open parentheses 3 x minus 1 close parentheses e to the power of sin space x end exponent D
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            Key Concepts
            Product Rule
            Chain Rule

            Question 2b

            Marks: 3
            b)
            g open parentheses x close parentheses equals ln open parentheses cos open parentheses x squared minus 1 close parentheses close parentheses
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              Question 2c

              Marks: 4
              c)
              h open parentheses x close parentheses equals fraction numerator negative sin open parentheses e to the power of negative x end exponent close parentheses over denominator e to the power of x cos x end exponent end fraction
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                Question 2d

                Marks: 4
                d)
                j open parentheses x close parentheses equals tan open parentheses fraction numerator 1 over denominator x squared space cube root of x end fraction close parentheses
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                  Question 3

                  Marks: 1

                  Consider the function f defined by f open parentheses x close parentheses equals negative x plus 2 over 3 sin cubed x comma space x element of straight real numbers

                  Show that f is decreasing everywhere on its domain.

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                    Question 4a

                    Marks: 4

                    Consider the function g defined by g open parentheses x close parentheses equals e to the power of 2 x end exponent minus 2 x comma space x element of straight real numbers

                    Point A is the point on the graph of g for which the x-coordinate is ln square root of 3  .

                    a)
                    Show that the equation of the tangent to the graph of gat point A may be expressed in the form 
                    y equals 4 x minus 3 open parentheses ln space 3 minus 1 close parentheses
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                      Question 4b

                      Marks: 5

                      Point B is the point on the graph of g at which the normal to the graph is vertical.

                      b)
                      Show that the coordinates of the point of intersection between the tangent to the graph of g at point A and the tangent to the graph of g at point B are
                      open parentheses fraction numerator 3 space ln space 3 minus 2 over denominator 4 end fraction comma 1 close parentheses

                       

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                        Question 5

                        Marks: 9

                        Consider the function h defined by h open parentheses x close parentheses equals sin space 3 x plus e to the power of 3 square root of 3 x end exponent cos space 3 x comma space x element of straight real numbers.

                        Show that the normal line to the graph of h at  x equals straight pi over 9 intercepts the y-axis at the point

                        open parentheses 0 comma fraction numerator 2 straight pi over denominator 27 end fraction plus fraction numerator square root of 3 plus e to the power of fraction numerator straight pi square root of 3 over denominator 3 end fraction end exponent over denominator 2 end fraction close parentheses

                         

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                          Question 6

                          Marks: 8

                          Let  f open parentheses x close parentheses equals g open parentheses x close parentheses h open parentheses x close parentheses,  where g and h are real-valued functions such that

                           g open parentheses x close parentheses equals ln open parentheses x over 3 close parentheses h open parentheses x close parentheses

                          for all x greater than 0.

                          Given that  h open parentheses 3 close parentheses equals a and h apostrophe open parentheses 3 close parentheses equals b,  where  a not equal to 0 comma find the distance between the  y-intercept of the tangent to the graph of f  at  x equals 3 and the y-intercept of the normal to the graph of f  at x equals 3.  Give your answer in terms of a  and/or b as appropriate.

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                            Question 7a

                            Marks: 1

                            Consider the curve with equation y equals cos open parentheses k x close parentheses e to the power of sin open parentheses k x close parentheses end exponent defined for all  x element of straight real numbers, where  k not equal to 0  is a positive integer.

                            a)
                            For the case where k equals 1, find the number of points in the interval negative straight pi over 2 less or equal than x less than fraction numerator 3 straight pi over denominator 2 end fraction at which the curve has a horizontal tangent.
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                              Key Concepts
                              Key Features of Graphs

                              Question 7b

                              Marks: 7
                              b)
                              i)
                              Show algebraically that in general the x-coordinates of the points at which the curve has horizontal tangents will be the solutions to the equation
                              sin squared open parentheses k x close parentheses plus sin open parentheses k x close parentheses minus 1 equals 0 
                              ii)
                              Hence, for the case where k equals 1, find the x-coordinates of the points identified in part (a).

                               

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                                Question 7c

                                Marks: 8
                                c)
                                i)
                                By considering fraction numerator straight d squared y over denominator d x squared end fraction, show algebraically that in general the x-coordinates of the points at which the curve is neither concave up nor concave down will be the solutions to the equation

                                 sin open parentheses k x close parentheses cos open parentheses k x close parentheses equals 0 

                                ii)
                                Hence, for the case where k equals 1, find the -coordinates of the points of inflection on the curve in the interval negative straight pi over 2 less or equal than x less than fraction numerator 3 straight pi over denominator 2 end fraction.
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                                  Question 7d

                                  Marks: 2
                                  d)
                                  In terms of k, state in general how many (i) turning points and (ii) points of inflection the curve will have in the interval negative straight pi over 2 less or equal than x less than fraction numerator 3 straight pi over denominator 2 end fraction.  Give a reason for your answers.
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                                    Key Concepts
                                    Using the Unit Circle

                                    Question 8

                                    Marks: 4

                                    Let f open parentheses x close parentheses equals fraction numerator g open parentheses x close parentheses over denominator h open parentheses x close parentheses end fraction,  where g  and h are well-defined functions with h open parentheses x close parentheses not equal to 0anywhere on their common domain. 

                                    By first writing f open parentheses x close parentheses equals g open parentheses x close parentheses open square brackets h open parentheses x close parentheses close square brackets to the power of negative 1 end exponent ,  use the product and chain rules to show that

                                    f open parentheses x close parentheses equals fraction numerator h open parentheses x close parentheses g apostrophe open parentheses x close parentheses minus g open parentheses x close parentheses h apostrophe open parentheses x close parentheses over denominator open square brackets h open parentheses x close parentheses close square brackets squared end fraction

                                     

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                                      Key Concepts
                                      Chain Rule
                                      Product Rule

                                      Question 9a

                                      Marks: 2

                                      Consider the function f defined by f open parentheses x close parentheses equals e to the power of x to the power of k end exponentx element of straight real numbers,  where k greater or equal than 1 is a positive integer.

                                      a)
                                      Show that the graph of f will have no points of inflection in the case where k equals 1.
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                                        Question 9b

                                        Marks: 5
                                        b)
                                        Show that, for k greater or equal than 2, the second derivative of is given by
                                        f " open parentheses x close parentheses equals k x to the power of k minus 2 end exponent open parentheses k x to the power of k plus k minus 1 close parentheses e to the power of x to the power of k end exponent

                                         

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                                          Key Concepts
                                          Chain Rule
                                          Product Rule

                                          Question 9c

                                          Marks: 7
                                          c)
                                          Hence show that the graph of f will only have points of inflection in the case where k is an odd integer greater than or equal to 3.  In that case, give the exact coordinates of the points of inflection, giving your answer in terms of k  where appropriate.  In your work you may use without proof the fact that for odd integers k with k greater or equal than 3
                                          negative 1 less than k-th root of negative fraction numerator k minus 1 over denominator k end fraction end root less than negative 1 half

                                           

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                                            Key Concepts
                                            Points of Inflection

                                            Question 10

                                            Marks: 7

                                            A small conical flask, in the shape of a right cone stood on its flat base, is being filled with perfume via a small hole at its vertex.  The cone has a height of 6 cm and a radius of 2 cm. 

                                            Perfume is being poured into the flask at a constant rate of 0.3 cm3s-1.

                                            Find the rate of change of the depth of the perfume in the flask at the instant when the flask is half full by volume.

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                                              Question 11

                                              Marks: 8

                                              A large block of ice is being prepared for use by a team of ice sculptors.  The block is in the shape of a cuboid with the ratio of its length to width to height being equal to  1 : 2 : 5. The block melts uniformly such that its surface area decreases at a constant rate, losing k space m squared of surface area every hour.  You may assume that as the block melts, its shape remains a cuboid with the dimensions in the same ratio to each other as in the original cuboid.

                                              The block of ice is considered stable enough to be sculpted so long as the loss of volume due to melting does not exceed a rate 0.05 space straight m cubed per hour. 

                                              Find, in terms of k, the volume of the largest block of ice that can be used for ice sculpting under such conditions.

                                               

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